php-general Digest 22 Jul 2013 08:03:50 -0000 Issue 8306
Topics (messages 321666 through 321668):
Foreach and mydql_query problem
321666 by: Karl-Arne Gjersøyen
321667 by: Tamara Temple
321668 by: Stuart Dallas
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----------------------------------------------------------------------
--- Begin Message ---
Hello again.
I have this this source code that not work as I want...
THe PHP/HTHML form fields is generated by a while loop and looks like this:
<input type="number" name="number_of_items[]" size="6" value="<?hp
echo "$item"; ?>" required="required">
the php source code look like this:
<?php
if(!empty($_POST['number_of_itemsi'])){
include('../../connect.php');
foreach($number_of_items as $itemi){
echo "$itemi<br>";
$sql = "UPDATE item_table SET number_item = '$item' WHERE date
= '$todays_date' AND sign = '$username'";
mysql_query($sql,$connect) or die(mysql_error());
}
}
?>
The problem is:
Foreach list every items as expected in PHP doc and I thought that $sql and
mysql_query should be run five times when I have five items.
But the problem is that only the very last number_of_items is written when
update the form..
I believe this is becayse number_of_items = '$item in $sqk override every
earlier result.
So my querstion is. How to to update the database in this case?
Thanks again for your good advice and time to help me.
Karl'
--- End Message ---
--- Begin Message ---
On Jul 22, 2013, at 1:19 AM, Karl-Arne Gjersøyen <karlar...@gmail.com> wrote:
> Hello again.
> I have this this source code that not work as I want...
>
> THe PHP/HTHML form fields is generated by a while loop and looks like this:
>
> <input type="number" name="number_of_items[]" size="6" value="<?hp
> echo "$item"; ?>" required="required">
>
>
> the php source code look like this:
> <?php
> if(!empty($_POST['number_of_itemsi'])){
> include('../../connect.php');
>
> foreach($number_of_items as $itemi){
> echo "$itemi<br>";
>
> $sql = "UPDATE item_table SET number_item = '$item' WHERE date
> = '$todays_date' AND sign = '$username'";
> mysql_query($sql,$connect) or die(mysql_error());
> }
> }
>
> ?>
>
> The problem is:
> Foreach list every items as expected in PHP doc and I thought that $sql and
> mysql_query should be run five times when I have five items.
> But the problem is that only the very last number_of_items is written when
> update the form..
> I believe this is becayse number_of_items = '$item in $sqk override every
> earlier result.
>
> So my querstion is. How to to update the database in this case?
>
> Thanks again for your good advice and time to help me.
>
> Karl'
Either the code you posted isn't the actual code, or if it is, the errors
should be rather obvious. Post *actual* code.
--- End Message ---
--- Begin Message ---
On 22 Jul 2013, at 08:04, Tamara Temple <tamouse.li...@gmail.com> wrote:
> On Jul 22, 2013, at 1:19 AM, Karl-Arne Gjersøyen <karlar...@gmail.com> wrote:
>
>> Hello again.
>> I have this this source code that not work as I want...
>>
>> THe PHP/HTHML form fields is generated by a while loop and looks like this:
>>
>> <input type="number" name="number_of_items[]" size="6" value="<?hp
>> echo "$item"; ?>" required="required">
>>
>>
>> the php source code look like this:
>> <?php
>> if(!empty($_POST['number_of_itemsi'])){
>> include('../../connect.php');
>>
>> foreach($number_of_items as $itemi){
>> echo "$itemi<br>";
>>
>> $sql = "UPDATE item_table SET number_item = '$item' WHERE date
>> = '$todays_date' AND sign = '$username'";
>> mysql_query($sql,$connect) or die(mysql_error());
>> }
>> }
>>
>> ?>
>>
>> The problem is:
>> Foreach list every items as expected in PHP doc and I thought that $sql and
>> mysql_query should be run five times when I have five items.
>> But the problem is that only the very last number_of_items is written when
>> update the form..
>> I believe this is becayse number_of_items = '$item in $sqk override every
>> earlier result.
>>
>> So my querstion is. How to to update the database in this case?
>>
>> Thanks again for your good advice and time to help me.
>>
>> Karl'
>
> Either the code you posted isn't the actual code, or if it is, the errors
> should be rather obvious. Post *actual* code.
The error is rather obvious: it loops around an array running an update
statement that will modify a single row in the table, so it's not surprising
that it appears like only the last entry in the array has been stored.
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
--- End Message ---
