Re: How to find out in which module an instance of a class is created?
Chris Rebert schrieb: On Sun, Aug 16, 2009 at 6:25 AM, Johannes Janssen wrote: Gabriel Genellina schrieb: The try/except around sys._getframe(1) is because that function is not mandatory/available on all Python implementations (that's the case for jython which doesn't provide it). Thanks, shouldn't such information be part of the python documentation of sys._getframe() (http://docs.python.org/library/sys.html?highlight=sys._getframe#sys._getframe)? The leading underscore kinda indirectly implies it, but yeah, it's worth mentioning. File a bug in the docs: http://bugs.python.org/ Cheers, Chris I filed a bug: http://bugs.python.org/issue6712 . Johannes -- http://mail.python.org/mailman/listinfo/python-list
Re: How to find out in which module an instance of a class is created?
On Sun, Aug 16, 2009 at 6:25 AM, Johannes Janssen wrote: > Gabriel Genellina schrieb: >> >> The try/except around sys._getframe(1) is because that function is not >> mandatory/available on all Python implementations (that's the case for >> jython which doesn't provide it). > > Thanks, shouldn't such information be part of the python documentation of > sys._getframe() > (http://docs.python.org/library/sys.html?highlight=sys._getframe#sys._getframe)? The leading underscore kinda indirectly implies it, but yeah, it's worth mentioning. File a bug in the docs: http://bugs.python.org/ Cheers, Chris -- http://blog.rebertia.com -- http://mail.python.org/mailman/listinfo/python-list
Re: How to find out in which module an instance of a class is created?
Gabriel Genellina schrieb: The try/except around sys._getframe(1) is because that function is not mandatory/available on all Python implementations (that's the case for jython which doesn't provide it). Thanks, shouldn't such information be part of the python documentation of sys._getframe() (http://docs.python.org/library/sys.html?highlight=sys._getframe#sys._getframe)? Johannes -- http://mail.python.org/mailman/listinfo/python-list
Re: How to find out in which module an instance of a class is created?
En Mon, 10 Aug 2009 18:51:59 -0300, Johannes Janssen escribió: class A(object): def __init__(self, mod=None): if mod is None: self.mod = sys._getframe(1).f_globals['__name__'] else: self.mod = mod In warnings.warn() they used try around sys._getframe(1). As far as I understand what is done in warnings, there it is not sure what object caused the warning and therefore it is not sure whether you can or cannot use sys._getframe(1). Though in my case it should be quite clear. Can I be sure that my code will always work? The try/except around sys._getframe(1) is because that function is not mandatory/available on all Python implementations (that's the case for jython which doesn't provide it). -- Gabriel Genellina -- http://mail.python.org/mailman/listinfo/python-list
Re: How to find out in which module an instance of a class is created?
Christian Heimes schrieb: Johannes Janssen wrote: > class A(object): > def __init__(self, mod=__name__): > self.mod = mod won't work. In this case mod would always be "foo". You have to inspect the stack in order to get the module of the caller. The implementation of warnings.warn() gives you some examples how to get the module name. Christian Thanks for the quick and very helpful reply. Basically just copying from warnings.warn(), I came up with this: import sys class A(object): def __init__(self, mod=None): if mod is None: self.mod = sys._getframe(1).f_globals['__name__'] else: self.mod = mod In warnings.warn() they used try around sys._getframe(1). As far as I understand what is done in warnings, there it is not sure what object caused the warning and therefore it is not sure whether you can or cannot use sys._getframe(1). Though in my case it should be quite clear. Can I be sure that my code will always work? Johannes -- http://mail.python.org/mailman/listinfo/python-list
Re: How to find out in which module an instance of a class is created?
Johannes Janssen wrote: > class A(object): > def __init__(self, mod=__name__): > self.mod = mod won't work. In this case mod would always be "foo". You have to inspect the stack in order to get the module of the caller. The implementation of warnings.warn() gives you some examples how to get the module name. Christian -- http://mail.python.org/mailman/listinfo/python-list
How to find out in which module an instance of a class is created?
Hi I like to know in which module an instance of a class was initialized. Using __module__ or __name__ within a class only gives me the module in which the class was defined not the instance of the class. Is there some (simple) way to do this? For better understanding I'll give an example how I want to use this. Okay let's say I've got a module *foo,* in which class A is defined as the following: > class A(object): > def __init__(self, mod): > self.mod = mod In a module called *bar* I do the following: > import foo > a = A(__name__) Then a.mod should be "bar". But I don't like to pass the value of a.mod manually rather than having it default to the module the instance a of A was created in (here "bar"). Unfortunately something like this ... > class A(object): > def __init__(self, mod=__name__): > self.mod = mod ... won't work. In this case mod would always be "foo". Kind regards johannes -- http://mail.python.org/mailman/listinfo/python-list
