Re: [PyQt] identify a QTreeWidgetItem

2007-10-24 Thread alteo_gange 
Le mardi 23 octobre 2007, Michael Towers a écrit :
 alteo_gange wrote:
 print item.text(0), \n
  UnicodeEncodeError: 'ascii' codec can't encode character u'\xe9' in
  position 11: ordinal not in range(128)

 I find this one of the most annoying things in PyQt, it confuses me
 terribly. I think in this case you can do (for example)

 print unicode(item.text(0)), \n

 (the original result from item.text() being a QString)

 But it may be that you need to specify an encoding and use the
 encode or decode methods of unicode or string ...

Thanks! It works. Generally i write ' uunicode characters ', but in this 
case it was impossible.

Moreover i forgot u in the next of my function:
 if item.text(0) == uFiltres Vidéos

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alteo_gange


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Re: [PyQt] identify a QTreeWidgetItem

2007-10-24 Thread alteo_gange 
Le mardi 23 octobre 2007, Jim Bublitz a écrit :
 On Tuesday 23 October 2007 02:13, alteo_gange wrote:
  Hi everybody!
 
  I have created several QTreeWidgetItem and connected a signal
  itemClicked(QTreeWidgetItem *,int) on the QTreeWidget.
 
   treeWidget=QtGui.QTreeWidget(widget)
   ...
   itemTree1=QtGui.QTreeWidgetItem(treeWidget)
   ...
   itemTree2=QtGui.QTreeWidgetItem(treeWidget)
   ...
   self.connect(treeWidget,QtCore.SIGNAL(itemClicked(QTreeWidgetItem
   *,int)),self.function)
   ...
   def function(self, item):
   print item
 
  'print item' return:
  PyQt4.QtGui.QTreeWidgetItem object at 0x82cf62c.
 
 
  It's very abstract!
 
  I must identify QTreeWidgetItem in order to connect it an action (view a
  widget on the right), but how? With a method of the item reference?
  Which? I don't know.

 Store the items in a dict as you create them:

 self.itemDict = {}
 itemTree1=QtGui.QTreeWidgetItem(treeWidget)
 self.itemDict [itemTree1] = ??  # could be the associated widget that you
 want #  to connect to, or a # string identifier
 itemTree2=QtGui.QTreeWidgetItem(treeWidget)
 self.itemDict [itemTree2] = ??

 ...

 def function (self, item):
   widget = self.itemDict [item]
   ...

Great! Now, my code is more secure. I can use several times the same text on 
several QTreeWidgetItem and i can rename QTreeWidgetItem text without 
problems (the function mustn't be change).

Thanks!

-- 
alteo_gange


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[PyQt] identify a QTreeWidgetItem

2007-10-23 Thread alteo_gange 
Hi everybody! 
 
I have created several QTreeWidgetItem and connected a 
signal itemClicked(QTreeWidgetItem *,int) on the QTreeWidget.:
 
 
 treeWidget=QtGui.QTreeWidget(widget) 
 ... 
 itemTree1=QtGui.QTreeWidgetItem(treeWidget) 
 ... 
 itemTree2=QtGui.QTreeWidgetItem(treeWidget) 
 ... 
 self.connect(treeWidget,QtCore.SIGNAL(itemClicked(QTreeWidgetItem 
*,int)),self.function) 
 ... 
 def function(self, item): 
 print item 
 
 
'print item' return: 
PyQt4.QtGui.QTreeWidgetItem object at 0x82cf62c. 
 
 
It's very abstract! 
 
I must identify QTreeWidgetItem in order to connect it an action (view a 
widget on the right), but how? With a method of the item reference? Which? I 
don't know.

-- 
alteo_gange

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Re: [PyQt] identify a QTreeWidgetItem

2007-10-23 Thread alteo_gange 
I'm sorry for the multiple messages.
Few subscription problems. Now, it's OK.

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alteo_gange

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Re: [PyQt] identify a QTreeWidgetItem

2007-10-23 Thread Jim Bublitz 
On Tuesday 23 October 2007 02:13, alteo_gange wrote:
 Hi everybody!

 I have created several QTreeWidgetItem and connected a signal
 itemClicked(QTreeWidgetItem *,int) on the QTreeWidget.

  treeWidget=QtGui.QTreeWidget(widget)
  ...
  itemTree1=QtGui.QTreeWidgetItem(treeWidget)
  ...
  itemTree2=QtGui.QTreeWidgetItem(treeWidget)
  ...
  self.connect(treeWidget,QtCore.SIGNAL(itemClicked(QTreeWidgetItem
  *,int)),self.function)
  ...
  def function(self, item):
  print item

 'print item' return:
 PyQt4.QtGui.QTreeWidgetItem object at 0x82cf62c.


 It's very abstract!

 I must identify QTreeWidgetItem in order to connect it an action (view a
 widget on the right), but how? With a method of the item reference? Which?
 I don't know.

Store the items in a dict as you create them:

self.itemDict = {}
itemTree1=QtGui.QTreeWidgetItem(treeWidget)
self.itemDict [itemTree1] = ??  # could be the associated widget that you want  

   #  to connect to, or a   
 
   # string identifier
itemTree2=QtGui.QTreeWidgetItem(treeWidget)
self.itemDict [itemTree2] = ??

...

def function (self, item):
widget = self.itemDict [item]
...

Jim
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