Re: neoPython : Fastest Python Implementation: Coming Soon
I wish you best of luck, on top of everything else it looks like the neopython namespace has already been eaten up by some crypto project On Wed, May 5, 2021 at 11:18 AM Benjamin Schollnick < bscholln...@schollnick.net> wrote: > > Why? The currently extant Python implementations contribute to climate > change as they are so inefficient; > > That same argument can be made for every triple-AAA video game, game > console, etc. > > Python is more efficient for some problem sets, and Python is less > efficient for other problem sets. > > Please feel free to come out with NeoPython. When you are done, and it is > backward compatible with existing Python code, I’ll be happy to benchmark > it against Native python. But don’t blame Python for global climate > change. There are plenty of bigger “causations” to Global climate change, > then a freakin’ computer programming language. > > - Benjamin > > > -- > https://mail.python.org/mailman/listinfo/python-list > -- https://mail.python.org/mailman/listinfo/python-list
Re: The sum of ten numbers inserted from the user
This is my whack at it, I can't wait to hear about it being the wrong big o
notation!
numbers=[]
while len(numbers) < 10:
try:
chip = int(input('please enter an integer: '))
except ValueError:
print('that is not a number, try again')
else:
numbers.append(chip)
print(sum(numbers))
On Thu, Feb 7, 2019 at 10:23 AM Schachner, Joseph <
joseph.schach...@teledyne.com> wrote:
> Well of course that doesn't work. For starters, x is an int or a float
> value. After the loop It holds the 10th value. It might hold 432.7 ...
> It is not a list.
> The default start for range is 0. The stop value, as you already know, is
> not part of the range. So I will use range(10).
>
> In the second loop, I think you thought x would be a list and you I'm sure
> you wanted to do
> for y in x:
> but instead you did
> for y in range(x)
> and remember x might be a very large number.So the second loop would
> loop that many times, and each pass it would assign y (which has first
> value of 0 and last value of whatever x-1 is) to sum. Even though its name
> is "sum" it is not a sum. After the loop it would hold x-1. You wanted to
> do sum += y.Or sum = sum + y. I prefer the former, but that could
> reflect my history as a C and C++ programmer.
>
> And then you printed y, but you really want to print sum (assuming that
> sum was actually the sum).
>
> Putting all of the above together, you want to do this:
>
> vallist =[] # an empty list, so we can append to it
> for n in range(10):
> x = input("Insert a number: ")# get 1 number into x
> vallist.append(x) # append it to our list
>
> # Now vallist holds 10 values
>
> sum = 0 # No need to start sum as a float, in Python if we add a float
> to an integer the result will be float. It doesn't matter in the program if
> sum is int or float.
> for y in vallist:
> sum += y
>
> print( "The sum is: ", sum)
>
>
>
> -Original Message-
> From: ^Bart
> Sent: Thursday, February 7, 2019 6:30 AM
> To: python-list@python.org
> Subject: The sum of ten numbers inserted from the user
>
> I thought something like it but doesn't work...
>
> for n in range(1, 11):
> x = input("Insert a number: ")
>
> for y in range(x):
> sum = y
>
> print ("The sum is: ",y)
>
> --
> https://mail.python.org/mailman/listinfo/python-list
>
--
https://mail.python.org/mailman/listinfo/python-list
Re: How to replace space in a string with \n
text = "The best day of my life!" output = '' for i in text: if i == ' ': output +='\n' else: output += i print(output) throwing my hat in the ring, not only is it .replace free it is entirely method free On Thu, Jan 31, 2019 at 3:41 AM ^Bart wrote: > [Solved by myself and I'm happy!!! :)] > > text = "The best day of my life!" > > space = text[3] > > print (text.replace(space, "\n")) > > [Like what I said in another message, in the afternoon I'll ask to the > teacher if for this exercise we're able to use .replace] > -- > https://mail.python.org/mailman/listinfo/python-list > -- https://mail.python.org/mailman/listinfo/python-list
Re: what considerations for changing height of replacement radiator?
looking for a Space heater? sorry, not the Java mailing list On Wed, Jan 30, 2019 at 3:11 PM jkn wrote: > Hi all > I'm looking at changing a radiator in a bedroom shortly and wondering > about > my options re. sizing. > > The current radiator is 900mm W x 600mm H, and is single panel, no > convector. So > looking at some representative specs, let's say 550W output. > > I would be replacing this with a single panel, single convector radiator. > From > looking at the spec again, the same sized radiator gives around 50% greater > output - 900W. > > I am wondering about fitting a 900mm W x 450mm H single panel, single > convector, > which would then reduce the output again to 700W or so, similar to the > original. > > My reason for doing this would simply be 'neater appearance' of the smaller > radiator, but it wouldn't be a problem if the replacement was the same > size as > the original. I am wondering if there is anything else (apart from power > output) > that I should be considering here? > > The radiator will be under a window and the CH is an olde school 'plan C', > I > think. I would probably fit a TRV in any case. There is no need to heat > the room > any better than currently... > > Thanks for any advice. > > Cheers > Jon N > -- > https://mail.python.org/mailman/listinfo/python-list > -- https://mail.python.org/mailman/listinfo/python-list
Re: Python stopped installing packages
according to https://pypi.org/project/discord.py/ Discord.py only supports 3.4 and 3.5 On Tue, Jan 29, 2019 at 4:52 PM Hamish Allen <101929...@gmail.com> wrote: > Hi, > > Recently I’ve been trying to code a Discord bot in Python 3.6.2, then I > realised that some features of discord.py were only available in Python > 3.7+ (as seen here on the right near the top > https://docs.python.org/3/library/asyncio.html), so I downloaded 3.7.2. > After correctly changing the environmental variables to have Python 3.7.2 > before Python 3.6.2, I tried installing (for installing I was using cmd > ‘pip install discord.py’, I’m not aware of any other way to install > packages) discord.py onto Python 3.7.2, but after a few seconds there would > be a whole page of red error text (attached), then it would say > successfully installed. I tried importing it in code, but it would return > errors implying it was incorrectly installed. I asked one of my friends for > some help. He suggested uninstalling Python 3.6.2 and 3.7.2 and > reinstalling Python 3.7.2. I thought this was a pretty good idea so I did > it. Discord.py still refuses to be installed. I tried installing some of > the packages I had in 3.6.2, but they had the same sort of problem. I’ve > tried running the installer to repair the files, but that didn’t work. I > would appreciate if you could help me. I got discord.py from here: > https://github.com/Rapptz/discord.py I’ve tried the 3 commands in the > Installing section and I’ve tried pip install discord.py. > > Thanks, > Hamish > -- > https://mail.python.org/mailman/listinfo/python-list > -- https://mail.python.org/mailman/listinfo/python-list
Re: Exercize to understand from three numbers which is more high
which version of Python? I get Syntax error on 3.7.1
On Tue, Jan 29, 2019 at 12:37 PM Adrian Ordona
wrote:
> The code actually works just the way i copy and pasted
>
> Sent from my iPhone
>
> On Jan 29, 2019, at 12:34, Ian Clark wrote:
>
> just the pure number of letters next to parenthesis would cause the Parser
> to error out
>
> On Tue, Jan 29, 2019 at 12:32 PM Schachner, Joseph <
> joseph.schach...@teledyne.com> wrote:
>
>> Yes, that works. Assuming it was correctly formatted when you ran it.
>> The formatting could not possibly be run in a Python interpreter, I think.
>>
>> --- Joseph S.
>>
>> From: Adrian Ordona
>> Sent: Tuesday, January 29, 2019 2:52 PM
>> To: Schachner, Joseph
>> Cc: Dan Sommers <2qdxy4rzwzuui...@potatochowder.com>;
>> python-list@python.org
>> Subject: Re: Exercize to understand from three numbers which is more high
>>
>> i'm also a beginner reading all the replies helps.
>> i was trying the problem myself and came up with the below code with a
>> users input.
>>
>>
>> num1 = int(input("Enter first number: "))num2 = int(input("Enter second
>> number: "))num3 = int(input("Enter third number: "))if num1 > num2 and num1
>> > num3:print(num1, " is th max number")elif num2 > num1 and num2 >
>> num3:print(num2, " is the max number")else: print(num3, "is the max
>> number")
>>
>> On Tue, Jan 29, 2019 at 1:48 PM Schachner, Joseph <
>> joseph.schach...@teledyne.com<mailto:joseph.schach...@teledyne.com>>
>> wrote:
>> Explanation: 5 > 4 so it goes into the first if. 5 is not greater than
>> 6, so it does not assign N1 to MaxNum. The elif (because of the lack of
>> indent) applies to the first if, so nothing further is executed. Nothing
>> has been assigned to MaxNum, so that variable does not exist. You're
>> right, it does not work.
