On Thu, 21 Nov 2002, Jason Wong wrote: > That's because it's expecting a _decimal_ and will automatically convert it to > hex for you.
AH! Must've been a longer day than I thought ... dunno how that escaped me. Somehow I was reading "x - the argument is treated as in integer and presented as a hexadecimal number" as if it meant the function would recognize the argument as a integer, even though it's in hex format (resembling a string). Thanks for clearing that up for me! ~Chris -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php