[Proto-Scripty] Re: Range utility increment
if you want an array then i wluld use push
var twos=new Array();
for(i=0;i=10;++i) {
if(i%2) {
twos[]=i;
}
}
.
Untested but i cant see why it wouldnt work
Alex Mcauley
http://www.thevacancymarket.com
- Original Message -
From: JoJo tokyot...@gmail.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Thursday, September 24, 2009 11:15 PM
Subject: [Proto-Scripty] Range utility increment
http://www.prototypejs.org/api/utility/dollar-r
From the documentation of the Range utility, it seems like it can only
increment by 1's. For example, $A($R(1,10,true)) gives you:
[1,2,3,4,5,6,7,8,9,10].
I'm looking for a way to specify that I want to increment by any
value. Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
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[Proto-Scripty] Re: Range utility increment
Hi,
I'm looking for a way to specify that I want to increment by any
value. Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
ObjectRange itself is for ranges of consecutive values, but you can
get an array of such values by applying Enumerable#collect to a range:
var twos;
twos = $R(1, 5).collect(function(x) { return x * 2; });
...although frankly I'd probably go with a straight loop like Alex did
(although a slightly different one):
function everyOther(start, end) {
var n;
var rv = [];
for (n = start; n = end; n += 2) {
rv[rv.length] = n;
}
return rv;
}
FWIW,
--
T.J. Crowder
tj / crowder software / com
www.crowdersoftware.com
On Sep 24, 11:15 pm, JoJo tokyot...@gmail.com wrote:
http://www.prototypejs.org/api/utility/dollar-r
From the documentation of the Range utility, it seems like it can only
increment by 1's. For example, $A($R(1,10,true)) gives you:
[1,2,3,4,5,6,7,8,9,10].
I'm looking for a way to specify that I want to increment by any
value. Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
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[Proto-Scripty] Re: Range utility increment
function everyOther(start, end, increment) {
var n;
var rv = [];
for (n = start; n = end; n += increment) {
rv[rv.length] = n;
}
return rv;
}
Just a mod to make it better to be able to change it to 3's, 4's, 5's
;)
Alex Mcauley
http://www.thevacancymarket.com
- Original Message -
From: T.J. Crowder t...@crowdersoftware.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Friday, September 25, 2009 8:29 AM
Subject: [Proto-Scripty] Re: Range utility increment
Hi,
I'm looking for a way to specify that I want to increment by any
value. Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
ObjectRange itself is for ranges of consecutive values, but you can
get an array of such values by applying Enumerable#collect to a range:
var twos;
twos = $R(1, 5).collect(function(x) { return x * 2; });
...although frankly I'd probably go with a straight loop like Alex did
(although a slightly different one):
function everyOther(start, end) {
var n;
var rv = [];
for (n = start; n = end; n += 2) {
rv[rv.length] = n;
}
return rv;
}
FWIW,
--
T.J. Crowder
tj / crowder software / com
www.crowdersoftware.com
On Sep 24, 11:15 pm, JoJo tokyot...@gmail.com wrote:
http://www.prototypejs.org/api/utility/dollar-r
From the documentation of the Range utility, it seems like it can only
increment by 1's. For example, $A($R(1,10,true)) gives you:
[1,2,3,4,5,6,7,8,9,10].
I'm looking for a way to specify that I want to increment by any
value. Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
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[Proto-Scripty] Re: Ajax accept headers in google chrome frame
yeah sure, that's what i thought too. was just testing the water to see if anyone else had come across the problem. nothing in google but then, as you say, it's still very early days. On Sep 24, 5:22 pm, T.J. Crowder t...@crowdersoftware.com wrote: Hi, That's strange. It sounds like something to report to the Google Frame team, though, since it doesn't happen normally. Google Frame is early-stage[1] after all... [1]http://code.google.com/chrome/chromeframe/ -- T.J. :-) On Sep 24, 3:53 pm, Alex alexandersand...@gmail.com wrote: fair point... yeah, with 1.6.1, rails still reports */* On Sep 24, 3:01 pm, T.J. Crowder t...@crowdersoftware.com wrote: Hi, This is with prototype 1.6.0.2. Any chance of trying it with something more recent? 1.6.0.3 was released a year ago, and 1.6.1 was released last month. -- T.J. On Sep 24, 1:07 pm, Alex alexandersand...@gmail.com wrote: hi everyone, just trying out our site at work with chrome frame, and found an odd effect: the HTTP_ACCEPT header from an ajax request only reports (according to rails) as */*. This is with prototype 1.6.0.2. This is not the case for standalone chrome. that works as expected. I realise it's still very early in it's development, just wondering if anyone seen this and had any ideas? cheers, alex. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Prototype script.aculo.us group. To post to this group, send email to prototype-scriptaculous@googlegroups.com To unsubscribe from this group, send email to prototype-scriptaculous+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/prototype-scriptaculous?hl=en -~--~~~~--~~--~--~---
[Proto-Scripty] Re: Remove onFocus borders from buttons in IE
$$().invoke('observe','click',function(element) {
$(element).blur();
});
Alex Mcauley
http://www.thevacancymarket.com
- Original Message -
From: clicforw...@googlemail.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Thursday, September 24, 2009 4:48 PM
Subject: [Proto-Scripty] Remove onFocus borders from buttons in IE
Hello,
i tried to remove this Borders around links and form buttons in IE
script type=text/javascript
document.observe(dom:loaded, function() {
$$('button').onclick = function() {
(this).blur();
}
});
/script
But this is not working!
