RE: [PHP] RegExp question: how to add a number?
-Original Message-
From: Andre Polykanine [mailto:an...@oire.org]
Sent: 14 October 2010 21:42
Hi everyone,
I hope you're doing well (haven't written here for a long time :-)).
The question is as follows: I have a regexp that would do the
following. If the string begins with Re:, it will change the
beginning to Re[2]:; if it doesn't, then it would add Re: at the
beginning. But (attention, here it is!) if the string starts with
something like Re[4]:, it should replace it by Re[5]:.
Here's the code:
$start=mb_strtolower(mb_substr($f['Subject'], 0, 3));
if ($start==re:) {
$subject=preg_replace(/^re:(.+?)$/usi, re[2]:$1, $f['Subject']);
} elseif ($start==re[) {
// Here $1+1 doesn't work, it returns Re[4+1]:!
$subject=preg_replace(/^re\[(\d+)\]:(.+?)$/usi, re[$1+1]:$2,
$f['Subject']);
} else {
$subject=Re: .$f['Subject'];
}
I know there actually exists a way to do the numeral addition
(Re[5]:, not Re[4+1]:).
How do I manage to do this?
This looks like a job for the e modifier (see
http://php.net/manual/en/reference.pcre.pattern.modifiers.php, and example #4
at http://php.net/preg_replace). Something like:
$subject = preg_replace(/^re\[(\d+)\:](.+?)$/eusi, 're['.(\\1+1).']:\\2',
$f['Subject']);
Cheers!
Mike
--
Mike Ford,
Electronic Information Developer, Libraries and Learning Innovation,
Leeds Metropolitan University, C507 City Campus,
Woodhouse Lane, LEEDS, LS1 3HE, United Kingdom
Email: m.f...@leedsmet.ac.uk
Tel: +44 113 812 4730
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Re: [PHP] RegExp question: how to add a number?
On 15 October 2010 10:16, Ford, Mike m.f...@leedsmet.ac.uk wrote:
-Original Message-
From: Andre Polykanine [mailto:an...@oire.org]
Sent: 14 October 2010 21:42
Hi everyone,
I hope you're doing well (haven't written here for a long time :-)).
The question is as follows: I have a regexp that would do the
following. If the string begins with Re:, it will change the
beginning to Re[2]:; if it doesn't, then it would add Re: at the
beginning. But (attention, here it is!) if the string starts with
something like Re[4]:, it should replace it by Re[5]:.
Here's the code:
$start=mb_strtolower(mb_substr($f['Subject'], 0, 3));
if ($start==re:) {
$subject=preg_replace(/^re:(.+?)$/usi, re[2]:$1, $f['Subject']);
} elseif ($start==re[) {
// Here $1+1 doesn't work, it returns Re[4+1]:!
$subject=preg_replace(/^re\[(\d+)\]:(.+?)$/usi, re[$1+1]:$2,
$f['Subject']);
} else {
$subject=Re: .$f['Subject'];
}
I know there actually exists a way to do the numeral addition
(Re[5]:, not Re[4+1]:).
How do I manage to do this?
This looks like a job for the e modifier (see
http://php.net/manual/en/reference.pcre.pattern.modifiers.php, and example #4
at http://php.net/preg_replace). Something like:
$subject = preg_replace(/^re\[(\d+)\:](.+?)$/eusi,
're['.(\\1+1).']:\\2', $f['Subject']);
Cheers!
Mike
Watch out for the missing '[1]'. This needs to become '[2]' and not '[1]'.
The callback seems to be the only way I could get the regex to work.
--
Richard Quadling
Twitter : EE : Zend
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY
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Re: [PHP] RegExp question: how to add a number?
On Fri, Oct 15, 2010 at 5:52 AM, Richard Quadling rquadl...@gmail.com wrote:
On 15 October 2010 10:16, Ford, Mike m.f...@leedsmet.ac.uk wrote:
-Original Message-
From: Andre Polykanine [mailto:an...@oire.org]
Sent: 14 October 2010 21:42
Hi everyone,
I hope you're doing well (haven't written here for a long time :-)).
The question is as follows: I have a regexp that would do the
following. If the string begins with Re:, it will change the
beginning to Re[2]:; if it doesn't, then it would add Re: at the
beginning. But (attention, here it is!) if the string starts with
something like Re[4]:, it should replace it by Re[5]:.
