[PyQt] [PyQt 4.5 Bug] Derived signals do not present
Code for reproduce: [code=python] from PyQt4 import QtGui sm = QtGui.QSortFilterProxyModel() sm.modelReset.conncet(lambda: None) [/code] Traceback (most recent call last): File C:\Lang\test\python\PyQtSignalBug\QtSortProxy.py, line 4, in module sm.modelReset.conncet(lambda: None) AttributeError: 'QSortFilterProxyModel' object has no attribute 'modelReset' Signal modelReset has in QAbstractItemModel. Os Windows Vista Home Ru + sp1 g++ (GCC) 3.4.5 (mingw-vista special r3) Qt 4.5 (self build) sip-4.8-snapshot-20090401 (self build) PyQt-win-gpl-4.5-snapshot-20090328.zip (self build) ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
Re: [PyQt] context menus for QTreeWidgetItem?
Christian Aubert a écrit : I currently have a context menu for the whole QTreeWidget but I need finer-grained control on a per item basis. Has anyone implemented context menus for QTreeWidgetItems? Any pointers? Christian ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt Hello, here is a solution that works. I hope tha will help you. To call the menu, just use : self.connect(self.treeWidget, QtCore.SIGNAL(customContextMenuRequested(const QPoint )), self.menuContextTree) Here is the method menuContextTree : def menuContextTree(self, point): # Infos about the node selected. index = self.treeWidget.indexAt(point) if not index.isValid(): return item = self.treeWidget.itemAt(point) name = item.text(0) # The text of the node. # We build the menu. menu=QtGui.QMenu(self) action=menu.addAction(Souris au-dessus de) action=menu.addAction(name) menu.addSeparator() action_1=menu.addAction(Choix 1) action_2=menu.addAction(Choix 2) action_3=menu.addAction(Choix 3) print QtGui.QCursor.pos() menu.exec_(QtGui.QCursor.pos()) ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
Re: [PyQt] SplashScreen and mousePressEvent
Thanks, I'll try to understand that. Maybe my problem is a problem of
windowflag. Where are all the avaibale windowflag ?
Best reagrds and a great thanks for your help.
Christophe.
Apologies for the C++ code, we have an info label that displays text
in a popup QFrame, this is the method that sets the text and makes the
widget visible.
The things you will find interesting are mapping from the cursor to
the current frame and then mapping this point (after moving out of the
way of the mouse) to the mainwindow (which is the parent of the Qframe).
Hope this helps.
void InfoLabel::SetInfoLabel( const std::string s )
{
if (s.empty())
{
if (!_hidden)
{
hide();
_hidden = true;
}
}
else
{
QPoint pos = mapFromGlobal(QCursor::pos());
setText(s.c_str());
adjustSize();
QPoint p(pos.x(), pos.y() - height());
move(this-mapTo(parent(), p));
raise();
if (_hidden)
show();
else
update();
_hidden = false;
}
}
On 4/8/09 11:40 AM, projetmbc projet...@club-internet.fr wrote:
Brian Kelley a écrit :
You can have the same effect using a timer:
class MyFrame(QFrame):
def __init__(self, parent, pixmapfile):
QFrame.__init__(self, parent,
Qt.X11BypassWindowManagerHint |
Qt.FramelessWindowHint |
Qt.WindowStaysOnTopHint | Qt.Tool )
# do something with pixmapfile
self.timer = QTimer()
self.connect( self.timer, QtCore.SIGNAL(timeout()),
self, QtCore.SLOT(hide()) )
def showEvent(self, evt):
self.timer.start(3000) # 3 seconds
QFrame.showEvent(self, evt)
On 4/8/09 9:39 AM, projetmbc projet...@club-internet.fr wrote:
You're right. I will try to do that with a frame but the
adventage
of a
SplashScreen is that it lives for a laps of time.
Best regards.
Christophe.
Qt.X11BypassWindowManagerHint | Qt.FramelessWindowHint |
Qt.WindowStaysOnTopHint | Qt.Tool
I do the following changes but there is still a very little problem
concerning the position of the frame. How can I do to use
QtGui.QCursor.pos() so as to put the frame where the mouse is ?