Anyone an idea how it can done right?
Thanks
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[Proto-Scripty] Periodic updater
Hello To all, I’m facing the problem with my over traffic site, My self using periodic updater but when traffic increase script will not respond any more. A browser sends the request to sever but it will not get back on the page (Response will not display on the page). Can any one help me how to tackle issue? Thank you. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Prototype script.aculo.us group. To post to this group, send email to prototype-scriptaculous@googlegroups.com To unsubscribe from this group, send email to prototype-scriptaculous+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/prototype-scriptaculous?hl=en -~--~~~~--~~--~--~---
[Proto-Scripty] Re: Periodic updater
is the server sending a response ? Alex Mcauley http://www.thevacancymarket.com - Original Message - From: MakeWebAPP makeweb...@gmail.com To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com Sent: Friday, September 25, 2009 12:04 PM Subject: [Proto-Scripty] Periodic updater Hello To all, I’m facing the problem with my over traffic site, My self using periodic updater but when traffic increase script will not respond any more. A browser sends the request to sever but it will not get back on the page (Response will not display on the page). Can any one help me how to tackle issue? Thank you. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups Prototype script.aculo.us group. To post to this group, send email to prototype-scriptaculous@googlegroups.com To unsubscribe from this group, send email to prototype-scriptaculous+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/prototype-scriptaculous?hl=en -~--~~~~--~~--~--~---
[Proto-Scripty] Re: Autocompleter not working in IE. Stumped.
Thanks!
Changing the span to a div was already enough, surprisingly enough. I
needed to keep the paramName, because it refers to what's to be passed
to the file from which the results are being picked up.
Anyway, who'd have thought! Thanks again!
Babak
On Sep 24, 8:10 pm, david david.brill...@gmail.com wrote:
Hi MastaBaba,
input name=post[tags] type=text id=tags value= /
span id=indicator1 style=display: noneLoading.../span
div id=hint1 class=hint/div
script type=text/javascript
new Ajax.Autocompleter(tags,hint1,../s/backend/tags.php,
{paramName: value,minChars: 2, tokens: ',', indicator:
'indicator1'});
/script
Try this, it could work :\\
I change the span element to receive the autocompleter response to a
div, and change the paramName to 'value' because it's value property
that handle the user input.
--
david
On 24 sep, 09:06, MastaBaba babak.fakhamza...@gmail.com wrote:
Hi all,
I've got autocompleter not working in IE, 6, 7 or 8. I'm not getting
thrown a JS error, it simply doesn't load the underlying file, almost
as if the library isn't even loaded, though it is. The script works in
FF, Opera, Safari and Chrome. Any thoughts would be wildly
appreciated.
Here's a page with the not-working script:
http://v2.ovcsupport.net/sandbox/javascripttest.php
Thanks in advance for any thoughts on this,
Babak Fakhamzadeh
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[Proto-Scripty] better solution for Observe.click
Hi.
I am using a Rails plugin called will_paginate. For AJAX pagination they
use the solution presented here:
http://wiki.github.com/mislav/will_paginate/ajax-pagination
The code is something like:
|document.observe(dom:loaded, function() {
[..]
container.observe('click', function(e) {
var el = e.element()
if (el.match('.pagination a')) {
el.up('.pagination').insert(createSpinner())
new Ajax.Request(el.href, { method: 'get' })
e.stop()
[..]
})
|
The only problem is that this doesn't work if there are images in the
links.
a class=next_page rel=next href=/link
img src=/images/right-point.gif?1244992605 alt=Right-point//a
When clicking on the image the trigger is called for the img tag, not
the link.
