[PHP] imagecopy() no errors, but does nothing :-(
What I'm planning to do is to add the logo of the site over every image
uploaded.
Here is the code after upload:
$dst_im = @ImageCreateFromJPEG ("../".$pathImg.$NomeFile);
$src_im = @ImageCreateFromJPEG ("../imgsite/logo.jpg");
$dst_size = GetImageSize("../".$pathImg.$NomeFile);//800x600
$src_size = GetImageSize("../imgsite/logo.jpg");//50x50
ImageCopy( $dst_im, $src_im, 150, 150, 0, 0, 50, 50);
I don't get errors but it happens nothing to the original img ($dst_im).
The image logo.jpg is 50x50 and the $dst_img is 800x600.
Thanks for your help,
Evan
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[PHP] imagecopy or why men don't use maps.
Help! I have an image file which is a map of the local area. I want to put symbols on the map at various points, but I first need to get the php image function to work. My site has imaging enabled and I can create graphs from scratch, but this has stumped me so far. Any help will be greatly appreciated. Hugh code? below: $image=imagecreate(400,400); // created image // source image info $source="map1.jpg"; $imageinfo = getimagesize($source); $source_00=0; // origin (0,0) $source_width=$imageinfo[0]; $source_height-$imageinfo[1]; $image_00=0; // origin (0,0) imagecopy($image,$source, $image_00, $image_00, $source_00, $source_00, $source_width, $source_height); / / this is line 36. Warning: Supplied argument is not a valid Image resource in /www/site.com/somepage.php on line 36
[PHP] ImageCopy() not working
I created a function (appears below) that crops a JPG and outputs it on the
fly. However Apache crashes when I use the function. Unfortunately, Apache
does not put an error message in the logs.
I'm running it on a Windows2000 machine with Apache 1.3.20 and PHP 4.0.6
(installed via EasyPHP 1.5.0.0).
I've isolated the problem to be the ImageCopy() function, I'm sure of this.
If I use ImageCopyMerge() instead (with pct = 100), it works albeit with
varying results.
Has anyone else encountered this? Does anyone know how to fix it?
---snip---
function ImageCropJPEG( $src_file, $dst_file, $dst_width, $dst_height,
$quality = '100', $crop_type = 'r' ) {
// Must be a valid file
if ( is_file( $src_file ) ) {
// Get image dimensions
list( $src_width, $src_height, $src_type ) = @GetImageSize(
$src_file );
// Must be a valid JPEG
if ( is_set( $src_width ) && is_set( $src_height ) && $src_type ==
2 ) {
// Generate crop coords
switch ( $crop_type ) {
// Centered crop coords
case 'c':
$src_x = max( 1, floor( ( $src_width - $dst_width ) /
2 ) );
$src_y = max( 1, floor( ( $src_height - $dst_height ) /
2 ) );
break;
// Random crop coords
case 'r':
default:
$src_x = mt_rand( 0, max( 1, $src_width - $dst_width -
1 ) );
$src_y = mt_rand( 0, max( 1, $src_height -
$dst_height - 1 ) );
break;
}
// Create resources pointers for source and destination images
$src_image = ImageCreateFromJPEG( $src_file );
$dst_image = ImageCreate( $dst_width, $dst_height );
// Copy cropped portion of source image to destination image
ImageCopy( $dst_image, $src_image, 0, 0, $src_x, $src_y,
$dst_width, $dst_height );
#ImageCopyMerge( $dst_image, $src_image, 0, 0, $src_x, $src_y,
$dst_width, $dst_height, 100 ); // testing...
// Output to STDOUT
if ( empty( $dst_file ) ) {
header( 'Content-type: image/jpeg' );
}
// Output image
ImageJPEG( $dst_image, $dst_file, $quality );
// Free any memory associated the source and destination images
ImageDestroy( $src_image );
ImageDestroy( $dst_image );
}
}
return( TRUE );
}
---snip---
Forgive me if this has been asked before. I searched the archives but
couldn't find the answer.
