Re: Parsing Python dictionary with multiple objects
json_split = {}
value = {Status: Submitted, m_Controller: Python}
a = range(31)
del a[0]
for i in a:
json_split[i] = value
keys = json_split.keys()
order = list(keys)
q1 = int(round(len(keys)*0.2))
q2 = int(round(len(keys)*0.3))
q3 = int(round(len(keys)*0.5))
b = [q1,q2,q3]
n=0
threedicts = []
for i in b:
queues = order[n:n+i]
n = n+i
lists = [(queues[j], json_split.get(queues[j])) for j in range(len(queues))]
onedict = {}
for q in queues:
onedict[q] = json_split[q]
threedicts.append (onedict)
queue1, queue2, queue3 = threedicts
keys1 = queue1.keys()
for i in keys1:
queue1[i]['Priority'] = ['1']
keys2 = queue2.keys()
for j in keys2:
queue2[j]['Priority'] = ['2']
keys3 = queue3.keys()
for z in keys3:
queue3[z]['Priority'] = ['3']
I am trying to add a key value pair of (Priority:1) to queue1,
(Priority:2) to queue2, and (Priority:3) to queue3.
When I just add (Priority:1) to queue1, it works.
But when I run the above code, (Priority:3) is being added to all the
queues.
This looks trivial and I don't understand why this is happening. Is there
something wrong with what I am doing?
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Re: Parsing Python dictionary with multiple objects
Thanks Rustom for the advice. I am new to Python and getting struck at some basic things. How do I assign the values that I am printing to 3 variables say dict1, dict2, dict3? When I try to assign them before the print statement like this: d1, d2, d3 =[(queues[j], json.get(queues[j])) for j in range(len(queues))] I get an error saying 'need more than one value to unpack' -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
On Wednesday, October 15, 2014 9:22:48 PM UTC+5:30, Anurag Patibandla wrote: Thanks Rustom for the advice. I am new to Python and getting struck at some basic things. How do I assign the values that I am printing to 3 variables say dict1, dict2, dict3? When I try to assign them before the print statement like this: d1, d2, d3 =[(queues[j], json.get(queues[j])) for j in range(len(queues))] I get an error saying 'need more than one value to unpack' Probably means your comprehension [(queues[j], json.get(queues[j])) for j in range(len(queues))] is having less than 3 values lst = [1,2,3] x,y,z = lst (x,y,z) # note no need to print (1, 2, 3) lst=[1] x,y,z=lst Traceback (most recent call last): File stdin, line 1, in module ValueError: need more than 1 value to unpack lst=[1,2,3,4] x,y,z=lst Traceback (most recent call last): File stdin, line 1, in module ValueError: too many values to unpack I suggest youdont directly start with multiple assignment Instead do it in two steps dicts = [(queues[j], json.get(queues[j])) for j in range(len(queues))] d0 = dicts[0] d1 = dicts[1] d2 = dicts[2] When that works go to the more compact form Also please get rid of the range(len(queues)) Its unpythonic! -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
First the values printed by '[(queues[j], json.get(queues[j])) for j in range(len(queues))] ' is a list, so I tried to convert it into a dict using dict(). And then I tried doing dict[0] but there is an error which says: 'type' object has no attribute '__getitem__' -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
On Wednesday, October 15, 2014 9:58:49 PM UTC+5:30, Anurag Patibandla wrote: First the values printed by '[(queues[j], json.get(queues[j])) for j in range(len(queues))] ' is a list, so I tried to convert it into a dict using dict(). And then I tried doing dict[0] but there is an error which says: 'type' object has no attribute '__getitem__' print each step in the process until the error step Also assuming [(queues[j], json.get(queues[j])) for j in range(len(queues))] is the same as [(q, json.get(q) for q in queues] do a = [(q, json.get(q) for q in queues] print a b = dict(a) print b c = b[0] print c or whatever it is you are doing and PASTE (not NARRATE) the results -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
