a class variable question
hi i have define a class like this class A: _var1 = 0 def __init__(self): ## some initialization self.func1() def func1(): . _var1 = 1 def getvarValue(self): return _var1 I wanted var1 to be global inside Class A. when i do AnInstance = A() AnInstance.getvarValue() it gives me 0. It should be 1. What am i doing wrong here..thanks -- http://mail.python.org/mailman/listinfo/python-list
automatic debugger?
hi is there something like an automatic debugger module available in python? Say if i enable this auto debugger, it is able to run thru the whole python program, print variable values at each point, or print calls to functions..etc...just like the pdb module, but now it's automatic. thanks -- http://mail.python.org/mailman/listinfo/python-list
MSoffice metadata
hi is there a module in Python to extract metadata in MS office documents thanks -- http://mail.python.org/mailman/listinfo/python-list
mapping None values to ''
hi i wish to map None or None values to . eg a = None b = None c = None map( something , [i for i in [a,b,c] if i in (None,None) ]) I can't seem to find a way to put all values to . Can anyone help? thanks -- http://mail.python.org/mailman/listinfo/python-list
a string problem
hi if i have a some lines like this a ) here is first string b ) here is string2 c ) here is string3 When i specify i only want to print the lines that contains string ie the first line and not the others. If i use re module, how to compile the expression to do this? I tried the re module and using simple search() and everytime it gives me all the 3 lines that have string in it, whereas i only need line 1. If re module is not needed, how can i use string manipulation to do this? thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: a string problem
John Salerno wrote: [EMAIL PROTECTED] wrote: hi if i have a some lines like this a ) here is first string b ) here is string2 c ) here is string3 When i specify i only want to print the lines that contains string ie the first line and not the others. If i use re module, how to compile the expression to do this? I tried the re module and using simple search() and everytime it gives me all the 3 lines that have string in it, whereas i only need line 1. If re module is not needed, how can i use string manipulation to do this? thanks As far as re goes, you can search for the pattern '\bstring\b', which will find just the word 'string' itself. Not sure if there's a better way to do it with REs. And I'm actually ashamed to admit that I know the RE way, but not the regular string manipulation way, if there is one! This seems like something easy enough to do without REs though. thanks ! -- http://mail.python.org/mailman/listinfo/python-list
Re: a string problem
John Salerno wrote: [EMAIL PROTECTED] wrote: hi if i have a some lines like this a ) here is first string b ) here is string2 c ) here is string3 When i specify i only want to print the lines that contains string ie the first line and not the others. If i use re module, how to compile the expression to do this? I tried the re module and using simple search() and everytime it gives me all the 3 lines that have string in it, whereas i only need line 1. If re module is not needed, how can i use string manipulation to do this? thanks As far as re goes, you can search for the pattern '\bstring\b', which will find just the word 'string' itself. Not sure if there's a better way to do it with REs. And I'm actually ashamed to admit that I know the RE way, but not the regular string manipulation way, if there is one! This seems like something easy enough to do without REs though. if RE has the \b and it works, can we look into the source of re and see how its done for \b ? -- http://mail.python.org/mailman/listinfo/python-list
Re: a string problem
John Salerno wrote: [EMAIL PROTECTED] wrote: hi if i have a some lines like this a ) here is first string b ) here is string2 c ) here is string3 When i specify i only want to print the lines that contains string ie the first line and not the others. If i use re module, how to compile the expression to do this? I tried the re module and using simple search() and everytime it gives me all the 3 lines that have string in it, whereas i only need line 1. If re module is not needed, how can i use string manipulation to do this? thanks As far as re goes, you can search for the pattern '\bstring\b', which will find just the word 'string' itself. Not sure if there's a better way to do it with REs. And I'm actually ashamed to admit that I know the RE way, but not the regular string manipulation way, if there is one! This seems like something easy enough to do without REs though. just curious , if RE has the \b and it works, can we look into the source of re and see how its done for \b ? -- http://mail.python.org/mailman/listinfo/python-list
Re: a string problem
John Salerno wrote: [EMAIL PROTECTED] wrote: just curious , if RE has the \b and it works, can we look into the source of re and see how its done for \b ? I had a look in the sre module (which re seems to import), but I couldn't find much. I'm not the best at analyzing source code, though. :) What is it you want to know about \b? It searches for the empty string before and after a word (word being an alphanumeric character that can include underscores). A little more specific info is in the docs: Matches the empty string, but only at the beginning or end of a word. A word is defined as a sequence of alphanumeric or underscore characters, so the end of a word is indicated by whitespace or a non-alphanumeric, non-underscore character. Note that \b is defined as the boundary between \w and \ W, so the precise set of characters deemed to be alphanumeric depends on the values of the UNICODE and LOCALE flags. Inside a character range, \b represents the backspace character, for compatibility with Python's string literals. thanks..actually i had seen \b in the docs before, just that it slipped my mind when i was doing the coding. was even meddling with look aheads ..which is not the answer anyway. well, since re has the \b, was wondering why there is no implementation of it in strings. So the idea of looking at the source or re on how it's done came to my mine..i suppose we have to go down to viewing the C source then..:-) -- http://mail.python.org/mailman/listinfo/python-list
