Re: Question about isinstance()

2006-01-27 Thread Rene Pijlman
Marc 'BlackJack' Rintsch:
>Rene Pijlman:
>> Well no, when comparing against things you didn't think of the __eq__
>> shouldn't return a false False, it should return NotImplemented. After
>> all, the things you didn't think of are not (yet) implemented.
>
>I think Steven thinks that it is possible that you compare to an object of
>a different type which has the same attributes as expected by the
>`__eq__()` method.  If the first test is `isinstance()` for the "correct"
>type you rule out those cases and give a false `False`.

Like I said, it wouldn't return False, it would return NotImplemented.

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Re: Question about isinstance()

2006-01-27 Thread Marc 'BlackJack' Rintsch
In <[EMAIL PROTECTED]>, Rene Pijlman wrote:

> Steven D'Aprano:
>>Rene Pijlman:
>>> Mr.Rech:
   def __eq__(self, other):
  try:
 return self.an_attribute == other.an_attribute
  except AttributeError:
 return False
>>> 
>>> This may give unexpected results when you compare a foo with an instance
>>> of a completely different type that happens to have an attribute called
>>> 'an_attribute'.
>>
>>That's a trade-off, isn't it?
>>
>>On the one hand, you risk false negatives, by refusing to compare against
>>things you didn't think of. 
> 
> Well no, when comparing against things you didn't think of the __eq__
> shouldn't return a false False, it should return NotImplemented. After
> all, the things you didn't think of are not (yet) implemented.

I think Steven thinks that it is possible that you compare to an object of
a different type which has the same attributes as expected by the
`__eq__()` method.  If the first test is `isinstance()` for the "correct"
type you rule out those cases and give a false `False`.

Ciao,
Marc 'BlackJack' Rintsch
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Re: Question about isinstance()

2006-01-27 Thread Rene Pijlman
Magnus Lycka:
>isinstance() wouldn't be in Python if you weren't supposed to use it,

If this argument was correct, 'goto' wouldn't be in Pascal :-)

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Re: Question about isinstance()

2006-01-27 Thread Magnus Lycka
Mr.Rech wrote:
> Hi all,
> I've read some thread about isinstance(), why it is considered harmful
> and how you can achieve the same results using a coding style that
> doesn't break polymorphism etc... Since I'm trying to improve my Python
> knowledge, and I'm going to design a class hierarchy from scratch, I'd
> like to have some feedback about this from those of you much more
> experienced than me in OOP.
[snip]
> Any better way to write this method? Any suggestion?

It's really impossible to tell what's good Python code
based on details like this. isinstance() wouldn't be in
Python if you weren't supposed to use it, but you need to
understand when you should limit your functions to work
with a specific kind of data, and when you should try to
be broader. This is a design decision that will influence
the usability and maintainability of your code. We can't
help you figure out how to make such trade-offs based on
your implementation of __eq__.
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Re: Question about isinstance()

2006-01-27 Thread bruno at modulix
bruno at modulix wrote:
> Dave Benjamin wrote:
> (snip)
> 
> 
>>You *could* have "b.__eq__" just call "a.__eq__", 
> 
> 
> Which could lead to strange results (well, actually a good ole infinite
> recursion) if b.__eq__ happens to call b.__eq__ too !-)

I meant:

'if a.__eq__ happens to call b.__eq__ too'

of course...



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Re: Question about isinstance()

2006-01-27 Thread Rene Pijlman
Steven D'Aprano:
>Rene Pijlman:
>> Mr.Rech:
>>>   def __eq__(self, other):
>>>  try:
>>> return self.an_attribute == other.an_attribute
>>>  except AttributeError:
>>> return False
>> 
>> This may give unexpected results when you compare a foo with an instance
>> of a completely different type that happens to have an attribute called
>> 'an_attribute'.
>
>That's a trade-off, isn't it?
>
>On the one hand, you risk false negatives, by refusing to compare against
>things you didn't think of. 

Well no, when comparing against things you didn't think of the __eq__
shouldn't return a false False, it should return NotImplemented. After
all, the things you didn't think of are not (yet) implemented.

"A rich comparison method may return NotImplemented if it does not
implement the operation for a given pair of arguments."
http://www.python.org/doc/ref/customization.html

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Re: Question about isinstance()

2006-01-27 Thread Mr.Rech
bruno at modulix wrote:
> Mr.Rech wrote:
> > All in all it seems that the implementation that uses isinstance() is
> > better in this case...
>
> You could also use something like Zope's Interfaces... But I'm not sure
> it's worth the extra complexity.

Thanks for your suggestion, but it's not worth the extra complexity at
all.

