RE: [PHP] $_SESSIONS and printing off..

2003-02-18 Thread Rich Gray 
Er... well I've seen a lot worse code than that but maybe you could use ...

if (isset($_SESSION['username'])  !empty($_SESSION['username'])) {
echo 'Welcome '.$_SESSION['username'].', you are still logged in.';
}
else {
header... etc etc
}

Rich
 -Original Message-
 From: Frank Keessen [mailto:[EMAIL PROTECTED]]
 Sent: 18 February 2003 09:00
 To: [EMAIL PROTECTED]
 Subject: [PHP] $_SESSIONS and printing off..
 
 
 Hi All,
 
 I'm a little bit confused and it's maybe a newbie question but 
 maybe you can help me out;
 
 A user is login in and after username password check it will 
 redirects to this page
 
 ?php
 session_start();
 if (isset($_SESSION['username'])){
 $username = $_SESSION['username'];
 echo 'Welcome, you are still loged in.';
 echo $username;
 }
 else{
 header ( Location: login.htm );
 }
 ?
 
 Question is; is this the way to print of his username?
 
 $username = $_SESSION['username'];
 Echo $username
 
 Or has anyone some alternatives..
 
 This is working o.k. but in my opinion it's a little bit quick and dirty?
 
 Thanks for the comments and suggestions!
 
 Frank

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Re: [PHP] $_SESSIONS and printing off..

2003-02-18 Thread Frank Keessen 
Thanks,

But then another question;

 if (isset($_SESSION['username'])  !empty($_SESSION['username'])) {
 echo 'Welcome '.$_SESSION['username'].', you are still logged in.';


I want also checked if the level of authentication = 2; for example
User Frank = level 1
User Rich = level 2

I've set $_SESSION['level'] to 2 but how can i check that with the above
line?

Thanks for your help,

Frank

- Original Message -
From: Rich Gray [EMAIL PROTECTED]
To: Frank Keessen [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Tuesday, February 18, 2003 11:53 AM
Subject: RE: [PHP] $_SESSIONS and printing off..


 Er... well I've seen a lot worse code than that but maybe you could use
...

 if (isset($_SESSION['username'])  !empty($_SESSION['username'])) {
 echo 'Welcome '.$_SESSION['username'].', you are still logged in.';
 }
 else {
 header... etc etc
 }

 Rich
  -Original Message-
  From: Frank Keessen [mailto:[EMAIL PROTECTED]]
  Sent: 18 February 2003 09:00
  To: [EMAIL PROTECTED]
  Subject: [PHP] $_SESSIONS and printing off..
 
 
  Hi All,
 
  I'm a little bit confused and it's maybe a newbie question but
  maybe you can help me out;
 
  A user is login in and after username password check it will
  redirects to this page
 
  ?php
  session_start();
  if (isset($_SESSION['username'])){
  $username = $_SESSION['username'];
  echo 'Welcome, you are still loged in.';
  echo $username;
  }
  else{
  header ( Location: login.htm );
  }
  ?
 
  Question is; is this the way to print of his username?
 
  $username = $_SESSION['username'];
  Echo $username
 
  Or has anyone some alternatives..
 
  This is working o.k. but in my opinion it's a little bit quick and
dirty?
 
  Thanks for the comments and suggestions!
 
  Frank

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RE: [PHP] $_SESSIONS and printing off..

2003-02-18 Thread Rich Gray 
Um... how about...

echo 'Welcome '.$_SESSION['username'].', you are still logged in and your
authentication level is '.(isset($_SESSION['level']) ? $_SESSION['level'] :
'unknown');

Or am I missing something here?

Rich

 -Original Message-
 From: Frank Keessen [mailto:[EMAIL PROTECTED]]
 Sent: 18 February 2003 12:15
 To: Rich Gray; [EMAIL PROTECTED]
 Subject: Re: [PHP] $_SESSIONS and printing off..


 Thanks,

 But then another question;

  if (isset($_SESSION['username'])  !empty($_SESSION['username'])) {
  echo 'Welcome '.$_SESSION['username'].', you are still logged in.';


 I want also checked if the level of authentication = 2; for example
 User Frank = level 1
 User Rich = level 2

 I've set $_SESSION['level'] to 2 but how can i check that with the above
 line?

 Thanks for your help,

 Frank


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Re: [PHP] $_SESSIONS and printing off..

2003-02-18 Thread Frank Keessen 
Uh, sorry for the bad explanation Rich.. Again;

?php
session_start();
if (isset($_SESSION['username'])  !empty($_SESSION['username'])){
echo 'Welcome '.$_SESSION['username'].', you are still logged in.';
echo $_SESSION['woonplaats'];
}
else{
header ( Location: login.htm );
}
?

This is working fine. But i've set $_SESSION['level'] to value 2 (that's
done in the php file that calls this one). Now i want the above code to
check for the level and if is not equal to two than go to the else (back to
login.htm) statement..

better explained??? ;

Thanks,

Frank

- Original Message -
From: Rich Gray [EMAIL PROTECTED]
To: Frank Keessen [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Tuesday, February 18, 2003 1:25 PM
Subject: RE: [PHP] $_SESSIONS and printing off..


 Um... how about...

 echo 'Welcome '.$_SESSION['username'].', you are still logged in and your
 authentication level is '.(isset($_SESSION['level']) ? $_SESSION['level']
:
 'unknown');

 Or am I missing something here?

 Rich

  -Original Message-
  From: Frank Keessen [mailto:[EMAIL PROTECTED]]
  Sent: 18 February 2003 12:15
  To: Rich Gray; [EMAIL PROTECTED]
  Subject: Re: [PHP] $_SESSIONS and printing off..
 
 
  Thanks,
 
  But then another question;
 
   if (isset($_SESSION['username'])  !empty($_SESSION['username'])) {
   echo 'Welcome '.$_SESSION['username'].', you are still logged in.';
 
 
  I want also checked if the level of authentication = 2; for example
  User Frank = level 1
  User Rich = level 2
 
  I've set $_SESSION['level'] to 2 but how can i check that with the above
  line?
 
  Thanks for your help,
 
  Frank


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Re: [PHP] $_SESSIONS and printing off..

2003-02-18 Thread Ernest E Vogelsinger 
At 13:33 18.02.2003, Frank Keessen said:
[snip]
This is working fine. But i've set $_SESSION['level'] to value 2 (that's
done in the php file that calls this one). Now i want the above code to
check for the level and if is not equal to two than go to the else (back to
login.htm) statement..
[snip] 

?php
session_start();
if (isset($_SESSION['username'])  !empty($_SESSION['username'])
 $_SESSION['level'] == 2){
echo 'Welcome '.$_SESSION['username'].', you are still logged in.';
echo $_SESSION['woonplaats'];
}
else{
header ( Location: login.htm );
}
?


-- 
   O Ernest E. Vogelsinger
   (\)ICQ #13394035
^ http://www.vogelsinger.at/



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