[issue24592] global var defined in module not returned by function
Steve Dower added the comment: You should start by posting this to python-list or StackOverflow, and I'd suggest including code that can actually be run - it's far more precise than pseudocode. (Functions and modules get used a lot. It's far more likely there's a bug in your code than in Python's implementation.) -- resolution: - not a bug stage: - resolved status: open - closed ___ Python tracker rep...@bugs.python.org http://bugs.python.org/issue24592 ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
[issue24592] global var defined in module not returned by function
New submission from arthur: defined global var, glob.myVar, in separated module imported module containing glob.myVar in function1, func1(): glob.myVar = func1Var = func2() in function2, func2(): if (...): glob.myVar+= abc func2() # call func2() again - recursive else: return glob.myVar I always find: func1Var is None = True An obvious workaround is func1Var = glob.myVar which is fine -- components: Windows messages: 246460 nosy: arthur, paul.moore, steve.dower, tim.golden, zach.ware priority: normal severity: normal status: open title: global var defined in module not returned by function type: behavior versions: Python 3.6 ___ Python tracker rep...@bugs.python.org http://bugs.python.org/issue24592 ___ ___ Python-bugs-list mailing list Unsubscribe: https://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
Re: shortcut for large amount of global var declarations?
In message mailman.2771.1273327690.23598.python-l...@python.org, Alex Hall wrote: ... I have about fifteen vars in a function which have to be global. Why not make them class variables, e.g. class my_namespace : var1 = ... var2 = ... #end my_namespace def my_function(...) : ... can directly read/assign my_namespace.var1 etc here ... #end my_function Also has the benefit of minimizing pollution of the global namespace. -- http://mail.python.org/mailman/listinfo/python-list
shortcut for large amount of global var declarations?
Hi all, I am sorry if this is the second message about this you get; I typed this and hit send (on gmail website) but I got a 404 error, so I am not sure if the previous message made it out or not. Anyway, I have about fifteen vars in a function which have to be global. Is there a faster and more space-efficient way of doing this than putting each var on its own line; that is, fifteen global varName declarations? Thanks. -- Have a great day, Alex (msg sent from GMail website) mehg...@gmail.com; http://www.facebook.com/mehgcap -- http://mail.python.org/mailman/listinfo/python-list
Re: shortcut for large amount of global var declarations?
Alex Hall wrote: Hi all, I am sorry if this is the second message about this you get; I typed this and hit send (on gmail website) but I got a 404 error, so I am not sure if the previous message made it out or not. Anyway, I have about fifteen vars in a function which have to be global. Is there a faster and more space-efficient way of doing this than putting each var on its own line; that is, fifteen global varName declarations? Thanks. 'global' will accept multiple names: def foo(): global a, b, c ... -- http://mail.python.org/mailman/listinfo/python-list
Re: shortcut for large amount of global var declarations?
On 8 May, 15:08, Alex Hall mehg...@gmail.com wrote: Hi all, I am sorry if this is the second message about this you get; I typed this and hit send (on gmail website) but I got a 404 error, so I am not sure if the previous message made it out or not. Anyway, I have about fifteen vars in a function which have to be global. Is there a faster and more space-efficient way of doing this than putting each var on its own line; that is, fifteen global varName declarations? Thanks. -- Have a great day, Alex (msg sent from GMail website) mehg...@gmail.com;http://www.facebook.com/mehgcap About 15 that *need* to be global; smells bad to me. However, you can amend a function's .func_globals attribute. Just wouldn't be going there myself. Why do you have this many? What's your use case? Jon. -- http://mail.python.org/mailman/listinfo/python-list
Re: shortcut for large amount of global var declarations?