I've tried to use rect=QtCore.QRect(position,
QtCore.QPoint(1000,1000)) and self.setFrameRect(rect) but it
doesn't
work.
Christophe.
Code
class MyFrame(QtGui.QFrame):
# Squelette donné par Brian Kelley sur la liste de PyQt.
def __init__(self, parent, titre, pixmapfile, position):
QtGui.QFrame.__init__(self, parent,
QtCore.Qt.WindowStaysOnTopHint | QtCore.Qt.Tool)
# QtCore.Qt.X11BypassWindowManagerHint |
QtCore.Qt.FramelessWindowHint
| QtCore.Qt.WindowStaysOnTopHint | QtCore.Qt.Tool
self.setWindowTitle(titre)
label = QtGui.QLabel(self)
label.setPixmap(pixmapfile)
label.show()
self.timer = QtCore.QTimer()
self.connect( self.timer, QtCore.SIGNAL(timeout()),
self,QtCore.SLOT(hide()) )
def showEvent(self, evt):
self.timer.start(1) # 10 seconds
QtGui.QFrame.showEvent(self, evt)
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Re:Re: [PyQt] context menus for QTreeWidgetItem?
Christian Aubert a écrit : I currently have a context menu for the whole QTreeWidget but I need finer-grained control on a per item basis. Has anyone implemented context menus for QTreeWidgetItems? Any pointers? Christian ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt Hello, here is a solution that works. I hope tha will help you. To call the menu, just use : self.connect(self.treeWidget, QtCore.SIGNAL(customContextMenuRequested(const QPoint )), self.menuContextTree) Here is the method menuContextTree : def menuContextTree(self, point): # Infos about the node selected. index = self.treeWidget.indexAt(point) if not index.isValid(): return item = self.treeWidget.itemAt(point) name = item.text(0) # The text of the node. # We build the menu. menu=QtGui.QMenu(self) action=menu.addAction(Souris au-dessus de) action=menu.addAction(name) menu.addSeparator() action_1=menu.addAction(Choix 1) action_2=menu.addAction(Choix 2) action_3=menu.addAction(Choix 3) print QtGui.QCursor.pos() menu.exec_(QtGui.QCursor.pos()) ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
[PyQt] [PyQt 4.5] TypeError: pyqtBoundSignal cannot be converted to QObject in this context
I try port my applications to PyQt 4.5 And I recive TypeError: [code] Traceback (most recent call last): ... File C:\Lang\Projects\Promsoft\mun_ob\doc_circ\src\links\DataRightOwner.py, line 48, in __init__ self.__connectAll() File C:\Lang\Projects\Promsoft\mun_ob\doc_circ\src\links\DataRightOwner.py, line 189, in __connectAll for dm in (self.__phys, self.__jur, self.__bus): TypeError: PyQt4.QtCore.pyqtBoundSignal cannot be converted to PyQt4.QtCore.QObject in this context [/code] How correct this error? Snipped Code for illustrate: [code] class DataLink(QtCore.QObject): data_adds = QtCore.QtCore.pyqtSignal(frozenset) class DataRightLandPhys(DataLink): pass class DataRightLandJur(DataLink): pass class DataRightLandJur(DataLink): pass class Data(DataLink): __phys = None __jur = None __bus = None def __init__(self): super(Data, self).__init__() self.__phys = DataRightLandPhys() self.__jur = DataRightLandJur() self.__bus = DataRightLandBus() self.__connectAll() def __connectAll(self): for dm in (self.__phys, self.__jur, self.__bus): dm.data_adds.connect(self.data_adds.emit) [/code] ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
[PyQt] Re: Connecting two QGraphicsItems
On Thursday, 9. April 2009, Mads wrote: is it possible to control the position of the item? just use item.setPos() - this uses a coordinate system relative to the parent item. -- Wolfgang ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
[PyQt] Bug: PyQt causes Python to abnormally exit upon creating QWidget without a QApplication
Hello. See the following: $ python Python 2.5.2 (r252:60911, Jul 31 2008, 17:28:52) [GCC 4.2.3 (Ubuntu 4.2.3-2ubuntu7)] on linux2 Type help, copyright, credits or license for more information. from PyQt4.QtGui import * w = QWidget () QWidget: Must construct a QApplication before a QPaintDevice $ I think this should be handled more gracefully with a Python exception (or error, if the two are not the same) thrown rather than Python abnormally exiting, like follows: $ python Python 2.5.2 (r252:60911, Jul 31 2008, 17:28:52) [GCC 4.2.3 (Ubuntu 4.2.3-2ubuntu7)] on linux2 Type help, copyright, credits or license for more information. a=b c=2 a+b Traceback (most recent call last): File stdin, line 1, in module NameError: name 'b' is not defined ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
[PyQt] will pyqt follow qt license model?
