Re: Instead of saving text files i need as html
Tim Chase [EMAIL PROTECTED] wrote:
[ ... ]
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.html')
[ ... ] I'm not sure what the odd
slicing is for, but I'll presume the OP knows what they're doing.
It's taking the http://; off the front of the URL.
len(http://;)
7
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Instead of saving text files i need as html
I have the following code which takes a list of urls
http://google.com;, without the quotes ofcourse, and then saves there
source code as a text file. I wan to alter the code so that for the
list of URLs an html file is saved.
-begin-
import urllib
urlfile = open(r'c:\temp\url.txt', 'r')
for lines in urlfile:
try:
outfilename = lines.replace('/', '-')
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.txt')
except:
pass
-end-
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Re: Instead of saving text files i need as html
Then just write HTML around your list. I would guess
you want them inside a table. Just write appropriate
HTML tags before/after the urls. If you want the URLs
to be clickable make them in into a hrefurl/a lines.
-Larry Bates
Shani wrote:
I have the following code which takes a list of urls
http://google.com;, without the quotes ofcourse, and then saves there
source code as a text file. I wan to alter the code so that for the
list of URLs an html file is saved.
-begin-
import urllib
urlfile = open(r'c:\temp\url.txt', 'r')
for lines in urlfile:
try:
outfilename = lines.replace('/', '-')
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.txt')
except:
pass
-end-
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Re: Instead of saving text files i need as html
Shani [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
I have the following code which takes a list of urls
http://google.com;, without the quotes ofcourse, and then saves there
source code as a text file. I wan to alter the code so that for the
list of URLs an html file is saved.
-begin-
import urllib
urlfile = open(r'c:\temp\url.txt', 'r')
for lines in urlfile:
try:
outfilename = lines.replace('/', '-')
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.txt')
except:
pass
-end-
Is this what you mean?
-begin-
import urllib
urlfile = open(r'c:\temp\url.txt', 'r')
for lines in urlfile:
try:
outfilename = lines.replace('/', '-')
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.html')
except:
pass
-end-
Louis
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Re: Instead of saving text files i need as html
Shani [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
I have the following code which takes a list of urls
http://google.com;, without the quotes ofcourse, and then saves there
source code as a text file. I wan to alter the code so that for the
list of URLs an html file is saved.
-begin-
import urllib
urlfile = open(r'c:\temp\url.txt', 'r')
for lines in urlfile:
try:
outfilename = lines.replace('/', '-')
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.txt')
except:
pass
-end-
Or is this what you mean?
-begin-
import urllib
urlfile = open('c:\\temp\\url.txt', 'r')
newurlfile = open('c:\\temp\\newurls.html', 'w')
newurlfile.write('html \nbody\n')
for lines in urlfile:
try:
if lines == '\n':
pass
else:
lines = 'a href=' + lines.strip() +''\
+ lines.strip() + '/a' + 'br\n'
newurlfile.write(lines)
except:
pass
newurlfile.write('/body \n/html')
urlfile.close()
newurlfile.close()
-end-
Louis
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Re: Instead of saving text files i need as html
3c273 [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
Or is this what you mean?
-begin-
import urllib
urlfile = open('c:\\temp\\url.txt', 'r')
newurlfile = open('c:\\temp\\newurls.html', 'w')
newurlfile.write('html \nbody\n')
for lines in urlfile:
try:
if lines == '\n':
pass
else:
lines = 'a href=' + lines.strip() +''\
+ lines.strip() + '/a' + 'br\n'
newurlfile.write(lines)
except:
pass
newurlfile.write('/body \n/html')
urlfile.close()
newurlfile.close()
-end-
Louis
Oops, I guess we don't need import urllib anymore.
Louis
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Re: Instead of saving text files i need as html
Shani wrote:
I have the following code which takes a list of urls
http://google.com;, without the quotes ofcourse, and then saves there
source code as a text file. I wan to alter the code so that for the
list of URLs an html file is saved.
What you write in a text file is up to you - and AFAICT, HTML is still
a text format.
--
bruno desthuilliers
python -c print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in '[EMAIL PROTECTED]'.split('@')])
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Re: Instead of saving text files i need as html
Is this what you mean?
-begin-
import urllib
urlfile = open(r'c:\temp\url.txt', 'r')
for lines in urlfile:
try:
outfilename = lines.replace('/', '-')
urllib.urlretrieve(lines.strip('/n'), 'c:\\temp\\' \
+ outfilename.strip('\n')[7:] + '.html')
except:
pass
-end-
[laughs] I suspect the urlretrieve line should contain
strip('\n') instead of strip('/n'), but otherwise, the
original code looked pretty kosher. I'm not sure what the odd
slicing is for, but I'll presume the OP knows what they're doing.
While not a python solution, the standard *nix tool would be
either wget or curl:
bash wget -i listofurls.txt
which is freely available with the Cygwin suite of GNU tools for
Win32 platforms.
-tkc
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