keys = json.keys() order = list(keys) q1 = int(round(len(keys)*0.2)) q2 = int(round(len(keys)*0.3)) q3 = int(round(len(keys)*0.5)) b = [q1,q2,q3] n=0 for i in b: queues = order[n:n+i] n = n+i #print queues #print [(queues[j], json.get(queues[j])) for j in range(len(queues))] lists = [(queues[j], json.get(queues[j])) for j in range(len(queues))] #print lists dicts = dict(lists) print dicts print dict[0] Print dicts works as expected giving me the combine dictionary values. But when I say dict[0]. I see the error: TypeError: 'type' object has no attribute '__getitem__' -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
On Wednesday, October 15, 2014 10:13:18 PM UTC+5:30, Rustom Mody wrote: On Wednesday, October 15, 2014 9:58:49 PM UTC+5:30, Anurag Patibandla wrote: First the values printed by '[(queues[j], json.get(queues[j])) for j in range(len(queues))] ' is a list, so I tried to convert it into a dict using dict(). And then I tried doing dict[0] but there is an error which says: 'type' object has no attribute '__getitem__' Also there are dictionary comprehensions recently added to python: http://legacy.python.org/dev/peps/pep-0274/ Can generally be used if you are doing dict(a list comprehension) To start with though, I suggest you stay with the longer older form until you understand how it works -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
keys = json.keys() order = list(keys) q1 = int(round(len(keys)*0.2)) q2 = int(round(len(keys)*0.3)) q3 = int(round(len(keys)*0.5)) b = [q1,q2,q3] n=0 for i in b: queues = order[n:n+i] n = n+i lists = [(queues[j], json.get(queues[j])) for j in range(len(queues))] dicts = dict(lists) print dicts print dict[0] print dicts works as expected. It gives me the entire dictionary. But when I do dicts[0], there is the following error: 'type' object has no attribute '__getitem__' -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
On Wednesday, October 15, 2014 10:30:49 PM UTC+5:30, Anurag Patibandla wrote: keys = json.keys() order = list(keys) q1 = int(round(len(keys)*0.2)) q2 = int(round(len(keys)*0.3)) q3 = int(round(len(keys)*0.5)) b = [q1,q2,q3] n=0 for i in b: queues = order[n:n+i] n = n+i lists = [(queues[j], json.get(queues[j])) for j in range(len(queues))] dicts = dict(lists) print dicts print dict[0] print dicts works as expected. It gives me the entire dictionary. But when I do dicts[0], there is the following error: 'type' object has no attribute '__getitem__' Do you want dict[0] ?? I think you want dicts[0] -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
On Wednesday, October 15, 2014 1:10:41 PM UTC-4, Rustom Mody wrote: On Wednesday, October 15, 2014 10:30:49 PM UTC+5:30, Anurag Patibandla wrote: keys = json.keys() order = list(keys) q1 = int(round(len(keys)*0.2)) q2 = int(round(len(keys)*0.3)) q3 = int(round(len(keys)*0.5)) b = [q1,q2,q3] n=0 for i in b: queues = order[n:n+i] n = n+i lists = [(queues[j], json.get(queues[j])) for j in range(len(queues))] dicts = dict(lists) print dicts print dict[0] print dicts works as expected. It gives me the entire dictionary. But when I do dicts[0], there is the following error: 'type' object has no attribute '__getitem__' Do you want dict[0] ?? I think you want dicts[0] Sorry about that. dicts[0] gives me a KeyError: 0 -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
