jorma kala wrote:
Hi,
I'd like to process files in a directory which is in fact a short cut link
to another directory (under windows XP).
If the path to the directory is for instance called c:\test. I have tried
both following code snipets for printing all names of files in the
directory:
++ snippet 1++
for filename in glob.glob( os.path.join(r'c:\test', '*') ):
print filename
++ snippet 2++
for filename in glob.glob( os.path.join(r'c:\test.lnk', '*') ):
print filename
Windows shortcuts are Shell (ie GUI Desktop) objects rather
than filesystem objects. The filesystem doesn't treat them
specially; just returns the .lnk file (or whatever it's
called). You need to invoke the Shell functionality specifically.
code
import os, sys
import glob
import pythoncom
from win32com.shell import shell, shellcon
def shortcut_target (filename):
shell_link = pythoncom.CoCreateInstance (
shell.CLSID_ShellLink,
None,
pythoncom.CLSCTX_INPROC_SERVER,
shell.IID_IShellLink
)
ipersist = shell_link.QueryInterface (pythoncom.IID_IPersistFile)
ipersist.Load (filename)
name, _ = shell_link.GetPath (1)
return name
def shell_glob (pattern):
for filename in glob.glob (pattern):
if filename.endswith (.lnk):
yield %s = %s % (filename, shortcut_target (filename))
else:
yield filename
for filename in shell_glob (c:/temp/*):
print filename
/code
TJG
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