Re: [protobuf] Maps and append-as-merge; expectation clarification please

['Jisi Liu' via Protocol Buffers]

Yes. It will replace the value with the same key.

On Sat, Jun 24, 2017 at 11:08 AM Marc Gravell 
wrote:

> Basically, if I have
>
> message Foo {
> int32 x = 1;
> int32 y = 2;
> }
> message Bar {
> map items = 1;
> }
>
> And I serialize 2 fragments appended:
>
> items = { 1: { x: 123 } }
>
> and (as the second appended chunk)
>
> items = { 1: { y: 456 } }
>
> And now I deserialize the entire chunk; is the map item with key 1:
>
> - { x: 123, y: 456 }, or
> - { y: 456 }, or
> - something else
>
> Or to put it another way: are message-based map items merged or strictly
> replaced?
>
> My understanding based on the docs is "replaced", so { y: 456 } - but: can
> I get a confirmation on this?
>
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[protobuf] Maps and append-as-merge; expectation clarification please

[Marc Gravell]

Basically, if I have

message Foo {
int32 x = 1;
int32 y = 2;
}
message Bar {
map items = 1;
}

And I serialize 2 fragments appended:

items = { 1: { x: 123 } }

and (as the second appended chunk)

items = { 1: { y: 456 } }

And now I deserialize the entire chunk; is the map item with key 1:

- { x: 123, y: 456 }, or
- { y: 456 }, or
- something else

Or to put it another way: are message-based map items merged or strictly
replaced?

My understanding based on the docs is "replaced", so { y: 456 } - but: can
I get a confirmation on this?

-- 
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