Parse command line output using textfsm
Hi List, I am using python to run command line utilities on Linux machine. I came across textfsm and feel that it fits my requirements. Here is the structure of the output from the 2 utilities Command 1: Id AddressPort Location State Tenant count Max tenants Description -- -- -- --- 1 10.0.32.20 8443 -ACTIVE712 - 2 10.0.32.21 8443 -ACTIVE712 - 3 10.0.32.22 8443 -ACTIVE712 - Command 2: 12012-04-04 19:54 00DD000q3di GOLDCompany 1 CA360 ACTIVE Yes https://10.0.32.26:7000 8 50 17 2012-04-09 23:01 00Dd000efRF SILVER Company 2 CA360 ACTIVE Yes https://10.0.32.20:7014 1 440 27 2012-04-10 03:42 00Dd000efdS TRIAL Company 3 CA360 ACTIVE Yes https://10.0.32.23:7021 4 10 32 2012-04-11 11:24 00Dd000eiGb TRIAL Company 4 CA360 INACTIVE Yes https://10.0.32.21:7000 2 25 I found this link documenting how to parse tabular data: http://code.google.com/p/textfsm/wiki/TextFSMCodeLab#Parsing_tabular_data My question is, what is the syntax of the pattern matching used. Is it the same as python regexp? Any other documentation/examples available for this library? I'm also open to suggestions of using other libraries. Basically, I would like this to be semantically as close as possible to working with data extracted from a database. Thanks and regards, Ferdi -- http://mail.python.org/mailman/listinfo/python-list
COM and threading, "CoInitialize"?
Greetings to list members,
I am trying to use an Acrobat COM object in a class that is subclassed from
threading.Thread.
Since threading.Thread is subclassed, the __init__ method of the inheriting
class must explicitly call the threading.Thread.__init__ method of the
parent. I guess I'm missing something similar for the COM object. Threading
code and traceback below. Any pointers?
CODE:
=
class process_file(threading.Thread):
def __init__(self,connection):
threading.Thread.__init__(self)
self.connection=connection
def run(self):
irrelevant code here
# Acrobat COM starts
AVD = win32com.client.Dispatch('AcroExch.AVDoc') # Traceback
refers to this line (89)
pdfname=pdfname.replace('.pdf',PDFNAME_SUFFIX)
AVD.Open(pdf.name, pdfname) #
print 'opened avdoc'
==
TRACEBACK:
==
Exception in thread Thread-1:
Traceback (most recent call last):
File "C:\Python25\lib\threading.py", line 486, in __bootstrap_inner
self.run()
File "D:\Ferdinand\#Storage\Ferdi-python\Acrobat Automation\temp
testing.py", line 89, in run
AVD = win32com.client.Dispatch('AcroExch.AVDoc')
File "C:\Python25\Lib\site-packages\win32com\client\__init__.py", line 95,
in Dispatch
dispatch, userName =
dynamic._GetGoodDispatchAndUserName(dispatch,userName,clsctx)
File "C:\Python25\Lib\site-packages\win32com\client\dynamic.py", line 98,
in _GetGoodDispatchAndUserName
return (_GetGoodDispatch(IDispatch, clsctx), userName)
File "C:\Python25\Lib\site-packages\win32com\client\dynamic.py", line 78,
in _GetGoodDispatch
IDispatch = pythoncom.CoCreateInstance(IDispatch, None, clsctx,
pythoncom.IID_IDispatch)
com_error: (-2147221008, 'CoInitialize has not been called.', None, None)
==
TIA. Best regards,
Ferdi
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Re: Varibles -- copies and references
People get a confused because if you pass a mutable object inside a def function and mutate that object the changes /are/ propagated outside-- because now you have a name inside the function and a name outside the object both pointing to the same object. Since tuples are immutable, I guess passing tuples to functions would achieve the result desired by me: result = func ( (anobject) ) If you want a function to work on a copy of a mutable object passed to it, and not the real object itself, you must explicitly make a copy of it. Or using deepcopy within the function definition. This would be better as I could simply pass an object to the function. I don't think there is another way to make an object mutable by something in the class definition. Is there? >>>class AA: a=111 >>> x=AA() >>> x.a 111 >>> y=x >>> y.a 111 >>> y.a=222 >>> x.a 222 # undesirable? >>> z=copy.deepcopy(x) >>> z.a 222 >>> z.a=444 >>> x.a 222 >>> y.a 222 The reason you see the "undesirable" behavior of a change to y.a showing the same result of x.a... is because those are the *exact* same instance. You didn't make a copy of the instance, you just made a new name and bound it to the same instance. If you want to copy in Python you have to explicitly do so, via the 'copy' module or any copy methods an object provides. Could someone please give me an example of how to implement this copy method for the AA class. Going the other way: >>> a=555 >>> d=copy.copy(a) # Supposed to be a shallow copy >>> d 555 >>> d=444 >>> a # But, it doesn't change the original 555 Is there any way to get ints/strings to refer to the same object? Thanks and Regards, Ferdi -- http://mail.python.org/mailman/listinfo/python-list
Varibles -- copies and references
Hi
Some weeks back I had been following the thread "Why can't assign to
function call". Today, I saw the "function scope" thread, and decided I
should ask about the behaviour below:
>>> #
Simple variables
>>>p=55
>>> q=p
>>> q
55
>>> q=44
>>> p
55
>>>
>>> #
In a function
>>> def dd(d):
del d['key']
return d
>>> adict={'pramod':'goodboy', 'ferdi':'badboy', 'key':'to be deleted'}
>>> dd(adict)
{'ferdi': 'badboy', 'pramod': 'goodboy'}
>>> adict
{'ferdi': 'badboy', 'pramod': 'goodboy'} #
undesirable?