I've read something about interfaces, but my project will be a
small/middle sized one, and using such a sophisticated tool it would be
like using a cannon to shoot a sparrow (as we are used to say here in
Italy).

Anyway thanks again for your comments.

 Andrea

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Re: Question about isinstance()

2006-01-27 Thread bruno at modulix
Mr.Rech wrote:
> All in all it seems that the implementation that uses isinstance() is
> better in this case...

You could also use something like Zope's Interfaces... But I'm not sure
it's worth the extra complexity.

-- 
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p in '[EMAIL PROTECTED]'.split('@')])"
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Re: Question about isinstance()

2006-01-27 Thread bruno at modulix
Dave Benjamin wrote:
(snip)

> You *could* have "b.__eq__" just call "a.__eq__", 

Which could lead to strange results (well, actually a good ole infinite
recursion) if b.__eq__ happens to call b.__eq__ too !-)


-- 
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p in '[EMAIL PROTECTED]'.split('@')])"
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Re: Question about isinstance()

2006-01-27 Thread Mr.Rech
After reading all your comments and thinking a little to my specific
case, I think it is definetively better to go with the "isinstance()"
implementation. My objects represent mathematical function defined over
a numerical grid, and I hardly think of an unrelated class objects that
could be compared with them in a meaningfull way.

Thanks again to all of you for helping me to better understand another
piece of the Python's world. ;-)

 Andrea

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Re: Question about isinstance()

2006-01-26 Thread Rocco Moretti
Mr.Rech wrote:
> All in all it seems that the implementation that uses isinstance() is
> better in this case...

Well what's "better" depends on what you want to happen when you compare 
an unrelated class that also defines 'an_attribute'. Unlike in 
statically typed languages, certain things are made easier when you 
don't check for strict inheritance (like mock and proxy objects). Google 
"Duck Typing" for more info.
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Re: Question about isinstance()

2006-01-26 Thread Steven D'Aprano
On Thu, 26 Jan 2006 19:04:13 +0100, Rene Pijlman wrote:

> Mr.Rech:
>>Now, avoiding isinstace() I've written the following code:
>>
>>class foo(object):
>>   ...
>>   def __eq__(self, other):
>>  try:
>> return self.an_attribute == other.an_attribute
>>  except AttributeError:
>> return False
> 
> This may give unexpected results when you compare a foo with an instance
> of a completely different type that happens to have an attribute called
> 'an_attribute'.


That's a trade-off, isn't it?


On the one hand, you risk false negatives, by refusing to compare against
things you didn't think of. On the other hand, you risk false positives,
by comparing against more generic objects.

I guess that trade-off is one each programmer must decide for herself, in
full understanding of the pros and cons of each method.


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Re: Question about isinstance()

2006-01-26 Thread Mr.Rech
All in all it seems that the implementation that uses isinstance() is
better in this case...

Thanks for your comments,
 Andrea.

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Re: Question about isinstance()

2006-01-26 Thread Dave Benjamin
On Thu, 26 Jan 2006, Dave Benjamin wrote:

> On Thu, 26 Jan 2006, Rocco Moretti wrote:
>
>>> You were better off with what you had before. Equality in this case is 
>>> left completely open-ended, and as a result, there is no way that you can 
>>> guarantee that "a == b" is the same as "b == a" if "a" is a "foo" and "b" 
>>> is of unknown type. This can lead to bizarre and unpredictable behavior.
>> 
>> Mind explaining that better? b == a *always* calls b.__eq__(a), if it 
>> exists. What a.__eq__(b) is doesn't matter at that point. So you have the 
>> same problems either way.
>
> Right, but we don't know what "b.__eq__" does, since "b" could be anything, 
> if it exists at all. So, it's quite possible that "a == b", since "a.__eq__"
   ^^^

By "it" here, I mean "b.__eq__".
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Re: Question about isinstance()

2006-01-26 Thread Dave Benjamin
On Thu, 26 Jan 2006, Rocco Moretti wrote:

>> You were better off with what you had before. Equality in this case is left 
>> completely open-ended, and as a result, there is no way that you can 
>> guarantee that "a == b" is the same as "b == a" if "a" is a "foo" and "b" 
>> is of unknown type. This can lead to bizarre and unpredictable behavior.
>
> Mind explaining that better? b == a *always* calls b.__eq__(a), if it exists. 
> What a.__eq__(b) is doesn't matter at that point. So you have the same 
> problems either way.