Here's the code:
$start=mb_strtolower(mb_substr($f['Subject'], 0, 3));
if ($start==re:) {
$subject=preg_replace(/^re:(.+?)$/usi, re[2]:$1, $f['Subject']);
} elseif ($start==re[) {
// Here $1+1 doesn't work, it returns Re[4+1]:!
$subject=preg_replace(/^re\[(\d+)\]:(.+?)$/usi, re[$1+1]:$2,
$f['Subject']);
} else {
$subject=Re: .$f['Subject'];
}
I know there actually exists a way to do the numeral addition
(Re[5]:, not Re[4+1]:).
How do I manage to do this?
This looks like a job for the e modifier (see
http://php.net/manual/en/reference.pcre.pattern.modifiers.php, and example
#4 at http://php.net/preg_replace). Something like:
$subject = preg_replace(/^re\[(\d+)\:](.+?)$/eusi,
're['.(\\1+1).']:\\2', $f['Subject']);
Cheers!
Mike
Watch out for the missing '[1]'. This needs to become '[2]' and not '[1]'.
The callback seems to be the only way I could get the regex to work.
How about preg_replace_callback()?
Andrew
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Re: [PHP] RegExp question: how to add a number?
On 15 October 2010 15:45, Andrew Ballard aball...@gmail.com wrote:
On Fri, Oct 15, 2010 at 5:52 AM, Richard Quadling rquadl...@gmail.com wrote:
On 15 October 2010 10:16, Ford, Mike m.f...@leedsmet.ac.uk wrote:
-Original Message-
From: Andre Polykanine [mailto:an...@oire.org]
Sent: 14 October 2010 21:42
Hi everyone,
I hope you're doing well (haven't written here for a long time :-)).
The question is as follows: I have a regexp that would do the
following. If the string begins with Re:, it will change the
beginning to Re[2]:; if it doesn't, then it would add Re: at the
beginning. But (attention, here it is!) if the string starts with
something like Re[4]:, it should replace it by Re[5]:.
Here's the code:
$start=mb_strtolower(mb_substr($f['Subject'], 0, 3));
if ($start==re:) {
$subject=preg_replace(/^re:(.+?)$/usi, re[2]:$1, $f['Subject']);
} elseif ($start==re[) {
// Here $1+1 doesn't work, it returns Re[4+1]:!
$subject=preg_replace(/^re\[(\d+)\]:(.+?)$/usi, re[$1+1]:$2,
$f['Subject']);
} else {
$subject=Re: .$f['Subject'];
}
I know there actually exists a way to do the numeral addition
(Re[5]:, not Re[4+1]:).
How do I manage to do this?
This looks like a job for the e modifier (see
http://php.net/manual/en/reference.pcre.pattern.modifiers.php, and example
#4 at http://php.net/preg_replace). Something like:
$subject = preg_replace(/^re\[(\d+)\:](.+?)$/eusi,
're['.(\\1+1).']:\\2', $f['Subject']);
Cheers!
Mike
Watch out for the missing '[1]'. This needs to become '[2]' and not '[1]'.
The callback seems to be the only way I could get the regex to work.
How about preg_replace_callback()?
Andrew
Already provided an example using that : http://news.php.net/php.general/308728
It was the 'e' modifier I couldn't get to work, though I suppose, as
the code is eval'd, I should have been able to do it.
The callback just seems a LOT easier.
--
Richard Quadling
Twitter : EE : Zend
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY
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Re: [PHP] RegExp question: how to add a number?
On Fri, Oct 15, 2010 at 11:07 AM, Richard Quadling rquadl...@gmail.com wrote:
On 15 October 2010 15:45, Andrew Ballard aball...@gmail.com wrote:
On Fri, Oct 15, 2010 at 5:52 AM, Richard Quadling rquadl...@gmail.com
wrote:
On 15 October 2010 10:16, Ford, Mike m.f...@leedsmet.ac.uk wrote:
-Original Message-
From: Andre Polykanine [mailto:an...@oire.org]
Sent: 14 October 2010 21:42
Hi everyone,
I hope you're doing well (haven't written here for a long time :-)).
The question is as follows: I have a regexp that would do the
following. If the string begins with Re:, it will change the
beginning to Re[2]:; if it doesn't, then it would add Re: at the
beginning. But (attention, here it is!) if the string starts with
something like Re[4]:, it should replace it by Re[5]:.