TIA!
geoff.catlin
programmer#Q15439
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RE: [PHP] imageCopy :-(
Hello!
You should open "test.bmp" first.
Best regards,
Andrew Kirilenko.
> -Original Message-
> From: jtjohnston [mailto:[EMAIL PROTECTED]]
> Sent: Saturday, November 10, 2001 1:15 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP] imageCopy :-(
>
>
> Not that I'm sleep deprived ... :o)
>
> Simple, I create an image, add a bunch of text and what not.
> Now I want to add a graphic. (Probably a couple, who knows?)
>
> imageCopy("test.bmp",$image,10,10,10,10,350,500,50); <== doesn't
> work.
>
> Is this even the right function??
>
> Description:
> int ImageCopyMerge (resource dst_im, resource, src_im,
> int dst_x, = 10
> int dst_y, = 10
> int src_x, = 10
> int src_y, = 10
> int src_w, = 350
> int src_h, = 500
> int pct = 50
> )
>
> So what am I doing wrong?
>
> snip---
> header("Content-type: image/png");
>
> $height = 350;
> $width = 500;
> $image = imagecreate($width, $height+350);
>
> $white = imagecolorallocate($image, 255, 255, 255);
> $red = imagecolorallocate($image, 255, 0, 0);
> $green = ImageColorAllocate($image, 0, 255, 0);
> $blue = ImageColorAllocate($image, 0, 0, 255);
> $black = imagecolorallocate($image, 0, 0, 0);
>
> ImageString($image,5,30, 30 +350, "hello",$blue);
>
> imageCopy("test.bmp",$image,10,10,10,10,350,500,50);
>
> imagepng($image);
> imagedestroy($image);
>
>
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[PHP] imageCopy :-(
Not that I'm sleep deprived ... :o)
Simple, I create an image, add a bunch of text and what not.
Now I want to add a graphic. (Probably a couple, who knows?)
imageCopy("test.bmp",$image,10,10,10,10,350,500,50); <== doesn't
work.
Is this even the right function??
Description:
int ImageCopyMerge (resource dst_im, resource, src_im,
int dst_x, = 10
int dst_y, = 10
int src_x, = 10
int src_y, = 10
int src_w, = 350
int src_h, = 500
int pct = 50
)
So what am I doing wrong?
snip---
header("Content-type: image/png");
$height = 350;
$width = 500;
$image = imagecreate($width, $height+350);
$white = imagecolorallocate($image, 255, 255, 255);
$red = imagecolorallocate($image, 255, 0, 0);
$green = ImageColorAllocate($image, 0, 255, 0);
$blue = ImageColorAllocate($image, 0, 0, 255);
$black = imagecolorallocate($image, 0, 0, 0);
ImageString($image,5,30, 30 +350, "hello",$blue);
imageCopy("test.bmp",$image,10,10,10,10,350,500,50);
imagepng($image);
imagedestroy($image);
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[PHP] ImageCopy
I am creating an image on the fly based on newest entries in one my mySQL tables. In this created image I am trying to add a small one to it. Now I am TRYING to use the below code: $image = ImageCreate(500, 70); $bg = ImageColorAllocate($image, 255, 255, 255); $blue = ImageColorAllocate($image, 0, 0, 255); $black = ImageColorAllocate($image, 0, 0, 0); $himage= "usr/hyrum/public_html/images/topics/hyrum.gif"; ImageRectangle($image, 0, 0, 500, 70, $white); ImageString($image, 4, 0, 0, $text, $blue); ImageString($image, 3, 0, 20, $title1, $black); ImageString($image, 3, 0, 35, $title2, $black); ImageString($image, 3, 0, 50, $title3, $black); //ImageCopy($image, $himage, 400, 20, 1, 1, 60, 60) Imagepng($image, "signature.png"); ImageDestroy($image); Am I using ImageCopy incorrectly? It doesn't put anything in the new image. Jeff
