Re: Get path of a class
Florian Lindner wrote: Hello, how can I get the path of a class. I managed to do it with c.__module__ + . + c.__name__ but I'm sure there is a better way. Please define what you mean by path (and how you hope to make use of this information). Generally a module has a path (i.e. a location where it can be loaded from the file system) but classes are merely created by class statements within a module. There is no one-to-one match with files, and in fact no requirement that a class even be traceable directly to statements in a source file. -Peter -- http://mail.python.org/mailman/listinfo/python-list
Re: Get path of a class
In [EMAIL PROTECTED], Florian Lindner wrote: Hello, how can I get the path of a class. I managed to do it with c.__module__ + . + c.__name__ but I'm sure there is a better way. How about using the `inspect` module:: In [33]: import inspect, zipfile In [34]: inspect.getsourcefile(zipfile.ZipInfo) Out[34]: '/usr/lib/python2.4/zipfile.py' Ciao, Marc 'BlackJack' Rintsch -- http://mail.python.org/mailman/listinfo/python-list
Get path of a class
Hello, how can I get the path of a class. I managed to do it with c.__module__ + . + c.__name__ but I'm sure there is a better way. Thanks, Florian -- http://mail.python.org/mailman/listinfo/python-list
