Re: [PHP] Problems with Arrays and print and echo
John Wells wrote:
echo $this-name[5]\n;
echo $this-ID[5]\n;
$a1 = $this-name;
$a2 = $this-ID;
echo \n$a1[5] $a2[5]\n;
use curly brackets to help PHP understand what you're after:
echo {$this-name[5]}\n;
When you're in a string like this, PHP has a hard time knowing when
you're wanting to access a variable, and when you're simply trying to
output text. Using curly brackets clears it up.
HTH,
John W
Thanks.
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Re: [PHP] Problems with Arrays and print and echo
On 4/7/06, Michael Felt [EMAIL PROTECTED] wrote:
Slowly I am getting the output I want.
Trying to use dynamic arrays, does creat the array I want, but getting
the info is sometimes surprising.
I notice a difference between arrays used locally in a function, and
arrays used as a 'var' in a class function (all in PHP 4 atm).
Code snippet:
echo ROWS returned are: $max\n;
$this-count = $max;
while ($max--) {
$row = mysql_fetch_row($result);
$this-name[$max] = sprintf(%s, $row[0]);
$Name[$max] = sprintf(%s, $row[0]);
echo init \$this-Xame[$max] = $row[0];
echo $Name[$max] $this-name[$max]\n;
$regionID[$max] = $row[1];
$constellationID[$max] = $row[2];
$this-ID[$max] = $row[3];
printf(%d:%d/%d/%s\n,$max,$regionID[$max],$constellationID[$max],
$this-name[$max]);
}
Line wrap is messing things up a bit.
Was trying sprintf to see if the was a buffer problem coming from mysql.
Problem seems to be the same, regardless.
Also, the names changes ($this-name[] versus $Name[]) are deliberate,
for just in case
Output (debuging):
ROWS returned are: 7
init $this-Xame[6] = 8-TFDX 8-TFDX Array[6]
Is the problem that you're getting array[6] instead of the value?
Explain what you see and what you expect to see.
What is var $name originally set to, ie:
var $name = array(); (or '' or ) ?
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Re: [PHP] Problems with Arrays and print and echo
chris smith wrote:
On 4/7/06, Michael Felt [EMAIL PROTECTED] wrote:
Slowly I am getting the output I want.
Trying to use dynamic arrays, does creat the array I want, but getting
the info is sometimes surprising.
I notice a difference between arrays used locally in a function, and
arrays used as a 'var' in a class function (all in PHP 4 atm).
Code snippet:
echo ROWS returned are: $max\n;
$this-count = $max;
while ($max--) {
$row = mysql_fetch_row($result);
$this-name[$max] = sprintf(%s, $row[0]);
$Name[$max] = sprintf(%s, $row[0]);
echo init \$this-Xame[$max] = $row[0];
echo $Name[$max] $this-name[$max]\n;
$regionID[$max] = $row[1];
$constellationID[$max] = $row[2];
$this-ID[$max] = $row[3];
printf(%d:%d/%d/%s\n,$max,$regionID[$max],$constellationID[$max],
$this-name[$max]);
}
Line wrap is messing things up a bit.
Was trying sprintf to see if the was a buffer problem coming from mysql.
Problem seems to be the same, regardless.
Also, the names changes ($this-name[] versus $Name[]) are deliberate,
for just in case
Output (debuging):
ROWS returned are: 7
init $this-Xame[6] = 8-TFDX 8-TFDX Array[6]
Is the problem that you're getting array[6] instead of the value?
Explain what you see and what you expect to see.
What is var $name originally set to, ie:
$row = mysql_fetch_row($result);
$this-name[$max] = sprintf(%s, $row[0]);
$Name[$max] = sprintf(%s, $row[0]);
Is the actual assignment of variables. What surprises me is that the
'local' variable echos what I expect, but the 'class' variable does not.
function init($id)
{
$this-ID[0] = ERROR;
$this-name[0] = ;
Hope this answers your question.
And yes, I am not happy the the 'Array[X]' output, I am expecting the
value, not what it is.
I have already tried establishing an array type early in the function...
var $name = array(); (or '' or ) ?
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Re: [PHP] Problems with Arrays and print and echo
Michael Felt wrote:
OK . a rewrite, bit shorter...
