RE: [PHP] How can I access the value in a variable whos name is in a string

[Jonathan Rosenberg]

I'm a PHP amateur, but a quick perusal of Eval in the manual says

In PHP 4, eval() returns FALSE unless return() is
called in the evaluated code, in which case the
value passed to return() is returned. In PHP 3,
eval() does not return a value.

> -Original Message-
> From: Henry [mailto:[EMAIL PROTECTED]]
> Sent: Saturday, May 18, 2002 10:30 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP] How can I access the value in a 
> variable whos name is in
> a string
> 
> 
> Dear All,
> 
> $variablename="variable";
> eval("\$".$variablename."=13;");
> echo $variable;
> 
> This works fine!! It echoes "13";
> 
> But this doesn't ->
> 
> echo eval("\"$variablename\"");
> 
> Why??
> 
> 
> Henry
> 
> 
> 
> 
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> 
> 

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Re: [PHP] How can I access the value in a variable whos name is in a string

[The_RadiX]

simple..


try this:
echo eval($variablename);

then again why are you eval()ing at all??


why can't you do this:

$var1="var2";
$$var1=13;
echo $var2;

//or perhaps even better:
//echo $$var1;

seems simple enough.. haven't tested but theory is there I think..

HTH

:::
:  Julien Bonastre [The-Spectrum.org CEO]
:  A.K.A. The_RadiX
:  [EMAIL PROTECTED]
:  ABN: 64 235 749 494
:  QUT Student #: 04475739
:::
- Original Message -
From: "Henry" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Sunday, May 19, 2002 12:29 AM
Subject: [PHP] How can I access the value in a variable whos name is in a
string


> Dear All,
>
> $variablename="variable";
> eval("\$".$variablename."=13;");
> echo $variable;
>
> This works fine!! It echoes "13";
>
> But this doesn't ->
>
> echo eval("\"$variablename\"");
>
> Why??
>
>
> Henry
>
>
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>


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