[PHP] need help breaking out of loop.

2003-06-26 Thread anders thoresson 
Hi,

I'm working of a PHP-MySQL-planning system for a newspaper. I want to add 
dates and number for each issue. I have to following code, where 
$current_date is a unix timestamp.

If $current_date is a Saturday or Sunday, I want to quit the current 
execution of the loop and contiune with the next date. But when the if- 
clause that checks if $issue_day_of_week is Sunday or Saturday is included 
in my while-loop, everything stalls. Without it, everything goes smooth.

What am I missing?

while ($i = $number_of_days)
{
$issue_date = strftime(%Y-%m-%d, $current_date);
$issue_month = date(m, $current_date);
$issue_day = date(d, $current_date);
$issue_day_of_week = date(l, $current_date);

// Check that $issue_date isn't Saturday or Sunday

if ($issue_day_of_week == Sunday | $issue_day_of_week == Saturday)
{
continue;
}

if ($issue_month == 1  $issue_day == 1)
{
$issue_number = 1;
$current_date = $current_date + 86400;
$i++;
$issue_number++;
continue;
}
$current_date = $current_date + 86400;  
$i++;
$issue_number++;
}
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anders thoresson
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RE: [PHP] need help breaking out of loop.[Scanned]

2003-06-26 Thread Michael Egan 
Anders,

Are you missing a '|' in the if condition?


Michael Egan

-Original Message-
From: anders thoresson [mailto:[EMAIL PROTECTED]
Sent: 26 June 2003 12:01
To: [EMAIL PROTECTED]
Subject: [PHP] need help breaking out of loop.[Scanned]


Hi,

 I'm working of a PHP-MySQL-planning system for a newspaper. I want to add 
dates and number for each issue. I have to following code, where 
$current_date is a unix timestamp.

 If $current_date is a Saturday or Sunday, I want to quit the current 
execution of the loop and contiune with the next date. But when the if- 
clause that checks if $issue_day_of_week is Sunday or Saturday is included 
in my while-loop, everything stalls. Without it, everything goes smooth.

 What am I missing?

while ($i = $number_of_days)
{
$issue_date = strftime(%Y-%m-%d, $current_date);
$issue_month = date(m, $current_date);
$issue_day = date(d, $current_date);
$issue_day_of_week = date(l, $current_date);

// Check that $issue_date isn't Saturday or Sunday

if ($issue_day_of_week == Sunday | $issue_day_of_week == Saturday)
{
continue;
}

if ($issue_month == 1  $issue_day == 1)
{
$issue_number = 1;
$current_date = $current_date + 86400;
$i++;
$issue_number++;
continue;
}
$current_date = $current_date + 86400;  
$i++;
$issue_number++;
}

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RE: [PHP] need help breaking out of loop.

2003-06-26 Thread Naintara Jain 
Are you incrementing number_of_days anywhere within the loop?

It looks like you have an infinite loop running. If you want to be able to
move to the next date, increment you date variable.
-Naintara


-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]
t]On Behalf Of anders thoresson
Sent: Thursday, June 26, 2003 4:31 PM
To: [EMAIL PROTECTED]
Subject: [PHP] need help breaking out of loop.


Hi,

 I'm working of a PHP-MySQL-planning system for a newspaper. I want to add
dates and number for each issue. I have to following code, where
$current_date is a unix timestamp.

 If $current_date is a Saturday or Sunday, I want to quit the current
execution of the loop and contiune with the next date. But when the if-
clause that checks if $issue_day_of_week is Sunday or Saturday is included
in my while-loop, everything stalls. Without it, everything goes smooth.

 What am I missing?

while ($i = $number_of_days)
{
$issue_date = strftime(%Y-%m-%d, $current_date);
$issue_month = date(m, $current_date);
$issue_day = date(d, $current_date);
$issue_day_of_week = date(l, $current_date);

// Check that $issue_date isn't Saturday or Sunday

if ($issue_day_of_week == Sunday | $issue_day_of_week == Saturday)
{
continue;
}

if ($issue_month == 1  $issue_day == 1)
{
$issue_number = 1;
$current_date = $current_date + 86400;
$i++;
$issue_number++;
continue;
}
$current_date = $current_date + 86400;
$i++;
$issue_number++;
}

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anders thoresson

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Re: [PHP] need help breaking out of loop.

2003-06-26 Thread David Otton 
On Thu, 26 Jun 2003 13:00:45 +0200, you wrote:

 What am I missing?

At first glance

while ($i = $number_of_days)
   {
   $issue_date = strftime(%Y-%m-%d, $current_date);
   $issue_month = date(m, $current_date);
   $issue_day = date(d, $current_date);
   $issue_day_of_week = date(l, $current_date);
   
   // Check that $issue_date isn't Saturday or Sunday
   
   if ($issue_day_of_week == Sunday | $issue_day_of_week == Saturday)

if ($issue_day_of_week == 'Sunday' || $issue_day_of_week == 'Saturday')

   {
   continue;
   }
   
   if ($issue_month == 1  $issue_day == 1)

if ($issue_month == 1  $issue_day == 1)

   {
   $issue_number = 1;
   $current_date = $current_date + 86400;
   $i++;
   $issue_number++;
   continue;
   }
   $current_date = $current_date + 86400;  
   $i++;
   $issue_number++;
   }


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