proper way to use popen4
hi i have to execute some SQL statements against a database using a SQL client i want to use the os.popen4 module can someone correct the way i use os.popen4? thanks fin = select * from some_table #sql statement client = osql server user password #sql client syntax fin, fout = os.popen4(client) fin.close() --- i need to close the stdin first right? print fout.read() I get no results when i did the above... thanks -- http://mail.python.org/mailman/listinfo/python-list
regexp questoin
hi i created a script to ask user for an input that can be a pattern right now, i use re to compile that pattern pat = re.compile(r%s %(userinput) ) #userinput is passed from command line argument if the user key in a pattern , eg [-] , and my script will search some lines that contains [-] pat.findall(lines) but the script produce some error: sre_constants.error: unexpected end of regular expression how can i successful catch patterns such as [-] in my regexp compilation where input is unknown...? thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: regexp questoin
Fredrik Lundh wrote: [EMAIL PROTECTED] wrote: pat = re.compile(r%s %(userinput) ) #userinput is passed from command line argument that r%s % (userinput) thing is a pointless operation: the r prefix controls how backslashes in a string literal is parsed; the result is an ordinary string (%s in this case). in other words, pat = re.compile(r%s % (userinput)) is just a slightly convoluted way to write pat = re.compile(str(userinput)) and since you know that userinput is a string (at least if you got it from sys.argv), you might as well write pat = re.compile(userinput) if the user key in a pattern , eg [-] , and my script will search some lines that contains [-] pat.findall(lines) but the script produce some error: sre_constants.error: unexpected end of regular expression for what pattern? [-] is a valid regular expression (it matches a single minus), but e.g. [- is invalid. to deal with this, catch the exception: try: pat = re.compile(userinput) except re.error: print invalid regular expression:, userinput sys.exit() hope this helps! /F hi. thanks for all the help. actually, i am doing an application that allows user to delete files by entering an input pattern. so if he has files that have special characters such as [-] or others, then i want to filter them off the solution for re.compile(re.escape(userinput)) might work, i have to give it a try. thanks again. -- http://mail.python.org/mailman/listinfo/python-list
printing backslash
hi i want to print something like this |\| first i tried it as string a = |\| it prints ok but when i put it to a list a = [|\|] it gives me '|\\|' .there are 2 back slashes...i only want one.. how can i properly escape it? I have tried [r|\|] , [r'\\'] but they do not work... thanks -- http://mail.python.org/mailman/listinfo/python-list
printing backslash
hi how can i sucessfully print |\| in the output of a print command a = |\| print a but it gives me |\\| i tried raw strings too, but it doesn't print |\| . It prints |\\| instead eventually, i also want |\| to be inside a list: alist = [|\|, 'blah', 'blah'] . How can i put |\| inside a list? can someone show me how it can be done? thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: printing backslash
Tim Chase wrote: i want to print something like this |\| first i tried it as string a = |\| it prints ok but when i put it to a list a = [|\|] it gives me '|\\|' .there are 2 back slashes...i only want one.. how can i properly escape it? I have tried [r|\|] , [r'\\'] but they do not work... You omit how you're printing matters. s1 = '|\|' s2 = r'|\|' s3 = '|\\|' print repr(s1), '-', s1 '|\\|' - |\| print repr(s2), '-', s2 '|\\|' - |\| print repr(s3), '-', s3 '|\\|' - |\| There's a difference between the repr() of a string (which escapes items that need to be escaped) and printing items. All three *print* the item as you request it. All three represent the item with the proper backslashes. The preferred form of putting backslashes in a string is the s2 or s3 form, as the s1 form can have some unpredictable(*) results: \| happens not to be a recognized escape sequence \t is, so you get things like s = '\t\|' s '\t\\|' -tkc (*) unpredictable defined as, predictable, if you happen to have memorized the exact set of characters that do or don't need to beescaped thanks, i got it -- http://mail.python.org/mailman/listinfo/python-list
check for dictionary keys
hi
in my code, i use dict(a) to make to a into a dictionary , a comes
from user input, so my program does not know in the first place. Then
say , it becomes
a = { '-A' : 'value1' , '-B' : value2 , -C : value3 , '-D' :
'value4' }
somewhere next in my code, i will check for these..:
1) -A and -B cannot exist together
2) -A and -C cannot exist together
3) -A and -B and -D cannot exist together
4) and lots of other combinations to check for
how can i efficiently check for the above? At first as i do simple
checks , i use if and else.