Here's the code:
$start=mb_strtolower(mb_substr($f['Subject'], 0, 3));
if ($start==re:) {
$subject=preg_replace(/^re:(.+?)$/usi, re[2]:$1, $f['Subject']);
} elseif ($start==re[) {
// Here $1+1 doesn't work, it returns Re[4+1]:!
$subject=preg_replace(/^re\[(\d+)\]:(.+?)$/usi, re[$1+1]:$2,
$f['Subject']);
} else {
$subject=Re: .$f['Subject'];
}
I know there actually exists a way to do the numeral addition
(Re[5]:, not Re[4+1]:).
How do I manage to do this?
This looks like a job for the e modifier (see
http://php.net/manual/en/reference.pcre.pattern.modifiers.php, and example
#4 at http://php.net/preg_replace). Something like:
$subject = preg_replace(/^re\[(\d+)\:](.+?)$/eusi,
're['.(\\1+1).']:\\2', $f['Subject']);
Cheers!
Mike
Watch out for the missing '[1]'. This needs to become '[2]' and not '[1]'.
The callback seems to be the only way I could get the regex to work.
How about preg_replace_callback()?
Andrew
Already provided an example using that :
http://news.php.net/php.general/308728
It was the 'e' modifier I couldn't get to work, though I suppose, as
the code is eval'd, I should have been able to do it.
The callback just seems a LOT easier.
Sorry - I missed the callback function in there. The loop threw me off
because I thought that was part of the solution rather than a test
container.
Andrew
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Re: [PHP] RegExp question: how to add a number?
On Thu, Oct 14, 2010 at 1:42 PM, Andre Polykanine an...@oire.org wrote:
But (attention, here it is!) if the string starts with
something like Re[4]:, it should replace it by Re[5]:.
Regular expressions do not support any mathematical operations. Instead, you
need to use preg_match() to extract the number inside the brackets,
increment it, and build a new string using simple concatenation (.).
elseif ($start==re[) {
if (preg_match('/^re\[(\d+)\](.*)/i', $f['Subject'], $matches) 0)
{
$f['Subject'] = 'Re[' . ($matches[1] + 1) . ']' . $matches[2];
}
else {
// no closing brace -- now what?
}
}
David
Re: [PHP] RegExp question: how to add a number?
On 14 October 2010 21:42, Andre Polykanine an...@oire.org wrote:
Hi everyone,
I hope you're doing well (haven't written here for a long time :-)).
The question is as follows: I have a regexp that would do the
following. If the string begins with Re:, it will change the
beginning to Re[2]:; if it doesn't, then it would add Re: at the
beginning. But (attention, here it is!) if the string starts with
something like Re[4]:, it should replace it by Re[5]:.
Here's the code:
$start=mb_strtolower(mb_substr($f['Subject'], 0, 3));
if ($start==re:) {
$subject=preg_replace(/^re:(.+?)$/usi, re[2]:$1, $f['Subject']);
} elseif ($start==re[) {
// Here $1+1 doesn't work, it returns Re[4+1]:!
$subject=preg_replace(/^re\[(\d+)\]:(.+?)$/usi, re[$1+1]:$2,
$f['Subject']);
} else {
$subject=Re: .$f['Subject'];
}
I know there actually exists a way to do the numeral addition
(Re[5]:, not Re[4+1]:).
How do I manage to do this?
Thanks!
Can you adapt this ...
?php
$s_Text = 'Re: A dummy subject.';
foreach(range(1,10) as $i_Test)
{
echo $s_Text = preg_replace_callback
(
'`^Re(\[(\d++)\])?:`',
function($a_Match)
{
if (count($a_Match) == 1)
{
$i_Count = 2;
}
else
{
$i_Count = 1 + $a_Match[2];
}
return Re[$i_Count]:;
},
$s_Text
), PHP_EOL;
}
Outputs ...
Re[2]: A dummy subject.
Re[3]: A dummy subject.
Re[4]: A dummy subject.
Re[5]: A dummy subject.
Re[6]: A dummy subject.
Re[7]: A dummy subject.
Re[8]: A dummy subject.
Re[9]: A dummy subject.
Re[10]: A dummy subject.
Re[11]: A dummy subject.
--
Richard Quadling
Twitter : EE : Zend
@RQuadling : e-e.com/M_248814.html : bit.ly/9O8vFY
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