Re: creating class objects inside methods
Carl, Thanks for the info, but a couple of points: 1. it wasn't meant to be production code, simply a way to teach python. 2. this should either be a compile time or a runtime error. 'Actions at a distance' like this are deadly both to productivity and to correctness - not only is this a runtime error, it is a *silent* runtime error. Any other language I know would catch this, whether it be lua, java, or perl. Saying that 'whoa, this coding error should be handled by naming convention' may be the only practical way of getting around this limitation, but it is a limitation nonetheless, and a pretty big one. Ed O -- http://mail.python.org/mailman/listinfo/python-list
defaults for function arguments bound only once(??)
All, Another one, this time a bit shorter. It looks like defaults for arguments are only bound once, and every subsequent call reuses the first reference created. Hence the following will print '[10,2]' instead of the expected '[1,2]'. Now my question - exactly why is 'default_me()' only called once, on the construction of the first object? And what's the best way to get around this if you want to have a default for an argument which so happens to be a reference or a new object? code begins here --- import copy class A: def default_me(): return [1,2] def __init__(self, _arg=default_me()): self.arg = _a a = A() a.arg[0] = 10 b = A() print b.arg # prints [10,2] -- http://mail.python.org/mailman/listinfo/python-list
Re: creating class objects inside methods
It's not a bug. In Python classes and global variables share the same namespace. Don't you think you should learn a bit more about how Python manages objects and namespaces before going around calling things bugs? Carl Banks No, I don't think so.. Say you went to another country, where the people wore lead shoes, hence not only going slower, but getting lead poisoning from time to time. Pointing out that shoes made of fabric might just be better should not be heresy. In this case, I think the overall goal was syntax simplicity, but it sure as hell makes things confusing. No warning, or anything. The sane behavior IMO would be to disallow the assignment unless put through a special function, something like: class(state) = ... After all, python does have a precedent when you try to join, when: :.join([1,2]) does not work because [1,2] is an array of ints, whereas : . join( str(x) for x in [1,2]) does. Ed -- http://mail.python.org/mailman/listinfo/python-list
Re: creating class objects inside methods
Thanks for the info, but a couple of points: 1. it wasn't meant to be production code, simply a way to teach python. Speaking as someone who does teach Python, Ew, no! If you start by teaching people bad habits, every educator who comes along afterwards will curse your name. That includes teaching yourself. -- Rhodri James *-* Wildebeest Herder to the Masses No offense, but I disagree. By programming without regards to pre- existing style or convention I learned far more than I otherwise would have if I had simply mimicked someone else. And I still think that unbridled assignment - especially assignment that can change the operational semantics of surrounding terms, at a distance no less - is a horrid thing. It gets even worse because the way python handles assignment. To go back to my original program: why isn't the state variable that I defined local to that 'if' loop? while len(dq): ... if curstate.is_answer(): ... else: for state in ... The answer? Because you can't explicitly declare it. It therefore looks globally, finds the 'class state:' statement, and runs with it. I should be able to say: for my state in curstate.next_states(): to show explicitly what I'm doing. Anyways, maybe I got off to a bad start, but I'm a bit leery of the language. In my estimation it's trying to be 'too clever by half', and this coming from a veteran bash/perl programmer. I mean, free form is one thing, but too much of a good thing can be harmful to your programming health. Maybe PyChecker or PyLint will help, I don't know. Ed ( ps - an aside, but what was the rationale behind only displaying one error at a time on trying to run a script? I typically like to run a compilation phase inside my editor (vim), get a list of errors, and then go to each one and fix them. And how do you just check a script's syntax without running it anyways? ) -- http://mail.python.org/mailman/listinfo/python-list
creating class objects inside methods
All, I've got a strange one.. I'm trying to create a class object inside another class object by using the code template below (note.. this isn't the exact code.. I'm having difficulty reproducing it without posting the whole thing) Anyways, the upshot is that the first time the Myclass() constructor is called, the __init__ function gets executed.. The second time, it calls the '__call__' method (and dies, because I don't have a call method defined). To get around this, I've made __call__ a synonym of __init__, which is a horrid hack, and doesn't help me much (since I don't have a good idea what's going on). So - anyone have an idea of what's going on here? It looks like the second time, the Myclass() call is interpreted as a class instance, not a class object, but that seems odd to me.. Is this a python bug? I'm seeing it in 2.6..If necessary, I can post the whole piece of code.. Ed class Myclass: def __init__(self, b='default1', c='default2'): self.b = b; self.c = c; def function(self): other = Myclass(); return(other) a = Myclass(); b = a.function() -- http://mail.python.org/mailman/listinfo/python-list