1. A class construct with two arrays:
var $name;
var $ID;
function init($id) {
$this-name = array();
$this-ID = array();
# firther in code assignment done from a mysql database:
while ($max--)
read
$this-name[$max] = $row[0];
$this-ID[$max] = $row[1];
$Name[$max] = $row[0];
$ID[$max] = $row[1];
}
and now some debug code
print_r($this-name);
print_r($this-ID);
echo \n$Name[5]\n;
echo $this-name[5]\n;
echo $this-ID[5]\n;
$a1 = $this-name;
$a2 = $this-ID;
echo \n$a1[5] $a2[5]\n;
Output:
Array
(
[6] = 8-TFDX
[5] = B-E3KQ
[4] = BR-6XP
[3] = G5ED-Y
[2] = O-LR1H
[1] = UL-4ZW
[0] = Y5J-EU
)
Array
(
[6] = 3312
[5] = 3307
[4] = 3311
[3] = 3310
[2] = 3309
[1] = 3313
[0] = 3308
)
B-E3KQ
Array[5]
Array[5]
B-E3KQ 3307
chris smith wrote:
var $name = array(); (or '' or ) ?
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Re: [PHP] Problems with Arrays and print and echo
Michael Felt wrote:
echo \n. $this-name[5] . . $this-ID[5]. \n;
This give the same output as:
$a1 = $this-name;
$a2 = $this-ID;
echo \n$a1[5] $a2[5]\n;
Looks like I may need to use the '.' constructor more often
Who can explain this (please)?
Michael Felt wrote:
OK . a rewrite, bit shorter...
1. A class construct with two arrays:
var $name;
var $ID;
function init($id) {
$this-name = array();
$this-ID = array();
.
# firther in code assignment done from a mysql database:
while ($max--)
read
$this-name[$max] = $row[0];
$this-ID[$max] = $row[1];
$Name[$max] = $row[0];
$ID[$max] = $row[1];
}
and now some debug code
print_r($this-name);
print_r($this-ID);
echo \n$Name[5]\n;
echo $this-name[5]\n;
echo $this-ID[5]\n;
$a1 = $this-name;
$a2 = $this-ID;
echo \n$a1[5] $a2[5]\n;
Output:
Array
(
[6] = 8-TFDX
[5] = B-E3KQ
[4] = BR-6XP
[3] = G5ED-Y
[2] = O-LR1H
[1] = UL-4ZW
[0] = Y5J-EU
)
Array
(
[6] = 3312
[5] = 3307
[4] = 3311
[3] = 3310
[2] = 3309
[1] = 3313
[0] = 3308
)
B-E3KQ
Array[5]
Array[5]
B-E3KQ 3307
chris smith wrote:
var $name = array(); (or '' or ) ?
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Re: [PHP] Problems with Arrays and print and echo
echo $this-name[5]\n;
echo $this-ID[5]\n;
$a1 = $this-name;
$a2 = $this-ID;
echo \n$a1[5] $a2[5]\n;
use curly brackets to help PHP understand what you're after:
echo {$this-name[5]}\n;
When you're in a string like this, PHP has a hard time knowing when
you're wanting to access a variable, and when you're simply trying to
output text. Using curly brackets clears it up.
HTH,
John W
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Re: [PHP] Problems with arrays
Phpu wrote:
Hi,
I have this array:
$array = array(element1, element2, element3, element4)
I want to list all elements of this array, so i used:
foreach ($array as $index = $element) {
$InputString = $element;
echo $InputString;
}
but this code lists the elements like this: element1 element2 element3 element4
How can i list my elements like this:
element1
element2
element3
element4
That's not a problem with arrays. This is one with outputting. You need
to add a newline to your echo Statement. Either echo $InputString\n;
or echo $InputStringbr; depending on wether you use html or plain text.
Oliver
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Re: [PHP] Problems with arrays
What are you outputting? html, text, email body...??
- Original Message -
From: Phpu [EMAIL PROTECTED]
To: Oliver Hankeln [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 9:06 AM
Subject: Re: [PHP] Problems with arrays
I've tried this but it is not working ...