On 5/8/10, Jon Clements jon...@googlemail.com wrote: On 8 May, 15:08, Alex Hall mehg...@gmail.com wrote: Hi all, I am sorry if this is the second message about this you get; I typed this and hit send (on gmail website) but I got a 404 error, so I am not sure if the previous message made it out or not. Anyway, I have about fifteen vars in a function which have to be global. Is there a faster and more space-efficient way of doing this than putting each var on its own line; that is, fifteen global varName declarations? Thanks. -- Have a great day, Alex (msg sent from GMail website) mehg...@gmail.com;http://www.facebook.com/mehgcap About 15 that *need* to be global; smells bad to me. However, you can amend a function's .func_globals attribute. How do you do this exactly? Just wouldn't be going there myself. Why do you have this many? What's your use case? They are in a setOptions function in config.py, which reads from an ini file and sets up all options for the program. All other files then can read these options. For example, anyone else can import config, then, if they are rounding a number, they can know how many places to round to by looking at config.rnd. I have everything in a function instead of being initialized upon importing since I offer a function to reload the ini file if the user changes something. Eventually I will have a gui for setting options, and that gui, to save options, will write an ini file then call setOptions so all options are then reset according to the newly created ini. If I do not make everything in setOptions global, no other file seems able to read it; I get an exception the first time another file tries to access a setting. Thanks. Jon. -- http://mail.python.org/mailman/listinfo/python-list -- Have a great day, Alex (msg sent from GMail website) mehg...@gmail.com; http://www.facebook.com/mehgcap -- http://mail.python.org/mailman/listinfo/python-list
Re: shortcut for large amount of global var declarations?
On Sun, May 9, 2010 at 12:08 AM, Alex Hall mehg...@gmail.com wrote: Hi all, I am sorry if this is the second message about this you get; I typed this and hit send (on gmail website) but I got a 404 error, so I am not sure if the previous message made it out or not. Anyway, I have about fifteen vars in a function which have to be global. Is there a faster and more space-efficient way of doing this than putting each var on its own line; that is, fifteen global varName declarations? Thanks. Using globals (global variables) is generally considered bad practise. Consider instead using a class/object. You could for example have a config object that is shared by other modules. cheers James -- http://mail.python.org/mailman/listinfo/python-list
Re: shortcut for large amount of global var declarations?
On 8 May, 16:03, Alex Hall mehg...@gmail.com wrote: On 5/8/10, Jon Clements jon...@googlemail.com wrote: On 8 May, 15:08, Alex Hall mehg...@gmail.com wrote: Hi all, I am sorry if this is the second message about this you get; I typed this and hit send (on gmail website) but I got a 404 error, so I am not sure if the previous message made it out or not. Anyway, I have about fifteen vars in a function which have to be global. Is there a faster and more space-efficient way of doing this than putting each var on its own line; that is, fifteen global varName declarations? Thanks. -- Have a great day, Alex (msg sent from GMail website) mehg...@gmail.com;http://www.facebook.com/mehgcap About 15 that *need* to be global; smells bad to me. However, you can amend a function's .func_globals attribute. How do you do this exactly? Just wouldn't be going there myself. Why do you have this many? What's your use case? They are in a setOptions function in config.py, which reads from an ini file and sets up all options for the program. All other files then can read these options. For example, anyone else can import config, then, if they are rounding a number, they can know how many places to round to by looking at config.rnd. I have everything in a function instead of being initialized upon importing since I offer a function to reload the ini file if the user changes something. Eventually I will have a gui for setting options, and that gui, to save options, will write an ini file then call setOptions so all options are then reset according to the newly created ini. If I do not make everything in setOptions global, no other file seems able to read it; I get an exception the first time another file tries to access a setting. Thanks. Jon. -- http://mail.python.org/mailman/listinfo/python-list -- Have a great day, Alex (msg sent from GMail website) mehg...@gmail.com;http://www.facebook.com/mehgcap Umm, okay at least now we know the context. Similar to what James suggested just have a dict object in your config module called 'settings' or something and access that. I still prefer the giveth rather than taketh approach though. But heck, if it works, who cares? Jon. -- http://mail.python.org/mailman/listinfo/python-list
Re: shortcut for large amount of global var declarations?
