Good day.
What is this message that you get, that you don't want?
A cursory glance of the code reveals two "else" statements attached to the
same "if" statement. You should address that.
Darren Gamble
Planner, Regional Services
Shaw Cablesystems GP
630 - 3rd Avenue SW
Calgary, Alberta, Canada
T2P 4L4
(403) 781-4948
-Original Message-
From: Martha S [mailto:[EMAIL PROTECTED]]
Sent: Monday, March 25, 2002 9:44 AM
To: [EMAIL PROTECTED]
Subject: [PHP] undefined variable when using if ($var) {}
I'm rather new to PHP, so this should be fairly easy to answer. I checked
the manual and FAQ already.
I'm using the following code, and I get the following message if $id has
nothing in the var (i have it set to a default of type int, not null in
mysql). Is there a way around this or something I'm missing?
Thanks :)
-- code---
if ($id) {
$result = mysql_query("SELECT * FROM entries WHERE id=$id",$db);
$myrow = mysql_fetch_array($result);
printf("\n");
printf("%s", $myrow["title"]);
printf("%s | ", $myrow["id"]);
printf("%s", $myrow["posted"]);
printf("%s\n", $myrow["post"]);
printf("\n");
printf("all");
} else {
do {
printf("%s %s\n", $myrow["id"], $PHP_SELF,
$myrow["id"], $myrow["title"], $myrow["post"]);
} while ($myrow = mysql_fetch_array($result));
} else {
// no records to display
echo "Sorry, no records were found!";
}
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
