Regexp problem when parsing a string
I'm a beginner and I was trying to write a program to parse recursively all file names in a directory specified as parameter. The problem is that I get a None printed to stdout when a file is positively matched. While when the file name doesn't match the regexp the output seems ok. C:\c:\python.exe g:\a.py sample foo - bar.txt , first part is: foo None skipping: foo.txt Instead I expect an output like this one: C:\c:\python.exe g:\a.py sample foo - bar.txt , first part is: foo None skipping: foo.txt Could anyone help me to figure out why None appears in the putput? Thanks and regards, Ale a.py Description: Binary data -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem when parsing a string
On Sun, 21 Mar 2010 19:12:18 +0100, Alessandro Marino wrote: Could anyone help me to figure out why None appears in the putput? I get: Attachment not shown: MIME type application/octet-stream; filename a.py Posting attachments to Usenet is tricky. Many newsgroups filter out anything they think isn't text, or even any attachment at all. Some news clients do the same thing. If you have too much code to include directly in your post, then you should put it up on a website somewhere and just include the link. Without looking at your code, I'd guess that using regular expressions is the wrong approach. Perhaps you should look at the glob module, and possibly os.walk. -- Steven -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem when parsing a string
Alessandro Marino wrote: I'm a beginner and I was trying to write a program to parse recursively all file names in a directory specified as parameter. The problem is that I get a None printed to stdout when a file is positively matched. While when the file name doesn't match the regexp the output seems ok. C:\c:\python.exe g:\a.py sample foo - bar.txt , first part is: foo None skipping: foo.txt Instead I expect an output like this one: C:\c:\python.exe g:\a.py sample foo - bar.txt , first part is: foo None skipping: foo.txt Could anyone help me to figure out why None appears in the putput? Thanks and regards, Ale It's caused by: print saveData(file, m) The function saveData() returns None, which is then printed. -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem
MRAB wrote: Ethan Furman wrote: Marcus Wanner wrote: Wow, I really need to learn more about regexp... Any tutorials you guys can recommend? Marcus Mastering Regular Expressions Powerful Techniques for Perl and Other Tools By Jeffrey E. F. Friedl Great book! +1 I have the first edition, seventh printing (December 1998). It refers to the 'regex' module of Python 1.4b1, which was subsequently replaced by the current 're' module and then removed from the standard library. I hope it's been updated since then. :-) I have the second edition (no idea which printing ;), and according to his preface it has indeed been much updated. Most examples are in perl, the few in python are decent. The knowledge embodied seems very thorough. Since I've had the book (two weeks now?) I've been able to solve two otherwise thorny issues using regular expressions. Yay! ~Ethan~ -- http://mail.python.org/mailman/listinfo/python-list
Regexp problem
Hi there! I have a problem and i'm not very good at regular expressions. I have a text like lalala lalala tiruri beldar-is-listening tiruri lalala I need a regexp to get the 'beldar' part, the format is 'something-is-listening', i need to get the something part, use it in my code, and then replace the whole 'something-is-listening' for another string. Someone can help me please? Thank you! -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem
I have a problem and i'm not very good at regular expressions.
I have a text like lalala lalala tiruri beldar-is-listening tiruri
lalala I need a regexp to get the 'beldar' part, the format is
'something-is-listening', i need to get the something part, use it in
my code, and then replace the whole 'something-is-listening' for
another string.