On Sat, 08 May 2010 10:08:08 -0400, Alex Hall wrote: Hi all, I am sorry if this is the second message about this you get; I typed this and hit send (on gmail website) but I got a 404 error, so I am not sure if the previous message made it out or not. Anyway, I have about fifteen vars in a function which have to be global. Is there a faster and more space-efficient way of doing this than putting each var on its own line; that is, fifteen global varName declarations? Thanks. global google, for_, global_, variables, considered, harmful -- Steven -- http://mail.python.org/mailman/listinfo/python-list
Global var access in imported modules?
I have a main module doStuff.py and another module utility.py. At the start of doStuff.py I call import utility.py Then I also proceed to initiallize some global variables sName = Then I create a class, some methods etc. In one of the methods I assign a value to my variable sName. Then I call a function from within my utility.py file: utility.makeOne(stuff) Within my utility.py file, I define the makeOne function. But I want to use that same global variable sName In utility.py I have tried to indicate that I'm using the global sName through the statement: global sName But when I go to use the variable it still gives me an error: NameError: global name 'sName' is not defined I thought perhaps I need to indicate 'globality' in my main module, so before I initiallized sName in doStuff.py I added: global sName But it doesn't help me. I had this issue before and resolved it by declaring the variable global in the sub-module utility.py, but then I needed to reference it in my main module with a prefix: utility.sName = It's more verbose,and defining globals in a submodule seems backward. But also, what if I need to access sName in another imported module, say otherstuff.py? I would do my import otherstuff call in my main module, but would I have to put an import utility into the otherstuff.py file? Is there some way I can define globals in my main module, and have them accessible in all my imported submodule? As you can see I'm a little unsure about the global handling in a multi-module environment. Any suggestions appreciated. I've read http://docs.python.org/ref/naming.html but it hasn't enlightened me on this one. -- http://mail.python.org/mailman/listinfo/python-list
Re: Global var access in imported modules?
RgeeK wrote: I have a main module doStuff.py and another module utility.py. At the start of doStuff.py I call import utility.py that tries to import a module named py from the package utility. Then I also proceed to initiallize some global variables sName = Within my utility.py file, I define the makeOne function. But I want to use that same global variable sName In utility.py I have tried to indicate that I'm using the global sName through the statement: global sName the global directive in Python is used *inside* a function or method to indicate that a given name is not local. Python doesn't have program-wide global variables; if you need that, create a support module and import that module everywhere you need to access those variables: # file: globalvars.py sName = # file: myprogram.py import globalvars print globalvars.sName etc. /F -- http://mail.python.org/mailman/listinfo/python-list
Re: Global var access in imported modules?
Fredrik Lundh wrote: import utility.py that tries to import a module named py from the package utility. oops - that was just a typo in my post - I meant of course import utility Python doesn't have program-wide global variables; if you need that, create a support module and import that module everywhere you need to access those variables: # file: globalvars.py sName = # file: myprogram.py import globalvars print globalvars.sName etc. /F That's news - thanks, I didn't realize that there just wasn't the concept of program-wide globals. The support module idea sounds like a path forward. -R. -- http://mail.python.org/mailman/listinfo/python-list
Re: Global var access in imported modules?
Fredrik Lundh wrote: import utility.py that tries to import a module named py from the package utility. oops - that was just a typo in my post - I meant of course import utility Python doesn't have program-wide global variables; if you need that, create a support module and import that module everywhere you need to access those variables: # file: globalvars.py sName = # file: myprogram.py import globalvars print globalvars.sName etc. /F That's news - thanks, I didn't realize that there just wasn't the concept of program-wide globals. The support module idea sounds like a path forward. -R. -- http://mail.python.org/mailman/listinfo/python-list
Re: Global var access in imported modules?