>>
>> How about this:
>> Mylist = [ N1, N2, N3]
>> Maxnum = N1
>> for value in Mylist:
>> if value > Maxnum:
>> Maxnum = value
>> print(Maxnum)
>>
>> Or were lists and for loops excluded from this exercise?
>> --- Joe S.
>>
>> On 1/29/19 9:27 AM, Jack Dangler wrote:
>>
>> > wow. Seems like a lot going on. You have 3 ints and need to determine
>> > the max? Doesn't this work?
>> >
>> > N1, N2, N3
>> >
>> > if N1>N2
>> >if N1>N3
>> > MaxNum = N1
>> > elif N2>N3
>> >MaxNum = N2
>> > elif N1> >MaxNum = N3
>>
>> No. Assuing that you meant to include colons where I think you did, what
>> if (N1, N2, N3) == (5, 4, 6)?
>>
>> --
>> https://mail.python.org/mailman/listinfo/python-list
>> --
>> https://mail.python.org/mailman/listinfo/python-list
>>
>
--
https://mail.python.org/mailman/listinfo/python-list
Re: Exercize to understand from three numbers which is more high
just the pure number of letters next to parenthesis would cause the Parser
to error out
On Tue, Jan 29, 2019 at 12:32 PM Schachner, Joseph <
joseph.schach...@teledyne.com> wrote:
> Yes, that works. Assuming it was correctly formatted when you ran it.
> The formatting could not possibly be run in a Python interpreter, I think.
>
> --- Joseph S.
>
> From: Adrian Ordona
> Sent: Tuesday, January 29, 2019 2:52 PM
> To: Schachner, Joseph
> Cc: Dan Sommers <2qdxy4rzwzuui...@potatochowder.com>;
> python-list@python.org
> Subject: Re: Exercize to understand from three numbers which is more high
>
> i'm also a beginner reading all the replies helps.
> i was trying the problem myself and came up with the below code with a
> users input.
>
>
> num1 = int(input("Enter first number: "))num2 = int(input("Enter second
> number: "))num3 = int(input("Enter third number: "))if num1 > num2 and num1
> > num3:print(num1, " is th max number")elif num2 > num1 and num2 >
> num3:print(num2, " is the max number")else: print(num3, "is the max
> number")
>
> On Tue, Jan 29, 2019 at 1:48 PM Schachner, Joseph <
> joseph.schach...@teledyne.com>
> wrote:
> Explanation: 5 > 4 so it goes into the first if. 5 is not greater than 6,
> so it does not assign N1 to MaxNum. The elif (because of the lack of
> indent) applies to the first if, so nothing further is executed. Nothing
> has been assigned to MaxNum, so that variable does not exist. You're
> right, it does not work.
>
> How about this:
> Mylist = [ N1, N2, N3]
> Maxnum = N1
> for value in Mylist:
> if value > Maxnum:
> Maxnum = value
> print(Maxnum)
>
> Or were lists and for loops excluded from this exercise?
> --- Joe S.
>
> On 1/29/19 9:27 AM, Jack Dangler wrote:
>
> > wow. Seems like a lot going on. You have 3 ints and need to determine
> > the max? Doesn't this work?
> >
> > N1, N2, N3
> >
> > if N1>N2
> >if N1>N3
> > MaxNum = N1
> > elif N2>N3
> >MaxNum = N2
> > elif N1 >MaxNum = N3
>
> No. Assuing that you meant to include colons where I think you did, what
> if (N1, N2, N3) == (5, 4, 6)?
>
> --
> https://mail.python.org/mailman/listinfo/python-list
> --
> https://mail.python.org/mailman/listinfo/python-list
>
--
https://mail.python.org/mailman/listinfo/python-list
Re: Problem in Installing version 3.7.2(64 bit)
back in my day we had to show our professors errors on punchcard! and we liked it On Sun, Jan 27, 2019 at 11:51 AM Terry Reedy wrote: > On 1/26/2019 6:24 AM, Vrinda Bansal wrote: > > Dear Sir/Madam, > > > > After Installation of the version 3.7.2(64 bit) in Windows 8 when I run > the > > program it gives an error. Screenshot of the error is attached below. > > Nope. This is text only mail list. Images are tossed. You must copy > and paste. > > -- > Terry Jan Reedy > > -- > https://mail.python.org/mailman/listinfo/python-list > -- https://mail.python.org/mailman/listinfo/python-list
Re: Exercize to understand from three numbers which is more high
threw this together, let me know what you think
num_list=[]
name_list =
['first','second','third','fourth','fifth','sixth','seventh','eighth','ninth','tenth']
name_it = name_list.pop(0)
while len(num_list) < 3:
try:
num_list.append( int( input(f"Insert the {name_it} number: ")))
except ValueError:
print('Not a number, try again!')
else:
name_it = name_list.pop(0)
print(f"Max number is: {sorted(num_list)[-1]}")
On Mon, Jan 28, 2019 at 1:58 AM Frank Millman wrote:
> "^Bart" wrote in message news:q2mghh$ah6$1...@gioia.aioe.org...
> >
> > > 1. The last two lines appear to be indented under the 'if number3 < '
> > > line. I think you want them to be unindented so that they run every
> > > time.
> >
> > I'm sorry but I didn't completely understand what you wrote about the
> last
> > two lines, please could you write how my code could be fixed?
> >
>
> The last four lines of your program look like this -
>
> if number3 < number2 and number3 < number1:
> numbermin = number3
>
> print("Number min is: ",numbermin)
>
> numbermiddle = (number1+number2+number3)-(numbermax+numbermin)
>
> print("Number middle is: ",numbermiddle)
>
> The last three lines all fall under the 'if number3 < number2' line, so
> they
> will only be executed if that line evaluates to True.
>
> I think that you want the last two lines to be executed every time. If so,
> they should be lined up underneath the 'if', not the 'print'.
>
> >
> > > if a == 1:
> > > do something
> > > elif a == 2:
> > > do something else
> >
> > Finally I understood the differences between if and elif! Lol! :D
> >
>
> It is actually short for 'else if', but I guess it is not obvious if you
> have not seen it before!
>
> Frank
>
>
> --
> https://mail.python.org/mailman/listinfo/python-list
>
--
https://mail.python.org/mailman/listinfo/python-list
Re: Exercize to understand from three numbers which is more high
Like this?
num_max = 0
num_index = 0
name_list =
['first','second','third','fourth','fifth','sixth','seventh','eighth','ninth','tenth']
name_it = name_list.pop(0)
while num_index <3:
try:
num_list = int( input(f"Insert the {name_it} number: "))
except ValueError:
print('Not a number, try again!')
else:
num_index += 1
if num_list > num_max:
num_max = num_list
name_it = name_list.pop(0)
print(f"Max number is: {num_max}")
On Tue, Jan 29, 2019 at 1:26 PM Chris Angelico wrote:
> On Wed, Jan 30, 2019 at 8:20 AM Bob van der Poel wrote:
> > Isn't the easiest way to do this is:
> >
> > sorted( [n1,n2,n3] )[-1]
> >
> > to get the largest value?
>
> >>> help(max)
>
> But the point of this exercise is not to use sorted() or max().