But as i began to check for more combinatoiuns, it gets messy
thanks.
--
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default argument values qns
hi i have declared a function like this: def aFunction ( arg1 , arg2 = 0): print type(arg2) when i try to print the type of arg2, it gives me 'str' type..why is it not integer type, since i have declared it as 0 ?? thanks -- http://mail.python.org/mailman/listinfo/python-list
deleting texts between patterns
hi say i have a text file line1 line2 line3 line4 line5 line6 abc line8 ---to be delete line9 ---to be delete line10 ---to be delete line11 ---to be delete line12 ---to be delete line13 ---to be delete xyz line15 line16 line17 line18 I wish to delete lines that are in between 'abc' and 'xyz' and print the rest of the lines. Which is the best way to do it? Should i get everything into a list, get the index of abc and xyz, then pop the elements out? or any other better methods? thanks -- http://mail.python.org/mailman/listinfo/python-list
find all index positions
hi say i have string like this astring = 'abcd efgd 1234 fsdf gfds abcde 1234' if i want to find which postion is 1234, how can i achieve this...? i want to use index() but it only give me the first occurence. I want to know the positions of both 1234 thanks -- http://mail.python.org/mailman/listinfo/python-list
printing out elements in list
hi
i have a list with contents like this
alist = ['QWER' , 'askfhs', 'REWR' ,'sfsdf' , 'FGDG',
'sdfsdgffdgfdg' ]
how can i convert this list into a dictionary such that
dictionary = { 'QWER':'askfhs' , 'REWR' : 'sfsdf' , 'FGDG',
'sdfsdgffdgfdg' }
thanks
--
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Re: printing out elements in list
thanks for all your replies...I will go test them out.. I was wondering what does this mean alist[1::2]? thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: printing out elements in list
thanks for the detailed explaination... i know about basic lists slicing..just havn't seen one with steps yet.. thanks again...clp rocks. -- http://mail.python.org/mailman/listinfo/python-list
pythonic way to sort
hi I have a file with columns delimited by '~' like this: 1SOME STRING ~ABC~12311232432D~20060401~ 2SOME STRING ~DEF~13534534543C~20060401~ 3SOME STRING ~ACD~14353453554G~20060401~ . What is the pythonic way to sort this type of structured text file? Say i want to sort by 2nd column , ie ABC, ACD,DEF ? so that it becomes 1SOME STRING ~ABC~12311232432D~20060401~ 3SOME STRING ~ACD~14353453554G~20060401~ 2SOME STRING ~DEF~13534534543C~20060401~ ? I know for a start, that i have to split on '~', then append all the second columns into a list, then sort the list using sort(), but i am stuck with how to get the rest of the corresponding columns after the sort thanks... -- http://mail.python.org/mailman/listinfo/python-list
stripping
hi i have a file test.dat eg abcdefgh ijklmn -newline opqrs tuvwxyz ---newline I wish to print the contents of the file such that it appears: abcdefgh ijklmn opqrs tuvwxyz here is what i did: f = open(test.dat) while 1: line = f.readline().rstrip(\n) if line == '': break #if not re.findall(r'^$',line): print line but it always give me first 2 lines, ie abcdefgh ijklmn What can i do to make it print all..? thanks -- http://mail.python.org/mailman/listinfo/python-list
stripping blanks
hi i have a file test.dat eg abcdefgh ijklmn -newline opqrs tuvwxyz ---newline I wish to print the contents of the file such that it appears: abcdefgh ijklmn opqrs tuvwxyz here is what i did: f = open(test.dat) while 1: line = f.readline().rstrip(\n) if line == '': break #if not re.findall(r'^$',line): print line but it always give me first 2 lines, ie abcdefgh ijklmn What can i do to make it print all..? thanks -- http://mail.python.org/mailman/listinfo/python-list
strip newlines and blanks
hi i have a file test.dat eg abcdefgh ijklmn -newline opqrs tuvwxyz I wish to print the contents of the file such that it appears: abcdefgh ijklmn opqrs tuvwxyz here is what i did: f = open(test.dat) while 1: line = f.readline().rstrip(\n) if line == '': break print line but it always give me first 2 lines, ie abcdefgh ijklmn What can i do to make it print all w/o the newlines..? and what is the proper way to skip printing blank lines while iterating file contents? thanks -- http://mail.python.org/mailman/listinfo/python-list