Dennis Lee Bieber wrote: On Wed, 27 Aug 2008 16:21:03 -0400, RgeeK [EMAIL PROTECTED] declaimed the following in comp.lang.python: I have a main module doStuff.py and another module utility.py. At the start of doStuff.py I call import utility.py I hope not... import utility no .py Then I also proceed to initiallize some global variables Python does not have global variables. Names belong within a module (or within functions defined within the module). sName = Then I create a class, some methods etc. In one of the methods I assign a value to my variable sName. Then I call a function from within my utility.py file: utility.makeOne(stuff) Within my utility.py file, I define the makeOne function. But I want to use that same global variable sName In utility.py I have tried to indicate that I'm using the global sName through the statement: global sName The global statement is only used within functions (def blocks) to indicate that writes to the specified name are to modify the MODULE level version of the name, otherwise a write modifies a function local version of the name (you don't need global for read-only access of names, the search for names first looks inside the function, then out to the module) But when I go to use the variable it still gives me an error: NameError: global name 'sName' is not defined I thought perhaps I need to indicate 'globality' in my main module, so before I initiallized sName in doStuff.py I added: global sName But it doesn't help me. I had this issue before and resolved it by declaring the variable global in the sub-module utility.py, but then I needed to reference it in my main module with a prefix: utility.sName = It's more verbose,and defining globals in a submodule seems backward. But also, what if I need to access sName in another imported module, say otherstuff.py? I would do my import otherstuff call in my main module, but would I have to put an import utility into the otherstuff.py file? If you really need globals the common solution is to create a module such as myglobals, define all the shared names within that module, and import that module where ever you need access to one of the names. And yes, you will need to qualify all those names with the module name (though you can do things like: import myglobals as mg and then use mg.somename instead of myglobals.somename) Thanks for the reply. Good to see that approach has broad support :) I'll do that. I like the idea of a nice short alias for the import to keep the qualifications brief. Ross. -- http://mail.python.org/mailman/listinfo/python-list
Re: problem with global var
Bruno Ferreira wrote: I wrote a very simple python program to generate a sorted list of lines from a squid access log file. Now that your immediate problem is solved it's time to look at the heapq module. It solves the problem of finding the N largest items in a list much more efficiently. I think the following does the same as your code: import heapq def key(record): return int(record[4]) logfile = open(squid_access.log, r) records = (line.split() for line in logfile) topsquid = heapq.nlargest(50, records, key=key) for record in topsquid: print record[4] Peter -- http://mail.python.org/mailman/listinfo/python-list
Re: problem with global var
Hello all, Amazing :) The program is working properly now, the code is much better and I learned a bit more Python. Thank you all, guys. Bruno. 2008/1/4, Peter Otten [EMAIL PROTECTED]: Bruno Ferreira wrote: I wrote a very simple python program to generate a sorted list of lines from a squid access log file. Now that your immediate problem is solved it's time to look at the heapq module. It solves the problem of finding the N largest items in a list much more efficiently. I think the following does the same as your code: import heapq def key(record): return int(record[4]) logfile = open(squid_access.log, r) records = (line.split() for line in logfile) topsquid = heapq.nlargest(50, records, key=key) for record in topsquid: print record[4] Peter -- http://mail.python.org/mailman/listinfo/python-list -- http://mail.python.org/mailman/listinfo/python-list
problem with global var
