[PHP] unset array here?

2002-07-25 Thread Bas Jobsen

Hello,

I have this  example code:
function doprint($a){foreach($a as $value)echo $value;}
doprint(array('1','test','hello','and'));

Question, is the array in memory after the function call?
So, should it be better to use this:

function doprint($a){foreach($a as $value)echo $value;}
doprint($temp=array('1','test','hello','and'));
unset($temp);

Thanks,

Bas

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Re: [PHP] unset array here?

2002-07-25 Thread Analysis Solutions

On Thu, Jul 25, 2002 at 10:26:03PM +0200, Bas Jobsen wrote:
 Hello,
 
 I have this  example code:
 function doprint($a){foreach($a as $value)echo $value;}
 doprint(array('1','test','hello','and'));
 
 Question, is the array in memory after the function call?
 So, should it be better to use this:
 
 function doprint($a){foreach($a as $value)echo $value;}
 doprint($temp=array('1','test','hello','and'));
 unset($temp);

Depends on the scope you're talking about.  The first way doesn't set the
array into memory outside the function, but it goes into memory inside the
function as $a.  The second way puts it into memory twice, first as $temp
and second as $a.

Now, I'm not certain of what happens to your memory allocation inside the
function.  I don't believe PHP automatically cleans up memory under such
circumstances.  If I'm correct and you want to keep memory down, you could
do an unset() INSIDE the function.

--Dan

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