RE: [PHP] Generate inline image
Hi: all: With helps from Martin, now I can create images on the fly. I used code like img src=\generateimage.php\ to create my images. However, with this option, how can I pass a variable to generateimage.php? The php scrip is supposed to take a variable: say ImageID and looks up the MySQL database for all values and then draw the graph. Anyone can give me some help? Thank you, Frank On Mon, 13 May 2002, Martin Towell wrote: yep, then in the file generateimage.php you'd have ? $im = imagecreate(...); // ... image creation code here header(Content-Type: image/png); // I do this anyway, I've found some browsers complain when you don't imagepng(); imagedestroy($im); ? obviously, the above code is for png, but you can use any that your gd library/broswer supports. -Original Message- From: Engineering Software Center [mailto:[EMAIL PROTECTED]] Sent: Monday, May 13, 2002 2:42 PM To: Martin Towell Cc: [EMAIL PROTECTED]; php Subject: RE: [PHP] Generate inline image Thanks for the reply. But how do I do that exactly? img src=\generateimage.php\ ? is this correct? HTML docs only contain text. If you want images inline then you use the img tag. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Generate inline image
How about the obvious way? img src=generateimage.php?id=3 -Rasmus On Tue, 28 May 2002, Engineering Software Center wrote: Hi: all: With helps from Martin, now I can create images on the fly. I used code like img src=\generateimage.php\ to create my images. However, with this option, how can I pass a variable to generateimage.php? The php scrip is supposed to take a variable: say ImageID and looks up the MySQL database for all values and then draw the graph. Anyone can give me some help? Thank you, Frank On Mon, 13 May 2002, Martin Towell wrote: yep, then in the file generateimage.php you'd have ? $im = imagecreate(...); // ... image creation code here header(Content-Type: image/png); // I do this anyway, I've found some browsers complain when you don't imagepng(); imagedestroy($im); ? obviously, the above code is for png, but you can use any that your gd library/broswer supports. -Original Message- From: Engineering Software Center [mailto:[EMAIL PROTECTED]] Sent: Monday, May 13, 2002 2:42 PM To: Martin Towell Cc: [EMAIL PROTECTED]; php Subject: RE: [PHP] Generate inline image Thanks for the reply. But how do I do that exactly? img src=\generateimage.php\ ? is this correct? HTML docs only contain text. If you want images inline then you use the img tag. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] Generate inline image
Your IMG tag calls a script (imagemaker.php) which generates the image for you the parent script (eg home.php) doesn't generate the image inline, to the best of my knowledge. Justin French on 13/05/02 10:01 AM, Engineering Software Center ([EMAIL PROTECTED]) wrote: Hi: How do I generate gif inline images using PHP's image functions using GD libs. Everything I have seen so far requires a header before generating the image. But I want the image embedded into a table with other texts. Thank you for the help. Frank -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Generate inline image
HTML docs only contain text. If you want images inline then you use the img tag. -Original Message- From: Justin French [mailto:[EMAIL PROTECTED]] Sent: Monday, May 13, 2002 10:31 AM To: [EMAIL PROTECTED]; php Subject: Re: [PHP] Generate inline image Your IMG tag calls a script (imagemaker.php) which generates the image for you the parent script (eg home.php) doesn't generate the image inline, to the best of my knowledge. Justin French on 13/05/02 10:01 AM, Engineering Software Center ([EMAIL PROTECTED]) wrote: Hi: How do I generate gif inline images using PHP's image functions using GD libs. Everything I have seen so far requires a header before generating the image. But I want the image embedded into a table with other texts. Thank you for the help. Frank -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Generate inline image
How do I generate gif inline images using PHP's image functions using GD libs. Everything I have seen so far requires a header before generating the image. But I want the image embedded into a table with other texts. Thank you for the help. Write the php to generate the image as a separate file. Then call that file from an image tag. Eg. img src=generate_image.php CYA, Dave -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Generate inline image
Thanks for the reply. But how do I do that exactly? img src=\generateimage.php\ ? is this correct? HTML docs only contain text. If you want images inline then you use the img tag. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] Generate inline image
yep, then in the file generateimage.php you'd have ? $im = imagecreate(...); // ... image creation code here header(Content-Type: image/png); // I do this anyway, I've found some browsers complain when you don't imagepng(); imagedestroy($im); ? obviously, the above code is for png, but you can use any that your gd library/broswer supports. -Original Message- From: Engineering Software Center [mailto:[EMAIL PROTECTED]] Sent: Monday, May 13, 2002 2:42 PM To: Martin Towell Cc: [EMAIL PROTECTED]; php Subject: RE: [PHP] Generate inline image Thanks for the reply. But how do I do that exactly? img src=\generateimage.php\ ? is this correct? HTML docs only contain text. If you want images inline then you use the img tag. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
