generating unique variable name via loops
Hi, I want to generate a unique variable name for list using python. list1=... list2=... . . . listx=... where x is a number. You can remember it from saving a file in a directory. If you have already created a new file, save dialog sugget that new file is already exist, do you want to save it as new file (1)? so I want to apply it for list names. Do you any idea about this. -- https://mail.python.org/mailman/listinfo/python-list
Re: generating unique variable name via loops
4 Kasım 2014 Salı 13:29:34 UTC+2 tarihinde Fatih Güven yazdı: Editted: Grammar revision. Hi, I want to generate a unique variable name for list using python. list1=... list2=... . . . listx=... where x is a number. You can remember it from saving a file in a directory. If you have already created a new file, save dialog suggest that new file is already exist, do you want to save it as new file (1)? so I want to apply it for list names. Do you have any idea about this. -- https://mail.python.org/mailman/listinfo/python-list
Re: generating unique variable name via loops
4 Kasım 2014 Salı 15:19:20 UTC+2 tarihinde Veek M yazdı: Fatih Güven wrote: 4 Kas?m 2014 Sal? 13:29:34 UTC+2 tarihinde Fatih Güven yazd?: I want to generate a unique variable name for list using python. list1=... list2=... for x in range(1,10): exec(list%d = [] % x) This is okay but i can't use the method .append for example list1.append(abc) -- https://mail.python.org/mailman/listinfo/python-list
Re: generating unique variable name via loops
4 Kasım 2014 Salı 15:37:59 UTC+2 tarihinde Peter Otten yazdı: Veek M wrote: Fatih Güven wrote: 4 Kas?m 2014 Sal? 13:29:34 UTC+2 tarihinde Fatih Güven yazd?: I want to generate a unique variable name for list using python. list1=... list2=... for x in range(1,10): exec(list%d = [] % x) Why would you do this? I have a structured and repetitive data. I want to read a .txt file line by line and classified it to call easily. For example employee1 has a name, a salary, shift, age etc. and employee2 and other 101 employee have all of it. Call employee1.name or employee2.salary and assign it to a new variable, something etc. -- https://mail.python.org/mailman/listinfo/python-list
Re: fill, expand from tkinter.pack() layout manager
4 Kasım 2014 Salı 16:16:52 UTC+2 tarihinde ast yazdı: Hi I dont really understood how fill and expand works with layout manager tkinter.pack() Example: from tkinter import * root = Tk() w = Label(root, text=Red, bg=red, fg=white) w.pack(side=LEFT, fill = BOTH) Here is the result: http://cjoint.com/?0Kepj1E3Tv3 Why is the label w only extended vertically and not horizontally too ? I specified fill = BOTH so it should extend in both direction. (I know that with expand = 1, it will expand in both direction) thx Hi, Packing widgets splits frame into equal areas with expand=1. if expand=false, widgets don't touch each other and widgets save their own dimension. -- https://mail.python.org/mailman/listinfo/python-list
Re: generating unique variable name via loops
4 Kasım 2014 Salı 17:01:17 UTC+2 tarihinde Peter Otten yazdı:
Fatih Güven wrote:
4 Kasım 2014 Salı 15:37:59 UTC+2 tarihinde Peter Otten yazdı:
Veek M wrote:
Fatih Güven wrote:
4 Kas?m 2014 Sal? 13:29:34 UTC+2 tarihinde Fatih Güven yazd?:
I want to generate a unique variable name for list using python.
list1=...
list2=...
for x in range(1,10):
exec(list%d = [] % x)
Why would you do this?
I have a structured and repetitive data.
I was actually asking Veek M.
I want to read a .txt file line
by line and classified it to call easily. For example employee1 has a
name, a salary, shift, age etc. and employee2 and other 101 employee have
all of it.
Call employee1.name or employee2.salary and assign it to a new variable,
something etc.
I can only repeat my previous advice. Instead of creating variables for
employee1, employee2, and so on make a list of employees:
$ cat employees.txt
Peter,3000
Paul,2000
Mary,1000
$ cat employees.py
#!/usr/bin/env python3
import csv
class Employee:
def __init__(self, name, salary):
self.name = name
self.salary = salary
if __name__ == __main__:
employees = []
with open(employees.txt) as f:
for row in csv.reader(f):
employees.append(Employee(row[0], int(row[1])))
for employee in employees:
print(employee.name, -- salary:, employee.salary, doubloons)
$ python3 employees.py
Peter -- salary: 3000 doubloons
Paul -- salary: 2000 doubloons
Mary -- salary: 1000 doubloons
You wouldn't want to reference Paul as employee2 -- what if the order in the
text file changed? Instead you can make a dict that maps name to employee...
employees_by_name = {}
for employee in employees:
name = employee.name
if name in employees_by_name:
raise ValueError(duplicate name {}.format(name))
employees_by_name[name] = employee
and use that dict to look up an employee:
while True:
name = input(enter a name )
if name == :
print(That's all folks)
break
if name not in employees_by_name:
print(unknown name)
else:
print(Salary:, employees_by_name[name].salary, doubloons)
$ python3 employees.py
Peter -- salary: 3000 doubloons
Paul -- salary: 2000 doubloons
Mary -- salary: 1000 doubloons
enter a name Peter
Salary: 3000 doubloons
enter a name Mary
Salary: 1000 doubloons
enter a name paul
unknown name
enter a name Paul
Salary: 2000 doubloons
enter a name
That's all folks
$
Thanks for your concern, I will try this. Actually, the main focus is that are
there any other Paul in my team. So i want to create a simple ID for employee
to distinguish two Paul. I belive that you have a solution for this.
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