>
> ChrisA
> --
> https://mail.python.org/mailman/listinfo/python-list
>
--
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Re: Raising exception on STDIN read
On 2008-02-28, Gabriel Genellina [EMAIL PROTECTED] wrote: I hope it's more clear now. Python objects are only meaningful *inside* a Python program, but an *external* program can't use them directly. Yes, sorry. This is what I was getting hung up on. My thinking was that subprocess was orchestrating it such that any reads would be funneled back into the Python object. Granted, that was my gut reaction to it. Thinking (and playing) with it a bit more I now realize that that makes no sense. Thank you for reminding me about the seperation of OS and Python files. Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Raising exception on STDIN read
On 2008-02-27, Gabriel Genellina [EMAIL PROTECTED] wrote: En Wed, 27 Feb 2008 15:06:36 -0200, Ian Clark [EMAIL PROTECTED] escribi�: On 2008-02-27, Michael Goerz [EMAIL PROTECTED] wrote: Hi, I would like to raise an exception any time a subprocess tries to read from STDIN: latexprocess = subprocess.Popen( \ 'pdflatex' + \ + 'test' + 21, \ shell=True, \ cwd=os.getcwd(), \ env=os.environ, \ stdin=StdinCatcher() # any ideas here? ) An exception should be raised whenever the pdflatex process reads from STDIN... and I have no idea how to do it. Any suggestions? How about with a file-like object? I haven't tested this with subprocess so you might want to read the manual on files if it doesn't work[1]. Won't work for an external process, as pdflatex (and the OS) knows nothing about Python objects. The arguments to subprocess.Popen must be actual files having real OS file descriptors. Taken from the subprocess documentation (emphasis mine). [1] stdin, stdout and stderr specify the executed programs' standard input, standard output and standard error file handles, respectively. Valid values are PIPE, an existing file descriptor (a positive integer), *an existing file object*, and None. The following peice of code works fine for me with the subprocess module. NOTE: the only difference from this and the last I posted is that I set fileno() to _error(). import sys import subprocess class ErrorFile(object): def _error(self, *args, **kwargs): raise AssertionError(Illegal Access) def _noop(self, *args, **kwargs): pass close = flush = seek = tell = _noop next = read = readline = readlines = xreadlines = tuncate = _error truncate = write = writelines = fileno = _error # ^^ proc = subprocess.Popen(cat -, shell=True, stdin=ErrorFile()) ret = proc.wait() print return, ret Ian [1] http://docs.python.org/lib/node528.html -- http://mail.python.org/mailman/listinfo/python-list
Re: Raising exception on STDIN read
On 2008-02-28, Gabriel Genellina [EMAIL PROTECTED] wrote: En Thu, 28 Feb 2008 14:29:04 -0200, Ian Clark [EMAIL PROTECTED] escribió: On 2008-02-27, Gabriel Genellina [EMAIL PROTECTED] wrote: En Wed, 27 Feb 2008 15:06:36 -0200, Ian Clark [EMAIL PROTECTED] escribi�: On 2008-02-27, Michael Goerz [EMAIL PROTECTED] wrote: Hi, I would like to raise an exception any time a subprocess tries to read from STDIN: latexprocess = subprocess.Popen( \ 'pdflatex' + \ + 'test' + 21, \ shell=True, \ cwd=os.getcwd(), \ env=os.environ, \ stdin=StdinCatcher() # any ideas here? ) An exception should be raised whenever the pdflatex process reads from STDIN... and I have no idea how to do it. Any suggestions? How about with a file-like object? I haven't tested this with subprocess so you might want to read the manual on files if it doesn't work[1]. Won't work for an external process, as pdflatex (and the OS) knows nothing about Python objects. The arguments to subprocess.Popen must be actual files having real OS file descriptors. Taken from the subprocess documentation (emphasis mine). [1] stdin, stdout and stderr specify the executed programs' standard input, standard output and standard error file handles, respectively. Valid values are PIPE, an existing file descriptor (a positive integer), *an existing file object*, and None. The following peice of code works fine for me with the subprocess module. NOTE: the only difference from this and the last I posted is that I set fileno() to _error(). import sys import subprocess class ErrorFile(object): def _error(self, *args, **kwargs): raise AssertionError(Illegal Access) def _noop(self, *args, **kwargs): pass close = flush = seek = tell = _noop next = read = readline = readlines = xreadlines = tuncate = _error truncate = write = writelines = fileno = _error # ^^ proc = subprocess.Popen(cat -, shell=True, stdin=ErrorFile()) ret = proc.wait() print return, ret I don't see how this could ever work. The shell knows nothing about your ErrorFile objects. If subprocess.Popen doesn't reject that ErrorFile instance, it's a bug. An ErrorFile instance is not an existing file object. Could you please explain why this won't work. ErrorFile exposes most all attributes of file objects, so I don't understand why it wouldn't be considered a file object. Did you try running the code by any chance? It works fine for me on 2.5.1 on Linux. Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Raising exception on STDIN read
On 2008-02-27, Michael Goerz [EMAIL PROTECTED] wrote: Hi, I would like to raise an exception any time a subprocess tries to read from STDIN: latexprocess = subprocess.Popen( \ 'pdflatex' + \ + 'test' + 21, \ shell=True, \ cwd=os.getcwd(), \ env=os.environ, \ stdin=StdinCatcher() # any ideas here? ) An exception should be raised whenever the pdflatex process reads from STDIN... and I have no idea how to do it. Any suggestions? Thanks, Michael How about with a file-like object? I haven't tested this with subprocess so you might want to read the manual on files if it doesn't work[1]. import sys class ErrorFile(object): def _error(self, *args, **kwargs): raise AssertionError(Illegal Access) def _noop(self, *args, **kwargs): pass close = flush = seek = tell = _noop next = read = readline = readlines = xreadlines = tuncate = _error truncate = write = writelines = _error sys.stdin = ErrorFile() print raw_input(? ) Ian [1] http://docs.python.org/lib/bltin-file-objects.html -- http://mail.python.org/mailman/listinfo/python-list
Re: Is crawling the stack bad? Why?
On 2008-02-25, Russell Warren [EMAIL PROTECTED] wrote:
the threading.local class seems defined for that purpose, not that I've ever
used it ;)
I hadn't heard of that... it seems very useful, but in this case I
think it just saves me the trouble of making a stash dictionary...
unless successive calls to threading.local return the same instance?
I'll have to try that, too.
No, successive calls to threading.local() will return different objects.
So, you call it once to get your 'data store' and then use that one
object from all your threads. It takes care of making sure each thread
gets it's own data.
Here is your example, but using threading.local instead of your own
version of it. :)
Ian
import xmlrpclib, threading, sys, thread
from SimpleXMLRPCServer import SimpleXMLRPCServer,
SimpleXMLRPCRequestHandler
thread_data = threading.local()
class RpcContainer(object):
def __init__(self):
self._Handlers = {} #keys = thread IDs, values=requestHandlers
def _GetRpcClientIP(self):
#connection = self._Handlers[thread.get_ident()].connection
connection = thread_data.request.connection
ip = connection.getpeername()[0]
return ip
def WhatIsMyIP(self):
return Your IP is: %s % self._GetRpcClientIP()
class ThreadCapableRequestHandler(SimpleXMLRPCRequestHandler):
def do_POST(self, *args, **kwargs):
#make the handler available to the RPCs, indexed by threadID...
thread_data.request = self
SimpleXMLRPCRequestHandler.do_POST(self, *args, **kwargs)
class MyXMLRPCServer(SimpleXMLRPCServer):
def __init__(self, RpcContainer, *args, **kwargs):
self.RpcContainer = RpcContainer
SimpleXMLRPCServer.__init__(self, *args, **kwargs)
class DaemonicServerLaunchThread(threading.Thread):
def __init__(self, RpcServer, **kwargs):
threading.Thread.__init__(self, **kwargs)
self.setDaemon(1)
self.server = RpcServer
def run(self):
self.server.serve_forever()
container = RpcContainer()
rpcServer = MyXMLRPCServer(
RpcContainer = container,
addr = (, 12390),
requestHandler = ThreadCapableRequestHandler,
logRequests = False)
rpcServer.register_function(container.WhatIsMyIP)
slt = DaemonicServerLaunchThread(rpcServer)
slt.start()
sp = xmlrpclib.ServerProxy(http://localhost:12390;)
print sp.WhatIsMyIP()
--
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Re: os.fork() not working on windows (help)
On 2008-02-25, A. Joseph [EMAIL PROTECTED] wrote: Please i`m trying to create a process using the os.fork() but it keep If you're not trying to clone your current process, just make a new one, you should look at the subprocess module. http://docs.python.org/lib/module-subprocess.html Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Curses and Threading
On 2008-01-22, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote: In fact you have *two* threads: the main thread, and the one you create explicitly. After you start the clock thread, the main thread continues executing, immediately entering the finally clause. If you want to wait for the other thread to finish, use the join() method. But I'm unsure if this is the right way to mix threads and curses. This is what the python documentation says: join([timeout]) Wait until the thread terminates. This blocks the calling thread until the thread whose join() method is called terminates. So according to this since I need to block the main thread until the clock thread ends I would need the main thread to call cadtime().join(), correct? I'm not sure how to do this because I don't have a class or anything for the main thread that I know of. I tried putting that after cadtime().start() but that doesn't work. I guess what I'm trying to say is how can I tell the main thread what to do when it doesn't exist in my code? Thanks for the help -Brett join() is a method on Thread objects. So you'll need a reference to the Thread you create, then call join() on that. thread = cadtime() thread.start() thread.join() Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: error/warning color customization in interactive console?