Hi, I've searched this mailing list and although the QT lgpl news was discussed at length, but I couldnt distill from this list whether pyqt will follow qt's licensing model. Has this been decided yet? Thanks, -jelle ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
Re: [PyQt] [SIP][PATCH]Errors occurring during execution of python __dtor__() function called from sip are discarded
On Mon, 06 Apr 2009 10:04:35 +0200, Alexis Boutillier alexis.boutill...@arteris.com wrote: Hi, When sip call the __dtor__() python function on a python object, it does not print errors that occurred during the execution of the python function. If something goes wrong in this function you are not informed and so you can leave objects in an unwanted state (because of an attributeError for example). Here is a patch to siplib.c that print the python error if it occurred during the call of the python __dtor__() function. Thanks, Phil ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
Re: [PyQt] Possible bug - global coordinates work but widget coordinates do not
On Wed, 08 Apr 2009 20:26:55 +0530, Shriramana Sharma samj...@gmail.com wrote: Hello first of all let me clarify that this is specific to PyQt and does not existing in C++/Qt. I am using PyQt 4.3.3 on Qt 4.4.0 on Kubuntu Hardy. I attach three files. 1. test.py is the one that demonstrates the problem. 2. test.cpp is the equivalent C++ version that shows no problem. 3. test-sol.py is the Python version that works. I wanted to draw a rubberband on a widget, and ended up finding this bug. Everytime the mouseMoveEvent is processed, the value of the variable rbOrigin (origin of the rubberband) is reset to the current event position, thereby making it impossible for a proper rubberband to be drawn. However, it appears that the mousePressEvent (which sets the value of rbOrigin) is definitely not called by mistake as I don't get any debug output. The equivalent C++ version works without problems. Using global coordinates on Python works around the bug but I don't see why. See... http://www.riverbankcomputing.com/software/pyqt/roadmap/index.html#implicit-copying-of-const Making an explicit copy of event.pos() in mousePressEvent() will probably fix it. Phil ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
Re: [PyQt] Re: Connecting two QGraphicsItems
Thanks for the replies. Using setParent works fine for one item, but is it possible to control the position of the item? I mean is it possible to place the EllipseItem at a certain point on the GraphicsItem, so the EllipseItems don't get placed at the same point. Mads - Original Message From: Wolfgang Rohdewald wolfg...@rohdewald.de To: pyqt@riverbankcomputing.com Sent: Tuesday, April 7, 2009 12:34:47 AM Subject: [PyQt] Re: Connecting two QGraphicsItems On Montag, 6. April 2009, Marcell Mars wrote: On Mon, Apr 6, 2009 at 4:13 PM, Mads kofo...@yahoo.com wrote: each item needs to have separate functionality, so you should be able to set different attributes on each item. Is the createItemGroup, still the best way forward? to be more sure i would need more info about your app but as i saw i would definitively try createItemGroup and QGraphicsView.. i love QGraphicsView why not simply make the 3 circles children of the rectangle with circle.setParentItem(rectangle)? The drawing seems to say that the line of the rectangle should not be visible below the circles. -- Wolfgang ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
