Re: break the loop in one object and then return
Alex Pavluck wrote: Peter, Why do you make such claims without any reason to do so? This is my own thing. So, I guess I am a student but just a student of my own accord. So, please don't reply if you don't have anything to contribute. First: This is not YOUR OWN THING. This group really can help, but this group AFAIK does not write homeworks. It is nothing wrong you are just a student, we are all students somehow :) Second: Few other posters were posting similar requests to this group last few days (maybe your classmates :)) so the chance it just a coincidence is very low. If I am wrong, sorry about that. Third: This group can help, but some effort (study, googling this group etc.) on your side is necessary as well. Other posters suggested you the way, where to go, but you didn't try to change your code a bit. Please read the following as well: http://www.albion.com/netiquette/corerules.html To your code: As for the - mynum I guess that could happen but I am just doing this so that they will never match on first try. I guess I should just hardcode it. This is what happens if I step though: mynum = 93***1*** use # sign for your comments in the code followed by the comment text. All the stuff after the # is ignored when the code is executed. Nobody can execute (examine) your code whit your comments like ***1*** To hardcode mynum value is IMHO very bad idea and your code will be useless if the value will be discovered. Other suggested how to generate random number at the beginning of the code. yournum = input(I am thinking of a number between 1 and 100.\n Guess which number: ) ***2*** def strt(): ***3******6*** if yournum == mynum: ***7*** print Wow! You got it! elif yournum mynum: ***8*** print Nope. Too low ***9*** again()***10*** ***15*** elif yournum mynum: print Oh, your too high def again(): ***4*** ***11*** global yournum ***12*** yournum = input(guess again: ) ***13*** strt() ***14*** strt() ***5*** ***15*** is the problem. It doesn't start at the top but rather where is leaves the loop. print statement can help to solve your problem, put it (with some text that will navigate you) on the rows where you are not sure the program is not running properly. Print out the values of the mynum and yournum as well. This will be just for your debugging purposes. Finally you will remove it. For example you can put: print starting the strt function, mynum = , mynum, yournum =, yournum on the first row of your strt function, so you will see the code is going through there. Finally: Try to thing what will happen if the person will input character rather than integer. Again: good luck in your effort Petr Jakes Petr Jakes wrote: It smells like many student are trying to do their homework last few days here ... Can we now the name of your school? :) AFAIK this group does not solve homeworks here :) Just few points: at the beginning try to test the input value you can use in range or using 0 yournum 101 you should test if the input is an integer as well.. http://tinyurl.com/j468c Other suggested here which way to go. Good luck :) Petr Jakes -- http://mail.python.org/mailman/listinfo/python-list
break the loop in one object and then return
I am trying to write the following code to block up evaluation and prompting for entering new information. However, when I break the loop in one object and then return it does not start at the beginning again but rather at the point where it exited. Can someone look at the following code and give me some feedback. yournum = input(I am thinking of a number between 1 and 100.\n Guess which number: ) mynum = (yournum-5) def eval(): if yournum == mynum: print Wow! You got it! elif yournum mynum: print Nope. Too low again() elif yournum mynum: print Oh, your too high again() def again(): global yournum yournum = input(guess again: ) eval() eval() -- http://mail.python.org/mailman/listinfo/python-list
Re: break the loop in one object and then return
Alex Pavluck wrote: I am trying to write the following code to block up evaluation and prompting for entering new information. However, when I break the loop in one object and then return it does not start at the beginning again but rather at the point where it exited. Can someone look at the following code and give me some feedback. yournum = input(I am thinking of a number between 1 and 100.\n Guess which number: ) mynum = (yournum-5) def eval(): if yournum == mynum: print Wow! You got it! elif yournum mynum: print Nope. Too low again() elif yournum mynum: print Oh, your too high again() def again(): global yournum yournum = input(guess again: ) eval() eval() Your code works fine for me. What's the problem exactly? Be aware, 'eval' is a built-in function, you might want to use a different name. And instead of your use you're the contraction of you are-- but that's not a code problem. FWIW, here's another way to structure your program without the recursion you're using. yournum = input(I am thinking of a number between 1 and 100.\n Guess which number: ) mynum = (yournum-5) def loop(): global yournum, mynum while yournum != mynum: if yournum mynum: print Nope. Too low elif yournum mynum: print Oh, you're too high again() print Wow! You got it! def again(): global yournum yournum = input(guess again: ) loop() HTH, ~Simon -- http://mail.python.org/mailman/listinfo/python-list
Re: break the loop in one object and then return
Alex Pavluck wrote: I am trying to write the following code to block up evaluation and prompting for entering new information. However, when I break the loop in one object and then return it does not start at the beginning again but rather at the point where it exited. Can someone look at the following code and give me some feedback. If you want a loop, write a loop. eval() is a built-in function. Better leave the names of builtins as they are. yournum = input(I am thinking of a number between 1 and 100.\n Guess which number: ) mynum = (yournum-5) If the users first guess is 2, mynum becomes -3... Better use this - to ensure 100 = mynum = 1, and the user can guess right on 1st try. import random mynum = random.randint(1,100) input evaluates a user-supplied string, and is a bit dangerous. (Run your original program, and give mynum as your second guess.) So use yournum = int(raw_input(I am thinking... you could use one while loop instead of two functions and one global variable. while (yournum != mynum): if yournum mynum: print Too low. else: print Too high. yournum = int(raw_input(Guess again:)) print You got it! -- http://mail.python.org/mailman/listinfo/python-list
Re: break the loop in one object and then return
It smells like many student are trying to do their homework last few days here ... Can we now the name of your school? :) AFAIK this group does not solve homeworks here :) Just few points: at the beginning try to test the input value you can use in range or using 0 yournum 101 you should test if the input is an integer as well.. http://tinyurl.com/j468c Other suggested here which way to go. Good luck :) Petr Jakes -- http://mail.python.org/mailman/listinfo/python-list
Re: break the loop in one object and then return
Peter, Why do you make such claims without any reason to do so? This is my own thing. So, I guess I am a student but just a student of my own accord. So, please don't reply if you don't have anything to contribute. As for the - mynum I guess that could happen but I am just doing this so that they will never match on first try. I guess I should just hardcode it. This is what happens if I step though: mynum = 93***1*** yournum = input(I am thinking of a number between 1 and 100.\n Guess which number: ) ***2*** def strt(): ***3******6*** if yournum == mynum: ***7*** print Wow! You got it! elif yournum mynum: ***8*** print Nope. Too low ***9*** again()***10*** ***15*** elif yournum mynum: print Oh, your too high def again(): ***4*** ***11*** global yournum ***12*** yournum = input(guess again: ) ***13*** strt() ***14*** strt() ***5*** ***15*** is the problem. It doesn't start at the top but rather where is leaves the loop. Petr Jakes wrote: It smells like many student are trying to do their homework last few days here ... Can we now the name of your school? :) AFAIK this group does not solve homeworks here :) Just few points: at the beginning try to test the input value you can use in range or using 0 yournum 101 you should test if the input is an integer as well.. http://tinyurl.com/j468c Other suggested here which way to go. Good luck :) Petr Jakes -- http://mail.python.org/mailman/listinfo/python-list