Pretty easy:
import re
s = lalala lalala tiruri beldar-is-listening tiruri lalala
r = re.compile(r'(\w+)-is-listening')
r.search(s).group(1)
'beldar'
r.sub('this is a replacement', s)
'lalala lalala tiruri this is a replacement tiruri lalala'
-tkc
--
http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem
Beldar wrote: Hi there! I have a problem and i'm not very good at regular expressions. I have a text like lalala lalala tiruri beldar-is-listening tiruri lalala I need a regexp to get the 'beldar' part, the format is 'something-is-listening', i need to get the something part, use it in my code, and then replace the whole 'something-is-listening' for another string. \w+ will match a word and enclosing it in (...) will capture what was matched: m = re.search(r(\w+)-is-listening, text) print Captured '%s' % m.group(1) print Matched from %d to %d % (m.start(), m.end()) -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem
On 30 jul, 15:07, MRAB pyt...@mrabarnett.plus.com wrote: Beldar wrote: Hi there! I have a problem and i'm not very good at regular expressions. I have a text like lalala lalala tiruri beldar-is-listening tiruri lalala I need a regexp to get the 'beldar' part, the format is 'something-is-listening', i need to get the something part, use it in my code, and then replace the whole 'something-is-listening' for another string. \w+ will match a word and enclosing it in (...) will capture what was matched: m = re.search(r(\w+)-is-listening, text) print Captured '%s' % m.group(1) print Matched from %d to %d % (m.start(), m.end()) Ok, thank you all, it was very helpful! -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem
On 7/30/2009 9:32 AM, Beldar wrote: On 30 jul, 15:07, MRAB pyt...@mrabarnett.plus.com wrote: Beldar wrote: Hi there! I have a problem and i'm not very good at regular expressions. I have a text like lalala lalala tiruri beldar-is-listening tiruri lalala I need a regexp to get the 'beldar' part, the format is 'something-is-listening', i need to get the something part, use it in my code, and then replace the whole 'something-is-listening' for another string. \w+ will match a word and enclosing it in (...) will capture what was matched: m = re.search(r(\w+)-is-listening, text) print Captured '%s' % m.group(1) print Matched from %d to %d % (m.start(), m.end()) Ok, thank you all, it was very helpful! Wow, I really need to learn more about regexp... Any tutorials you guys can recommend? Marcus -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem
Marcus Wanner marc...@cox.net writes: On 7/30/2009 9:32 AM, Beldar wrote: On 30 jul, 15:07, MRAB pyt...@mrabarnett.plus.com wrote: Beldar wrote: Hi there! I have a problem and i'm not very good at regular expressions. I have a text like lalala lalala tiruri beldar-is-listening tiruri lalala I need a regexp to get the 'beldar' part, the format is 'something-is-listening', i need to get the something part, use it in my code, and then replace the whole 'something-is-listening' for another string. \w+ will match a word and enclosing it in (...) will capture what was matched: m = re.search(r(\w+)-is-listening, text) print Captured '%s' % m.group(1) print Matched from %d to %d % (m.start(), m.end()) Ok, thank you all, it was very helpful! Wow, I really need to learn more about regexp... Any tutorials you guys can recommend? I have to confess that after fiddling with regexps for quite a while with no great success, I learnt the hard (and best) way, i.e. using them to write something vile and horrible. [*] I commend this path to you also. ;-) Cheers, Peter [*] http://git.gpleda.org/?p=gaf.git;a=blob;f=libgeda/desktop-i18n;h=6fab9b85b -- Peter Brett pe...@peter-b.co.uk Remote Sensing Research Group Surrey Space Centre -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem
Marcus Wanner wrote: On 7/30/2009 9:32 AM, Beldar wrote: On 30 jul, 15:07, MRAB pyt...@mrabarnett.plus.com wrote: Beldar wrote: Hi there! I have a problem and i'm not very good at regular expressions. I have a text like lalala lalala tiruri beldar-is-listening tiruri lalala I need a regexp to get the 'beldar' part, the format is 'something-is-listening', i need to get the something part, use it in my code, and then replace the whole 'something-is-listening' for another string. \w+ will match a word and enclosing it in (...) will capture what was matched: m = re.search(r(\w+)-is-listening, text) print Captured '%s' % m.group(1) print Matched from %d to %d % (m.start(), m.end()) Ok, thank you all, it was very helpful! Wow, I really need to learn more about regexp... Any tutorials you guys can recommend? Marcus Mastering Regular Expressions Powerful Techniques for Perl and Other Tools By Jeffrey E. F. Friedl Great book! ~Ethan~ -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem
Ethan Furman wrote: Marcus Wanner wrote: On 7/30/2009 9:32 AM, Beldar wrote: On 30 jul, 15:07, MRAB pyt...@mrabarnett.plus.com wrote: Beldar wrote: Hi there! I have a problem and i'm not very good at regular expressions. I have a text like lalala lalala tiruri beldar-is-listening tiruri lalala I need a regexp to get the 'beldar' part, the format is 'something-is-listening', i need to get the something part, use it in my code, and then replace the whole 'something-is-listening' for another string. \w+ will match a word and enclosing it in (...) will capture what was matched: m = re.search(r(\w+)-is-listening, text) print Captured '%s' % m.group(1) print Matched from %d to %d % (m.start(), m.end()) Ok, thank you all, it was very helpful! Wow, I really need to learn more about regexp... Any tutorials you guys can recommend? Marcus Mastering Regular Expressions Powerful Techniques for Perl and Other Tools By Jeffrey E. F. Friedl Great book! +1 I have the first edition, seventh printing (December 1998). It refers to the 'regex' module of Python 1.4b1, which was subsequently replaced by the current 're' module and then removed from the standard library. I hope it's been updated since then. :-) -- http://mail.python.org/mailman/listinfo/python-list
Re: regexp problem in Python
On Aug 3, 10:41 pm, Ehsan [EMAIL PROTECTED] wrote: ... what can I do? what's wrong whit this pattern? thanx for your comments Nothing. There's something wrong with the code you are using the regex with. Post it and we may be able to help. Like Lawrence has said, it's likely to be that you are using m.group(1) with your match object instead of m.group(0) - the former gets the first group (i.e. everything between the first set of parens - in your case the wmv|3gp expression), whereas the latter will return the entire match. Post your actual code, not just the regex. -- Ant... http://antroy.blogspot.com/ -- http://mail.python.org/mailman/listinfo/python-list
Re: regexp problem in Python
In message [EMAIL PROTECTED], Ehsan wrote: I use this pattern : http.*?\.(wmv|3gp).* but it returns only 'wmv' and '3gp' instead of http://www.2shared.com/ download/1716611/e2000f22/Jadeed_Mlak14.wmv? tsid=20070803-164051-9d637d11 What's the actual Python code that uses this regexp? My guess is, you're not using the group method correctly in the returned match object http://docs.python.org/lib/match-objects.html. -- http://mail.python.org/mailman/listinfo/python-list
Re: regexp problem in Python
On 4 A ustos, 00:41, Ehsan [EMAIL PROTECTED] wrote:
I want to find http://www.2shared.com/download/1716611/e2000f22/
Jadeed_Mlak14.wmv?tsid=20070803-164051-9d637d11 or 3gp instead of
wmv in the text file like this :
html
some code
function reportAbuse() {
var windowname=abuse;
var url=/abuse.jsp?link= + http://www.2shared.com/file/1716611/
e2000f22/Jadeed_Mlak14.html;
OpenWindow =
window.open(url,windowname,'toolbar=no,scrollbars=no,resizable=no,width=500,height=500,left=50,top=50');
OpenWindow.focus();
}
function startDownload(){
window.location = http://www.2shared.com/download/1716611/
e2000f22/Jadeed_Mlak14.wmv?tsid=20070803-164051-9d637d11;
//document.downloadForm.submit();
}
/script
/head
/htmlhttp://www.2shared.com/download/1716611/e2000f22/
Jadeed_Mlak14.3gp?tsid=20070803-164051-9d637d11sfgsfgsfgv
I use this pattern :
http.*?\.(wmv|3gp).*
but it returns only 'wmv' and '3gp' instead of http://www.2shared.com/
download/1716611/e2000f22/Jadeed_Mlak14.wmv?
tsid=20070803-164051-9d637d11
what can I do? what's wrong whit this pattern? thanx for your comments
You could use r'window.location = (.*?\.(wmv|3gp);' as your regex
string, I guess..
--
http://mail.python.org/mailman/listinfo/python-list
Re: regexp problem in Python
On Aug 4, 1:22 pm, Sönmez Kartal [EMAIL PROTECTED] wrote:
On 4 A ustos, 00:41, Ehsan [EMAIL PROTECTED] wrote:
I want to find http://www.2shared.com/download/1716611/e2000f22/
Jadeed_Mlak14.wmv?tsid=20070803-164051-9d637d11 or 3gp instead of
wmv in the text file like this :
html
some code
function reportAbuse() {
var windowname=abuse;
var url=/abuse.jsp?link= + http://www.2shared.com/file/1716611/
e2000f22/Jadeed_Mlak14.html;
OpenWindow =
window.open(url,windowname,'toolbar=no,scrollbars=no,resizable=no,width=500,height=500,left=50,top=50');
OpenWindow.focus();
}
function startDownload(){
window.location = http://www.2shared.com/download/1716611/
e2000f22/Jadeed_Mlak14.wmv?tsid=20070803-164051-9d637d11;
//document.downloadForm.submit();
}
/script
/head
/htmlhttp://www.2shared.com/download/1716611/e2000f22/
Jadeed_Mlak14.3gp?tsid=20070803-164051-9d637d11sfgsfgsfgv
I use this pattern :
http.*?\.(wmv|3gp).*
but it returns only 'wmv' and '3gp' instead of http://www.2shared.com/
download/1716611/e2000f22/Jadeed_Mlak14.wmv?