Re: [PyQt] SplashScreen and mousePressEvent - SOLVED
Hello. Finaly here is the solution to have a frame where the cursor is. We have to use setGeomtry and not setRectangle. Best regards. Christophe. == THE CODE == class MyFrame(QtGui.QFrame): def __init__(self, parent, titre, pixmapfile): QtGui.QFrame.__init__(self, parent, QtCore.Qt.WindowStaysOnTopHint | QtCore.Qt.Tool) rect = QtCore.QRect(QtGui.QCursor.pos(), pixmapfile.size()) self.setGeometry(rect) label = QtGui.QLabel(self) label.setPixmap(pixmapfile) label.show() self.timer = QtCore.QTimer() self.connect( self.timer, QtCore.SIGNAL(timeout()), self, QtCore.SLOT(hide()) ) def showEvent(self, evt): self.timer.start(1) # 10 seconds QtGui.QFrame.showEvent(self, evt) ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
Re: [PyQt] Bug: PyQt causes Python to abnormally exit upon creating QWidget without a QApplication
On 09.04.09 13:45:47, Shriramana Sharma wrote: Hello. See the following: $ python Python 2.5.2 (r252:60911, Jul 31 2008, 17:28:52) [GCC 4.2.3 (Ubuntu 4.2.3-2ubuntu7)] on linux2 Type help, copyright, credits or license for more information. from PyQt4.QtGui import * w = QWidget () QWidget: Must construct a QApplication before a QPaintDevice $ I think this should be handled more gracefully with a Python exception (or error, if the two are not the same) thrown rather than Python abnormally exiting, like follows: PyQt has no control over that, this is happening in the C++ part and QWidget uses qFatal() which in turn calls abort() at that point to end the application. And thats actually the correct way for the C++ part to handle this case (as Qt doesn't use exceptions). Andreas -- You definitely intend to start living sometime soon. ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
Re: [PyQt] [PyQt 4.5 Bug] Derived signals do not present
On Thu, 09 Apr 2009 13:15:24 +0700, Alexandr N Zamaraev to...@promsoft.ru wrote: Code for reproduce: [code=python] from PyQt4 import QtGui sm = QtGui.QSortFilterProxyModel() sm.modelReset.conncet(lambda: None) [/code] Traceback (most recent call last): File C:\Lang\test\python\PyQtSignalBug\QtSortProxy.py, line 4, in module sm.modelReset.conncet(lambda: None) AttributeError: 'QSortFilterProxyModel' object has no attribute 'modelReset' Signal modelReset has in QAbstractItemModel. Os Windows Vista Home Ru + sp1 g++ (GCC) 3.4.5 (mingw-vista special r3) Qt 4.5 (self build) sip-4.8-snapshot-20090401 (self build) PyQt-win-gpl-4.5-snapshot-20090328.zip (self build) Should be fixed in tonight's PyQt snapshot - there was a whole group of signals missing from the .sip file. Phil ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
Re: [PyQt] QAbstractItemModel modelAboutToBeReset signal
On Wed, 8 Apr 2009 11:55:39 -0400, Patrick Boucher
pbouc...@patrickboucher.com wrote:
Hi all,
I've subclassed QAbstractItemModel and overloaded reset to be:
def reset(self):
self.modelAboutToBeReset.emit()
self._loadPeople()
self.modelReset.emit()
and I get errors pertaining to missing attributes modelAboutToBeReset
and modelReset. Do I have something wrong with the new syntax for
emitting signals or is this a known thing or a bug? I'm using latest
snapshots of sip and pyqt.
The pre-4.5 version of the code works fine:
def reset(self):
self.emit(QtCore.SIGNAL('modelAboutToBeReset()'))
self._loadPeople()
self.emit(QtCore.SIGNAL('modelReset()'))
Should be fixed in tonight's PyQt snapshot.
