Re: [PHP] warning:supplied argument to mysql_fetch_array not valid resource type?
On Wednesday 07 April 2004 23:16, Andy B wrote: > anybody know why that is or what the deal is... i had to modify the query > set to read: > mysql_connect(...)||die(mysql_error())//works > $EditQuery="select * from $EventsTable where Id='$edit'"; > $query=mysql_query($EditQuery);//||die(mysql_error()) > //taken out (bug or something??) > mysql_error();//have no clue why its even there it will > //never get ran... > im running php 4.3.3 if it makes any difference on that part Please post the *full* and *concise* code which illustrates your problem. -- Jason Wong -> Gremlins Associates -> www.gremlins.biz Open Source Software Systems Integrators * Web Design & Hosting * Internet & Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* It's a funny thing that when a woman hasn't got anything on earth to worry about, she goes off and gets married. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] warning:supplied argument to mysql_fetch_array not valid resource type?
>[snip] >i have this query set: >$EditQuery="select * from $EventsTable where >Id='$edit'"; >$query=mysql_query($EditQuery)||die(mysql_error()); >[/snip] > >You forgot the connection string arguement in >mysql_query even after putting in my standard mysql_connect(.) stuff it still fails now the interesting thing here: normally i can do any mysql valid functions in php and append "||die(//whatever);" after it... but for some really odd reason mysql_query has a fit when i do that and for some reason it thinks im appending the litteral string "warning:" to the query itself... anybody know why that is or what the deal is... i had to modify the query set to read: mysql_connect(...)||die(mysql_error())//works $EditQuery="select * from $EventsTable where Id='$edit'"; $query=mysql_query($EditQuery);//||die(mysql_error()) //taken out (bug or something??) mysql_error();//have no clue why its even there it will //never get ran... im running php 4.3.3 if it makes any difference on that part -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] warning:supplied argument to mysql_fetch_array not valid resource type?
From: "Andy B" <[EMAIL PROTECTED]> > i have this query set: > $EditQuery="select * from $EventsTable where Id='$edit'"; > $query=mysql_query($EditQuery)||die(mysql_error()); > //later in the code i have this: > while($old=mysql_fetch_array($query)){ > //do stuff > } > when i run the page i get: > warning: supplied argument to mysql_fetch_array is not a valid mysql > resource type on line 98 You must be overwriting $query somewhere before you use it in mysql_fetch_array(). Do a var_dump() on $query just before you try to retrieve rows from it. ---John Holmes... -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] warning:supplied argument to mysql_fetch_array not valid resource type?
Andy B wrote: i have this query set: $EditQuery="select * from $EventsTable where Id='$edit'"; $query=mysql_query($EditQuery)||die(mysql_error()); //later in the code i have this: while($old=mysql_fetch_array($query)){ //do stuff } when i run the page i get: warning: supplied argument to mysql_fetch_array is not a valid mysql resource type on line 98 im lost i wrote this code hundreds of times and it always works... the query looks right : echo $EditQuery; output: select * from rnjresort.events where Id='1' and that is exactly what i want (i ran that exact string in mysql client) and it gave me what i was looking for... Did you select a database to run you query on? -- *** * _ __ __ __ _ * John Nichel * * | |/ /___ __ \ \/ /__ _ _| |__ ___ __ ___ _ __ * 716.856.9675 * * | ' http://www.KegWorks.com[EMAIL PROTECTED] * 14203 - 1321 * *** -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] warning:supplied argument to mysql_fetch_array not valid resource type?
On Wednesday 07 April 2004 22:56, Andy B wrote: > i have this query set: > $EditQuery="select * from $EventsTable where Id='$edit'"; > $query=mysql_query($EditQuery)||die(mysql_error()); > //later in the code i have this: > while($old=mysql_fetch_array($query)){ > //do stuff > } > when i run the page i get: > warning: supplied argument to mysql_fetch_array is not a valid mysql > resource type on line 98 Apparently $query contains something invalid, find out what it is and WHY. -- Jason Wong -> Gremlins Associates -> www.gremlins.biz Open Source Software Systems Integrators * Web Design & Hosting * Internet & Intranet Applications Development * -- Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general -- /* It's hard to think of you as the end result of millions of years of evolution. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
RE: [PHP] warning:supplied argument to mysql_fetch_array not valid resource type?
[snip] i have this query set: $EditQuery="select * from $EventsTable where Id='$edit'"; $query=mysql_query($EditQuery)||die(mysql_error()); [/snip] You forgot the connection string arguement in mysql_query -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php