Re: Logging Custom Levels?

[Didymus]

On Tuesday, March 31, 2015 at 1:37:29 PM UTC-4, Jean-Michel Pichavant wrote:
> 
> A solution is pretty simple, do not use an intermediate log function pdebug.
> 
> import logging
> PDEBUG_NUM=20
> logging.addLevelName(PDEBUG_NUM, "PDEBUG")
>  
> logger = logging.getLogger('foo')
> logging.basicConfig(level=logging.DEBUG, format='%(message)s %(lineno)d')
> 
> logger.log(PDEBUG_NUM, 'This will work :')
> 
> 
> If you *really* want to go for the hackish way, forget about the inspect 
> module, the following pdebug function should do the trick:
> 
> def pdebug(self, message, *args, **kws):
> if self.isEnabledFor(PDEBUG_NUM):
> self._log(PDEBUG_NUM, message, args, **kws)
> 
> Cheers,
> 
> JM
> 

Very good, thank you!
Tom
 

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Re: Logging Custom Levels?

[Jean-Michel Pichavant]

- Original Message -
> From: "Didymus" 
> To: python-list@python.org
> Sent: Tuesday, 31 March, 2015 5:20:52 PM
> Subject: Logging Custom Levels?
> 
> Hi,
> 
> I've create a Python file called "log.py" and placed in the custom
> levels:
> 
> # Performance Debug...
> logging.addLevelName(PDEBUG_NUM, "PDEBUG")
> 
> def pdebug(self, message, *args, **kws):
> """ Performance Debug Message Level """
> self.log(PDEBUG_NUM, message, *args, **kws)
> 
> logging.Logger.pdebug = pdebug
> 
> 
> This works except that the %(module) and %(lineno) does not print
> properly, it instead prints out as the "log.py" and the line that
> this is on. I think I figured out a way to get the module and line
> from the calling custom level:
> 
> import inspect
> frame = inspect.currentframe()
> filename =
> os.path.splitext(os.path.basename(frame.f_back.f_code.co_filename))[0]
> linenumber = frame.f_back.f_lineno
> 
> 
> My question is how do I pass this into the "self.log" call properly?
> I've tried a few different things without any luck. Any ideas how I
> can pass this into the custom logging level and get it to work?
> 
> Thanks in Advance for any help!
> Tom

A solution is pretty simple, do not use an intermediate log function pdebug.

import logging
PDEBUG_NUM=20
logging.addLevelName(PDEBUG_NUM, "PDEBUG")
 
logger = logging.getLogger('foo')
logging.basicConfig(level=logging.DEBUG, format='%(message)s %(lineno)d')

logger.log(PDEBUG_NUM, 'This will work :')


If you *really* want to go for the hackish way, forget about the inspect 
module, the following pdebug function should do the trick:

def pdebug(self, message, *args, **kws):
if self.isEnabledFor(PDEBUG_NUM):
self._log(PDEBUG_NUM, message, args, **kws)

Cheers,

JM


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Logging Custom Levels?

[Didymus]

Hi,

I've create a Python file called "log.py" and placed in the custom levels:

# Performance Debug...
logging.addLevelName(PDEBUG_NUM, "PDEBUG")

def pdebug(self, message, *args, **kws):
""" Performance Debug Message Level """
self.log(PDEBUG_NUM, message, *args, **kws) 

logging.Logger.pdebug = pdebug


This works except that the %(module) and %(lineno) does not print properly, it 
instead prints out as the "log.py" and the line that this is on. I think I 
figured out a way to get the module and line from the calling custom level:

import inspect
frame = inspect.currentframe()
filename = 
os.path.splitext(os.path.basename(frame.f_back.f_code.co_filename))[0]
linenumber = frame.f_back.f_lineno


My question is how do I pass this into the "self.log" call properly? I've tried 
a few different things without any luck. Any ideas how I can pass this into the 
custom logging level and get it to work?

Thanks in Advance for any help!
Tom
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