Building a dict from a tuple of tuples
Hello everyone!
I have a tuple of tuples, coming from an Excel range, such as this:
((None, u'x', u'y'),
(u'a', 1.0, 7.0),
(u'b', None, 8.0))
I need to build a dictionary that has, as key, the row and column
header.
For example:
d={ (u'a',u'x'):1.0, (u'a',u'y'): 7.0, (u'b',u'y'):8.0 }
As you can see, if the value in the matrix is None, no key has to be
added to the dictionary.
Of course, my tuple of tuples is a lot bigger.
How can I possibly do this?
Thank you
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Re: Building a dict from a tuple of tuples
vsoler wrote:
Hello everyone!
I have a tuple of tuples, coming from an Excel range, such as this:
((None, u'x', u'y'),
(u'a', 1.0, 7.0),
(u'b', None, 8.0))
I need to build a dictionary that has, as key, the row and column
header.
For example:
d={ (u'a',u'x'):1.0, (u'a',u'y'): 7.0, (u'b',u'y'):8.0 }
As you can see, if the value in the matrix is None, no key has to be
added to the dictionary.
Of course, my tuple of tuples is a lot bigger.
How can I possibly do this?
Thank you
Does this help?
matrix = ((None, u'x', u'y'),
(u'a', 1.0, 7.0),
(u'b', None, 8.0))
for row in matrix[1 : ]:
for col, val in zip(matrix[0][1 : ], row[1 : ]):
print row[0], col, val
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Re: Building a dict from a tuple of tuples
On Feb 20, 7:00 pm, MRAB pyt...@mrabarnett.plus.com wrote:
vsoler wrote:
Hello everyone!
I have a tuple of tuples, coming from an Excel range, such as this:
((None, u'x', u'y'),
(u'a', 1.0, 7.0),
(u'b', None, 8.0))
I need to build a dictionary that has, as key, the row and column
header.
For example:
d={ (u'a',u'x'):1.0, (u'a',u'y'): 7.0, (u'b',u'y'):8.0 }
As you can see, if the value in the matrix is None, no key has to be
added to the dictionary.
Of course, my tuple of tuples is a lot bigger.
How can I possibly do this?
Thank you
Does this help?
matrix = ((None, u'x', u'y'),
(u'a', 1.0, 7.0),
(u'b', None, 8.0))
for row in matrix[1 : ]:
for col, val in zip(matrix[0][1 : ], row[1 : ]):
print row[0], col, val
and the dictionary?
it is the ultimate goal of what I am intending...
Thank you
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Re: Building a dict from a tuple of tuples
vsoler wrote:
On Feb 20, 7:00 pm, MRAB pyt...@mrabarnett.plus.com wrote:
vsoler wrote:
Hello everyone!
I have a tuple of tuples, coming from an Excel range, such as this:
((None, u'x', u'y'),
(u'a', 1.0, 7.0),
(u'b', None, 8.0))
I need to build a dictionary that has, as key, the row and column
header.
For example:
d={ (u'a',u'x'):1.0, (u'a',u'y'): 7.0, (u'b',u'y'):8.0 }
As you can see, if the value in the matrix is None, no key has to be
added to the dictionary.
Of course, my tuple of tuples is a lot bigger.
How can I possibly do this?
Thank you
Does this help?
matrix = ((None, u'x', u'y'),
(u'a', 1.0, 7.0),
(u'b', None, 8.0))
for row in matrix[1 : ]:
for col, val in zip(matrix[0][1 : ], row[1 : ]):
print row[0], col, val
and the dictionary?
it is the ultimate goal of what I am intending...
Thank you
The difficult bit is working out how to produce the keys and values for
the dict from the tuple of tuples, and I've shown you that. The rest is
straightforward.
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Re: Building a dict from a tuple of tuples
On Feb 20, 8:54 pm, MRAB pyt...@mrabarnett.plus.com wrote:
vsoler wrote:
On Feb 20, 7:00 pm, MRAB pyt...@mrabarnett.plus.com wrote:
vsoler wrote:
Hello everyone!
I have a tuple of tuples, coming from an Excel range, such as this:
((None, u'x', u'y'),
(u'a', 1.0, 7.0),
(u'b', None, 8.0))
I need to build a dictionary that has, as key, the row and column
header.
For example:
d={ (u'a',u'x'):1.0, (u'a',u'y'): 7.0, (u'b',u'y'):8.0 }
As you can see, if the value in the matrix is None, no key has to be
added to the dictionary.
Of course, my tuple of tuples is a lot bigger.
How can I possibly do this?
Thank you
Does this help?
matrix = ((None, u'x', u'y'),
(u'a', 1.0, 7.0),
(u'b', None, 8.0))
for row in matrix[1 : ]:
for col, val in zip(matrix[0][1 : ], row[1 : ]):
print row[0], col, val
and the dictionary?
it is the ultimate goal of what I am intending...
Thank you
The difficult bit is working out how to produce the keys and values for
the dict from the tuple of tuples, and I've shown you that. The rest is
straightforward.
I'll try. Thank you very much MRAB
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