blank lines representation in python
hi what is the correct way to represent blank lines in python (while iterating a file) without regexp? I know one way is to use re.search((line,r'^$') to grab a blank line, but i wanna try not to use regexp... is it 1) if line == '': dosomething() (this also means EOF right? ) 2) if line is None: dosomething() 3) if not line: dosomething() thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: strip newlines and blanks
thanks..and sorry, i am using the web version of google groups and didn't find an option i can edit my post, so i just removed it.. thanks again for the reply.. -- http://mail.python.org/mailman/listinfo/python-list
can anyone advise me
why the output of this code : x = 0 while x 10: z = 0 print x x = x + 1 while z x: print z, z = z + 1 is 0 0 1 0 1 2 0 1 2 3 0 1 2 3 4 0 1 2 3 4 5 0 1 2 3 4 5 6 0 1 2 3 4 5 6 7 0 1 2 3 4 5 6 7 8 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 ---extra instead of : 0 0 1 0 1 2 0 1 2 3 0 1 2 3 4 0 1 2 3 4 5 0 1 2 3 4 5 6 0 1 2 3 4 5 6 7 0 1 2 3 4 5 6 7 8 0 1 2 3 4 5 6 7 8 9 thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: can anyone advise me
Dan Sommers wrote: On 27 Apr 2006 02:48:46 -0700, [EMAIL PROTECTED] wrote: why the output of this code : x = 0 while x 10: z = 0 print x x = x + 1 while z x: print z, z = z + 1 is 0 Okay, that was x, from the print statement inside the x-loop. 0 1 And that's z, from the print statement inside the z-loop. z is 0, and then when z is 1, it's not less than x, so we're done printing z's. And then we get the next x. 0 1 2 And two more z's, 0 and 1, since x is now 2. And another x. Since this might be homework, I'll stop at a hint: you need to think about when you want each printed line to end, and make sure that you tell python to end it there. Regards, Dan -- Dan Sommers http://www.tombstonezero.net/dan/ I wish people would die in alphabetical order. -- My wife, the genealogist thanks..solved...just removed the print x.. -- http://mail.python.org/mailman/listinfo/python-list
Re: python pyc or pyo files
thanks! got it -- http://mail.python.org/mailman/listinfo/python-list
a subprocess qns
hi i wanted to start execute a command and put it in the background. i am using Unix. Usually i start this command using something like this : /path/somecmd with the to put it to background. i looked at the subprocess module docs and came across this statement Replacing os.spawn* --- P_NOWAIT example: pid = os.spawnlp(os.P_NOWAIT, /bin/mycmd, mycmd, myarg) == pid = Popen([/bin/mycmd, myarg]).pid Can i ask if P_NOWAIT means the same as ?? so if it is, then this statement pid = os.spawnlp(os.P_NOWAIT, /bin/mycmd, mycmd, myarg) will put mycmd into background and return to the caller...? thanks -- http://mail.python.org/mailman/listinfo/python-list
python pyc or pyo files
hi any good websites or articles that describes about pyc or pyo files , how they are generated and what's the difference between them and Java's bytecode?? thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: python pyc or pyo files
thanks ! can i ask again... I have two scripts , A.py and B.py In B.py, i have an import statement to import A.py When i executed B.py, i saw a A.pyc in the same directory, but not B.pyc This is an expected behaviour right? why is B.pyc not generated? thanks -- http://mail.python.org/mailman/listinfo/python-list
any update to this?
hi i was looking at this : http://www.python.org/doc/essays/comparisons.html on comparisons of python and other languages? are there any updates to this doc? or is there other reliable source for such comparison elsewhere? thanks -- http://mail.python.org/mailman/listinfo/python-list
nested functions
hi just curious , if i have a code like this? def a(): def b(): print b def c(): print c how can i call c() ?? -- http://mail.python.org/mailman/listinfo/python-list