Thanks anyway
- Original Message -
From: Oliver Hankeln [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 4:04 PM
Subject: Re: [PHP] Problems with arrays
Phpu wrote:
Hi,
I have this array:
$array = array(element1, element2, element3, element4)
I want to list all elements of this array, so i used:
foreach ($array as $index = $element) {
$InputString = $element;
echo $InputString;
}
but this code lists the elements like this: element1 element2 element3
element4
How can i list my elements like this:
element1
element2
element3
element4
That's not a problem with arrays. This is one with outputting. You need
to add a newline to your echo Statement. Either echo $InputString\n;
or echo $InputStringbr; depending on wether you use html or plain
text.
Oliver
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Re: [PHP] Problems with arrays
I want the element of the array to be displayed in a select field
- Original Message -
From: Steve Douville [EMAIL PROTECTED]
To: Phpu [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 4:12 PM
Subject: Re: [PHP] Problems with arrays
What are you outputting? html, text, email body...??
- Original Message -
From: Phpu [EMAIL PROTECTED]
To: Oliver Hankeln [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 9:06 AM
Subject: Re: [PHP] Problems with arrays
I've tried this but it is not working ...
Thanks anyway
- Original Message -
From: Oliver Hankeln [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 4:04 PM
Subject: Re: [PHP] Problems with arrays
Phpu wrote:
Hi,
I have this array:
$array = array(element1, element2, element3, element4)
I want to list all elements of this array, so i used:
foreach ($array as $index = $element) {
$InputString = $element;
echo $InputString;
}
but this code lists the elements like this: element1 element2
element3
element4
How can i list my elements like this:
element1
element2
element3
element4
That's not a problem with arrays. This is one with outputting. You
need
to add a newline to your echo Statement. Either echo $InputString\n;
or echo $InputStringbr; depending on wether you use html or plain
text.
Oliver
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Re: [PHP] Problems with arrays
Can you give us the code from select to /select?
- Original Message -
From: Phpu [EMAIL PROTECTED]
To: Steve Douville [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 9:14 AM
Subject: Re: [PHP] Problems with arrays
I want the element of the array to be displayed in a select field
- Original Message -
From: Steve Douville [EMAIL PROTECTED]
To: Phpu [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 4:12 PM
Subject: Re: [PHP] Problems with arrays
What are you outputting? html, text, email body...??
- Original Message -
From: Phpu [EMAIL PROTECTED]
To: Oliver Hankeln [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 9:06 AM
Subject: Re: [PHP] Problems with arrays
I've tried this but it is not working ...
Thanks anyway
- Original Message -
From: Oliver Hankeln [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 4:04 PM
Subject: Re: [PHP] Problems with arrays
Phpu wrote:
Hi,
I have this array:
$array = array(element1, element2, element3, element4)
I want to list all elements of this array, so i used:
foreach ($array as $index = $element) {
$InputString = $element;
echo $InputString;
}
but this code lists the elements like this: element1 element2
element3
element4
How can i list my elements like this:
element1
element2
element3
element4
That's not a problem with arrays. This is one with outputting. You
need
to add a newline to your echo Statement. Either echo $InputString\n
;
or echo $InputStringbr; depending on wether you use html or
plain
text.
Oliver
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Re: [PHP] Problems with arrays
Here is the code:
select name=model class=gform onchange=model_jump('parent', this)
option value=0
?
foreach ($nav_model_names as $index = $element) {
$InputString = $element;
echo $InputString;
}
?/option
/select
- Original Message -
From: Steve Douville [EMAIL PROTECTED]
To: Phpu [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 4:23 PM
Subject: Re: [PHP] Problems with arrays
Can you give us the code from select to /select?
- Original Message -
From: Phpu [EMAIL PROTECTED]
To: Steve Douville [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 9:14 AM
Subject: Re: [PHP] Problems with arrays
I want the element of the array to be displayed in a select field
- Original Message -
From: Steve Douville [EMAIL PROTECTED]
To: Phpu [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 4:12 PM
Subject: Re: [PHP] Problems with arrays
What are you outputting? html, text, email body...??
- Original Message -
From: Phpu [EMAIL PROTECTED]
To: Oliver Hankeln [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 9:06 AM
Subject: Re: [PHP] Problems with arrays
I've tried this but it is not working ...
