subject:"Re\: Re\[2\]\: \[PHP\] counting words in a string"

Re: Re[2]: [PHP] counting words in a string

2002-09-28 Thread Justin French


You need to look at a few options... one is regular expression (not my
forte), or perhaps winding through the string one character at a time,
writing a very simple state engine.

Justin French


on 28/09/02 4:47 PM, [EMAIL PROTECTED] ([EMAIL PROTECTED]) wrote:

 Hello Justin,
 
 That worked perfect but I have one more problem I need to know if one
 of the word is UNAVAILABLE I need to know if it is the first one or
 the second one. I don't know if there is any way to do this.
 1st 2nd
 $string =UNAVAILABLE AVAILABLE More Info;
 1st   2nd
 $string =AVAILABLE More Info UNAVAILABLE ;
 
 Friday, September 27, 2002, 11:22:42 PM, you wrote:
 
 
 JF if this is your SPECIFIC problem, putting a space at the beginning of
 $srch
 JF will help, eliminating XAVAILABLE... but this will cause a problem with
 the
 JF word AVAILABLE appearing at the start of the string, so temporarily put a
 JF space at the start of the string:
 
 JF ?
 JF // UNTESTED
 JF $count = substr_count(' '.strtolower($string), strtolower(' '.$srch));
 JF echo $count;
 ?
 
 JF this won't help if there are newlines and other white space instead of
 JF spaces, and won't help (so far) for a different set of circumstances...
 
 JF it would be nice to extend substr_count() could be extended to have an
 JF option.
 
 JF Justin
 
 
 
 JF on 28/09/02 3:41 PM, [EMAIL PROTECTED] ([EMAIL PROTECTED]) wrote:
 
 
 I need to count how many times the word AVAILABLE appears in a string
 like this
 $string =AVAILABLE More Info AVAILABLE More Info;
 some time the string looks like this
 $string =UNAVAILABLE More Info AVAILABLE More Info;
 or
 $string =AVAILABLE More Info UNAVAILABLE More Info;
 when I use
 $srch=AVAILABLE;
 $count=substr_count(strtolower($string), strtolower($srch));
 echo $count;
 it puts the count a 2 even when one of the words is UNAVAILABLE
 how can I make it only count AVAILABLE and not UNAVAILABLE or visa
 verse
 
 
 
 


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Re: Re[2]: [PHP] counting words in a string

2002-09-28 Thread debbie_dyer


You can get all the terms into an array using preg_match_all:-

$str = UNAVAILABLE More Info AVAILABLE More Info;
$regExp = /(?:UN)?AVAILABLE|More Info/;
preg_match_all($regExp, $str, $regs);

$regs[0] will contain the matched terms - you should then be able to use
array functions to do whatever else you need to do - counting, positions,
etc

Debbie

- Original Message -
From: Justin French [EMAIL PROTECTED]
To: Richard Kurth [EMAIL PROTECTED]; php-general
[EMAIL PROTECTED]
Sent: Saturday, September 28, 2002 6:26 PM
Subject: Re: Re[2]: [PHP] counting words in a string


 You need to look at a few options... one is regular expression (not my
 forte), or perhaps winding through the string one character at a time,
 writing a very simple state engine.

 Justin French


 on 28/09/02 4:47 PM, [EMAIL PROTECTED] ([EMAIL PROTECTED]) wrote:

  Hello Justin,
 
  That worked perfect but I have one more problem I need to know if one
  of the word is UNAVAILABLE I need to know if it is the first one or
  the second one. I don't know if there is any way to do this.
  1st 2nd
  $string =UNAVAILABLE AVAILABLE More Info;
  1st   2nd
  $string =AVAILABLE More Info UNAVAILABLE ;
 
  Friday, September 27, 2002, 11:22:42 PM, you wrote:
 
 
  JF if this is your SPECIFIC problem, putting a space at the beginning
of
  $srch
  JF will help, eliminating XAVAILABLE... but this will cause a problem
with
  the
  JF word AVAILABLE appearing at the start of the string, so temporarily
put a
  JF space at the start of the string:
 
  JF ?
  JF // UNTESTED
  JF $count = substr_count(' '.strtolower($string), strtolower('
'.$srch));
  JF echo $count;
  ?
 
