Re: [PHP] OOP Newbie - why does this not work?
On 2005-10-21 06:17, Stephen Leaf wrote: most likely var is depreciated in php5. (can someone confirm this?) Well, if I try to use Var in a class i get this message: Strict Standards: var: Deprecated. Please use the public/private/protected modifiers in C:\code\test\var.php on line 3* /*Jesper* * -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Re: [PHP] OOP Newbie - why does this not work?
Bob,
'wrapping' you class definition within HTML like you have done is
not only weird but down right ugly. I recommend sticking each class
you write in a seperate file and using include_once() or require_once()
before you output anything to the browser. basically try to
seperate you code into 'stages' (for want of a better word) e.g.:
1. setup an environment (includes loading classes)
2. process the request
3. redirect or output a page
Bob Hartung wrote:
Hi all,
...
/head
body
br
PThis is outside the php code block/P
br
?php
echo Start defining the class here: BR ;
/* class Test
{
function __constructor()
{
var $saying ;
'var' doesn't belong here. it belongs directly in the body of class def.
$saying = Im in the Test Class ;
}
function get()
{
return $saying ;
there is a missing '}' here.
also you should be returning and setting $this-saying
}
var $liveclass ;
drop the 'var' - it's only for php4 and then only for
defining the properties of classes/objects:
class Test {
var $myProperty;
}
$liveclass = new Test ;
echo $liveclass-get() ;
echo BR ;
echo This is in the php code block ;
*/
?
/body
/html
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Re: [PHP] OOP Newbie - why does this not work?
would have to be.
http://smileaf.org/bob.php
as you can see it's working great.
did make few more changes:
class Test {
public $saying = ;
function __construct() {
$this-saying = I'm in the Test
Class. ;
}
function get() {
return $this-saying ;
}
}
when accessing a class variable _always_ in php use $this-
On Friday 21 October 2005 04:42 am, Bob Hartung wrote:
Stephen,
I copied your code and ran it. Same thing - a totally blank page.
Therefore I have to surmise that there is a a) bug in the rpm I
downloaded or more likely b) I have a conf setting wrong. I will
investigate further -- boy oh boy what a way to start! Every line of
code is a new chance to learn.
Thanks again,
Bob
snip all before
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Re: [PHP] OOP Newbie - why does this not work?
Try removing the /* and */
Other than that, check your brackets.
you never closed the get() function's
On Thursday 20 October 2005 09:35 pm, Bob Hartung wrote:
Hi all,
I'm trying to get started in OOP with PHP. I have the following
short code snipped. I'f I comment out the 'class Test' definition and
the following references to it, it prints
This is outside the php code block
and
Start defining the class here:
If I do not comment out the code as noted, then the page returned is
totally blank. It does this with or without using the constructor.
PHP 5 on apache. Same behavior both on Win32 and FC4.
All help appreciated to get me going.
Code Snippet:
html
head
titlePHP Class testing/title
/head
body
br
PThis is outside the php code block/P
br
?php
echo Start defining the class here: BR ;
/* class Test
{
function __constructor()
{
var $saying ;
$saying = Im in the Test Class ;
}
function get()
{
return $saying ;
}
var $liveclass ;
$liveclass = new Test ;
echo $liveclass-get() ;
echo BR ;
echo This is in the php code block ;
*/
?
/body
/html
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Re: [PHP] OOP Newbie - why does this not work?
Sorry.. 1 more thing.
php5 does not use var.
use public $variable=value; instead.
public is only within a class however. you cannot use it outside.
On Thursday 20 October 2005 09:35 pm, Bob Hartung wrote:
Hi all,
I'm trying to get started in OOP with PHP. I have the following
short code snipped. I'f I comment out the 'class Test' definition and
the following references to it, it prints
This is outside the php code block
and
Start defining the class here:
If I do not comment out the code as noted, then the page returned is
totally blank. It does this with or without using the constructor.
PHP 5 on apache. Same behavior both on Win32 and FC4.
All help appreciated to get me going.
Code Snippet:
html
head
titlePHP Class testing/title
/head
body
br
PThis is outside the php code block/P
br
?php
echo Start defining the class here: BR ;
/* class Test
{
function __constructor()
{
var $saying ;
$saying = Im in the Test Class ;
}
function get()
{
return $saying ;
}
var $liveclass ;
$liveclass = new Test ;
echo $liveclass-get() ;
echo BR ;
echo This is in the php code block ;
*/
?
/body
/html
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Re: [PHP] OOP Newbie - why does this not work?
Here is the working code
You had __constructor() it's __construct()
notice I also moved your saying declaration outside of the constructor.
this is to make it a class level variable.
the way that you had it set it was only in scope until you finished the
construct code.
I guess I was wrong about the var bit. I do remember having lots of issues
with it back a few months ago. perhaps theses were fixed in newer versions.
most likely var is depreciated in php5. (can someone confirm this?)
html
head
titlePHP Class testing/title
/head
body
br/
pThis is outside the php code block/p
br/
?php
echo Start defining the class here: br/ ;
class Test {
public $saying = ;
function __construct() {
$saying = Im in the Test Class ;
}
function get() {
return $saying ;
}
}
$liveclass = new Test ;
echo $liveclass-get() ;
echo br/ ;
echo This is in the php code block ;
?
/body
/html
On Thursday 20 October 2005 09:53 pm, Bob Hartung wrote:
Changed to:
var $saying ;
public $saying = .
Again, blank page. Funny though, even the title.../title html block
is not rendered. Again, same beavior on 2 FC4 and 1 Win32 install.
Tnx
Bob
Stephen Leaf wrote:
Sorry.. 1 more thing.
php5 does not use var.
use public $variable=value; instead.
public is only within a class however. you cannot use it outside.
On Thursday 20 October 2005 09:35 pm, Bob Hartung wrote:
Hi all,
I'm trying to get started in OOP with PHP. I have the following
short code snipped. I'f I comment out the 'class Test' definition and
the following references to it, it prints
This is outside the php code block
and
Start defining the class here:
If I do not comment out the code as noted, then the page returned is
totally blank. It does this with or without using the constructor.
PHP 5 on apache. Same behavior both on Win32 and FC4.
All help appreciated to get me going.
Code Snippet:
html
head
titlePHP Class testing/title
/head
body
br
PThis is outside the php code block/P
br
?php
echo Start defining the class here: BR ;
/*class Test
{
function __constructor()
{
var $saying ;
$saying = Im in the Test Class ;
}
function get()
{
return $saying ;
}
var $liveclass ;
$liveclass = new Test ;
echo $liveclass-get() ;
echo BR ;
echo This is in the php code block ;
*/
?
/body
/html
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