php-general Digest 9 Sep 2012 17:00:10 -0000 Issue 7957
Topics (messages 319024 through 319026):
Re: a little trickery
319024 by: David McGlone
319025 by: Stuart Dallas
319026 by: David McGlone
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----------------------------------------------------------------------
--- Begin Message ---
On Saturday, September 08, 2012 11:19:29 PM David McGlone wrote:
> On Saturday, September 08, 2012 03:49:27 PM you wrote:
> > <?php
> >
> > function completeImageFilename($prefix)
> > {
> >
> > $matches = glob('images/property_pics/'.$prefix.'*');
> > return $matches[0];
> >
> > }
> >
> > echo '<img src="'.completeImageFilename($row['MSL_No']).'" />';
> >
> > ?>
> >
> > If you need to extract more than one image filename you should be able to
> > modify that pretty easily.
>
> YEOW! LOL I looked at this and I'm very stumped on 1 thing. How in the world
> did you get $prefix to contain the image name without first assigning it to
> $prefix? I understand the rest, but..... Holy smokes, that's blown my mind.
I read about glob() on php.net before I replied, but I believe now it's
registering. From what I understand glob works just like opendir() but does
everything all in just 1 function. so in your code I realize you passed the
variable $prefix into glob, along with the path to the files. This put the path
images/property_pics/ and each image name from glob into $prefix you then
assigne the value of $glob to $matches. Sound about right? :-)
--
Regards
David M.
--- End Message ---
--- Begin Message ---
On 9 Sep 2012, at 04:19, David McGlone <da...@dmcentral.net> wrote:
> On Saturday, September 08, 2012 03:49:27 PM you wrote:
>> On 8 Sep 2012, at 15:35, David McGlone <da...@dmcentral.net> wrote:
>>> I have a function that reads a directory and gets all the file names of
>>> images, and I am wondering if it's possible to concatinate this function
>>> withint an image tag. Here's an example I tried.
>>>
>>> function pictures() {
>>>
>>> $dir = 'images/property_pics/';
>>> $file = array();
>>>
>>> if(is_dir($dir)){
>>>
>>> if($open = opendir($dir)){
>>>
>>> while (($file = readdir($open)) !== false && $file !== ".") {
>>>
>>> $names = substr($file, 9, 20);
>>> echo $names;
>>>
>>> }
>>>
>>> }
>>>
>>> closedir($handle);
>>>
>>> }
>>>
>>> }
>>>
>>> $rs = $pager->paginate();
>>>
>>> if(!$rs) die(mysql_error());
>>> while($row = mysql_fetch_assoc($rs)) {
>>>
>>> echo "<div id='record'>";
>>> echo "<span>";
>>> echo <im src = "images/$row[$MSL_No]pictures();">
>>>
>>> What I am trying to do is get the last part of an image name, because I
>>> know the $MSL_No is always a 9 character name which matches the image
>>> name in but in the database, the last bit of characters are not there so
>>> I'm trying to take the last characters of the image name and concatinate
>>> them to each image name..
>>>
>>> Wow this is harder to explain that I thought. Here's an example
>>>
>>> In the DB I have a row MSL_No and the contents is: 123456789
>>>
>>> In my images folder I have an image named 123456789_R13_1.jpg
>>>
>>> My goal: get the MSL_No out of the DB and concatenate anything after it
> so
>>> I would end up with the whole image name..
>>>
>>> I hope this all made sense. :-/
>>
>> Is there just one image in the folder that starts with the 9 digit number?
>> In that case it's dead simple (untested code):
>>
>> <?php
>> function completeImageFilename($prefix)
>> {
>> $matches = glob('images/property_pics/'.$prefix.'*');
>> return $matches[0];
>> }
>>
>> echo '<img src="'.completeImageFilename($row['MSL_No']).'" />';
>> ?>
>>
>> If you need to extract more than one image filename you should be able to
>> modify that pretty easily.
>
> YEOW! LOL I looked at this and I'm very stumped on 1 thing. How in the world
> did you get $prefix to contain the image name without first assigning it to
> $prefix? I understand the rest, but..... Holy smokes, that's blown my mind.
> :-/
I really can't tell whether you're being sarcastic, so I'll assume you're not.
Read about function arguments: http://php.net/functions.arguments
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
--- End Message ---
--- Begin Message ---
On Sunday, September 09, 2012 03:02:17 PM Stuart Dallas wrote:
> On 9 Sep 2012, at 04:19, David McGlone <da...@dmcentral.net> wrote:
> > On Saturday, September 08, 2012 03:49:27 PM you wrote:
> >> On 8 Sep 2012, at 15:35, David McGlone <da...@dmcentral.net> wrote:
> >>> I have a function that reads a directory and gets all the file names of
> >>> images, and I am wondering if it's possible to concatinate this function
> >>> withint an image tag. Here's an example I tried.
> >>>
> >>> function pictures() {
> >>>
> >>> $dir = 'images/property_pics/';
> >>> $file = array();
> >>>
> >>> if(is_dir($dir)){
> >>>
> >>> if($open = opendir($dir)){
> >>>
> >>> while (($file = readdir($open)) !== false && $file !== ".") {
> >>>
> >>> $names = substr($file, 9, 20);
> >>> echo $names;
> >>>
> >>> }
> >>>
> >>> }
> >>>
> >>> closedir($handle);
> >>>
> >>> }
> >>>
> >>> }
> >>>
> >>> $rs = $pager->paginate();
> >>>
> >>> if(!$rs) die(mysql_error());
> >>> while($row = mysql_fetch_assoc($rs)) {
> >>>
> >>> echo "<div id='record'>";
> >>> echo "<span>";
> >>> echo <im src = "images/$row[$MSL_No]pictures();">
> >>>
> >>> What I am trying to do is get the last part of an image name, because I
> >>> know the $MSL_No is always a 9 character name which matches the image
> >>> name in but in the database, the last bit of characters are not there so
> >>> I'm trying to take the last characters of the image name and concatinate
> >>> them to each image name..
> >>>
> >>> Wow this is harder to explain that I thought. Here's an example
> >>>
> >>> In the DB I have a row MSL_No and the contents is: 123456789
> >>>
> >>> In my images folder I have an image named 123456789_R13_1.jpg
> >>>
> >>> My goal: get the MSL_No out of the DB and concatenate anything after it
> >
> > so
> >
> >>> I would end up with the whole image name..
> >>>
> >>> I hope this all made sense. :-/
> >>
> >> Is there just one image in the folder that starts with the 9 digit
> >> number?
> >> In that case it's dead simple (untested code):
> >>
> >> <?php
> >>
> >> function completeImageFilename($prefix)
> >> {
> >>
> >> $matches = glob('images/property_pics/'.$prefix.'*');
> >> return $matches[0];
> >>
> >> }
> >>
> >> echo '<img src="'.completeImageFilename($row['MSL_No']).'" />';
> >>
> >> ?>
> >>
> >> If you need to extract more than one image filename you should be able to
> >> modify that pretty easily.
> >
> > YEOW! LOL I looked at this and I'm very stumped on 1 thing. How in the
> > world did you get $prefix to contain the image name without first
> > assigning it to $prefix? I understand the rest, but..... Holy smokes,
> > that's blown my mind. :-/
> I really can't tell whether you're being sarcastic, so I'll assume you're
> not.
Sorry about that. No sarcasm here. I was so taken aback on how different your
code was. I thought I was never going to understand the way you did it vs the
way I tried. Sorry about that.
>
> Read about function arguments: http://php.net/functions.arguments
Thanks. I'll go read it now. :-)
--
Regards
David M.
--- End Message ---