Here is my sample dict if that helps:
json = {1: {Status: Submitted, Startdate: [01/01/2011], Enddate:
[02/02/2012], Job_ID: 1, m_Quantile: 80, m_Controller: Python,
m_Method: Distributed, Allocation_3: [50], Allocation_2: [30],
Allocation_1: [20], Note: , m_Iterations: 1000, submit:
[Submit], VaR: , Asset_2: [YHOO], Asset_3: [CAT], Asset_1:
[AAPL]}, 3: {Status: Submitted, Startdate: [01/01/2011], Enddate:
[02/02/2012], Job_ID: 3, m_Quantile: 90, m_Controller: Python,
m_Method: Distributed, Allocation_3: [50], Allocation_2: [30],
Allocation_1: [20], Note: , m_Iterations: 1000, submit:
[Submit], VaR: , Asset_2: [YHOO], Asset_3: [CAT], Asset_1:
[AAPL]}, 2: {Status: Submitted, Startdate: [01/01/2011], Enddate:
[02/02/2012], Job_ID: 2, m_Quantile: 80, m_Controller: Python,
m_Method: GARCH, Allocation_3: [50], Allocation_2: [30],
Allocation_1: [20], No
te: , m_Iterations: 1000, submit: [Submit], VaR: , Asset_2:
[YHOO], Asset_3: [CAT], Asset_1: [AAPL]}, 4: {Status:
Submitted, Startdate: [01/01/2011], Enddate: [02/02/2012], Job_ID:
4, m_Quantile: 90, m_Controller: Python, m_Method: GARCH,
Allocation_3: [50], Allocation_2: [30], Allocation_1: [20], Note:
, m_Iterations: 1000, submit: [Submit], VaR: , Asset_2:
[YHOO], Asset_3: [CAT], Asset_1: [AAPL]}}
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Re: Parsing Python dictionary with multiple objects
On Wednesday, October 15, 2014 10:51:11 PM UTC+5:30, Anurag Patibandla wrote:
Here is my sample dict if that helps:
json = {1: {Status: Submitted, Startdate: [01/01/2011], Enddate:
[02/02/2012], Job_ID: 1, m_Quantile: 80, m_Controller: Python,
m_Method: Distributed, Allocation_3: [50], Allocation_2: [30],
Allocation_1: [20], Note: , m_Iterations: 1000, submit:
[Submit], VaR: , Asset_2: [YHOO], Asset_3: [CAT], Asset_1:
[AAPL]}, 3: {Status: Submitted, Startdate: [01/01/2011],
Enddate: [02/02/2012], Job_ID: 3, m_Quantile: 90, m_Controller:
Python, m_Method: Distributed, Allocation_3: [50], Allocation_2:
[30], Allocation_1: [20], Note: , m_Iterations: 1000, submit:
[Submit], VaR: , Asset_2: [YHOO], Asset_3: [CAT], Asset_1:
[AAPL]}, 2: {Status: Submitted, Startdate: [01/01/2011],
Enddate: [02/02/2012], Job_ID: 2, m_Quantile: 80, m_Controller:
Python, m_Method: GARCH, Allocation_3: [50], Allocation_2:
[30], Allocation_1: [20],
Note: , m_Iterations: 1000, submit: [Submit], VaR: , Asset_2:
[YHOO], Asset_3: [CAT], Asset_1: [AAPL]}, 4: {Status:
Submitted, Startdate: [01/01/2011], Enddate: [02/02/2012], Job_ID:
4, m_Quantile: 90, m_Controller: Python, m_Method: GARCH,
Allocation_3: [50], Allocation_2: [30], Allocation_1: [20], Note:
, m_Iterations: 1000, submit: [Submit], VaR: , Asset_2:
[YHOO], Asset_3: [CAT], Asset_1: [AAPL]}}
Right
So your dict (which is dicts !) we have
json.keys()
['1', '3', '2', '4']
And so
json[0]
Traceback (most recent call last):
File stdin, line 1, in module
KeyError: 0
json['0']
Traceback (most recent call last):
File stdin, line 1, in module
KeyError: '0'
json['1']
{'Status': 'Submitted', 'Startdate': ['01/01/2011'], 'Enddate': ['02/02/2012'],
'Job_ID': 1, 'm_Quantile': '80', 'Allocation_3': ['50'], 'm_Method':
'Distributed', 'm_Controller': 'Python', 'Allocation_2': ['30'],
'Allocation_1': ['20'], 'Asset_2': ['YHOO'], 'Note': '', 'VaR': '', 'submit':
['Submit'], 'm_Iterations': '1000', 'Asset_3': ['CAT'], 'Asset_1': ['AAPL']}
IOW 0 is not a key
Neither is '0' (the string containing the char 0)
But the string '1' is a valid key
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Re: Parsing Python dictionary with multiple objects
Anurag Patibandla anuragpatiband...@gmail.com Wrote in message:
Thanks for the response.