tsid=20070803-164051-9d637d11
what can I do? what's wrong whit this pattern? thanx for your comments
You could use r'window.location = (.*?\.(wmv|3gp);' as your regex
string, I guess..- Hide quoted text -
- Show quoted text -
I didn't get what do you mean? i think i must just change the pattern
but I don't know how to find bestfit pattern
--
http://mail.python.org/mailman/listinfo/python-list
Re: regexp problem in Python
Il Fri, 03 Aug 2007 14:41:52 -0700, Ehsan ha scritto:
maybe you can use this to solve your prob:
myurl = http://www.2shared.com/download/1716611/e2000f22/
Jadeed_Mlak14.wmv?tsid=20070803-164051-9d637d11
if myurl.startswith('http') and ('wmv' in myurl or '3pg' in myurl):
# myurl is the complete address you want
print myurl
#
about re, I'm waiting for someone enlightening all us,
bye
Fabio
--
http://mail.python.org/mailman/listinfo/python-list
Re: regexp problem in Python
On 4 A ustos, 17:10, Ehsan [EMAIL PROTECTED] wrote:
On Aug 4, 1:22 pm, Sönmez Kartal [EMAIL PROTECTED] wrote:
On 4 A ustos, 00:41, Ehsan [EMAIL PROTECTED] wrote:
I want to find http://www.2shared.com/download/1716611/e2000f22/
Jadeed_Mlak14.wmv?tsid=20070803-164051-9d637d11 or 3gp instead of
wmv in the text file like this :
html
some code
function reportAbuse() {
var windowname=abuse;
var url=/abuse.jsp?link= + http://www.2shared.com/file/1716611/
e2000f22/Jadeed_Mlak14.html;
OpenWindow =
window.open(url,windowname,'toolbar=no,scrollbars=no,resizable=no,width=500,height=500,left=50,top=50');
OpenWindow.focus();
}
function startDownload(){
window.location = http://www.2shared.com/download/1716611/
e2000f22/Jadeed_Mlak14.wmv?tsid=20070803-164051-9d637d11;
//document.downloadForm.submit();
}
/script
/head
/htmlhttp://www.2shared.com/download/1716611/e2000f22/
Jadeed_Mlak14.3gp?tsid=20070803-164051-9d637d11sfgsfgsfgv
I use this pattern :
http.*?\.(wmv|3gp).*
but it returns only 'wmv' and '3gp' instead of http://www.2shared.com/
download/1716611/e2000f22/Jadeed_Mlak14.wmv?
tsid=20070803-164051-9d637d11
what can I do? what's wrong whit this pattern? thanx for your comments
You could use r'window.location = (.*?\.(wmv|3gp);' as your regex
string, I guess..- Hide quoted text -
- Show quoted text -
I didn't get what do you mean? i think i must just change the pattern
but I don't know how to find bestfit pattern
If you append window.location = and ';' to your pattern, it would
be more clear to detect it.
r'window.location = (.*?);'
... I have used this and it gave me ...
data = html
... some code
... function reportAbuse() {
... var windowname=abuse;
... var url=/abuse.jsp?link= + http://www.2shared.com/file/
1716611/e2000f22/Jadeed_Mlak14.html;
... OpenWindow =
...
window.open(url,windowname,'toolbar=no,scrollbars=no,resizable=no,width=500,height=500,left=50,top=50');
... OpenWindow.focus();
... }
... function startDownload(){
... window.location = http://www.2shared.com/download/1716611/
e2000f22/Jadeed_Mlak14.wmv?tsid=20070803-164051-9d637d11;
... //document.downloadForm.submit();
... }
... /script
... /head
... /html
re.findall(r'window.location = (.*?);', data)
['http://www.2shared.com/download/1716611/e2000f22/Jadeed_Mlak14.wmv?