Hi, I wrote a very simple python program to generate a sorted list of lines from a squid access log file. Here is a simplified version: ## 1 logfile = open (squid_access.log, r) 2 topsquid = [[0, 0, 0, 0, 0, 0, 0]] 3 4 def add_sorted (list): 5 for i in range(50): 6 if int(list[4]) int(topsquid[i][4]): 7 topsquid.insert(i,list) 8 break 8 # Max len = 50 10 if len(topsquid) 50: 11 topsquid = topsquid[0:50] 12 13 while True: 14 logline = logfile.readline() 15 linefields = logline.split() 16 17 if logline != : 18 add_sorted (linefields) 19 else: 20 break 21 22 for i in range (len(topsquid)): 23 print topsquid[i][4] When I execute the program _without_ the lines 10 and 11: 10 if len(topsquid) 50: 11 topsquid = topsquid[0:50] it runs perfectly. But if I execute the program _with_ those lines, this exception is thrown: [EMAIL PROTECTED]:~$ python topsquid.py Traceback (most recent call last): File topsquid.py, line 20, in module add_sorted (linefields) File topsquid.py, line 6, in add_sorted if int(list[4]) int(topsquid[i][4]): UnboundLocalError: local variable 'topsquid' referenced before assignment Note that now the error shown is not related with the lines 10 and 11, but wiht a line prior to them. Any hints? -- Bruno A. C. Ferreira Linux Registered User #181386 -- http://mail.python.org/mailman/listinfo/python-list
Re: problem with global var
Bruno Ferreira wrote: Hi, I wrote a very simple python program to generate a sorted list of lines from a squid access log file. Here is a simplified version: ## 1 logfile = open (squid_access.log, r) 2 topsquid = [[0, 0, 0, 0, 0, 0, 0]] 3 4 def add_sorted (list): Don't call your variable list. There's already the built-in type list. 5 for i in range(50): You should probably use xrange here. 6 if int(list[4]) int(topsquid[i][4]): 7 topsquid.insert(i,list) 8 break 8 # Max len = 50 10 if len(topsquid) 50: 11 topsquid = topsquid[0:50] I'd just use [:50], the 0 is implied. 13 while True: 14 logline = logfile.readline() 15 linefields = logline.split() 16 17 if logline != : 18 add_sorted (linefields) 19 else: 20 break for logline in logfile: if logline: linefields = logline.split() add_sorted(linefields) else: break 22 for i in range (len(topsquid)): 23 print topsquid[i][4] for i in topsquid: print i[4] (You probably want to use a name other than i then.) When I execute the program _without_ the lines 10 and 11: 10 if len(topsquid) 50: 11 topsquid = topsquid[0:50] it runs perfectly. But if I execute the program _with_ those lines, this exception is thrown: [EMAIL PROTECTED]:~$ python topsquid.py Traceback (most recent call last): File topsquid.py, line 20, in module add_sorted (linefields) File topsquid.py, line 6, in add_sorted if int(list[4]) int(topsquid[i][4]): UnboundLocalError: local variable 'topsquid' referenced before assignment Note that now the error shown is not related with the lines 10 and 11, but wiht a line prior to them. Any hints? Basically, you're trying to read the global variable topsquid, and then you're trying to define a local variable topsquid. Python doesn't like that. Declare it as global by adding global topsquid to the top of the function. -- -- http://mail.python.org/mailman/listinfo/python-list
Re: problem with global var
Bruno Ferreira wrote: Hi, I wrote a very simple python program to generate a sorted list of lines from a squid access log file. Here is a simplified version: ## 1 logfile = open (squid_access.log, r) 2 topsquid = [[0, 0, 0, 0, 0, 0, 0]] 3 4 def add_sorted (list): global topsquid 5 for i in range(50): 6 if int(list[4]) int(topsquid[i][4]): 7 topsquid.insert(i,list) 8 break 8 # Max len = 50 10 if len(topsquid) 50: 11 topsquid = topsquid[0:50] 12 13 while True: 14 logline = logfile.readline() 15 linefields = logline.split() 16 17 if logline != : 18 add_sorted (linefields) 19 else: 20 break 21 22 for i in range (len(topsquid)): 23 print topsquid[i][4] When I execute the program _without_ the lines 10 and 11: 10 if len(topsquid) 50: 11 topsquid = topsquid[0:50] it runs perfectly. But if I execute the program _with_ those lines, this exception is thrown: [EMAIL PROTECTED]:~$ python topsquid.py Traceback (most recent call last): File topsquid.py, line 20, in module add_sorted (linefields) File topsquid.py, line 6, in add_sorted if int(list[4]) int(topsquid[i][4]): UnboundLocalError: local variable 'topsquid' referenced before assignment Note that now the error shown is not related with the lines 10 and 11, but wiht a line prior to them. Any hints? Try line 4 add. -- http://mail.python.org/mailman/listinfo/python-list
