Re: [PHP] is_null question

[Jason White]

You can use:

if($row[1]){print Email:$row[1];}else{print  ;}

Jason White

- Original Message -
From: Matthew K. Gold [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, July 12, 2002 9:23 PM
Subject: [PHP] is_null question


 Hi Everyone,

 Here's my problem:  I'd like to make the printing of some text dependent
on
 whether or not a variable is null.  In the following example, when $row[1]
 is null, what gets printed on the page is Email: .  I'd like the
 script to not print Email: if row[1] is null.

 It looks like I should be using is_null(), but I'm not sure how to use it,
 especially since all of this is embedded in a print statement.

 while ($row = mysql_fetch_row ($result))
 {
  print (\ttr bgcolor=\#ff9900\\n\t\tth$row[0]/th\n/tr\n\ttr
 class=\default\ bgcolor=\#ff\\n\t\ttdp$row[10]/ppEmail:
a
 href=\mailto:$row[1]\;$row[1]/abr /Phone: $row[2]/p\n\npAddress:
 $row[3]br /$row[4]br /$row[5] $row[6] $row[7]/p pURL: a
 href=\$row[8]\ target=\_blank\$row[8]/a/p/td/tr);
 }


 Instead of just printing Email: $row[1], I'd like to test whether it's
null
 first--maybe something like this?

 if (is_null($row[1])) print   else print (Email: $row[0])

 but can I put that line inside of another print statement?  if so, do I
have
 to escape the quotation marks?  Please forgive my confusion--I'm new to
 programming in general and PHP in particular.

 Thanks in advance for your help.

 best,

 Matt


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Re: [PHP] is_null question

[Jason White]

My appologies, I didn't read clear through, your code block confused me :-)

What I usually do in a situation like this, although I'm new to PHP is.

$temp=Some stuff before Email;
if($row[1]){
$temp .= Email:$row[1];
}
$temp .= The rest of the stuff after Email;
print $temp;

Jason White

- Original Message -
From: Jason White [EMAIL PROTECTED]
To: Matthew K. Gold [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Friday, July 12, 2002 9:28 PM
Subject: Re: [PHP] is_null question


 You can use:

 if($row[1]){print Email:$row[1];}else{print  ;}

 Jason White

 - Original Message -
 From: Matthew K. Gold [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Friday, July 12, 2002 9:23 PM
 Subject: [PHP] is_null question


  Hi Everyone,
 
  Here's my problem:  I'd like to make the printing of some text dependent
 on
  whether or not a variable is null.  In the following example, when
$row[1]
  is null, what gets printed on the page is Email: .  I'd like the
  script to not print Email: if row[1] is null.
 
  It looks like I should be using is_null(), but I'm not sure how to use
it,
  especially since all of this is embedded in a print statement.
 
  while ($row = mysql_fetch_row ($result))
  {
   print (\ttr bgcolor=\#ff9900\\n\t\tth$row[0]/th\n/tr\n\ttr
  class=\default\ bgcolor=\#ff\\n\t\ttdp$row[10]/ppEmail:
 a
  href=\mailto:$row[1]\;$row[1]/abr /Phone:
$row[2]/p\n\npAddress:
  $row[3]br /$row[4]br /$row[5] $row[6] $row[7]/p pURL: a
  href=\$row[8]\ target=\_blank\$row[8]/a/p/td/tr);
  }
 
 
  Instead of just printing Email: $row[1], I'd like to test whether it's
 null
  first--maybe something like this?
 
  if (is_null($row[1])) print   else print (Email: $row[0])
 
  but can I put that line inside of another print statement?  if so, do I
 have
  to escape the quotation marks?  Please forgive my confusion--I'm new to
  programming in general and PHP in particular.
 
  Thanks in advance for your help.
 
  best,
 
  Matt
 
 
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  PHP General Mailing List (http://www.php.net/)
  To unsubscribe, visit: http://www.php.net/unsub.php
 
 


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