Re: empty stdout (subprocess.run)

[James Smith]

On Wednesday, January 19, 2022 at 11:14:28 PM UTC-5, cameron...@gmail.com wrote:

> But I recommend you use shell=False and make: 
> 
> cmd = ["/usr/bin/transmission-remote", "--torrent", str(torrentno), "--info"] 

I like that. :-)
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Re: empty stdout (subprocess.run)

[James Smith]

On Wednesday, January 19, 2022 at 11:08:58 PM UTC-5, Dennis Lee Bieber wrote:

> Don't you need to provide for that %s? Perhaps 
> 
> cmd="/usr/bin/transmission-remote --torrent %s --info" % torrentno 

That works, thanks.
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empty stdout (subprocess.run)

[James Smith]

I'm trying to run a shell command but the stdout is empty:

import subprocess

torrentno=8
cmd="/usr/bin/transmission-remote --torrent %s --info", str(torrentno)
res=subprocess.run(cmd, shell=True, check=True, universal_newlines=True, 
capture_output=True)
print(res)

CompletedProcess(args=('/usr/bin/transmission-remote --torrent %s --info', 
'1'), returncode=0, stdout='', stderr='')
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=+ for strings

[James Smith]

I tried:
dt=+"{:02d}".format(day)
but I got:
dt=+"{:02d}".format(day)
TypeError: bad operand type for unary +: 'str'

This works:
dt=dt+"{:02d}".format(day)

Why can't I do the shortcut on strings?
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pickle and then object changes

[James Smith]

Say an object like this exists:
class test:
a = 
b = 

You pickle it.

You change the object definition to have a new field:
class test
a = 
b = 
c = 

You read the pickled object.
Will it load but ignore the new field?
That is what I want.
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help with regex

[James Smith]

I want the last 1
I can't this to work:

 pattern=re.compile( (\d+)$ )
 match=pattern.match( LINE: 235 : Primary Shelf Number (attempt 1): 1)
 print match.group()
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Re: regex line by line over file

[James Smith]

On Thursday, March 27, 2014 1:32:03 AM UTC-4, Steven D'Aprano wrote:

 - are you mistaken about the content of the file?
 
 I can't help you with the first. But the second: try running this:
 
 # line2 and pat as defined above
 filename = sys.argv[1]
 with open(filename) as f:
 for line in f:
 print(len(line), line==line2, repr(line))
 print(repr(pat.match(line)))
 
 which will show you what you have and whether or not it matches 
 what you think it has. I expect that the file contents is not what 
 you think it is, because the regex is matching the sample line.
 
 Good luck!
 
 -- 
 
 Steven

It should match this:
(134, False, '\'   SHELF-17:LOG_COLN_IP,SC,03-25,01-18-58,NEND,NA,,,:Log 
Collection In 
Progress,NONE:170035-6364-1048,:YEAR=2014,MODE=NONE\\r\\n\'')

Is the \r\n on the end of the line screwing it up?
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Re: regex line by line over file

[James Smith]

On Thursday, March 27, 2014 9:41:55 AM UTC-4, James Smith wrote:

 (134, False, '\'   
 SHELF-17:LOG_COLN_IP,SC,03-25,01-18-58,NEND,NA,,,:Log Collection In 
 Progress,NONE:170035-6364-1048,:YEAR=2014,MODE=NONE\\r\\n\'')
 
 
 
 Is the \r\n on the end of the line screwing it up?

Got it.
I needed an extra \ where I had 3 in the compile.
It's kinda weird it didn't need the extra \ when I ran it manually from the 
shell.
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regex line by line over file

[James Smith]

I can't get this to work.
It runs but there is no output when I try it on a file.


#!/usr/bin/python

import os
import sys
import re
from datetime import datetime

#logDir = '/nfs/projects/equinox/platformTools/RTLG/RTLG_logs';
#os.chdir( logDir );

programName = sys.argv[0]
fileName = sys.argv[1]

#pattern = re.compile('\s*\\SHELF-.*,SC,.*,:\\Log Collection In Progress\\')
re.M
p = re.compile('^\s*\SHELF-.*,SC,.*,:\\\Log Collection In Progress\\\')
l = 'SHELF-17:LOG_COLN_IP,SC,03-25,01-18-58,NEND,NA,,,:\Log Collection In 
Progress\,NONE:170035-6364-1048,:YEAR=2014,MODE=NONE'

# this works :-)
m = p.match( l )
if m:
print( l )

# this doesn't match anything (or the if doesn't work) :-(
with open(fileName) as f:
for line in f:
# debug code (print the line without adding a linefeed)
# sys.stdout.write( line )
if p.match(line):
print(line)


The test file just has one line:
SHELF-17:LOG_COLN_IP,SC,03-25,01-18-58,NEND,NA,,,:\Log Collection In 
Progress\,NONE:170035-6364-1048,:YEAR=2014,MODE=NONE
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Re: regex line by line over file

[James Smith]

On Wednesday, March 26, 2014 11:23:29 PM UTC-4, James Smith wrote:
 I can't get this to work.
 
 It runs but there is no output when I try it on a file.
 
 
 
 
 
 #!/usr/bin/python
 
 
 
 import os
 
 import sys
 
 import re
 
 from datetime import datetime
 
 
 
 #logDir = '/nfs/projects/equinox/platformTools/RTLG/RTLG_logs';
 
 #os.chdir( logDir );
 
 
 
 programName = sys.argv[0]
 
 fileName = sys.argv[1]
 
 
 
 #pattern = re.compile('\s*\\SHELF-.*,SC,.*,:\\Log Collection In 
 Progress\\')
 
 re.M
 
 p = re.compile('^\s*\SHELF-.*,SC,.*,:\\\Log Collection In Progress\\\')
 
 l = 'SHELF-17:LOG_COLN_IP,SC,03-25,01-18-58,NEND,NA,,,:\Log Collection 
 In Progress\,NONE:170035-6364-1048,:YEAR=2014,MODE=NONE'
 
 
 
 # this works :-)
 
 m = p.match( l )
 
 if m:
 
 print( l )
 
 
 
 # this doesn't match anything (or the if doesn't work) :-(
 
 with open(fileName) as f:
 
 for line in f:
 
 # debug code (print the line without adding a linefeed)
 
 # sys.stdout.write( line )
 
 if p.match(line):
 
 print(line)
 
 
 
 
 
 The test file just has one line:
 
 SHELF-17:LOG_COLN_IP,SC,03-25,01-18-58,NEND,NA,,,:\Log Collection In 
 Progress\,NONE:170035-6364-1048,:YEAR=2014,MODE=NONE

I tried the re.M in the compile and that didn't help.
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