Here is the fix I've implemented:
container.observe('click', function(e) {
if (e.element().match('img'))
var el = e.element().ancestors()[0]
else
var el = e.element()
if (el.match('.pagination a')) {
el.up('.pagination').insert(createSpinner())
new Ajax.Request(el.href, { method: 'get' })
e.stop()
}
})
I am not the best JS programmer, so maybe someone has a better solution.
--
Cheers,
M.
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[Proto-Scripty] Re: Range utility increment
I'd just use an 'iterator' class to do this...
var EvenNumber = Class.create(
{
initialize : function(num){
this.num = (num % 2 == 1) ? num - 1 : num;
},
succ : function(){
return new EvenNumber(this.num + 2);
},
toString : function(){
return this.num;
}
});
var bottom = new EvenNumber(1);
var top = new EvenNumber(21);
var range = $A($R(bottom, top));
console.log(range);
I had done this to a much greater extent in my date range selector
gadget. Where it became the master range, held a range of calendar
objects, which were in themselves ranges of date objects... fun stuff.
https://positionabsolute.net/blog/2008/01/google-calendar-date-range-selection.php
ps just looking over that, should rename that class to
PositiveEvenNumber, only going to work one way, but you get the idea
On Sep 25, 4:15 am, Alex McAuley webmas...@thecarmarketplace.com
wrote:
function everyOther(start, end, increment) {
var n;
var rv = [];
for (n = start; n = end; n += increment) {
rv[rv.length] = n;
}
return rv;
}
Just a mod to make it better to be able to change it to 3's, 4's, 5's
;)
Alex Mcauleyhttp://www.thevacancymarket.com
- Original Message -
From: T.J. Crowder t...@crowdersoftware.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Friday, September 25, 2009 8:29 AM
Subject: [Proto-Scripty] Re: Range utility increment
Hi,
I'm looking for a way to specify that I want to increment by any
value. Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
ObjectRange itself is for ranges of consecutive values, but you can
get an array of such values by applying Enumerable#collect to a range:
var twos;
twos = $R(1, 5).collect(function(x) { return x * 2; });
...although frankly I'd probably go with a straight loop like Alex did
(although a slightly different one):
function everyOther(start, end) {
var n;
var rv = [];
for (n = start; n = end; n += 2) {
rv[rv.length] = n;
}
return rv;
}
FWIW,
--
T.J. Crowder
tj / crowder software / comwww.crowdersoftware.com
On Sep 24, 11:15 pm, JoJo tokyot...@gmail.com wrote:
http://www.prototypejs.org/api/utility/dollar-r
From the documentation of the Range utility, it seems like it can only
increment by 1's. For example, $A($R(1,10,true)) gives you:
[1,2,3,4,5,6,7,8,9,10].
I'm looking for a way to specify that I want to increment by any
value. Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
--~--~-~--~~~---~--~~
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[Proto-Scripty] Re: Range utility increment
That only gives you even or odd increments to the top number...
WHat if you wanted every 5th number ...
Better to go with my/TJ's loop
Alex Mcauley
http://www.thevacancymarket.com
- Original Message -
From: Matt Foster mattfoste...@gmail.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Friday, September 25, 2009 5:57 PM
Subject: [Proto-Scripty] Re: Range utility increment
I'd just use an 'iterator' class to do this...
var EvenNumber = Class.create(
{
initialize : function(num){
this.num = (num % 2 == 1) ? num - 1 : num;
},
succ : function(){
return new EvenNumber(this.num + 2);
},
toString : function(){
return this.num;
}
});
var bottom = new EvenNumber(1);
var top = new EvenNumber(21);
var range = $A($R(bottom, top));
console.log(range);
I had done this to a much greater extent in my date range selector
gadget. Where it became the master range, held a range of calendar
objects, which were in themselves ranges of date objects... fun stuff.