On 2008-01-16, yhvh [EMAIL PROTECTED] wrote: Is it possible to output error messages in a different color? I'm using Terminal on Gnome. print \033[1;31mHello\033[0m There! Some reading: http://en.wikipedia.org/wiki/ANSI_escape_code http://www.ioncannon.net/ruby/101/fun-with-ansi-escape-codes/ Also, you might look at sys.excepthook to colorize an uncaught exception, and PYTHONSTARTUP to load code automagically before an interactive session. Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: mysqldb SELECT COUNT reurns 1
On 2007-12-27, SMALLp [EMAIL PROTECTED] wrote:
connectionString = {host:localhost, user:root,
passwd:pofuck, db:fileshare}
dataTable = files
conn = mysql.connect(host=connectionString[host],
user=connectionString[user], passwd=connectionString[passwd],
db=connectionString[db])
Just to let you know, that last line can be rewritten as:
conn = mysql.connect(**connectionString)
Ian
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Re: Debugging pipe IPC
Jim B. Wilson wrote: Ian Clark wrote: Jim B. Wilson wrote: ... The child/client sends requests on its stdout and receives responses on stdin. So, why can't you just run this client on the command line and let the shell handle stdin/stdout for you? I'm not sure I understand the topology of your proposal? And, it's certainly possible the shell has mystical powers of which I am unaware. Are you suggesting a run client that spews the mother's messages to the terminal, and I somehow cut/paste them into the client, running with stdin/stdout unconnected to anything but me? Or is there some combination of tee, etal., I can lash together so that my commands (to the client) don't get mixed up with mother's messages? Some such arrangement would surely help. I often forget the stderr, on my scratch-head debugging prints, and mother gets quite upset when the incoming message doesn't fit the mold :) Jim What I'm suggesting is to run the following from the shell: python internal_python_program.py. Then you type into the terminal whatever 'mother' was sending it (Clean your room! most like) and see what it spits back. If the script is simply reading from stdin and writing to stdout there shouldn't be much of a problem. The hardest part might be figuring out what 'mother' actually sends it. If it's very verbose you can type it out once to a file and redirect that file to the python process: python internal_python_program.py file_with_mother_commands.txt. Another idea is to open a file somewhere and write your debug output to that. I would also suggest the logging[1] module as well. It's very handy for his sort of thing. Ian [1] http://docs.python.org/lib/module-logging.html -- http://mail.python.org/mailman/listinfo/python-list
Re: Debugging pipe IPC
Jim B. Wilson wrote: ... My fondest wish is to play the role of the child at the good old prompt. ... Jim Okay, I misunderstood the direction you wanted to go. I thought that you wanted to play the part of the mother, giving commands to the child and not the other way around. Assuming you're on a *nix make child.py as: import os os.system(netcat -l -p 1234 localhost) Run it though mother and on another terminal type: netcat localhost 1234 HTH, Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Debugging pipe IPC
Jim B. Wilson wrote: I have the mother (of all) application(s, written in C++) that occasionally outsources certain tasks to a child Python script. The mother fork/execs (or equivalent) the child and then begins serving the child's requests. The child/client sends requests on its stdout and receives responses on stdin. The interaction is facilitated by a Pyrex extension which handles the lower-level aspects of the conversation and exposes a few functions and classes to the script. This part works peachy keen, but debugging has so far been via printstderr-and-scratch-head. On a contemplative bike ride one day, I imagined how neat it would be to run interactively. On returning, I began to experiment with rebinding sys.stdin and sys.stdout to /dev/tty, using the -i command-line switch, etc. to see if I could devise a child that prompted me with and allowed me to compose/test small snippets on the terminal. So far, no joy. Is this possible? If so, can someone nudge me toward a solution or better yet a recipe? Jim Wilson Gainesville, FL You're looking for the cmd module. http://docs.python.org/lib/module-cmd.html Ian Clark -- http://mail.python.org/mailman/listinfo/python-list
Re: Debugging pipe IPC
Jim B. Wilson wrote: ... The child/client sends requests on its stdout and receives responses on stdin. So, why can't you just run this client on the command line and let the shell handle stdin/stdout for you? Ian Clark -- http://mail.python.org/mailman/listinfo/python-list
Re: cx_Oracle + array parameter
[EMAIL PROTECTED] wrote:
Hello,
I'm trying to pass array as an argument into PL/SQL procedure.
According to cursor manual (http://cx-oracle.sourceforge.net/html/
cursorobj.html) arrayvar() should be use to do it. I've created my
array type in PL/SQL:
CREATE OR REPLACE TYPE cx_array_string is table of varchar2(200);
and simple procedure:
CREATE OR REPLACE PROCEDURE text(ret IN cx_array_string) IS
BEGIN
null;
END text;
My python code:
p_array = curs.arrayvar(cx_Oracle.STRING, ['1','3'])
curs.execute('BEGIN text( :1 ); end;', [p_array] )
And it gives me back an error:
cx_Oracle.DatabaseError: ORA-06550: line 1, column 7:
PLS-00306: wrong number or types of arguments in call to 'TEXT'
ORA-06550: line 1, column 7:
PL/SQL: Statement ignored
It's the same when i try to use callproc() instead of execute(). I've
searched whole internet with no luck. Could anyone please give me a
working example python + pl/sql how to pass string array form py to
oracle procedure, please.
Thank you!
First off I've never used cxOracle or done any PL/SQL from python, but
it looks like you're passing a list of a list to text().
p_array = curs.arrayvar(cx_Oracle.STRING, ['1','3'])
curs.execute('BEGIN text( :1 ); end;', [p_array] )
p_array appears to be some sort of cxOracle array, but when you pass it
to curs.execute you wrap it in a new list: [p_array]. Try removing the
parens and see what happens.
Ian
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Re: Iterable Flattener with Depth.
thebjorn wrote: On Nov 2, 6:32 am, praddy [EMAIL PROTECTED] wrote: On Nov 1, 5:03 pm, [EMAIL PROTECTED] wrote: Pradeep Jindal: Any comments? Something with similar functionality (plus another 20 utility functions/classes or so) has probably to go into the std lib... :-) Bye, bearophile Same Here! - Pradeep Yeah, everyone has to write a flatten sooner or later :-) My version is at: http://blog.tkbe.org/archive/python-flatten/ -- bjorn And here is mine. Note that it is very similar to Michael Spencer's implementation[1]. The only difference is that this adds a depth counter. def iflat(itr, depth=0): itr = iter(itr) stack = [] cur_depth = 0 while True: try: elem = itr.next() if hasattr(elem, __iter__) and cur_depth depth: stack.append(itr) itr = iter(elem) cur_depth += 1 else: yield elem except StopIteration: if not stack: raise StopIteration cur_depth -= 1 itr = stack.pop() if __name__ == __main__: test1 = ((0, 1, 2), ((3, 4), 5), (((6, 7), 8), 9)) test2 = [1,[2,[3,4,5],'bash'],6,[7,[8,[9,10,['hi', 'hello', 11, 12] for x in (test1, test2): print print list(iflat(x)) print print list(iflat(x, 1)) print list(iflat(x, 2)) print list(iflat(x, 3)) print list(iflat(x, 4)) print iflat(x, 10) Ian [1] http://mail.python.org/pipermail/python-list/2005-March/312022.html -- http://mail.python.org/mailman/listinfo/python-list
Re: Combine two dictionary...
Abandoned wrote:
On 1 Ekim, 20:41, Carsten Haese [EMAIL PROTECTED] wrote:
On Mon, 2007-10-01 at 10:24 -0700, Abandoned wrote:
Hi..
dict1={1: 4, 3: 5}... and 2 millions element
dict2={3: 3, 8: 6}... and 3 millions element
I want to combine dict1 and dict2 and i don't want to use FOR because
i need to performance.
You'll have to be a bit more precise here about how and where you want
to combine. Should the result be a new dictionary or should it replace
one of dict1 or dict2? You're also not saying how you want conflicts
between dict1 and dict2 should be resolved. For example, both dict1 and
dict2 say something about the key 3. One says 5, the other says 3.
Should the combined dict say 3 or 5 or (3,5) or maybe even 4?
Also, based on your earlier posts from today, I'm wondering if those
dicts come from executing SQL queries. If so, you might want to consider
combining the results in SQL (using a UNION query) instead of combining
them in Python.
--
Carsten Haesehttp://informixdb.sourceforge.net
I want to total score..
For example
dict1={1: 4, 3: 5}... and 2 millions element
dict2={3: 3, 8: 6}... and 3 millions element
result should be dict3={1:4, 3:8, 8:6}
Well not sure how this will work with 5+ million elements, but here's
one stab at it:
dict1={1: 4, 3: 5}
dict2={3: 3, 8: 6}
for key in set(dict1.keys() + dict2.keys()):
... x = dict1.get(key, 0)
... y = dict2.get(key, 0)
... dict3[key] = x + y
...
dict3
{8: 6, 1: 4, 3: 8}
As Carsten Haese pointed out this should really be done in SQL. You
might try something along these lines:
SELECT
t1.id AS id,
NVL(t1.count, 0) + NVL(t2.count, 0) AS count
FROM DUAL
LEFT JOIN (
SELECT
id,
count
FROM table1
) AS t1 ON 1=1
LEFT JOIN (
SELECT
id,
count
FROM table2
) AS t2 ON t1.id = t2.id
NOTE: I've never actually used a UNION, but you might want to look into it.