Re: problem with global var
Bruno Ferreira wrote: Hi, I wrote a very simple python program to generate a sorted list of lines from a squid access log file. Here is a simplified version: ## 1 logfile = open (squid_access.log, r) 2 topsquid = [[0, 0, 0, 0, 0, 0, 0]] 3 4 def add_sorted (list): 5 for i in range(50): 6 if int(list[4]) int(topsquid[i][4]): 7 topsquid.insert(i,list) 8 break 8 # Max len = 50 10 if len(topsquid) 50: 11 topsquid = topsquid[0:50] 12 13 while True: 14 logline = logfile.readline() 15 linefields = logline.split() 16 17 if logline != : 18 add_sorted (linefields) 19 else: 20 break 21 22 for i in range (len(topsquid)): 23 print topsquid[i][4] When I execute the program _without_ the lines 10 and 11: 10 if len(topsquid) 50: 11 topsquid = topsquid[0:50] it runs perfectly. But if I execute the program _with_ those lines, this exception is thrown: [EMAIL PROTECTED]:~$ python topsquid.py Traceback (most recent call last): File topsquid.py, line 20, in module add_sorted (linefields) File topsquid.py, line 6, in add_sorted if int(list[4]) int(topsquid[i][4]): UnboundLocalError: local variable 'topsquid' referenced before assignment Note that now the error shown is not related with the lines 10 and 11, but wiht a line prior to them. Any hints? Use def add_sorted(list): global topsquid ... to make topsquid a global variable to add_sorted. Otherwise python sees that it gets referred by in the if-statement before assigning to it, thus resulting in the error you see. The reason for this is that a (limited) static analysis of python-code is performed to determine which variables are local to a function and which not. The criteria essentially is the appearance on the left-hand-side of an expression makes a variable (or name) local to that function. Which makes it require the explicit global declaration. Apart from that there are quite a few things worth mentioning in your code: - don't shadow built-in names like list - it's superfluous to do for i in xrange(len(some_list)): .. some_list[i] .. as you do, unless you need the index. Instead do for element in some_list: ... element ... If you need an index, do for i, element in enumerate(some_list): ... - don't use range, use xrange if you don't need a list but rather want to enumerate indices. - the while-loop is superfluous as well, just do for line in logfile: ... or if your python is older do for line in logfile.xreadlines(): ... Diez -- http://mail.python.org/mailman/listinfo/python-list
Re: problem with global var
Bruno Ferreira wrote: When I execute the program _without_ the lines 10 and 11: 10 if len(topsquid) 50: 11 topsquid = topsquid[0:50] it runs perfectly. But if I execute the program _with_ those lines, this exception is thrown: [EMAIL PROTECTED]:~$ python topsquid.py Traceback (most recent call last): File topsquid.py, line 20, in module add_sorted (linefields) File topsquid.py, line 6, in add_sorted if int(list[4]) int(topsquid[i][4]): UnboundLocalError: local variable 'topsquid' referenced before assignment Python uses static analysis to determine if a variable is local to a function; somewhat simplified, if you assign to the variable inside the function, *all* uses of that variable inside the function will be considered local. for the full story, see: http://docs.python.org/ref/naming.html to fix this, you can insert a global declaration at the top of the def add_sorted (list): global topsquid # mark topsquid as global in this function ... in this case, you can also avoid the local assignment by modifying the list in place; if len(topsquid) 50: topsquid[:] = topsquid[0:50] or, as a one-liner: del topsquid[50:] /F -- http://mail.python.org/mailman/listinfo/python-list
Re: problem with global var