https://positionabsolute.net/blog/2008/01/google-calendar-date-range-selection.php
ps just looking over that, should rename that class to
PositiveEvenNumber, only going to work one way, but you get the idea
On Sep 25, 4:15 am, Alex McAuley webmas...@thecarmarketplace.com
wrote:
function everyOther(start, end, increment) {
var n;
var rv = [];
for (n = start; n = end; n += increment) {
rv[rv.length] = n;
}
return rv;
}
Just a mod to make it better to be able to change it to 3's, 4's, 5's
;)
Alex Mcauleyhttp://www.thevacancymarket.com
- Original Message -
From: T.J. Crowder t...@crowdersoftware.com
To: Prototype script.aculo.us
prototype-scriptaculous@googlegroups.com
Sent: Friday, September 25, 2009 8:29 AM
Subject: [Proto-Scripty] Re: Range utility increment
Hi,
I'm looking for a way to specify that I want to increment by any
value. Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
ObjectRange itself is for ranges of consecutive values, but you can
get an array of such values by applying Enumerable#collect to a range:
var twos;
twos = $R(1, 5).collect(function(x) { return x * 2; });
...although frankly I'd probably go with a straight loop like Alex did
(although a slightly different one):
function everyOther(start, end) {
var n;
var rv = [];
for (n = start; n = end; n += 2) {
rv[rv.length] = n;
}
return rv;
}
FWIW,
--
T.J. Crowder
tj / crowder software / comwww.crowdersoftware.com
On Sep 24, 11:15 pm, JoJo tokyot...@gmail.com wrote:
http://www.prototypejs.org/api/utility/dollar-r
From the documentation of the Range utility, it seems like it can only
increment by 1's. For example, $A($R(1,10,true)) gives you:
[1,2,3,4,5,6,7,8,9,10].
I'm looking for a way to specify that I want to increment by any
value. Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
--~--~-~--~~~---~--~~
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[Proto-Scripty] Re: Range utility increment
so generalize the class...
- Original Message -
From: Alex McAuley
To: prototype-scriptaculous@googlegroups.com
Sent: Friday, September 25, 2009 12:25 PM
Subject: [Proto-Scripty] Re: Range utility increment
That only gives you even or odd increments to the top number...
WHat if you wanted every 5th number ...
Better to go with my/TJ's loop
Alex Mcauley
http://www.thevacancymarket.com
- Original Message -
From: Matt Foster mattfoste...@gmail.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Friday, September 25, 2009 5:57 PM
Subject: [Proto-Scripty] Re: Range utility increment
I'd just use an 'iterator' class to do this...
var EvenNumber = Class.create(
{
initialize : function(num){
this.num = (num % 2 == 1) ? num - 1 : num;
},
succ : function(){
return new EvenNumber(this.num + 2);
},
toString : function(){
return this.num;
}
});
var bottom = new EvenNumber(1);
var top = new EvenNumber(21);
var range = $A($R(bottom, top));
console.log(range);
I had done this to a much greater extent in my date range selector
gadget. Where it became the master range, held a range of calendar
objects, which were in themselves ranges of date objects... fun stuff.
https://positionabsolute.net/blog/2008/01/google-calendar-date-range-selection.php
ps just looking over that, should rename that class to
PositiveEvenNumber, only going to work one way, but you get the idea
On Sep 25, 4:15 am, Alex McAuley webmas...@thecarmarketplace.com
wrote:
function everyOther(start, end, increment) {
var n;
var rv = [];
for (n = start; n = end; n += increment) {
rv[rv.length] = n;
}
return rv;
}
Just a mod to make it better to be able to change it to 3's, 4's, 5's
;)
Alex Mcauleyhttp://www.thevacancymarket.com
- Original Message -
From: T.J. Crowder t...@crowdersoftware.com
To: Prototype script.aculo.us
prototype-scriptaculous@googlegroups.com
Sent: Friday, September 25, 2009 8:29 AM
Subject: [Proto-Scripty] Re: Range utility increment
Hi,
I'm looking for a way to specify that I want to increment by any
value. Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
ObjectRange itself is for ranges of consecutive values, but you can
get an array of such values by applying Enumerable#collect to a range:
var twos;
twos = $R(1, 5).collect(function(x) { return x * 2; });
...although frankly I'd probably go with a straight loop like Alex did
(although a slightly different one):
function everyOther(start, end) {
var n;
var rv = [];
for (n = start; n = end; n += 2) {
rv[rv.length] = n;
}
return rv;
}
FWIW,
--
T.J. Crowder
tj / crowder software / comwww.crowdersoftware.com
On Sep 24, 11:15 pm, JoJo tokyot...@gmail.com wrote:
http://www.prototypejs.org/api/utility/dollar-r
From the documentation of the Range utility, it seems like it can only
increment by 1's. For example, $A($R(1,10,true)) gives you:
[1,2,3,4,5,6,7,8,9,10].
I'm looking for a way to specify that I want to increment by any
value. Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
--~--~-~--~~~---~--~~
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[Proto-Scripty] Re: Range utility increment
That only gives you even or odd increments to the top number...