Ian
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Re: acronym program
Shawn Minisall wrote: I'm trying to write a program that gets the first letter of every word of a phrase and prints it on screen. I'm having problems with it. I'm thinking a for loop would be good since I don't know the exact number of words the user is going to enter, but after that I get confused. How do I tell python to just goto the beg of each word in the phrase and include it in the acronym? Am I on the right track? for a in string.split(phrase) acronym = phrase [0] acronym = acronym + 1 thx List comprehensions[1] to the rescue! phrase = 'hello there i am well how are you?' acronym = [word[0] for word in phrase.split()] acronym ['h', 't', 'i', 'a', 'w', 'h', 'a', 'y'] Ian [1] http://docs.python.org/tut/node7.html#SECTION00714 -- http://mail.python.org/mailman/listinfo/python-list
Re: newb: Simple regex problem headache
crybaby wrote:
import re
s1 ='nbsp;25000nbsp;'
s2 = 'nbsp;5.5910nbsp;'
mypat = re.compile('[0-9]*(\.[0-9]*|$)')
rate= mypat.search(s1)
print rate.group()
rate=mypat.search(s2)
print rate.group()
rate = mypat.search(s1)
price = float(rate.group())
print price
I get an error when it hits the whole number, that is in this format:
s1 ='nbsp;25000nbsp;'
For whole number s2, mypat catching empty string. I want it to give
me 25000.
I am getting this error:
price = float(rate.group())
ValueError: empty string for float()
Anyone knows, how I can get 25000 out of s2 = 'nbsp;5.5910nbsp;'
using regex pattern, mypat = re.compile('[0-9]*(\.[0-9]*|$)'). mypat
works fine for real numbers, but doesn't work for whole numbers.
thanks
Try this:
import re
s1 ='nbsp;25000nbsp;'
s2 = 'nbsp;5.5910nbsp;'
num_pat = re.compile(r'([0-9]+(\.[0-9]+)?)')
num_pat.search(s1).group(1)
'25000'
num_pat.search(s2).group(1)
'5.5910'
Ian
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Re: I could use some help making this Python code run faster using only Python code.
[EMAIL PROTECTED] wrote:
On Sep 20, 5:46 pm, Paul Hankin [EMAIL PROTECTED] wrote:
On Sep 20, 10:59 pm, Python Maniac [EMAIL PROTECTED] wrote:
I am new to Python however I would like some feedback from those who
know more about Python than I do at this time.
def scrambleLine(line):
s = ''
for c in line:
s += chr(ord(c) | 0x80)
return s
def descrambleLine(line):
s = ''
for c in line:
s += chr(ord(c) 0x7f)
return s
...
Well, scrambleLine will remove line-endings, so when you're
descrambling
you'll be processing the entire file at once. This is particularly bad
because of the way your functions work, adding a character at a time
to
s.
Probably your easiest bet is to iterate over the file using read(N)
for some small N rather than doing a line at a time. Something like:
process_bytes = (descrambleLine, scrambleLine)[action]
while 1:
r = f.read(16)
if not r: break
ff.write(process_bytes(r))
In general, rather than building strings by starting with an empty
string and repeatedly adding to it, you should use ''.join(...)
For instance...
def descrambleLine(line):
return ''.join(chr(ord(c) 0x7f) for c in line)
def scrambleLine(line):
return ''.join(chr(ord(c) | 0x80) for c in line)
It's less code, more readable and faster!
I would have thought that also from what I've heard here.
def scrambleLine(line):
s = ''
for c in line:
s += chr(ord(c) | 0x80)
return s
def scrambleLine1(line):
return ''.join([chr(ord(c) | 0x80) for c in line])
if __name__=='__main__':
from timeit import Timer
t = Timer(scrambleLine('abcdefghijklmnopqrstuvwxyz'), from
__main__ import scrambleLine)
print t.timeit()
## scrambleLine
## 13.0013366039
## 12.9461998318
##
## scrambleLine1
## 14.4514098748
## 14.3594400695
How come it's not? Then I noticed you don't have brackets in
the join statement. So I tried without them and got
## 17.6010847978
## 17.6111472418
Am I doing something wrong?
--
Paul Hankin
I got similar results as well. I believe the reason for join actually
performing slower is because join iterates twice over the sequence. [1]
The first time is to determine the size of the buffer to allocate and
the second is to populate the buffer.
Ian
[1] http://mail.python.org/pipermail/python-list/2007-September/458119.html
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Re: HTTP Protocol Client
[EMAIL PROTECTED] wrote:
h = httplib.HTTP('http://Google.com',80)
This should be:
h = httplib.HTTP('Google.com',80)
And I certainly agree with the others, check out urllib*.
Ian
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Re: curses: x, y positioning
7stud wrote:
However, now I am having a problem trying to set the color of the text
that is output:
import curses
def example(screen):
if curses.has_colors():
curses.init_pair(1, curses.COLOR_GREEN, curses.COLOR_BLACK)
curses.init_pair(2, curses.COLOR_YELLOW, curses.COLOR_BLACK)
curses.init_pair(3, curses.COLOR_RED, curses.COLOR_BLACK)
screen.addstr(1, 1, 'Hello', curses.color_pair(1))
screen.addstr(1, 7, 'World', curses.color_pair(2))
screen.addstr(1, 12, '!!!', curses.color_pair(3) + curses.A_BOLD)
else:
screen.addstr(1, 1, 'You don\'t have colors enabled. :(')
screen.addstr(3, 0, 'Press any key to continue')
screen.refresh()
screen.getch()
if __name__ == '__main__':
curses.wrapper(example)
Ian
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Re: subclass of integers
Mark Morss wrote: I would like to construct a class that includes both the integers and None. I desire that if x and y are elements of this class, and both are integers, then arithmetic operations between them, such as x+y, return the same result as integer addition. However if either x or y is None, these operations return None. It's simple enough to construct a subclass of integers that behave in this way: class Nint(int): def __add__(self,other): if (other != None): return self+other else: return None def __radd__(self,other): if (other != None): return other+self else: return None #...and so forth However I have not been able to figure out how to make it so that None, as well as an integer, could be an element of my class. My preliminary impression is that I have to override int.__new__; but I am uncertain how to do that and have been unable to find anything on the web explaining that. Indeed I haven't been able to find much about __new__ at all. Overriding this method of built-in classes seems to be quite unusual. I would very much appreciate anyone's help. My thought would be rather than trying to cram None into a subclass of int, to use delegation instead... -8-- class NoneInt(object): def __init__(self, value): self.value = value def __add__(self, other): if isinstance(other, NoneInt): if None in (self.value, other.value): return NoneInt(None) return NoneInt(self.value + other.value) elif isinstance(other, int): if self.value is None: return NoneInt(None) return NoneInt(self.value + other) else: raise TypeError( unsupported operand type(s) for +: 'NoneInt' and '%s' % str(other.__class__.__name__) ) __radd__ = __add__ def __str__(self): return 'NoneInt(%s)' % str(self.value) def main(): print '42? ', NoneInt(40) + NoneInt(2) print '41? ', NoneInt(40) + 1 print '40? ', 25 + NoneInt(15) print 'None? ', NoneInt(None) print 'None? ', NoneInt(None) + 1 print 'None? ', 1 + NoneInt(None) print 'Error? ', NoneInt(0) + 'spam' if __name__ == '__main__': main() -8-- Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: subclass of integers
Ian Clark wrote:
Mark Morss wrote:
I would like to construct a class that includes both the integers and
None. I desire that if x and y are elements of this class, and both
are integers, then arithmetic operations between them, such as x+y,
return the same result as integer addition. However if either x or y
is None, these operations return None.
(snip)
I would very much appreciate anyone's help.
My thought would be rather than trying to cram None into a subclass of
int, to use delegation instead...
(snip)
Ian
A more robust implementation that accounts for ints/longs as well as
implementing more operations...