Phil
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Re: [PyQt] [PyQt 4.5] TypeError: pyqtBoundSignal cannot be converted to QObject in this context
On Thu, 09 Apr 2009 15:13:27 +0700, Alexandr N Zamaraev to...@promsoft.ru wrote: I try port my applications to PyQt 4.5 And I recive TypeError: [code] Traceback (most recent call last): ... File C:\Lang\Projects\Promsoft\mun_ob\doc_circ\src\links\DataRightOwner.py, line 48, in __init__ self.__connectAll() File C:\Lang\Projects\Promsoft\mun_ob\doc_circ\src\links\DataRightOwner.py, line 189, in __connectAll for dm in (self.__phys, self.__jur, self.__bus): TypeError: PyQt4.QtCore.pyqtBoundSignal cannot be converted to PyQt4.QtCore.QObject in this context [/code] How correct this error? Snipped Code for illustrate: [code] class DataLink(QtCore.QObject): data_adds = QtCore.QtCore.pyqtSignal(frozenset) class DataRightLandPhys(DataLink): pass class DataRightLandJur(DataLink): pass class DataRightLandJur(DataLink): pass class Data(DataLink): __phys = None __jur = None __bus = None def __init__(self): super(Data, self).__init__() self.__phys = DataRightLandPhys() self.__jur = DataRightLandJur() self.__bus = DataRightLandBus() self.__connectAll() def __connectAll(self): for dm in (self.__phys, self.__jur, self.__bus): dm.data_adds.connect(self.data_adds.emit) I don't understand what you are trying to do in the last line. Phil ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
Re: [PyQt] QAbstractItemModel modelAboutToBeReset signal
Thanks!
Patrick
On Thu, Apr 9, 2009 at 8:57 AM, Phil Thompson
p...@riverbankcomputing.com wrote:
On Wed, 8 Apr 2009 11:55:39 -0400, Patrick Boucher
pbouc...@patrickboucher.com wrote:
Hi all,
I've subclassed QAbstractItemModel and overloaded reset to be:
def reset(self):
self.modelAboutToBeReset.emit()
self._loadPeople()
self.modelReset.emit()
and I get errors pertaining to missing attributes modelAboutToBeReset
and modelReset. Do I have something wrong with the new syntax for
emitting signals or is this a known thing or a bug? I'm using latest
snapshots of sip and pyqt.
The pre-4.5 version of the code works fine:
def reset(self):
self.emit(QtCore.SIGNAL('modelAboutToBeReset()'))
self._loadPeople()
self.emit(QtCore.SIGNAL('modelReset()'))
Should be fixed in tonight's PyQt snapshot.
Phil
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[PyQt] segfault when using a proxy and SIGNAL( clicked(QModelIndex) )
Hi everybody,
Here you will find a small (170 lines) self-contained Python script.
http://paratribulations.free.fr/help/python/simpleproxy.py
I use a model, and a proxy (that does nothing, but in a more complicated
version, not given here, it works perfectly). The view is a QTreeView.
The problem appears when I connect the SIGNAL( clicked(QModelIndex) ) to
some method cellClicked in the view, I obtain segfaults.
Difficult for me to find the problem.
Here are the most important lines:
self.view = QTreeView( parent )
self.connect( self.view, SIGNAL( clicked(QModelIndex) )
, self.cellClicked )
def cellClicked( self, qmodelindex ):
if qmodelindex.isValid():
print qmodelindex.internalPointer()
The problem seems to be related to qmodelindex, the segfault appears when
taking internalPointer method.
Any idea?
Thanks a lot.
Julien
--
python -c print ''.join([chr(154 - ord(c)) for c in '*9(9(18%.\
91+,\'Z4(55l4('])
When a distinguished but elderly scientist states that something is
possible, he is almost certainly right. When he states that something is
impossible, he is very probably wrong. (first law of AC Clarke)
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Re: [PyQt] How do you close a QDialog?