Incorrect, notice the constructor method? It ensures that the number
given is even such that you'll never get a range of odd numbers.
Granted the last line of the Jojo's question was
Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
Hence why I went with this specific implementation, to demonstrate how
you can create classes that the ObjectRange class can use to create
proper ranges. I didn't feel it was necessary to abstract out the
class such that it covers all bases but demonstrate how to do it one
way and then Jojo could modify for their own purposes.
Better to go with my/TJ's loop
What an arrogant plug of your own spaghetti code and hasty discredit
to my contribution. Exposing your shortfalls isn't difficult, you
aren't creating a range object, completely bypassing the ObjectRange's
functionality and just simply creating a hacked out array.
So to put the nail in the coffin, here is the classes abstracted out
var IncrementNumber = Class.create({
initialize : function(num, increment){
this.num = num;
this.increment = increment;
},
succ : function(){
return this.clone(this.num + this.increment,
this.increment);
},
clone : function(num, increment){
return new IncrementNumber(num, increment);
},
toString : function(){
return this.num;
}
});
var EvenNumber = Class.create(IncrementNumber,
{
initialize : function($super, num){
$super(num, 2);
this.num = (num % 2 == 1) ? num - 1 : num;
},
clone : function(num, increment){
return new EvenNumber(num);
}
});
var NumberRange = Class.create(ObjectRange,
{
_each: function(iterator) {
var value = this.start;
while (this.include(value.num)) {
iterator(value.num);
value = value.succ();
}
},
});
var bottom = new IncrementNumber(-10, 2);
//var bottom = new EvenNumber(-20);
var top = new EvenNumber(25);
var range = $A(new NumberRange(bottom, top));
console.log(range);
nothing gets me fired up like a flame...
On Sep 25, 2:25 pm, Alex McAuley webmas...@thecarmarketplace.com
wrote:
That only gives you even or odd increments to the top number...
WHat if you wanted every 5th number ...
Better to go with my/TJ's loop
Alex Mcauleyhttp://www.thevacancymarket.com
- Original Message -
From: Matt Foster mattfoste...@gmail.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Friday, September 25, 2009 5:57 PM
Subject: [Proto-Scripty] Re: Range utility increment
I'd just use an 'iterator' class to do this...
var EvenNumber = Class.create(
{
initialize : function(num){
this.num = (num % 2 == 1) ? num - 1 : num;
},
succ : function(){
return new EvenNumber(this.num + 2);
},
toString : function(){
return this.num;
}
});
var bottom = new EvenNumber(1);
var top = new EvenNumber(21);
var range = $A($R(bottom, top));
console.log(range);
I had done this to a much greater extent in my date range selector
gadget. Where it became the master range, held a range of calendar
objects, which were in themselves ranges of date objects... fun stuff.
https://positionabsolute.net/blog/2008/01/google-calendar-date-range-...
ps just looking over that, should rename that class to
PositiveEvenNumber, only going to work one way, but you get the idea
On Sep 25, 4:15 am, Alex McAuley webmas...@thecarmarketplace.com
wrote:
function everyOther(start, end, increment) {
var n;
var rv = [];
for (n = start; n = end; n += increment) {
rv[rv.length] = n;
}
return rv;
}
Just a mod to make it better to be able to change it to 3's, 4's, 5's
;)
Alex Mcauleyhttp://www.thevacancymarket.com
- Original Message -
From: T.J. Crowder t...@crowdersoftware.com
To: Prototype script.aculo.us
prototype-scriptaculous@googlegroups.com
Sent: Friday, September 25, 2009 8:29 AM
Subject: [Proto-Scripty] Re: Range utility increment
Hi,
I'm looking for a way to specify that I want to increment by any
value. Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
ObjectRange itself is for ranges of consecutive values, but you can
get an array of such values by applying Enumerable#collect to a range:
var twos;
twos = $R(1, 5).collect(function(x) { return x * 2; });
...although frankly I'd probably go with a straight loop like Alex did
(although a slightly different one):
function everyOther(start, end) {
var n;
var rv = [];
for (n = start; n = end; n += 2) {
[Proto-Scripty] Re: Range utility increment
Omg get over yourself you have taken what i said completely the wrong way..
What arrogant plug was that?...
Lets take your code and look at it shall we...
30+ lines for no reason other than Hey look at me, i can write a
function/class in 30 lines that only needs to be 5.
Chill out dude, i wasn't knocking your code, it was just OTT.