Thanks anyway
- Original Message -
From: Oliver Hankeln [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 4:04 PM
Subject: Re: [PHP] Problems with arrays
Phpu wrote:
Hi,
I have this array:
$array = array(element1, element2, element3, element4)
I want to list all elements of this array, so i used:
foreach ($array as $index = $element) {
$InputString = $element;
echo $InputString;
}
but this code lists the elements like this: element1 element2
element3
element4
How can i list my elements like this:
element1
element2
element3
element4
That's not a problem with arrays. This is one with outputting. You
need
to add a newline to your echo Statement. Either echo
$InputString\n
;
or echo $InputStringbr; depending on wether you use html or
plain
text.
Oliver
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Re: [PHP] Problems with arrays
I'm going to take a leap and make an assumption that what you want to end up
with is a select list of model names. I'm not sure what the value should be,
whether you want the value returned to you to be the $index the model or the
$element value. You can adjust either way. (By the way, you don't need to
set $InputString at all in this loop, you could just use $element.)
select name=model class=gform onchange=model_jump('parent', this)
option value=0/option
?
foreach ($nav_model_names as $index = $element) {
$InputString = $element;
echo option value=$InputString$InputString/option\n;
}
?
/select
Hope that helps.
Steve
- Original Message -
From: Phpu [EMAIL PROTECTED]
To: Steve Douville [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 9:26 AM
Subject: Re: [PHP] Problems with arrays
Here is the code:
select name=model class=gform onchange=model_jump('parent', this)
option value=0
?
foreach ($nav_model_names as $index = $element) {
$InputString = $element;
echo $InputString;
}
?/option
/select
- Original Message -
From: Steve Douville [EMAIL PROTECTED]
To: Phpu [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 4:23 PM
Subject: Re: [PHP] Problems with arrays
Can you give us the code from select to /select?
- Original Message -
From: Phpu [EMAIL PROTECTED]
To: Steve Douville [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 9:14 AM
Subject: Re: [PHP] Problems with arrays
I want the element of the array to be displayed in a select field
- Original Message -
From: Steve Douville [EMAIL PROTECTED]
To: Phpu [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 4:12 PM
Subject: Re: [PHP] Problems with arrays
What are you outputting? html, text, email body...??
- Original Message -
From: Phpu [EMAIL PROTECTED]
To: Oliver Hankeln [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 9:06 AM
Subject: Re: [PHP] Problems with arrays
I've tried this but it is not working ...
Thanks anyway
- Original Message -
From: Oliver Hankeln [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, June 17, 2004 4:04 PM
Subject: Re: [PHP] Problems with arrays
Phpu wrote:
Hi,
I have this array:
$array = array(element1, element2, element3, element4)
I want to list all elements of this array, so i used:
foreach ($array as $index = $element) {
$InputString = $element;
echo $InputString;
}
but this code lists the elements like this: element1 element2
element3
element4
How can i list my elements like this:
element1
element2
element3
element4
That's not a problem with arrays. This is one with outputting.
You
need
to add a newline to your echo Statement. Either echo
$InputString\n
;
or echo $InputStringbr; depending on wether you use html or
plain
text.
Oliver
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Re: [PHP] Problems with arrays
echo $InputString . 'BR'; // for HTML
echo $InputString\n; // for output to screen
Hi,
I have this array:
$array = array(element1, element2, element3, element4)
I want to list all elements of this array, so i used:
foreach ($array as $index = $element) {
$InputString = $element;
echo $InputString;
}
but this code lists the elements like this: element1 element2 element3 element4
How can i list my elements like this:
element1
element2
element3
element4
Thanks
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RE: [PHP] Problems with arrays
On 17 June 2004 14:27, Phpu wrote:
Here is the code:
select name=model class=gform
onchange=model_jump('parent', this)
option value=0
?
foreach ($nav_model_names as $index = $element) {
$InputString = $element;
echo $InputString;
}
/option
/select
Each option needs to be in, er, option/option tags, do you want something like:
foreach ($nav_model_names as $index = $element) {
echo option value='$index'$element/option\n;
}
Cheers!
Mike
-
Mike Ford, Electronic Information Services Adviser,
Learning Support Services, Learning Information Services,
JG125, James Graham Building, Leeds Metropolitan University,
Headingley Campus, LEEDS, LS6 3QS, United Kingdom
Email: [EMAIL PROTECTED]
Tel: +44 113 283 2600 extn 4730 Fax: +44 113 283 3211
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