[PHP] Function Not Working...Little help
Hello,
I am trying to get this function working but it gives me a PHP error
(blank page):
function Validate_Page_Nav($LastPage, $ErrorPage) {
$trimmed = str_replace($staffroot, '', $_SERVER['SCRIPT_NAME']);
$resul = $db->query("SELECT * FROM Page_Access WHERE URI =
'$trimmed'") or die("failed to get access data");
$page_access = $resul->fetch_assoc();
$URI_access = explode(",", $page_access['User_Level']);
if($_SESSION['Last_Page'] != $LastPage}) {
header("location: {$ErrorPage}?message=Unable to update user
information.");
exit();
}
if(in_array($_SESSION['Staff_level'], $URI_access)) {
echo "Access";
exit();
}else{
echo "No Access";
//header("location: {$ErrorPage}?message=Unable to update user
information.");
exit();
}
}
Validate_Page_Nav("user_list.php", "user_list.php");
There are parts of the code I was trying to debug.
Any help would be appreciated.
Don Wieland
D W D a t a C o n c e p t s
~
d...@dwdataconcepts.com
Direct Line - (949) 305-2771
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Re: [PHP] function not working after header call
Well, what can I say??? Magic windows Reboot the system or post a message and it works! johannes ""Johannes Janson"" <[EMAIL PROTECTED]> schrieb im Newsbeitrag 9d93c3$7d8$[EMAIL PROTECTED]">news:9d93c3$7d8$[EMAIL PROTECTED]... > Hi, > > I just don't get it...I have a form where the user enters name, surname > and a personal code. The action page checks for correct input which > is only letters for the two names and only numbers for the code. > If there is a wrong input in one of the fields a variable is set > which is then (amongst others) passed in the URL to the page containing > the form. > > formscript.php?code=1&name=1&surname=1&.. // for all three fields wrong, > if they are ok they aren't passed > > Now in order to highlight the fields with worng input I worte a > function. > > function wrong_input($var) > > global $var; > echo isset($var) ? " color=\"#FF\">" : ""; > } > > This function is called in the like this: > Code > > It is executed the first time but if the input is wrong and the user is sent > back to the form page it is not. > Desperately trying to get it to work I tried lots of combinations like using > print in the function or use > echo function($var) in the but nothing worked out. > > I'm completely stuck. > Any hlep is greately appreciated > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > To contact the list administrators, e-mail: [EMAIL PROTECTED] > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
[PHP] function not working after header call
Hi, I just don't get it...I have a form where the user enters name, surname and a personal code. The action page checks for correct input which is only letters for the two names and only numbers for the code. If there is a wrong input in one of the fields a variable is set which is then (amongst others) passed in the URL to the page containing the form. formscript.php?code=1&name=1&surname=1&.. // for all three fields wrong, if they are ok they aren't passed Now in order to highlight the fields with worng input I worte a function. function wrong_input($var) global $var; echo isset($var) ? "" : ""; } This function is called in the like this: Code It is executed the first time but if the input is wrong and the user is sent back to the form page it is not. Desperately trying to get it to work I tried lots of combinations like using print in the function or use echo function($var) in the but nothing worked out. I'm completely stuck. Any hlep is greately appreciated -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
Re: [PHP] function not working?
your function
function display_contents($table,$session)
{
$count = 0;
$result = mysql_query( "SELECT * FROM $table WHERE session = '$session'");
while($row = mysql_fetch_array($result))
{
$result_inv = mysql_query( "SELECT * FROM retailseafood WHERE pid =
'{$row['items']}' ");
$row_inventory = mysql_fetch_array($result_inv);
$contents['items'][$count] = $row_inventory['pid'];
$contents['price'][$count] = $row_inventory['price'];
$contents['total'][$count] = $row_inventory['price'] * $row['quantity'];
$count ++;
}
$total = $this->cart_total($table, $session);
$contents['final'] = $total;
return $contents;
}
looks ok, there are some code snippits missing ($this->cart_total()) but I'll assume
its rudamentry. the code you are missing is how your accually calling your function
View Contents Of Cart
is a url, you forgot to include the src of cart.php to see where you are accually
calling the function.
cart.php
please email me if you have more questions or comments.
--
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Mediawaveonline.com
ph. 250.377.1095
ph. 250.376.2690
fx. 250.554.1120
[EMAIL PROTECTED]
"Kurth Bemis" <[EMAIL PROTECTED]> wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
i can't get his function to work. i pass the correct data to it...but no
results
heres the function
function display_contents($table,$session)
{
$count = 0;
$result = mysql_query( "SELECT * FROM $table WHERE session='$session'");
while($row = mysql_fetch_array($result)){
$result_inv = mysql_query( "SELECT * FROM retailseafood WHERE
pid='$row[items]'");
$row_inventory = mysql_fetch_array($result_inv);
$contents[ "items"][$count] = $row_inventory[pid];
$contents[ "price"][$count] = $row_inventory[price];
//$contents[ "quantity"][$count] = $row[quantity];
$contents[ "total"][$count] = ($row_inventory[price] * $row[quantity]);
$count ++;
}
$total = $this->cart_total($table,$session);
$contents[ "final"] = $total;
return $contents;
}
// return number of items in cart
and heres what i do to call the function
View Contents Of Cart
what or where am i doing/going wrong?
~kurth
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[PHP] function not working?
i can't get his function to work. i pass the correct data to it...but no
results
heres the function
function display_contents($table,$session)
{
$count = 0;
$result = mysql_query( "SELECT * FROM $table WHERE
session='$session'");
while($row = mysql_fetch_array($result)){
$result_inv = mysql_query( "SELECT * FROM
retailseafood WHERE
pid='$row[items]'");
$row_inventory = mysql_fetch_array($result_inv);
$contents[ "items"][$count] = $row_inventory[pid];
$contents[ "price"][$count] = $row_inventory[price];
//$contents[ "quantity"][$count] = $row[quantity];
$contents[ "total"][$count] = ($row_inventory[price] *
$row[quantity]);
$count ++;
}
$total = $this->cart_total($table,$session);
$contents[ "final"] = $total;
return $contents;
}
// return number of items in cart
and heres what i do to call the function
View Contents Of Cart
what or where am i doing/going wrong?
~kurth
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