Here is the code that I have tried.
from operator import itemgetter
keys = json.keys()
order = list(keys)
q1 = int(round(len(keys)*0.2))
q2 = int(round(len(keys)*0.3))
q3 = int(round(len(keys)*0.5))
b = [q1,q2,q3]
n=0
threedicts = []
for i in b:
queues = order[n:n+i]
n = n+i
print queues
for j in range(len(queues)):
q = (queues[j], json.get(queues[j]))
print q
onedict = {}
for q in queues:
onedict[q] = json[q]
threedicts.append (onedict)
dict1, dictw, dict3 = threedicts
By this I am able to get the 3 smaller dicts I want, but can you help me
assign them to 3 variables?
The dicts need not be ordered but it would be better if they are ordered.
dicts are not ordered. If you want the items in a particular
order, you have to do that after extraction from the dict. There
is a related type called collections.OrderedDict, which
'remembers' the order things were added.
--
DaveA
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Re: Parsing Python dictionary with multiple objects
Anurag Patibandla anuragpatiband...@gmail.com Wrote in message: On Wednesday, October 15, 2014 1:10:41 PM UTC-4, Rustom Mody wrote: On Wednesday, October 15, 2014 10:30:49 PM UTC+5:30, Anurag Patibandla wrote: keys = json.keys() order = list(keys) q1 = int(round(len(keys)*0.2)) q2 = int(round(len(keys)*0.3)) q3 = int(round(len(keys)*0.5)) b = [q1,q2,q3] n=0 for i in b: queues = order[n:n+i] n = n+i lists = [(queues[j], json.get(queues[j])) for j in range(len(queues))] dicts = dict(lists) print dicts print dict[0] print dicts works as expected. It gives me the entire dictionary. But when I do dicts[0], there is the following error: 'type' object has no attribute '__getitem__' Do you want dict[0] ?? I think you want dicts[0] Sorry about that. dicts[0] gives me a KeyError: 0 If the keys are all strings, why would you expect to find any items with an int key? -- DaveA -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
Anurag Patibandla anuragpatiband...@gmail.com Wrote in message: dicts = dict(lists) print dicts print dict[0] Print dicts works as expected giving me the combine dictionary values. But when I say dict[0]. I see the error: TypeError: 'type' object has no attribute '__getitem__' Of course. You forgot the s in the name dicts. So you were referring to the dict class, not your variable. -- DaveA -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
On Wednesday, October 15, 2014 1:35:43 PM UTC-4, Rustom Mody wrote:
On Wednesday, October 15, 2014 10:51:11 PM UTC+5:30, Anurag Patibandla wrote:
Here is my sample dict if that helps:
json = {1: {Status: Submitted, Startdate: [01/01/2011],
Enddate: [02/02/2012], Job_ID: 1, m_Quantile: 80, m_Controller:
Python, m_Method: Distributed, Allocation_3: [50],
Allocation_2: [30], Allocation_1: [20], Note: , m_Iterations:
1000, submit: [Submit], VaR: , Asset_2: [YHOO], Asset_3:
[CAT], Asset_1: [AAPL]}, 3: {Status: Submitted, Startdate:
