reloading all modules
Hi, Is there a way to use the reload() func or something else, to refresh all of the modules you have imported? I don't care whether the module that will run this code will be reloaded or not, so whichever is the easiest... Thanks, Noam -- http://mail.python.org/mailman/listinfo/python-list
RE: Kill a function while it's being executed
Hi, Sorry for resurrecting an old thread, but it just bothers me that this is the best way that python has to deal with killing running functions... it's quite an ugly hack, no? Is it a feature that's needed bit missing from python, or is it left out on purpose (same way like java has deprecated thread.stop and thread.suspend because they were not safe)? Thanks, Noam -Original Message- From: python-list-bounces+noama=answers@python.org [mailto:python-list-bounces+noama=answers@python.org] On Behalf Of Albert Hopkins Sent: Wednesday, February 04, 2009 5:26 PM To: python-list@python.org Subject: Re: Kill a function while it's being executed On Wed, 2009-02-04 at 13:40 +0200, Noam Aigerman wrote: Hi All, I have a script in which I receive a list of functions. I iterate over the list and run each function. This functions are created by some other user who is using the lib I wrote. Now, there are some cases in which the function I receive will never finish (stuck in infinite loop). Suppose I use a thread which times the amount of time passed since the function has started, Is there some way I can kill the function after a certain amount of time has passed (without asking the user who's giving me the list of functions to make them all have some way of notifying them to finish)? Thanks, Noam Noam, did you hijack a thread? You could decorate the functions with a timeout function. Here's one that I either wrote or copied from a recipe (can't recall): class FunctionTimeOut(Exception): pass def function_timeout(seconds): Function decorator to raise a timeout on a function call import signal def decorate(f): def timeout(signum, frame): raise FunctionTimeOut() def funct(*args, **kwargs): old = signal.signal(signal.SIGALRM, timeout) signal.alarm(seconds) try: result = f(*args, **kwargs) finally: signal.signal(signal.SIGALRM, old) signal.alarm(0) return result return funct return decorate Then func_dec = function_timeout(TIMEOUT_SECS) for func in function_list: timeout_function = func_dec(func) try: timeout_function(...) except FunctionTimeout: ... -a -- http://mail.python.org/mailman/listinfo/python-list -- http://mail.python.org/mailman/listinfo/python-list
Referencing resources from python
Hi,
What is the best way to reference a non-python file's path from inside
python ?
Until now, I (stupidly) had such lines as:
theFile=open('../somefile.txt')
in my python files. Now I moved my python files to another dir, and all
those relative filenames broke.
On the other hand, the solution of writing the full path of each
resource isn't welcome either, as we're working from a SVN repository
and we sometimes checkout to different dir's. I am sure there is a third
way which didn't occur to me...
What do you recommend?
Thanks, Noam
--
http://mail.python.org/mailman/listinfo/python-list
Propagating function calls
Suppose I have a python object X, which holds inside it a python object Y. How can I propagate each function call to X so the same function call in Y will be called, i.e: X.doThatFunkyFunk() Would cause Y.doThatFunkyFunk() Thanks, Noam -- http://mail.python.org/mailman/listinfo/python-list
Distributing simple tasks
Hi, Suppose I have an array of functions which I execute in threads (each thread get a slice of the array, iterates over it and executes each function in it's slice one after the other). Now I want to distribute these tasks between two machines, i.e give each machine half of the slices and let it run them in threads as described above. Is there an easy way, or an article on this matter you can point me to? Thanks, Noam -- http://mail.python.org/mailman/listinfo/python-list
RE: Distributing simple tasks
Hi, The delta between the finishing times of each machine is insignificant compared to the actual runtime, thus I don't feel it's necessary at the moment. Anyway, I want to keep it simple until I understand how to distribute tasks J Thanks! From: Thomas Raef [mailto:tr...@ebasedsecurity.com] Sent: Friday, February 06, 2009 4:01 PM To: Noam Aigerman; python-list@python.org Subject: RE: Distributing simple tasks Hi, Suppose I have an array of functions which I execute in threads (each thread get a slice of the array, iterates over it and executes each function in it's slice one after the other). Now I want to distribute these tasks between two machines, i.e give each machine half of the slices and let it run them in threads as described above. Is there an easy way, or an article on this matter you can point me to? Thanks, Noam I would suggest maybe a separate queue machine that would hand out each next function. That way if one machine takes a little longer, the faster machine can keep picking off functions and running them, while the slower machine can finish it's task. Just a thought. -- http://mail.python.org/mailman/listinfo/python-list
Kill a function while it's being executed
Hi All, I have a script in which I receive a list of functions. I iterate over the list and run each function. This functions are created by some other user who is using the lib I wrote. Now, there are some cases in which the function I receive will never finish (stuck in infinite loop). Suppose I use a thread which times the amount of time passed since the function has started, Is there some way I can kill the function after a certain amount of time has passed (without asking the user who's giving me the list of functions to make them all have some way of notifying them to finish)? Thanks, Noam -- http://mail.python.org/mailman/listinfo/python-list
RE: Kill a function while it's being executed
About the hijacking - I *might* have done it without understanding what I did (replied to a previous message and then changed the subject), if that's what you mean... Sorry -Original Message- From: python-list-bounces+noama=answers@python.org [mailto:python-list-bounces+noama=answers@python.org] On Behalf Of Albert Hopkins Sent: Wednesday, February 04, 2009 5:26 PM To: python-list@python.org Subject: Re: Kill a function while it's being executed On Wed, 2009-02-04 at 13:40 +0200, Noam Aigerman wrote: Hi All, I have a script in which I receive a list of functions. I iterate over the list and run each function. This functions are created by some other user who is using the lib I wrote. Now, there are some cases in which the function I receive will never finish (stuck in infinite loop). Suppose I use a thread which times the amount of time passed since the function has started, Is there some way I can kill the function after a certain amount of time has passed (without asking the user who's giving me the list of functions to make them all have some way of notifying them to finish)? Thanks, Noam Noam, did you hijack a thread? You could decorate the functions with a timeout function. Here's one that I either wrote or copied from a recipe (can't recall): class FunctionTimeOut(Exception): pass def function_timeout(seconds): Function decorator to raise a timeout on a function call import signal def decorate(f): def timeout(signum, frame): raise FunctionTimeOut() def funct(*args, **kwargs): old = signal.signal(signal.SIGALRM, timeout) signal.alarm(seconds) try: result = f(*args, **kwargs) finally: signal.signal(signal.SIGALRM, old) signal.alarm(0) return result return funct return decorate Then func_dec = function_timeout(TIMEOUT_SECS) for func in function_list: timeout_function = func_dec(func) try: timeout_function(...) except FunctionTimeout: ... -a -- http://mail.python.org/mailman/listinfo/python-list -- http://mail.python.org/mailman/listinfo/python-list
A replacement to closures in python?
Hi, I want to create an array of functions, each doing the same thing with a change to the parameters it uses... something like: arr=['john','terry','graham'] funcs=[] for name in arr: def func(): print 'hello, my name is '+name funcs.append(func) for f in funcs: f() And I would like that to print hello, my name is john hello, my name is terry hello, my name is graham of course... Now I understand why the above code doesn't work as I want it to, but is there some simple workaround for it? Thanks, Noam -- http://mail.python.org/mailman/listinfo/python-list