tsid=20070803-164051-9d637d11']
print 'It works! :-)'
It works! :-)
Happy coding
--
http://mail.python.org/mailman/listinfo/python-list
regexp problem in Python
I want to find http://www.2shared.com/download/1716611/e2000f22/
Jadeed_Mlak14.wmv?tsid=20070803-164051-9d637d11 or 3gp instead of
wmv in the text file like this :
html
some code
function reportAbuse() {
var windowname=abuse;
var url=/abuse.jsp?link= + http://www.2shared.com/file/1716611/
e2000f22/Jadeed_Mlak14.html;
OpenWindow =
window.open(url,windowname,'toolbar=no,scrollbars=no,resizable=no,width=500,height=500,left=50,top=50');
OpenWindow.focus();
}
function startDownload(){
window.location = http://www.2shared.com/download/1716611/
e2000f22/Jadeed_Mlak14.wmv?tsid=20070803-164051-9d637d11;
//document.downloadForm.submit();
}
/script
/head
/htmlhttp://www.2shared.com/download/1716611/e2000f22/
Jadeed_Mlak14.3gp?tsid=20070803-164051-9d637d11sfgsfgsfgv
I use this pattern :
http.*?\.(wmv|3gp).*
but it returns only 'wmv' and '3gp' instead of http://www.2shared.com/
download/1716611/e2000f22/Jadeed_Mlak14.wmv?
tsid=20070803-164051-9d637d11
what can I do? what's wrong whit this pattern? thanx for your comments
--
http://mail.python.org/mailman/listinfo/python-list
Re: regexp problem in Python
On Aug 3, 4:41 pm, Ehsan [EMAIL PROTECTED] wrote: I want to find http://www.2shared.com/download/1716611/e2000f22/ [...] I use this pattern : http.*?\.(wmv|3gp).* but it returns only 'wmv' and '3gp' instead of http://www.2shared.com/ download/1716611/e2000f22/Jadeed_Mlak14.wmv? tsid=20070803-164051-9d637d11 what can I do? what's wrong whit this pattern? thanx for your comments Just a guess, based on too little information: Try (http.*?\.(wmv| 3gp).*) Regards, -=Dave -- http://mail.python.org/mailman/listinfo/python-list
Re: regexp problem in Python
On Aug 4, 1:36 am, Dave Hansen [EMAIL PROTECTED] wrote: On Aug 3, 4:41 pm, Ehsan [EMAIL PROTECTED] wrote: I want to find http://www.2shared.com/download/1716611/e2000f22/ [...] I use this pattern : http.*?\.(wmv|3gp).* but it returns only 'wmv' and '3gp' instead of http://www.2shared.com/ download/1716611/e2000f22/Jadeed_Mlak14.wmv? tsid=20070803-164051-9d637d11 what can I do? what's wrong whit this pattern? thanx for your comments Just a guess, based on too little information: Try (http.*?\.(wmv| 3gp).*) Regards, -=Dave no, it doesn't work -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem with `('
Zeng Nan wrote: On Thu, Mar 22, 2007 at 01:26:22AM -0700, Johny wrote: I have the following text titleGoods Item 146 (174459989) - OurWebSite/title from which I need to extract `Goods Item 146 ' Can anyone help with regexp? Thank you for help L. (Goods\s+Item\s+146\s+) [snigger] regards Steve -- Steve Holden +44 150 684 7255 +1 800 494 3119 Holden Web LLC/Ltd http://www.holdenweb.com Skype: holdenweb http://del.icio.us/steve.holden Recent Ramblings http://holdenweb.blogspot.com -- http://mail.python.org/mailman/listinfo/python-list
Regexp problem with `('
I have the following text titleGoods Item 146 (174459989) - OurWebSite/title from which I need to extract `Goods Item 146 ' Can anyone help with regexp? Thank you for help L. -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem with `('
On Thu, Mar 22, 2007 at 01:26:22AM -0700, Johny wrote: I have the following text titleGoods Item 146 (174459989) - OurWebSite/title from which I need to extract `Goods Item 146 ' Can anyone help with regexp? Thank you for help L. (Goods\s+Item\s+146\s+) -- Zeng Nan MY BLOG: http://zengnan.blogspot.com Public Key: http://pgp.mit.edu/ | www.keyserver.net ~~~ In Lexington, Kentucky, it's illegal to carry an ice cream cone in your pocket. ~~~ pgp46CeY9IZzI.pgp Description: PGP signature -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem with `('
Johny a écrit : I have the following text titleGoods Item 146 (174459989) - OurWebSite/title from which I need to extract `Goods Item 146 ' Can anyone help with regexp? Sure : the documentation is here: http://docs.python.org/lib/module-re.html And there's a nice tutorial here: http://www.amk.ca/python/howto/regex/ Read all this, try to solve your problem, and come back with what you've done so far if you need more help. Thank you for help You're welcome. -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem with `('