Right, but we don't know what "b.__eq__" does, since "b" could be 
anything, if it exists at all. So, it's quite possible that "a == b", 
since "a.__eq__" is defined and only depends on "b" having an 
attribute named "an_attribute", but "b == a" is:

   a) an error
   b) false, even though "a == b" is true

If we control the class of "a" and the class of "b", we can ensure that 
the two "__eq__" methods behave identically. The problem is that, in the 
supposed interest of "polymorphism" we are relaxing the dependency on 
"a.__eq__"'s parameter so that it can be any class with "an_attribute". 
This implies that we would like other classes besides those we control to 
be able to participate in equality tests with the class of "a". However, 
to do this properly, we need to be able to modify *both classes*, or we 
will have inconsistent results depending on whether we say "a == b" or
"b == a". It is reasonable to expect that these two expressions produce 
the same result, isn't it?

> The only difference between the two is in the case where b is of an unrelated 
> class and b.an_attribute exists (1). In this case, the first always returns 
> False, and the second returns (a.an_attribute == b.an_attribute). Which you 
> prefer depends on how strictly you adhere to  duck typing.

I don't think duck typing buys you anything valuable here. The usual 
flexibility of duck typing is lost because of the symmetric nature of 
equality; all participating classes need to be involved to guarantee 
correctness. You *could* have "b.__eq__" just call "a.__eq__", but once 
again this assumes we have control over the implementation of "b".

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Re: Question about isinstance()

2006-01-26 Thread Rocco Moretti
Dave Benjamin wrote:
> On Thu, 26 Jan 2006, Mr.Rech wrote:
> 
>> Suppose I'm writing a base class with an __eq__ special methods, using
>> isinstance() I would have wrote:
>> 
>> class foo(object):
>>...
>>def __eq__(self, other):
>>   return isinstance(other, type(self)) and self.an_attribute ==
>> other.an__attribute

>> Now, avoiding isinstace() I've written the following code:
>>
>> class foo(object):
>>   ...
>>   def __eq__(self, other):
>>  try:
>> return self.an_attribute == other.an_attribute
>>  except AttributeError:
>> return False
> 
> 
> You were better off with what you had before. Equality in this case is 
> left completely open-ended, and as a result, there is no way that you 
> can guarantee that "a == b" is the same as "b == a" if "a" is a "foo" 
> and "b" is of unknown type. This can lead to bizarre and unpredictable 
> behavior.

Mind explaining that better? b == a *always* calls b.__eq__(a), if it 
exists. What a.__eq__(b) is doesn't matter at that point. So you have 
the same problems either way.

The only difference between the two is in the case where b is of an 
unrelated class and b.an_attribute exists (1). In this case, the first 
always returns False, and the second returns (a.an_attribute == 
b.an_attribute). Which you prefer depends on how strictly you adhere to 
  duck typing.

(1) To be honest, they also vary when a.an_attribute is undefined. The 
second always returns False, and the first raises an AttributeError.
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Re: Question about isinstance()

2006-01-26 Thread Dave Benjamin
On Thu, 26 Jan 2006, Mr.Rech wrote:

> I've read some thread about isinstance(), why it is considered harmful
> and how you can achieve the same results using a coding style that
> doesn't break polymorphism etc... Since I'm trying to improve my Python
> knowledge, and I'm going to design a class hierarchy from scratch, I'd
> like to have some feedback about this from those of you much more
> experienced than me in OOP.

When trying to write OO code, you should of course always be suspicious of 
any use of "isinstance". However, it is not always "considered harmful", 
and this is one case where it is perfectly reasonable.

> Now, avoiding isinstace() I've written the following code:
>
> class foo(object):
>   ...
>   def __eq__(self, other):
>  try:
> return self.an_attribute == other.an_attribute
>  except AttributeError:
> return False

You were better off with what you had before. Equality in this case is 
left completely open-ended, and as a result, there is no way that you can 
guarantee that "a == b" is the same as "b == a" if "a" is a "foo" and "b" 
is of unknown type. This can lead to bizarre and unpredictable behavior.

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Re: Question about isinstance()

2006-01-26 Thread Mr.Rech
Mmm... I've not considered such an event... Would you say it is one of
those rare case in which isinstance() "can be used"? Any other
suggestion?

Thanks,
 Andrea

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Re: Question about isinstance()

2006-01-26 Thread Rene Pijlman
Mr.Rech:
>Now, avoiding isinstace() I've written the following code:
>
>class foo(object):
>   ...
>   def __eq__(self, other):
>  try:
> return self.an_attribute == other.an_attribute
>  except AttributeError:
> return False

This may give unexpected results when you compare a foo with an instance
of a completely different type that happens to have an attribute called
'an_attribute'.

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