[01/01/2011], Enddate: [02/02/2012], Job_ID: 3, m_Quantile: 90,
m_Controller: Python, m_Method: Distributed, Allocation_3:
[50], Allocation_2: [30], Allocation_1: [20], Note: ,
m_Iterations: 1000, submit: [Submit], VaR: , Asset_2:
[YHOO], Asset_3: [CAT], Asset_1: [AAPL]}, 2: {Status:
Submitted, Startdate: [01/01/2011], Enddate: [02/02/2012],
Job_ID: 2, m_Quantile: 80, m_Controller: Python, m_Method:
GARCH, Allocation_3: [50], Allocation_2: [30], Allocation_1:
[20],
Note: , m_Iterations: 1000, submit: [Submit], VaR: ,
Asset_2: [YHOO], Asset_3: [CAT], Asset_1: [AAPL]}, 4: {Status:
Submitted, Startdate: [01/01/2011], Enddate: [02/02/2012], Job_ID:
4, m_Quantile: 90, m_Controller: Python, m_Method: GARCH,
Allocation_3: [50], Allocation_2: [30], Allocation_1: [20], Note:
, m_Iterations: 1000, submit: [Submit], VaR: , Asset_2:
[YHOO], Asset_3: [CAT], Asset_1: [AAPL]}}
Right
So your dict (which is dicts !) we have
json.keys()
['1', '3', '2', '4']
And so
json[0]
Traceback (most recent call last):
File stdin, line 1, in module
KeyError: 0
json['0']
Traceback (most recent call last):
File stdin, line 1, in module
KeyError: '0'
json['1']
{'Status': 'Submitted', 'Startdate': ['01/01/2011'], 'Enddate':
['02/02/2012'], 'Job_ID': 1, 'm_Quantile': '80', 'Allocation_3': ['50'],
'm_Method': 'Distributed', 'm_Controller': 'Python', 'Allocation_2': ['30'],
'Allocation_1': ['20'], 'Asset_2': ['YHOO'], 'Note': '', 'VaR': '', 'submit':
['Submit'], 'm_Iterations': '1000', 'Asset_3': ['CAT'], 'Asset_1': ['AAPL']}
IOW 0 is not a key
Neither is '0' (the string containing the char 0)
But the string '1' is a valid key
Yes, but I can't just do 'json['1']', at the end of the code I need to do a
'dicts['1']', or 'dicts['2']', to get the smaller dicts which still gives me a
'KeyError: 1'
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Re: Parsing Python dictionary with multiple objects
On Wednesday, October 15, 2014 1:41:13 PM UTC-4, Dave Angel wrote:
Anurag Patibandla anuragpatiband...@gmail.com Wrote in message:
Thanks for the response.
Here is the code that I have tried.
from operator import itemgetter
keys = json.keys()
order = list(keys)
q1 = int(round(len(keys)*0.2))
q2 = int(round(len(keys)*0.3))
q3 = int(round(len(keys)*0.5))
b = [q1,q2,q3]
n=0
threedicts = []
for i in b:
queues = order[n:n+i]
n = n+i
print queues
for j in range(len(queues)):
q = (queues[j], json.get(queues[j]))
print q
onedict = {}
for q in queues:
onedict[q] = json[q]
threedicts.append (onedict)
dict1, dictw, dict3 = threedicts
By this I am able to get the 3 smaller dicts I want, but can you help me
assign them to 3 variables?
The dicts need not be ordered but it would be better if they are ordered.
dicts are not ordered. If you want the items in a particular
order, you have to do that after extraction from the dict. There
is a related type called collections.OrderedDict, which
'remembers' the order things were added.
--
DaveA
Thanks DaveA!
This works perfectly!