-8--
import operator
class NoneInt(object):
_LEFT = 1
_RIGHT = 2
def __init__(self, value):
self.value = value
def _get_arguments(self, other, direction=_LEFT):
Given a direction (left or right), returns the left hand
side and right hand side values.
if direction == self._LEFT:
lhs = self.value
if isinstance(other, (int, long, type(None))):
rhs = other
else:
rhs = other.value
elif direction == self._RIGHT:
rhs = self.value
if isinstance(other, (int, long, type(None))):
lhs = other
else:
lhs = other.value
else:
raise ValueError('direction must be either _LEFT or _RIGHT')
return (lhs, rhs)
def _operation(op, direction):
Given a direction and an operation will return a function
that calls the operation with the arguments in the correct
order.
def func(self, other):
if not isinstance(other, (int, long, NoneInt, type(None))):
fmt = unsupported operand type(s) for %s: 'NoneInt'
and '%s'
args = (op.__name__, other.__class__.__name__)
raise TypeError(fmt % args)
lhs, rhs = self._get_arguments(other, direction)
if None in (lhs, rhs):
return NoneInt(None)
return NoneInt(op(lhs, rhs))
return func
__add__ = _operation(operator.add, _LEFT)
__radd__ = _operation(operator.add, _RIGHT)
__sub__ = _operation(operator.sub, _LEFT)
__rsub__ = _operation(operator.sub, _RIGHT)
__div__ = _operation(operator.div, _LEFT)
__rdiv__ = _operation(operator.div, _RIGHT)
__mul__ = _operation(operator.mul, _LEFT)
__rmul__ = _operation(operator.mul, _RIGHT)
# ... etc
def __eq__(self, other):
lhs, rhs = self._get_arguments(other)
return lhs == rhs
def __nonzero__(self):
return bool(self.value)
def __str__(self):
return 'NoneInt(%s)' % str(self.value)
__repr__ = __str__
-8--
Ian
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Re: Spaces from string specifier
Gabriel Genellina wrote:
En Fri, 14 Sep 2007 01:57:43 -0300, Gavin Tomlins [EMAIL PROTECTED]
escribi�:
I'm trying to work out when using a format specifier I get spaces in the
resulting string. Eg. Looking at the outputted string you can see that
there are spaces after T5LAT, F4LAT etc. as I result from trying to keep
the
code aligned
- You should *not* build the SQL text yourself; use a parametrised query
instead. It's not only easier to write; it's safer, less error prone, and
maybe faster. See this previous post
http://groups.google.com/group/comp.lang.python/browse_thread/thread/b8c1ef8471f55995/
- Spaces are not significant in SQL, but you may have your own reasons to
format the SQL text in a certain way. In addition to the ideas already
menctioned on that thread (avoid \, use parenthesis, and auto-concatenate
adjacent strings), you may use a triple-quoted string + function dedent
from textwrap module:
py fmtSqlP300Amp = textwrap.dedent('''\
... UPDATE Patient SET
... O2AMP = %s, O1AMP = %s, OzAMP = %s, PzAMP = %s,
... P4AMP = %s, CP4AMP = %s, T6AMP = %s, C4AMP = %s,
... TP8AMP = %s, T4AMP = %s, T5AMP = %s, P3AMP = %s
... WHERE Pat_Id = %s''')
py print fmtSqlP300Amp
UPDATE Patient SET
O2AMP = %s, O1AMP = %s, OzAMP = %s, PzAMP = %s,
P4AMP = %s, CP4AMP = %s, T6AMP = %s, C4AMP = %s,
TP8AMP = %s, T4AMP = %s, T5AMP = %s, P3AMP = %s
WHERE Pat_Id = %s
I hope any of these ideas will fit your own needs.
Completely agree that this should not be written by hand. But if you
absolutely *must* you might try something like this:
fmt =
... UPDATE Patient SET
... 02AMP = %(o2amp)s
... O1AMP = %(o1amp)s
... ...
...
args = {
... 'o1amp': 2.77413,
... 'o2amp': 2.43119
... }
print fmt % args
UPDATE Patient SET
02AMP = 2.43119
O1AMP = 2.77413
...
Ian
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Re: recursion
Neil Cerutti wrote: On 2007-09-13, Gigs_ [EMAIL PROTECTED] wrote: Can someone explain me this def f(l): if l == []: return [] else: return f(l[1:]) + l[:1] # = cant figure this, how is all sum at the end? In plain English, the above program says: The sum of the items in list l is zero if the list is empty. Otherwise, the sum is the value of the first item plus the sum of the rest of the items in the list. Am I missing something? What does this have to do with summing? def f(l): ... if l == []: ... return [] ... else: ... return f(l[1:]) + l[:1] ... f([1, 2, 3, 4]) [4, 3, 2, 1] Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: sys.argv index out of range error
Brian McCann wrote: init.sh #!/bin/sh WORKSPACE_ROOT=$1; export JAVA_OPTIONS=-Djava.library.path=$WORKSPACE_ROOT/:$WORKSPACE_ROOT/:$WORKSPACE_ROOT/ echo JAVA_OPTIONS=$JAVA_OPTIONS; set PATH=$WORKSPACE_ROOT/vendor/basistech/rlp5.4/rlp/bin/ia32-glibc23-gcc32:$WORKSPACE_ROOT/vendor/basistech/rlp5.4/rlp/bin/ia32-w32-msvc71:$WORKSPACE_ROOT/lib/core:$PATH Taken from `help set` (at the bottom of the page; emphasis mine): Using + rather than - causes these flags to be turned off. The flags can also be used upon invocation of the shell. The current set of flags may be found in $-. *The remaining n ARGs are positional parameters and are assigned, in order, to $1, $2, .. $n. If no ARGs are given, all shell variables are printed.* Short answer: change set to export. Slightly longer answer: What this invocation of set is doing is setting the shell variable PATH to the value you give *and* setting the $1 variable to the same value and removing all other numbered variables. So if you put a print $2 after `source init.sh $1` in bootstrap.sh you'll notice it's blank, as set is removing it. The reason this happens when you source the file rather than just calling it is that when you source a file it runs in the current shell. So calling set then wipes out all the other numbered variables. When simply calling the script it creates a subshell where those things still happen, just not in the parent shell. Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Beginners Query - Simple counter problem
Carsten Haese wrote: On Thu, 2007-09-06 at 11:00 -0700, Scott David Daniels wrote: def d6(count): result = 0 for die in range(count): result += random.randint(1, 6) return result This, of course, can be further improved into: def d6(count): return sum(random.randint(1, 6) for die in range(count)) My stab at it: def roll(times=1, sides=6): ... return random.randint(times, times*sides) Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Getting original working directory
rave247 rave247 wrote: ..the *original* directory location *after* os.chdir() is performed.. os.getcwd() is not helping much as it returns the location that was set up in os.chdir() call Thanks Your question is akin to having a name X that is bound to some value, setting it to 2 and then wanting to know what the original value is. It just ain't gonna happen. Simply follow the advice given by Gary and use os.getcwd() *before* the call to os.chdir(). Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Beginners Query - Simple counter problem
Carsten Haese wrote: On Thu, 2007-09-06 at 11:24 -0700, Ian Clark wrote: Carsten Haese wrote: def d6(count): return sum(random.randint(1, 6) for die in range(count)) My stab at it: def roll(times=1, sides=6): ... return random.randint(times, times*sides) That produces an entirely different probability distribution if times1. Consider times=2, sides=6. Your example will produce every number between 2 and 12 uniformly with the same probability, 1 in 11. When rolling two six-sided dice, the results are not evenly distributed. E.g. the probability of getting a 2 is only 1 in 36, but the probability of getting a 7 is 1 in 6. Doh. I stand corrected. Probability was never a fun subject for me. :) Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Symbolic Link
Hyuga wrote: On Aug 19, 4:29 pm, mosscliffe [EMAIL PROTECTED] wrote: The source file is in an area which python can see, but not the browser. I am trying to make a link in a browser friendly area so I can use it to display an image file. You might want to try using an .htaccess file. Place a file called .htaccess in the browser friendly area and place in it the line: Options +FollowSymLinks Assuming your hosting service will allow that, then it should work. If not, then why not just copy the image files? Storage is cheap these days. Hyuga My question would be why a symbolic link? Why not a hard link? Are the two directories on different mount points? After the script finishes does python need to see that image file again? Why not just move it? Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Question on SPE and pwintypes.dll
Gerry wrote: ... but the OS wasn't migrated ... There's your problem right there. It's hard to run most software these days without an OS. Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: All names in the current module
Torsten Bronger wrote: Hallöchen! How can I get a list with all classes defined in the current module? Thank you! Tschö, Torsten. Assuming you want to see all classes in the re module: import re help(re) #best way def isclass(cls): ... try: ... return issubclass(cls, cls) ... except TypeError: ... pass ... return False ... [cls for cls in dir(re) if isclass(getattr(re, cls))] ['Scanner', '_pattern_type', 'error'] Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: All names in the current module
Ian Clark wrote: Torsten Bronger wrote: Hallöchen! How can I get a list with all classes defined in the current module? Thank you! Tschö, Torsten. Assuming you want to see all classes in the re module: import re help(re) #best way def isclass(cls): ... try: ... return issubclass(cls, cls) ... except TypeError: ... pass ... return False ... [cls for cls in dir(re) if isclass(getattr(re, cls))] ['Scanner', '_pattern_type', 'error'] Ian I love this list, I learn something new everyday. Didn't know about inspect.isclass(). Ignore this post and look at Lawrence's. Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Getting started with JPype
Disclaimer: I have never used (or even heard of) JPype before... porter wrote: (snip) Package myclass.HelloWorld is not Callable (snip) from jpype import * startJVM(getDefaultJVMPath(), -ea, -Djava.class.path=D:/tmp/jpype- reli/test/dist/test.jar'' ) package = JPackage(myclass) Shouldn't this be `package = JPackage(myclasses)` as your Java code is contained in the package 'myclasses' not 'myclass'? x = package.HelloWorld() Change this last line to: `x = package.HelloWorld` (class would be a better name than x IMO) x.do_a_message() shutdownJVM() It looks like JPype exports Java classes as members of the object referred to by `package`. You then try and call it with () and python throws it's hands in the air as it must not be a callable. Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: JPype - passing to Java main
[EMAIL PROTECTED] wrote:
I am trying to get JPype to pass a String into a Java class main
function. Demonstration code below:
=JAVA
package com;
public class JPypeTest {
public static void main(String args[]) {
System.out.println(args[0]);
}
public void printArgument(String arg) {
System.out.println(arg);
}
}
===PYTHON===
from jpype import *
startJVM(C:/Program Files/Java/jdk1.5.0_12/jre/bin/server/jvm.dll,-
Djava.class.path=C:/jpypetest/test/)
com = JPackage(com);
jp = com.JPypeTest();
jp.printArgument('');
#WANT TO CALL main(arg) HERE
shutdownJVM()
===
What I want is to be able to call main() with an argument from the
python file (using JPype) and have it echo
args[0]. I can get this to work for printArgument(), but not for
main().