You should read the Python tutorial. It would probably help. http://docs.python.org/tutorial/ GatorAlli wrote: Thanks! It worked! =) Now how could you run this dialog from another script? (I'm no good at self, classes, and inheritance.) -- View this message in context: http://www.nabble.com/How-do-you-close-a-QDialog--tp22874235p22977765.html Sent from the PyQt mailing list archive at Nabble.com. ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
Re: [PyQt] context menus for QTreeWidgetItem?
I had this from the previous contextMenu that covered the whole treeWidget: self.treeWidget.setContextMenuPolicy(Qt.ActionsContextMenu) After I changed the line to this (makes sense), everything's all good: self.treeWidget.setContextMenuPolicy(Qt.CustomContextMenu) Thanks to everyone who replied. Christian projetmbc wrote: Christian Aubert a écrit : I currently have a context menu for the whole QTreeWidget but I need finer-grained control on a per item basis. Has anyone implemented context menus for QTreeWidgetItems? Any pointers? Christian ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt Hello, here is a solution that works. I hope tha will help you. To call the menu, just use : self.connect(self.treeWidget, QtCore.SIGNAL(customContextMenuRequested(const QPoint )), self.menuContextTree) Here is the method menuContextTree : def menuContextTree(self, point): # Infos about the node selected. index = self.treeWidget.indexAt(point) if not index.isValid(): return item = self.treeWidget.itemAt(point) name = item.text(0) # The text of the node. # We build the menu. menu=QtGui.QMenu(self) action=menu.addAction(Souris au-dessus de) action=menu.addAction(name) menu.addSeparator() action_1=menu.addAction(Choix 1) action_2=menu.addAction(Choix 2) action_3=menu.addAction(Choix 3) print QtGui.QCursor.pos() menu.exec_(QtGui.QCursor.pos()) ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
Re: [PyQt] How do you close a QDialog?
I don't follow 100%, but I guess you have say a GameMainWindow (non Qt), and you want to open a new QtDialog from within your MainWindow? The problem might be if you run your own even loop, then you run PyQt's event loop, messages for your window are no longer being received, causing the freeze. Since I don't know what your MainWindow is I can only haphazard a guess. Can you post a short sample reproducing the freeze? GatorAlli wrote: You see... I have a main application window. There is a button in the main window. Whan you click the button, the dialog should pop up. When the dialog's close command is called, I want the dialog to close cleanly, returning to the main window. I tried this... __Mainwindow.py import sprite import sys app = QtGui.QApplication(sys.argv) ui = sprite.action_select_dialog() ui.show() sys.exit(app.exec_()) ___ It opens the dialog perfectly, but when I call the hide command on the dialog, the dialog closes, but the main window is frozen. :-(( That's all I want you to answer. -- View this message in context: http://www.nabble.com/How-do-you-close-a-QDialog--tp22874235p22981747.html Sent from the PyQt mailing list archive at Nabble.com. ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
Re: [PyQt] [PyQt 4.5] TypeError: pyqtBoundSignal cannot be converted to QObject in this context
Phil Thompson wrote: def __connectAll(self): for dm in (self.__phys, self.__jur, self.__bus): dm.data_adds.connect(self.data_adds.emit) I don't understand what you are trying to do in the last line. It may well be more intuitive: [code] class DataLink(QtCore.QObject): data_adds = QtCore.QtCore.pyqtSignal(frozenset) ... def addObjects(self, objs): obj_oids = self._internalAddObjects(objs, *args, **kwd) self.data_adds.emit(obj_oids) ... class DataPhys(DataLink): pass class DataJur(DataLink): pass class DataBus(DataLink): pass class DataPerson(DataLink): __phys = None __jur = None __bus = None def __init__(self): super(DataPerson, self, phys, jur, bus).__init__() self.__phys = phys or DataPhys() self.__jur = jur or DataJur() self.__bus = bus or DatadBus() self.__connectAll() def __connectAll(self): for dm in (self.__phys, self.__jur, self.__bus): dm.data_adds.connect(self.data_adds.emit) [/code] I need to retransmit signals from the members. ___ PyQt mailing listPyQt@riverbankcomputing.com http://www.riverbankcomputing.com/mailman/listinfo/pyqt