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Re: Parsing Python dictionary with multiple objects
Anurag Patibandla anuragpatiband...@gmail.com Wrote in message:
On Wednesday, October 15, 2014 1:35:43 PM UTC-4, Rustom Mody wrote:
On Wednesday, October 15, 2014 10:51:11 PM UTC+5:30, Anurag Patibandla wrote:
Here is my sample dict if that helps:
json = {1: {Status: Submitted, Startdate: [01/01/2011],
Enddate: [02/02/2012], Job_ID: 1, m_Quantile: 80,
m_Controller: Python, m_Method: Distributed, Allocation_3:
[50], Allocation_2: [30], Allocation_1: [20], Note: ,
m_Iterations: 1000, submit: [Submit], VaR: , Asset_2:
[YHOO], Asset_3: [CAT], Asset_1: [AAPL]}, 3: {Status:
Submitted, Startdate: [01/01/2011], Enddate: [02/02/2012],
Job_ID: 3, m_Quantile: 90, m_Controller: Python, m_Method:
Distributed, Allocation_3: [50], Allocation_2: [30],
Allocation_1: [20], Note: , m_Iterations: 1000, submit:
[Submit], VaR: , Asset_2: [YHOO], Asset_3: [CAT], Asset_1:
[AAPL]}, 2: {Status: Submitted, Startdat
e: [01/01/2011], Enddate: [02/02/2012], Job_ID: 2, m_Quantile:
80, m_Controller: Python, m_Method: GARCH, Allocation_3: [50],
Allocation_2: [30], Allocation_1: [20],
Note: , m_Iterations: 1000, submit: [Submit], VaR: ,
Asset_2: [YHOO], Asset_3: [CAT], Asset_1: [AAPL]}, 4:
{Status: Submitted, Startdate: [01/01/2011], Enddate:
[02/02/2012], Job_ID: 4, m_Quantile: 90, m_Controller: Python,
m_Method: GARCH, Allocation_3: [50], Allocation_2: [30],
Allocation_1: [20], Note: , m_Iterations: 1000, submit:
[Submit], VaR: , Asset_2: [YHOO], Asset_3: [CAT], Asset_1:
[AAPL]}}
Right
So your dict (which is dicts !) we have
json.keys()
['1', '3', '2', '4']
And so
json[0]
Traceback (most recent call last):
File stdin, line 1, in module
KeyError: 0
json['0']
Traceback (most recent call last):
File stdin, line 1, in module
KeyError: '0'
json['1']
{'Status': 'Submitted', 'Startdate': ['01/01/2011'], 'Enddate':
['02/02/2012'], 'Job_ID': 1, 'm_Quantile': '80', 'Allocation_3': ['50'],
'm_Method': 'Distributed', 'm_Controller': 'Python', 'Allocation_2': ['30'],
'Allocation_1': ['20'], 'Asset_2': ['YHOO'], 'Note': '', 'VaR': '',
'submit': ['Submit'], 'm_Iterations': '1000', 'Asset_3': ['CAT'], 'Asset_1':
['AAPL']}
IOW 0 is not a key
Neither is '0' (the string containing the char 0)
But the string '1' is a valid key
Yes, but I can't just do 'json['1']', at the end of the code I need to do a
'dicts['1']', or 'dicts['2']', to get the smaller dicts which still gives me
a 'KeyError: 1'
Did you read the code I supplied, where you would wind up with
three variables, dict1, ict2, and dict3? Just before assigning
those, I had a LIST of dicts. Such a list can be accessed by
threedicts [0] to get the first dictionary, threedicts [1] to get
the next, etc.
--
DaveA
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Parsing Python dictionary with multiple objects
I have a dictionary that looks like this:
{1:{Key1:Value1, Key2:Value2, Key3:Value3},
2:{Key1:Value1, Key2:Value2, Key3:Value3},
3:{Key1:Value1, Key2:Value2, Key3:Value3},
4:{Key1:Value1, Key2:Value2, Key3:Value3}}
Now if I have 100 objects like these and I need to split them into 3 smaller
dicts in a ratio 2:3:5, how could I do that?
I tried using numpy.random.choice(), but it says it needs to be a 1-d array.
Can someone please help with this?
Thanks
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Re: Parsing Python dictionary with multiple objects
On Tuesday, October 14, 2014 12:59:27 PM UTC-4, Dave Angel wrote:
anuragpatiband...@gmail.com Wrote in message:
I have a dictionary that looks like this:
{1:{Key1:Value1, Key2:Value2, Key3:Value3},
2:{Key1:Value1, Key2:Value2, Key3:Value3},
3:{Key1:Value1, Key2:Value2, Key3:Value3},
4:{Key1:Value1, Key2:Value2, Key3:Value3}}
Now if I have 100 objects like these and I need to split them into 3
smaller dicts in a ratio 2:3:5, how could I do that?
