SV: [PHP] Difficulty with SQL LIKE clause

2005-02-25 Thread Wiberg
Hi there!

A little off-topic but what the heck (it's a more MySQL - related question)

Is 197* a numbertype field?
Try maybe $query= SELECT * FROM my_table WHERE Year LIKE '197*';

/G
@varupiraten.se

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Från: David Freedman [mailto:[EMAIL PROTECTED]
Skickat: den 25 februari 2005 21:28
Till: php-general@lists.php.net
Ämne: [PHP] Difficulty with SQL LIKE clause


When I use this query in PHP it works, and I get all things with the YEAR of
1977, as I expected.

$query= SELECT * FROM my_table WHERE Year LIKE 1977 ;

But, when I use this query it does not work.

$query= SELECT * FROM my_table WHERE Year LIKE 197* ;

I thought I should get the result of ALL things with the years in the 1970's
(1970-1979).  But the asterisk in the LIKE clause does not seem to work.
I have tried various syntax's to try to get the 197* recognized but without
any luck.

Can the '*' be used? What am I doing wrong.

David F.



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Re: SV: [PHP] Difficulty with SQL LIKE clause

2005-02-25 Thread Andre Dubuc
On Friday 25 February 2005 04:28 pm, Wiberg wrote:
 Hi there!

 A little off-topic but what the heck (it's a more MySQL - related question)

 Is 197* a numbertype field?
 Try maybe $query= SELECT * FROM my_table WHERE Year LIKE '197*';

 /G
 @varupiraten.se

 -Ursprungligt meddelande-
 Från: David Freedman [mailto:[EMAIL PROTECTED]
 Skickat: den 25 februari 2005 21:28
 Till: php-general@lists.php.net
 Ämne: [PHP] Difficulty with SQL LIKE clause


 When I use this query in PHP it works, and I get all things with the YEAR
 of 1977, as I expected.

 $query= SELECT * FROM my_table WHERE Year LIKE 1977 ;

 But, when I use this query it does not work.

 $query= SELECT * FROM my_table WHERE Year LIKE 197* ;

 I thought I should get the result of ALL things with the years in the
 1970's (1970-1979).  But the asterisk in the LIKE clause does not seem to
 work. I have tried various syntax's to try to get the 197* recognized but
 without any luck.

 Can the '*' be used? What am I doing wrong.

 David F.


Try:

$query= SELECT * FROM my_table WHERE year ~* '^(197).*';

Hth,
Andre

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