Re: Format Code Repeat Counts?
Thanks all! That was most helpful and informative. Best, Josiah -- http://mail.python.org/mailman/listinfo/python-list
Re: Format Code Repeat Counts?
Scott David Daniels wrote: MRAB wrote: The shortest I can come up with is: [ + ][.join(letters) + ] Maybe a golf shot: ][.join(letters).join([]) Even shorter: [+][.join(letters)+] :-) -- http://mail.python.org/mailman/listinfo/python-list
Re: Format Code Repeat Counts?
MRAB wrote: Scott David Daniels wrote: MRAB wrote: The shortest I can come up with is: [ + ][.join(letters) + ] Maybe a golf shot: ][.join(letters).join([]) Even shorter: [+][.join(letters)+] :-) I was going by PEP8 rules. ;-) --Scott David Daniels Scott David dani...@acm.org -- http://mail.python.org/mailman/listinfo/python-list
Re: Format Code Repeat Counts?
MRAB wrote: The shortest I can come up with is: [ + ][.join(letters) + ] Maybe a golf shot: ][.join(letters).join([]) --Scott David Daniels scott.dani...@acm.org -- http://mail.python.org/mailman/listinfo/python-list
Re: Format Code Repeat Counts?
jschwab wrote:
Are repeat counts supported Python's str.format() in some fashion?
In Fortran my format strings can have repeat counts.
pseudocode
write(*, fmt=3F8.3) [1, 2, 3]
1.000 2.000 3.000
/pseudocode
I don't think printf-style format codes, which is what'd I'd
previously used in Python, allow for repeat counts.
As a more concrete example, say I have several sets of letters in a
list of strings
letters = [aeiou, hnopty, egs, amsp]
and I wanted to build a regular expression string out of them like
re_str == [aeiou][hnopty][egs][amsp]
Right now, the best I've got that doesn't require an explicit string
like [{1}][{2}][{3}][{4}] is
re_str = .join(map(lambda x: [{0}].format(x), letters))
Is there a better way?
The shortest I can come up with is:
[ + ][.join(letters) + ]
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Re: Format Code Repeat Counts?
On Wed, Aug 12, 2009 at 4:34 PM, jschwabjsch...@gmail.com wrote:
snip
As a more concrete example, say I have several sets of letters in a
list of strings
letters = [aeiou, hnopty, egs, amsp]
and I wanted to build a regular expression string out of them like
re_str == [aeiou][hnopty][egs][amsp]
Right now, the best I've got that doesn't require an explicit string
like [{1}][{2}][{3}][{4}] is
re_str = .join(map(lambda x: [{0}].format(x), letters))
Is there a better way?
Slightly better, by using a generator expression instead of map() and lambda:
re_str = .join([{0}].format(x) for x in letters)
Though obviously MRAB's is shorter (and a good show of lateral thinking).
Cheers,
Chris
--
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--
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Re: Format Code Repeat Counts?
Chris Rebert wrote:
On Wed, Aug 12, 2009 at 4:34 PM, jschwabjsch...@gmail.com wrote:
snip
As a more concrete example, say I have several sets of letters in a
list of strings
letters = [aeiou, hnopty, egs, amsp]
and I wanted to build a regular expression string out of them like
re_str == [aeiou][hnopty][egs][amsp]
Right now, the best I've got that doesn't require an explicit string
like [{1}][{2}][{3}][{4}] is
re_str = .join(map(lambda x: [{0}].format(x), letters))
Is there a better way?
Slightly better, by using a generator expression instead of map() and lambda:
re_str = .join([{0}].format(x) for x in letters)
Though obviously MRAB's is shorter (and a good show of lateral thinking).
Python 3.1 supports auto-numbered placeholders [{}], so:
re_str = ([{}] * len(letters)).format(*letters)
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Re: Format Code Repeat Counts?
On 8/12/2009 1:34 PM jschwab said...
Are repeat counts supported Python's str.format() in some fashion?
In Fortran my format strings can have repeat counts.
pseudocode
write(*, fmt=3F8.3) [1, 2, 3]
1.000 2.000 3.000
/pseudocode
I don't think printf-style format codes, which is what'd I'd
previously used in Python, allow for repeat counts.
As a more concrete example, say I have several sets of letters in a
list of strings
letters = [aeiou, hnopty, egs, amsp]
and I wanted to build a regular expression string out of them like
re_str == [aeiou][hnopty][egs][amsp]
Right now, the best I've got that doesn't require an explicit string
like [{1}][{2}][{3}][{4}] is
re_str = .join(map(lambda x: [{0}].format(x), letters))
Is there a better way?
I don't know. I often end up at something like:
[%s]*len(letters) % tuple(letters)
Emile
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Re: Format Code Repeat Counts?
En Wed, 12 Aug 2009 19:23:32 -0300, Chris Rebert c...@rebertia.com
escribió:
On Wed, Aug 12, 2009 at 4:34 PM, jschwabjsch...@gmail.com wrote:
snip
As a more concrete example, say I have several sets of letters in a
list of strings
letters = [aeiou, hnopty, egs, amsp]
and I wanted to build a regular expression string out of them like
re_str == [aeiou][hnopty][egs][amsp]
Right now, the best I've got that doesn't require an explicit string
like [{1}][{2}][{3}][{4}] is
re_str = .join(map(lambda x: [{0}].format(x), letters))
Is there a better way?
Slightly better, by using a generator expression instead of map() and
lambda:
re_str = .join([{0}].format(x) for x in letters)
Though obviously MRAB's is shorter (and a good show of lateral thinking).
Another way, using {} auto-numbering (requires Python 3.1 or the future
2.7)
p3 letters = [aeiou, hnopty, egs, amsp]
p3 ([{}]*len(letters)).format(*letters)
'[aeiou][hnopty][egs][amsp]'
--
Gabriel Genellina
--
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