  JF this won't help if there are newlines and other white space instead
of
  JF spaces, and won't help (so far) for a different set of
circumstances...
 
  JF it would be nice to extend substr_count() could be extended to have
an
  JF option.
 
  JF Justin
 
 
 
  JF on 28/09/02 3:41 PM, [EMAIL PROTECTED] ([EMAIL PROTECTED])
wrote:
 
 
  I need to count how many times the word AVAILABLE appears in a string
  like this
  $string =AVAILABLE More Info AVAILABLE More Info;
  some time the string looks like this
  $string =UNAVAILABLE More Info AVAILABLE More Info;
  or
  $string =AVAILABLE More Info UNAVAILABLE More Info;
  when I use
  $srch=AVAILABLE;
  $count=substr_count(strtolower($string), strtolower($srch));
  echo $count;
  it puts the count a 2 even when one of the words is UNAVAILABLE
  how can I make it only count AVAILABLE and not UNAVAILABLE or visa
  verse
 
 
 
 


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Re: Re[2]: [PHP] counting words in a string

2002-09-28 Thread olinux


wouldn't it be easier and more efficient to simply
count the number of spaces in the string (and add 1)?

using substr_count or something similar

olinux


--- Justin French [EMAIL PROTECTED] wrote:
 You need to look at a few options... one is regular
 expression (not my
 forte), or perhaps winding through the string one
 character at a time,
 writing a very simple state engine.
 
 Justin French
 
 
 on 28/09/02 4:47 PM, [EMAIL PROTECTED]
 ([EMAIL PROTECTED]) wrote:
 
  Hello Justin,
  
  That worked perfect but I have one more problem I
 need to know if one
  of the word is UNAVAILABLE I need to know if it is
 the first one or
  the second one. I don't know if there is any way
 to do this.
  1st 2nd
  $string =UNAVAILABLE AVAILABLE More Info;
  1st   2nd
  $string =AVAILABLE More Info UNAVAILABLE ;
  
  Friday, September 27, 2002, 11:22:42 PM, you
 wrote:
  
  
  JF if this is your SPECIFIC problem, putting a
 space at the beginning of
  $srch
  JF will help, eliminating XAVAILABLE... but this
 will cause a problem with
  the
  JF word AVAILABLE appearing at the start of the
 string, so temporarily put a
  JF space at the start of the string:
  
  JF ?
  JF // UNTESTED
  JF $count = substr_count(' '.strtolower($string),
 strtolower(' '.$srch));
  JF echo $count;
  ?
  
  JF this won't help if there are newlines and
 other white space instead of
  JF spaces, and won't help (so far) for a
 different set of circumstances...
  
  JF it would be nice to extend substr_count()
 could be extended to have an
  JF option.
  
  JF Justin
  
  
  
  JF on 28/09/02 3:41 PM, [EMAIL PROTECTED]
 ([EMAIL PROTECTED]) wrote:
  
  
  I need to count how many times the word
 AVAILABLE appears in a string
  like this
  $string =AVAILABLE More Info AVAILABLE More
 Info;
  some time the string looks like this
  $string =UNAVAILABLE More Info AVAILABLE More
 Info;
  or
  $string =AVAILABLE More Info UNAVAILABLE More
 Info;
  when I use
  $srch=AVAILABLE;
  $count=substr_count(strtolower($string),
 strtolower($srch));
  echo $count;
  it puts the count a 2 even when one of the words
 is UNAVAILABLE
  how can I make it only count AVAILABLE and not
 UNAVAILABLE or visa
  verse
  
  
  
  
 
 
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Re: Re[2]: [PHP] counting words in a string

Re: Re[2]: [PHP] counting words in a string

Re: Re[2]: [PHP] counting words in a string

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