Re: creating class objects inside methods
a __main__.Myclass instance at 0x95cd3ec b __main__.Myclass instance at 0x95cd5ac What's the problem? Like I said, the code was a sample of what I was trying to do, not the entire thing.. I just wanted to see if the metaphor was kosher. It sounds to me from your answer that this is unexpected behavior, so I'll go ahead and post the whole thing. My guess is that it is a python bug.. Run it (a simple puzzle game solved by breadth first search), and the first time state() is called inside the method, it calls __init__. Second time, and therafter, it calls __call__. I've highlighted where the code fails by putting a pdb.set_trace(). Anyways, I've got a workaround (simply pass in any new objects needed from the caller), but it is truly annoying that python is either misleading or broken in this way. Attached find code, does not work vs. 2.6.. Ed from collections import deque import copy import pdb class state: def default_board(): return [ [ 1, 'x', 'x', 0 ], [ 2, 2, 3, 4 ], [ 5, 6, 6, 7 ], [ 5, 6, 6, 7 ], [ 8, 9, 10, 10 ], [ 0, 'x', 'x', 0 ] ] def default_types(): return { 1 : [ 0, 0 ], 2 : [ 0, 0, 0, 1 ], 3 : [ 0, 0 ], 4 : [ 0, 0 ], 5 : [ 0, 0, 1, 0 ], 6 : [ 0, 0, 1, 0, 0, 1, 1, 1 ], 7 : [ 0, 0, 1, 0 ], 8 : [ 0, 0 ], 9 : [ 0, 0 ], 10 : [ 0, 0, 0, 1 ] } def default_moves(): return [] def print_move(self, moveno, move): print str(moveno) + : + str(move) + \n def __init__(self, _board=default_board(), _moves=default_moves(), _types=default_types()): self.board = _board self.moves = _moves self.types = _types def possible_moves(self): moves_so_far = set() moves_so_far.add('x') moves_so_far.add(0) ret = [] for y_idx in range(0, len(self.board)): for x_idx in range(0, len(self.board[y_idx])): piece = self.board[y_idx][x_idx] if not piece in moves_so_far: moves = self.legal_moves(y_idx, x_idx) moves_so_far.add(piece) if moves: ret.extend(moves) return ret def is_answer(self): if self.board[5][3] == 1: return True else: return False def legal_moves(self, ycoord, xcoord): ret = [] for dir in [ [ 0, 1 ], [ 0, -1 ], [ 1, 0 ], [ -1, 0 ] ]: ret.extend(self.addmove(dir[0], dir[1], ycoord, xcoord)) return ret def empty(self, type, ycoord, xcoord, pieceno): for itr in range(0, len(type), 2): yy = type[itr] xx = type[itr+1] if not (len(self.board) (yy+ycoord) = 0) or not (len (self.board[yy+ycoord]) xx+xcoord = 0): return False if not self.board[yy+ycoord][xx+xcoord] in [ 0, pieceno ]: return False return True def addmove(self, ymult, xmult, ycoord, xcoord): ret = [] pieceno = self.board[ycoord][xcoord] type= self.types[pieceno] if xmult != 0: for xx in range(xcoord + xmult, -1 if xmult 0 else 4, -1 if xmult 0 else 1): # if xx == 0: # continue if self.empty(type, ycoord, xx, pieceno): ret.append(self.newmove(ycoord, xcoord, ycoord, xx )) else: break if ymult != 0: for yy in range(ycoord + ymult, -1 if ymult 0 else 6, -1 if ymult 0 else 1): # if yy == 0: # continue if self.empty(type, yy, xcoord, pieceno): ret.append(self.newmove(ycoord, xcoord, yy, xcoord)) else: break return ret def newmove(self, fromy, fromx, toy, tox): move = { 'fromx' : fromx, 'fromy' : fromy, 'toy' : toy, 'tox' : tox, 'piece' : self.board[fromy][fromx] } return move def printout_path(self): # print self pdb.set_trace() answer = state() moveno = 0 print \n==\n for moveno in range(0, len(self.moves)): move = self.moves[moveno] self.print_move(moveno, move) answer.apply_move(move) answer.print_board() print \n==\n def print_board(self): for xx in self.board: print : .join([ %2s % str(ii) for ii in xx ]) def to_string(self): return str(self.board) def apply_move(self, move):
Re: creating class objects inside methods
Anyways, I see what's going on here: With the line, for state in curstate.next_states(): if not state.to_string() in seen_states: dq.append(state) Inadvertently using the name of a module as a variable seems to be causing this. In any case, this shouldn't cause issues with constructors, so I'd call this a bug.. Ed -- http://mail.python.org/mailman/listinfo/python-list
importing fully qualified scripts to check syntax
hey all, I'm trying to make a syntax checker, where I say: python -c import /path/to/script to check the syntax of the script named '/path/to/script' (note: no py extension needed). Of course this doesn't work because the functionality for import is bundled up with the environment.. So - is there any simple, generic way in python to import a python file without worrying about naming convention or environment? Sort of like require in perl? Ed -- http://mail.python.org/mailman/listinfo/python-list
syntax checker in python
ps - I just realized that it isn't enough to do: python -c 'import /path/to/script' since that actually executes any statement inside of the script (wheras all I want to do is check syntax) So - let me reprhase that - exactly how can you do a syntax check in python? Something like perl's -c: perl -c script_name.p Ed -- http://mail.python.org/mailman/listinfo/python-list