On Mar 22, 3:26 am, Johny [EMAIL PROTECTED] wrote: I have the following text titleGoods Item 146 (174459989) - OurWebSite/title from which I need to extract `Goods Item 146 ' Can anyone help with regexp? Thank you for help L. Here's the immediate answer to your question. import re src = titleGoods Item 146 (174459989) - OurWebSite/title pattern = rtitle(.*)\( re.search(pattern,src).groups()[0] I post it this way so that you can relate the re to your specific question, and then maybe apply this to whatever else you are scraping from this web page. Please don't follow up with a post asking how to extract 45,Rubber chicken from trtd45/tdtdRubber chicken/td/tr. At this point, you should try a little experimentation on your own. -- Paul -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem with `('
Johny wrote:
I have the following text
titleGoods Item 146 (174459989) - OurWebSite/title
from which I need to extract
`Goods Item 146 '
Can anyone help with regexp?
Thank you for help
L.
In general, parsing HTML with regular expressions is a bad idea.
Usually, you use something like BeautifulSoup to parse the HTML,
extract the desired field, like the contents of title, then
work on that.
If you try to do this line by line with regular expressions,
it will fail when the line breaks aren't where you expect. If
you try to do a whole document with regular expressions, other
material such as content in comments can be misrecognized.
Try something like this:
# Regular expression to extract group before (N)
kreextractitem = re.compile(r'^(.*)\(\d+\))
pagetree = BeautifulSoup.BeautifulSoup(stringcontaininghtml)
titleitem = pagetree.find({'title':True, 'TITLE':True})
if titleitem :
titletext = .join(atag.findAll(text=True, recursive=True))
# Text of TITLE item is now in titletext as a string.
groups = kreextractitem.search(titletext)
if groups :
goodsitem = groups.group(1).strip()
# goodsitem now contains everything before ()
This approach will work no matter where the line breaks are in the original
HTML.
John Nagle
--
http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem, which pattern to use in split
Hans Almåsbakk wrote: Is there a relatively hassle-free way to get the csv module working with 2.1? The server is running Debian stable/woody, and it also seemed 2.2 can coexist with 2.1, when I checked the distro packages, if that is any help. 2.3 and 2.4 can also coexist with 2.1 (use make altinstall to leave python alone, so if you're using a pure-Python application, upgrading might be a good idea. alternatively, the following module (with a slightly different API) should work under 2.1: http://www.object-craft.com.au/projects/csv/ /F -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem, which pattern to use in split
Hans Almåsbakk wrote: These lines are in a csv file exported from excel. Any pointer will be greatly appreciated. Maybe I'm attacking this problem the wrong way already from the start? (Not that I can see another way myself :) import csv http://online.effbot.org/2003_08_01_archive.htm#librarybook-csv-module /F -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem, which pattern to use in split
Hans Almåsbakk (14.12.2004 16:02): Any pointer will be greatly appreciated. Maybe I'm attacking this problem the wrong way already from the start? (Not that I can see another way myself :) Hans, did you try the csv module in the Python library? Matthias -- http://mail.python.org/mailman/listinfo/python-list
Re: Regexp problem, which pattern to use in split
Fredrik Lundh [EMAIL PROTECTED] writes: import csv http://online.effbot.org/2003_08_01_archive.htm#librarybook-csv-module This seems be just the thing I need. Now ofcourse, another problem arouse: The csv module is new in Python 2.3. hans:~# python -V Python 2.1.3 Is there a relatively hassle-free way to get the csv module working with 2.1? The server is running Debian stable/woody, and it also seemed 2.2 can coexist with 2.1, when I checked the distro packages, if that is any help. Regards -- Hans Almåsbakk -remove .invalid for correct email -- http://mail.python.org/mailman/listinfo/python-list