Thanks,
Sarah
Try this:
com.JPypeTest.main(arg)
Ian
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Re: programmatically define a new variable on the fly
Lee Sander wrote: Hi, I would like to define a new variable which is not predefined by me. For example, I want to create an array called X%s where %s is to be determined based on the data I am processing. So, for example, if I the file I'm reading has g 99 on the first line, I want to create a new variable called Xg whose length is 99. I tried eval(Xg=[0]*99) but that did not work. any help would be greatly appreciated Lee Xg Traceback (most recent call last): File stdin, line 1, in module NameError: name 'Xg' is not defined namespace = globals() var_name = 'Xg' var_value = [0] * 9 namespace[var_name] = var_value Xg [0, 0, 0, 0, 0, 0, 0, 0, 0] Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: problems playing with dates from any month.
krishnakant Mane wrote: hello, I have a very strange problem and I can't find any solution for that. I am working on an accounting package which I wish to develop in python. the simple problem is that I want to knoe how I can know if the given date is the nth day of a month. for example if a customer is supposed to pay his installment on every 5th of all months, I want to know if today is the fifth day (jan the fifth, feb the fifth etc) for any given month. I have not found any such function. if I have looked (or over looked ) in the wrong places I am really sorry. secondly I also want to know the way in which I can convert a given string to a date object. for example if I have a string 29/09/2005, I know it is a valid date although it is in a string form. now I want to convert the above string into a real date object. how can I cast it this way? regards, Krishnakant. http://docs.python.org/lib/node85.html Then it's just: if date_obj.day == 5: print 'It's the fifth day of the month' Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: problems playing with dates from any month.
krishnakant Mane wrote: On 02/08/07, Ian Clark [EMAIL PROTECTED] wrote: http://docs.python.org/lib/node85.html I looked there even before. but could not figure out what the code did. I know in that variable called s there was a string in a valid date format. but when datetime.strptime was used, I did not understand the place where a date object say d was created. I would expect some thing like d = and the function. but I did not fine that. only reference was the datetime module and the documentation is not as good. import datetime import time fmt_string = '29/05/2005' date_tuple = time.strptime(fmt_string, '%d/%m/%Y') print date_tuple (2005, 5, 29, 0, 0, 0, 6, 149, -1) date_tuple_minus_tz = date_tuple[0:6] print date_tuple_minus_tz (2005, 5, 29, 0, 0, 0) date_obj = datetime.datetime(*date_tuple_minus_tz) This last line is equivalent to the following: date_obj = datetime.datetime(2005, 5, 29, 0, 0, 0) The * in front of a tuple expands it's arguments when making a function call print date_obj 2005-05-29 00:00:0 print date_obj.day == 5 False another question I am getting is that where is the list of all formatting characters. like for example Y is 4 digit year M is month MM is month in 2 digits etc. I am trying to locate a list of all these denoters. can you provide me the place? http://docs.python.org/lib/module-time.html Look for the strptime() function. Then it's just: if date_obj.day == 5: print 'It's the fifth day of the month' this was much better than the documentation, thanks, regards, Krishnakant. Hope that helps. Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Berkely Db. How to iterate over large number of keys quickly
lazy wrote: I have a berkely db and Im using the bsddb module to access it. The Db is quite huge (anywhere from 2-30GB). I want to iterate over the keys serially. I tried using something basic like for key in db.keys() but this takes lot of time. I guess Python is trying to get the list of all keys first and probbaly keep it in memory. Is there a way to avoid this, since I just want to access keys serially. I mean is there a way I can tell Python to not load all keys, but try to access it as the loop progresses(like in a linked list). I could find any accessor methonds on bsddb to this with my initial search. I am guessing BTree might be a good choice here, but since while the Dbs were written it was opened using hashopen, Im not able to use btopen when I want to iterate over the db. db.iterkeys() Looking at the doc for bsddb objects[1] it mentions that Once instantiated, hash, btree and record objects support the same methods as dictionaries. Then looking at the dict documentation[2] you'll find the dict.iterkeys() method that should do what you're asking. Ian [1] http://docs.python.org/lib/bsddb-objects.html [2] http://docs.python.org/lib/typesmapping.html -- http://mail.python.org/mailman/listinfo/python-list
Re: Bug in execfile?
Fernando Perez wrote:
Hi all,
(snip)
I'm really, really puzzled by this. From reading the execfile() docs, I had
the hunch to change the call to:
execfile(fname,{})
and now the problem disappears, so I can keep on working.
But I'm still very bothered by the fact that changing that first call 'if 0'
to 'if 1' has any effect on the later call to runscript(). That really
doesn't feel right to me...
First an example:
#foo.py
from math import sin
#EOF
dir()
['__builtins__', '__doc__', '__name__']
execfile('foo.py')
dir()
['__builtins__', '__doc__', '__name__', 'sin']
New session:
dir()
['__builtins__', '__doc__', '__name__']
execfile('foo.py', {})
dir()
['__builtins__', '__doc__', '__name__']
help(execfile)
Help on built-in function execfile in module __builtin__:
execfile(...)
execfile(filename[, globals[, locals]])
Read and execute a Python script from a file.
The globals and locals are dictionaries, defaulting to the current
globals and locals. If only globals is given, locals defaults to
it.
By default execfile works on the *current* namespace. So exec'ing a
script that modified it's global namespace will also modify the global
namespace of the calling module (see my first example). If you specify a
dictionary then execfile will use that as the global and local (maybe)
namespace of the file that it is running (hence the global namespace of
the calling module stays in tact per the second example). That is why
execfile(fname, {}) works for you, it doesn't pollute your current
namespace. It uses a different namespace when calling the file then is
being used by the calling module.
No idea why your function failed though. *shrug*
Ian
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Re: (no) fast boolean evaluation ?
Stef Mientki wrote: hello, I discovered that boolean evaluation in Python is done fast (as soon as the condition is ok, the rest of the expression is ignored). Is this standard behavior or is there a compiler switch to turn it on/off ? thanks, Stef Mientki It's called short circuit evaluation and as far as I know it's standard in most all languages. This only occurs if a conditional evaluates to True and the only other operators that still need to be evaluated are 'or's or the condition evaluates to False and all the other operators are 'and's. The reason is those other operators will never change the outcome: True or'd with any number of False's will still be True and False and'ed to any number of Trues will still be False. My question would be why would you *not* want this? Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Awkward format string
beginner wrote:
Hi,
In order to print out the contents of a list, sometimes I have to use
very awkward constructions. For example, I have to convert the
datetime.datetime type to string first, construct a new list, and then
send it to print. The following is an example.
x=(e[0].strftime(%Y-%m-%d), e[1].strftime(%Y-%m-%d))+e[2:]
print f, %s\t%s\t%d\t%f\t%f\t%f\t%d % x
e is a tuple. x is my new tuple.
Does anyone know better ways of handling this?