>>>
>>> #
In a class
>>>class AA:
a=111
>>> x=AA()
>>> x.a
111
>>> y=x
>>> y.a
111
>>> y.a=222
>>> x.a
222 #
undesirable?
>>> z=copy.deepcopy(x)
>>> z.a
222
>>> z.a=444
>>> x.a
222
>>> y.a
222
>>>
Guess the simple types show the expected behaviour (even though they are
technically instances of existing classes). The user defined classes seem to
be references/shallow copies. The "function scope" thread refers to
http://www.python.org/doc/faq/general/#why-are-default-values-shared-between-objectsto
explain why default parameters should not be modified. But, in the
function example above, the dictionary passed as a variable *in the calling
scope* gets modified.
How can you avoid the dictionary being changed?
Assigning one object to another always creates references? Can you modify
anything in the class def to get a copy? [I have a tingling feeling this is
how the default types (integers, strings etc) are defined]
Thanks and best regards,
Ferdi
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Re: Python-list Digest, Vol 64, Issue 617
>
> Secondly, it has no way to display the image drawn on. Is it possible, or
>>> do
>>> I have to pass the image off to another module's methods?
>>
>> im.show() this will display the image (and any modification(s) made to
it)
>
>> Example: Draw a Grey Cross Over an Image
>> import Image, ImageDraw
>> im = Image.open("lena.pgm")
>> draw = ImageDraw.Draw(im)
>> draw.line((0, 0) + im.size, fill=128)
>> draw.line((0, im.size[1], im.size[0], 0), fill=128)
>> del draw
>> # write to stdout
>> im.save(sys.stdout, "PNG")
>>
>> Hope that helps
>>
> That's pretty much the code I used. In fact, I borrowed it from the pdf. I
> just tried it, and it output "%PNG".
>
> im.save("picture1.png")
OR
im.save("picture1" "png") # not sure if it has to be "PNG"
What was happening earlier was that the binary data was being directed to
the standard output, which is where all your text is printed by a print
statement (print func in Py 3000). If you open a png in notepad, you will
notice that the 1st four characters are indeed %PNG, which is the magic
number for a PNG file.
For further info, see:
http://en.wikipedia.org/wiki/Magic_number_(programming)#Magic_numbers_in_files
http://en.wikipedia.org/wiki/Portable_Network_Graphics#File_header
Regards,
Ferdi
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Re: strange dict issue
James
First off, the computer is always right :-)
> {'value': 'Route66', 'key': 'NAME'}
>
>
>
> Yet when the second line of my code throws an error saying the key 'NAME'
> doesn't exist.
>
If you look carefully the key NAME indeed does not exist. The dictionary
contains 2 key-value pairs.
This should clear things out:
*key * *value
*'value' 'Route66'
'key' 'NAME'
Get it? NAME is a value, not a key. You have used the string 'key' itself as
a dictionary key. My advice would be to not use such conflicting names.
Regards,
Ferdi
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Transferring a file over sockets
I am using sockets to transfer a file over LAN. There are 2 scripts, the
server opens a listens for connection and the client is run on another
machine. I always make sure the server is run first. The strange thing is
that if the the server script is double-clicked and executed (run in a
console with title %Python path%python.exe) the output file saved on the
server is truncated. It works just fine if you open the server script in
IDLE and then run it. The client script can be run in either way, it still
works. You could try using any arbitrary file to test this behaviour after
changing the file name in both the scripts.
==
# file receiver
# work in progress
import socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
HOST = '192.168.1.17'
PORT = 31400
s.bind((HOST, PORT))
s.listen(3)
conn, addr = s.accept()
print 'conn at address',addr
conn.send('READY')
f = open('C:\\Documents and Settings\\USER\\Desktop\\test.pdf','wb')
fsize=int(conn.recv(8))
print 'File size',fsize
f.write(conn.recv(fsize))
f.close()
conn.close()
s.close()
raw_input('Press any key to exit')
===
# file sender !!!
# Work in progress
import socket, os
from stat import ST_SIZE
HOST = '192.168.1.17'
PORT = 31400 # Arbitrary non-privileged port
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((HOST,PORT))
if s.recv(5)!='READY':
raw_input('Unable to connect \n\n Press any key to exit ...')
s.close()
exit()
f=open('C:\\Documents and Settings\\USER\\Desktop\\t.pdf', 'rb')
fsize=os.stat(f.name)[ST_SIZE]
s.send(str(fsize))
s.send(f.read())
s.close()
f.close()
===
Thanks for reading!!
Best regards,
Ferdi
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