I really have no idea what that means. You have 100 dicts of
dicts? Are the keys unique? If so, you could combine them with a
loop of update.
I tried using numpy.random.choice(), but it says it needs to be a 1-d array.
How about random.choice? It needs a sequence.
To get anything more concrete, you need to specify Python version,
and make a clearer problem statement, perhaps with example of
what you expect.
--
DaveA
Hey DaveA,
I am using Python 2.7.
Yes. I have a dict of dicts with keys ranging from 1..100
And the value of each of these keys is another dict. What I need to do is make
3 smaller dicts and assign the values of keys 1..100 in the ratio 2:3:5.
For example, if my original dict is
d={1:{Key1:Value1, Key2:Value2, Key3:Value3},
2:{Key1:Value1, Key2:Value2, Key3:Value3},
3:{Key1:Value1, Key2:Value2, Key3:Value3},
4:{Key1:Value1, Key2:Value2, Key3:Value3}}
...
...
100:{Key1:Value1, Key2:Value2, Key3:Value3}
I need to have three dicts d1, d2, d3 with d1 containing the values of first 20
keys, d2 containing the values on next 30 keys and d3 containing the values of
the next 50.
Can you please help me with this?
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Re: Parsing Python dictionary with multiple objects
Shuffle the keys, then grab the first 20 for one dictionary, the next 30 for the second, and the last 50 for the third. Skip -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
On Tuesday, October 14, 2014 5:33:01 PM UTC-4, Skip Montanaro wrote: Shuffle the keys, then grab the first 20 for one dictionary, the next 30 for the second, and the last 50 for the third. Skip Could you please be more specific? -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
On 2014-10-14 22:15, Anurag Patibandla wrote:
On Tuesday, October 14, 2014 12:59:27 PM UTC-4, Dave Angel wrote:
anuragpatiband...@gmail.com Wrote in message:
I have a dictionary that looks like this:
{1:{Key1:Value1, Key2:Value2, Key3:Value3},
2:{Key1:Value1, Key2:Value2, Key3:Value3},
3:{Key1:Value1, Key2:Value2, Key3:Value3},
4:{Key1:Value1, Key2:Value2, Key3:Value3}}
Now if I have 100 objects like these and I need to split them into 3 smaller
dicts in a ratio 2:3:5, how could I do that?
I really have no idea what that means. You have 100 dicts of
dicts? Are the keys unique? If so, you could combine them with a
loop of update.
I tried using numpy.random.choice(), but it says it needs to be a 1-d array.
How about random.choice? It needs a sequence.
To get anything more concrete, you need to specify Python version,
and make a clearer problem statement, perhaps with example of
what you expect.
Hey DaveA,
I am using Python 2.7.
Yes. I have a dict of dicts with keys ranging from 1..100
And the value of each of these keys is another dict. What I need to do is make
3 smaller dicts and assign the values of keys 1..100 in the ratio 2:3:5.
For example, if my original dict is
d={1:{Key1:Value1, Key2:Value2, Key3:Value3},
2:{Key1:Value1, Key2:Value2, Key3:Value3},
3:{Key1:Value1, Key2:Value2, Key3:Value3},
4:{Key1:Value1, Key2:Value2, Key3:Value3}}
...
...
100:{Key1:Value1, Key2:Value2, Key3:Value3}
I need to have three dicts d1, d2, d3 with d1 containing the values of first 20
keys, d2 containing the values on next 30 keys and d3 containing the values of
the next 50.
Can you please help me with this?
You can get a list of the entries using the dict's .items method. It's
then a simple matter of slicing the list.
Note that dicts aren't ordered, i.e. its keys aren't in a fixed order,
so if you want then in a particular order, you'll need to sort the list.