You can continue to think you are right which is arrogance in itself...
there is more than one way to skin a cat.
TJ's/My loop that took all of 30 seconds to create is faster no doubt, has
less weight and does the job. I personaly have better things to do than
write some amazing class to achieve what can be done in 30 seconds -
evidently you do not so good luck with that.
Alex Mcauley
http://www.thevacancymarket.com
- Original Message -
From: Matt Foster mattfoste...@gmail.com
To: Prototype script.aculo.us prototype-scriptaculous@googlegroups.com
Sent: Friday, September 25, 2009 9:16 PM
Subject: [Proto-Scripty] Re: Range utility increment
That only gives you even or odd increments to the top number...
Incorrect, notice the constructor method? It ensures that the number
given is even such that you'll never get a range of odd numbers.
Granted the last line of the Jojo's question was
Let's say count up by 2's: [2,4,6,8,10]. How do you do this?
Hence why I went with this specific implementation, to demonstrate how
you can create classes that the ObjectRange class can use to create
proper ranges. I didn't feel it was necessary to abstract out the
class such that it covers all bases but demonstrate how to do it one
way and then Jojo could modify for their own purposes.
Better to go with my/TJ's loop
What an arrogant plug of your own spaghetti code and hasty discredit
to my contribution. Exposing your shortfalls isn't difficult, you
aren't creating a range object, completely bypassing the ObjectRange's
functionality and just simply creating a hacked out array.
So to put the nail in the coffin, here is the classes abstracted out
var IncrementNumber = Class.create({
initialize : function(num, increment){
this.num = num;
this.increment = increment;
},
succ : function(){
return this.clone(this.num + this.increment, this.increment);
},
clone : function(num, increment){
return new IncrementNumber(num, increment);
},
toString : function(){
return this.num;
}
});
var EvenNumber = Class.create(IncrementNumber,
{
initialize : function($super, num){
$super(num, 2);
this.num = (num % 2 == 1) ? num - 1 : num;
},
clone : function(num, increment){
return new EvenNumber(num);
}
});
var NumberRange = Class.create(ObjectRange,
{
_each: function(iterator) {
var value = this.start;
while (this.include(value.num)) {
iterator(value.num);
value = value.succ();
}
},
});
var bottom = new IncrementNumber(-10, 2);
//var bottom = new EvenNumber(-20);
var top = new EvenNumber(25);
var range = $A(new NumberRange(bottom, top));
console.log(range);
nothing gets me fired up like a flame...
On Sep 25, 2:25 pm, Alex McAuley webmas...@thecarmarketplace.com
wrote:
That only gives you even or odd increments to the top number...
WHat if you wanted every 5th number ...
Better to go with my/TJ's loop
Alex Mcauleyhttp://www.thevacancymarket.com
- Original Message -
From: Matt Foster mattfoste...@gmail.com
To: Prototype script.aculo.us
prototype-scriptaculous@googlegroups.com
Sent: Friday, September 25, 2009 5:57 PM
Subject: [Proto-Scripty] Re: Range utility increment
I'd just use an 'iterator' class to do this...
var EvenNumber = Class.create(
{
initialize : function(num){
this.num = (num % 2 == 1) ? num - 1 : num;
},
succ : function(){
return new EvenNumber(this.num + 2);
},
toString : function(){
return this.num;
}
});
var bottom = new EvenNumber(1);
var top = new EvenNumber(21);
var range = $A($R(bottom, top));
console.log(range);
I had done this to a much greater extent in my date range selector
gadget. Where it became the master range, held a range of calendar
objects, which were in themselves ranges of date objects... fun stuff.
https://positionabsolute.net/blog/2008/01/google-calendar-date-range-...
ps just looking over that, should rename that class to
PositiveEvenNumber, only going to work one way, but you get the idea
On Sep 25, 4:15 am, Alex McAuley webmas...@thecarmarketplace.com
wrote:
function everyOther(start, end, increment) {
var n;
var rv = [];
for (n = start; n = end; n += increment) {
rv[rv.length] = n;
}
return rv;
}
Just a mod to make it better to be able to change it to 3's, 4's, 5's
;)
Alex Mcauleyhttp://www.thevacancymarket.com
- Original Message -
From: T.J. Crowder t...@crowdersoftware.com
To: Prototype script.aculo.us
prototype-scriptaculous@googlegroups.com
Sent: Friday, September 25, 2009 8:29 AM
Subject: [Proto-Scripty] Re: Range utility increment
Hi,
I'm looking for a way to specify that I want to increment by any
value.