Thanks,
Geoffrey
import datetime
old_tuple = (
... datetime.datetime(2007, 8, 1),
... datetime.datetime(2007, 8, 2),
... 1,
... 2.0,
... 3.0,
... 4
... )
first_date = old_tuple[0].strftime('%Y-%m-%d')
second_date = old_tuple[1].strftime('%Y-%m-%d')
new_tuple = (first_date, second_date) + old_tuple[2:]
print '\t'.join(str(i) for i in new_tuple)
2007-08-01 2007-08-02 1 2.0 3.0 4
Without more information that's the best I can think of.
Ian
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Re: Awkward format string
Gerard Flanagan wrote: (snip) def tostring(data): return tuple(strftime(x) for x in data[:2]) + data[2:] Hrmm, not sure that having a function named tostring() that returns a tuple is the best idea. ;) Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Inverse of id()?
On 5/20/07, Michael Hoffman [EMAIL PROTECTED] wrote: [snip] That's not what I get: Python 2.5 (r25:51908, Mar 13 2007, 08:13:14) [GCC 3.4.4 (cygming special, gdc 0.12, using dmd 0.125)] on cygwin Type help, copyright, credits or license for more information. class A: pass ... class B: pass ... a = A() id(a) 2146651820 b = B() id(b) 2146651948 -- Michael Hoffman That's because you didn't have 'del a'. Now I tried this in the shell and got different id's for a and b, but when I typed it into a file and ran from there the id's where always the same. Must have something to do with other programs allocating space faster than I can type everything out (I do have a few processes going). Interesting. Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: need help with python
On 11 May 2007 18:47:27 -0700, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
ya so im pretty much a newb to this whole python thing... its pretty
cool but i just started today and im already having trouble. i
started to use a tutorial that i found somewhere and i followed the
instructions and couldnt get the correct results. heres the code
stuff...
temperature=input(what is the temperature of the spam?)
if temperature50:
print the salad is properly cooked.
else:
print cook the salad some more.
ya i was trying to do that but when i told it what the spams
temperature was, it just turned off... well it wasnt working at all at
first until i realized that i hadnt been following the instructions
completely correctly and that i was supposed to type that code up in a
notepad then save and open with python... so ya thats when it asked me
what temperature the spam was and i typed a number then it just closed
itself... im not really sure what went wrong... itd be real nice if
someone would be like a mentor or something...
I'm making a couple of assumptions here (correct me if I'm wrong):
1. You're using windows
2. You double clicked on the .py file
What this does is open up a new terminal window and start execution of
the program. The program will execute to completion and then the
window will close automatically without waiting for you to tell it to
(lovely isn't it?). To get around this you have a couple options:
1. Run the script from the command line
2. Put this at the end of the .py file: input('Press ENTER to continue')
Ian
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Re: e-mailing multiple values
On 5/8/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote: I have a script which has a method which returns multiple strings at once using the yield. I would like to send an e-mail of these values in a single e-mail instead of a mail for each string. How would I be able to do that? Thanks AJ Are you looking for something like the following? If not, try posting a small sampling of your code. def get_data(): ... data = ['ham', 'eggs', 'spam'] ... for item in data: ... yield item ... all_data = [item for item in get_data()] all_data ['ham', 'eggs', 'spam'] Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: FW: Re: e-mailing multiple values
On 5/8/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
Thanks.
That does help. When teh script sends a mail of the list item(all_data), the
data shows up like this:
[(' Ham\n', ' eggs \n'),
(' chicken \n', ' thighs \n')]
So I have to figure out a way to cleanup the content
Thanks
Anil
Have to run, but look at strip() on string objects.
Ian
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Re: curses mystical error output
On 5/2/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote: I have a fairly simple curses app which is giving me this error: addstr() returned ERR I'm trapping it and continuing. I can see that *some* of my addstring calls succeed. This one happens to be screen.addstr(row, 39, |) where row is 3. You might be trying to write to a section that is currently off screen. Seems to me when I was doing some curses stuff that when I tried to write to one more row than could be fit onto my terminal that error would come up. Try doing the following code and make sure that you can enough space to draw it. (height, width) = screen.getmaxyx() Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Slicing Arrays in this way
Yeah, having an elegant_solution() function would solve soo many of my problems. ;) Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: Removing the continous newline characters from the pythong string
On 1 May 2007 14:30:12 -0700, mobil [EMAIL PROTECTED] wrote:
Hi guys i m trying out newline characters and to clean them up
a\n\n\n\n\n\n\n\n\nsss\n\n\n\n\n\n\n\n\n\n\n\n\n\n\nvsa\n\n\n\nasf
\n\nafs
hello guys
im trying to replace
\n\n\n\n\n\n\n\n\n with \n
thanks for help
\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n\r\n also with \n as the browser gives
\r carrriage returns
thanks for any help or pointers
Is this what you were looking for?
import re
message = '\n\r\n\r\n\n\nhello there\n\r\n!\n'
regex = re.compile('[\n\r]+')
regex.sub('\n', s)
'\nhello there\n!\n'
Ian
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Re: Read and Write the same file
On 1 May 2007 16:03:28 -0700, JonathanB [EMAIL PROTECTED] wrote: Ok, so this is the scenario. I need to create a simple, no-frills XML editor for non-technical users. It doesn't have to do anything fancy, what I want is a series of text boxes with the text contents of the elements pre-printed. Then the users can type their changes into the text boxes and click submit and it will load the changes in. So here is the problem, this means I need to open the same file as both read and write. How do I do this? I'm slowly learning the DOM stuff that I need to know to do this, but this file thing I haven't been able to find anywhere. JonathanB Well the most straight forward approach is to read data from the file into memory. Let the user make any changes. Then save the data back to the file, overwriting the oringinal copy. Now, this only really works if you're dealing with small files. Regardless though, you never really need to have a file open for both reading and writing. Since they occur (so it sounds) at distinct times during your program flow, just open it twice: the first to read, the second to write. Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: strip newline from string
On 4/28/07, James [EMAIL PROTECTED] wrote: [snip] username = getuser() string.strip (username) print username is %s % username [snip] The autoconf.txt contains two lines, which first has an ip address and second a username. The problem I'm having is that the string.strip() doesn't appear to be stripping the newline off the username. Any ideas? If you need more information, just ask! James string.strip() returns a copy of the string with whitespace removed, it does not modify it in place. What you really want is: username = getuser().strip() Someone correct me if I'm wrong, but I believe just about all functions from the string module are deprecated. Use the methods from the string class. As I'm assuming getuser() returns a string object, just use the string functions on that directly. Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: creating an object from base class
Quote iogilvy: i wish to have some extended functionality added to sockets i can create my own socket class class mysocket(socket.socket): and all should be fine. Except, the sockets are created for me by the accept method, listening on port. So how can i take the standard socket created for me and create a 'mysocket'. I need a method that will initialise any new properties i have added in my class, but how can i change the class of the socket created? Someone correct me if I'm wrong, but I don't believe it's possible to change the type of objects made from builtin classes. Though if it's a custom class you can, for example: class Foo: pass class Bar: pass obj = Foo() obj.__class__ = Bar One option is to make your custom socket a wrapper around socket.socket and then pass through the calls you don't want to handle to socket.socket. The downside to this is there are quite a lot of methods that need to be accounted for. For example: class CustomSocket: def __init__(self, socket): self.socket = socket def connect(self, address): self.socket.connect( address + '.some.tld' ) [etc] ... s = server_socket.accept() s = CustomSocket(s) Another approach you might want to look at is populating your object at runtime through a function. This won't give it the type you want, but it will give it any methods and attributes it would have gotten from your class with the added benefit of it still being of type socket.socket. Example: def modify_socket( socket ): socket.cabbages = 'Yuk' socket.apples = 'Yum' def info(): print 'Cabbages? %s\nApples? %s' % (socket.cabbages, socket.apples) obj.show_info = info ... s = server_socket.accept() modify_socket( s ) s.show_info() Cabbages? Yuk Apples? Yum s.apples = 'Yummie' s.show_info() Cabbages? Yuk Apples? Yummie type(s) class 'socket._socketobject' Good luck. Ian -- http://mail.python.org/mailman/listinfo/python-list
Re: mysql rows affected
Both cursor.execute() and cursor.executemany() return the number of rows affected. Here is a link to the documentation: http://mysql-python.sourceforge.net/MySQLdb-1.2.2/public/MySQLdb.cursors.BaseCursor-class.html#execute Ian On 4/26/07, Carl K [EMAIL PROTECTED] wrote: using MySQLdb, I do cursor.execute(update...) How can I tell how many rows were affected ? Carl K -- http://mail.python.org/mailman/listinfo/python-list -- http://mail.python.org/mailman/listinfo/python-list