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Re: Parsing Python dictionary with multiple objects
On Wednesday, October 15, 2014 7:35:18 AM UTC+5:30, Dave Angel wrote:
anurag Wrote in message:
I have a dictionary that looks like this:
{1:{Key1:Value1, Key2:Value2, Key3:Value3},
2:{Key1:Value1, Key2:Value2, Key3:Value3},
3:{Key1:Value1, Key2:Value2, Key3:Value3},
4:{Key1:Value1, Key2:Value2, Key3:Value3}}
Now if I have 100 objects like these and I need to split them into 3
smaller dicts in a ratio 2:3:5, how could I do that?
I tried using numpy.random.choice(), but it says it needs to be a 1-d array.
What have you actually tried? You haven't shown any actual code.
Look up the method dict.keys, and see how you might use that. Then
look up random.shuffle, and see what it would do. Also look up
dict.sort, since your two messages on this thread imply two
conflicting goals as to which sub dictionaries should go in which
of your buckets.
As for extracting 20% of the keys, slicing is your answer. If
there are 100 keys, 20, 30, and 50 need to be sliced
off.
Then you'll need a loop to build each result dictionary from its keys.
There are shortcuts, but it's best to learn the fundamentals first.
Try writing the code. If it doesn't all work show us what you've
tried, and what you think is wrong. And when you get an
exception, show the whole traceback, don't just paraphrase one
of the lines.
Yes that is what is in general expected out here -- code --
maybe working, maybe not, maybe incomplete, maybe 'pseudo' etc
Then others here will improve it
However there is one conceptual thing that perhaps should be mentioned: order.
Is your data *essentially* ordered?
And by 'essentially' I mean you think of it independent of python.
Yeah in python dicts are unordered and lists are ordered and one can fudge
one to behave a bit like the other. But before you fudge, please ponder which
you really need/want.
Below a bit of going from one to other
# dict - list
d = {a:1,b:2,c:3}
d
{'a': 1, 'c': 3, 'b': 2}
list(d)
['a', 'c', 'b']
# alternate
d.keys()
['a', 'c', 'b']
d.items()
[('a', 1), ('c', 3), ('b', 2)]
d.values()
[1, 3, 2]
# list - dict
dict(d.items())
{'a': 1, 'c': 3, 'b': 2}
# round-tripping
dict(d.items()) == d
True
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Re: Parsing Python dictionary with multiple objects
Thanks for the response. Here is the code that I have tried. from operator import itemgetter keys = json.keys() order = list(keys) q1 = int(round(len(keys)*0.2)) q2 = int(round(len(keys)*0.3)) q3 = int(round(len(keys)*0.5)) b = [q1,q2,q3] n=0 for i in b: queues = order[n:n+i] n = n+i print queues for j in range(len(queues)): q = (queues[j], json.get(queues[j])) print q By this I am able to get the 3 smaller dicts I want, but can you help me assign them to 3 variables? The dicts need not be ordered but it would be better if they are ordered. Thanks -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
'json' has my original larger dict -- https://mail.python.org/mailman/listinfo/python-list
Re: Parsing Python dictionary with multiple objects
On Wednesday, October 15, 2014 9:10:54 AM UTC+5:30, Anurag Patibandla wrote: Thanks for the response. Here is the code that I have tried. from operator import itemgetter keys = json.keys() order = list(keys) q1 = int(round(len(keys)*0.2)) q2 = int(round(len(keys)*0.3)) q3 = int(round(len(keys)*0.5)) b = [q1,q2,q3] n=0 for i in b: queues = order[n:n+i] n = n+i print queues for j in range(len(queues)): q = (queues[j], json.get(queues[j])) print q Converting the end for loop (last 3 lines) into: print [(queues[j], json.get(queues[j])) for j in range(len(queues))] Does that help? General advice: 1. Instead of writing 'naked' code as you have done, if you wrap it into functions (preferably small) 2. Contents similar to the original naked code but with print's replaced by return's you make your as well as those trying to help/collaborate with you life easier Also the above is a more or mechanical translation. However something[j] ... for j in range(len(something)) is usually a sign of a C programmer writing python :-) Usually better to write x for x in something So... Better to write that comprehension as print [(q, json.get(q)) for q in queues] -- https://mail.python.org/mailman/listinfo/python-list