On Thu, 03 Jan 2008 11:38:48 -0300, Bruno Ferreira wrote: Hi, I wrote a very simple python program to generate a sorted list of lines from a squid access log file. Here is a simplified version: ## 1 logfile = open (squid_access.log, r) 2 topsquid = [[0, 0, 0, 0, 0, 0, 0]] [snip] Others have already solved the immediate problem, but a much better design would be to avoid using a global variable in the first place. def add_sorted(alist, data): Add figures from alist to collated data and return data. # do your processing here... return data topsquid=[[0, 0, 0, 0, 0, 0, 0]] for line in logfile: linefields = logline.split() topsquid = add_sorted(linefields, topsquid) -- Steven -- http://mail.python.org/mailman/listinfo/python-list
Re: Count nb call of a function, without global var or decorator
Méta-MCI [EMAIL PROTECTED] wrote: Example, with meta-data (attributs of function) : def ff(this): try: this.count=this.count+1 except: this.count=1 a=1 b=2 c=a+b ff(ff) fa=ff ff(ff) fa(fa) print ff.count How to improve that? If I've managed to guess what you are asking, you want to use a class: class Ff: def __init__(self): self.count = 0 def __call__(self, notused): self.count += 1 a, b = 1, 2 c = a+b return c ff = Ff() fa = Ff() ff(ff) 3 ff.count 1 fa.count 0 -- http://mail.python.org/mailman/listinfo/python-list
Re: Count nb call of a function, without global var or decorator
Re! I can do : def ff(): this=ff try: this.count=this.count+1 except: this.count=1 a=1 b=2 c=a+b ff() fa=ff ff() fa() print ff.count But that use, inside the function, the litteral name of the function; and I want no use litteral name (inside) @+ Michel Claveau -- http://mail.python.org/mailman/listinfo/python-list
Re: Count nb call of a function, without global var or decorator
Méta-MCI wrote: Example, with meta-data (attributs of function) : Apart from asking what counting nb call of a function means, I wonder why you didn't use an iterator? @-salutations @-less Regards, Björn -- BOFH excuse #65: system needs to be rebooted -- http://mail.python.org/mailman/listinfo/python-list
Re: Count nb call of a function, without global var or decorator
Re! why you didn't use an iterator? If the iterator is extern (to the function), it's like decorator, or global var. If it is internal, it's huge, compare to this.count=this.count+1 (or this.count+=1) @+ Michel Claveau -- http://mail.python.org/mailman/listinfo/python-list
Re: Count nb call of a function, without global var or decorator
Méta-MCI wrote: If the iterator is extern (to the function), it's like decorator, or global var. Please excuse me, I don't understand your point. I'm not even sure if both of us speak of the same iterators. If it is internal, it's huge, compare to this.count=this.count+1 (or this.count+=1) In which way huge? If you want top notch performance you should use a C extension anyway ... Regards, Björn -- BOFH excuse #339: manager in the cable duct -- http://mail.python.org/mailman/listinfo/python-list
Re: global var
Nick Coghlan wrote: Michael Hoffman wrote: raver2046 wrote: How to have a global var in python ? global var will give you a global variable named var. Whether this advice is correct or not depends greatly on what the OP means by 'global' :) Module global, it's right, application global it's wrong. Given the nature of the question, I suspect the latter. And even there, one must be careful. global var won't really give you a global variable; it will cause the name var, when used locally, to refer to a pre-existing module-level reference var. No variables are actually created in the execution of global var. Jeff Shannon -- http://mail.python.org/mailman/listinfo/python-list
Re: global var
Michael Hoffman wrote: raver2046 wrote: How to have a global var in python ? global var will give you a global variable named var. Whether this advice is correct or not depends greatly on what the OP means by 'global' :) Module global, it's right, application global it's wrong. Given the nature of the question, I suspect the latter. Cheers, Nick. -- Nick Coghlan | [EMAIL PROTECTED] | Brisbane, Australia --- http://boredomandlaziness.skystorm.net -- http://mail.python.org/mailman/listinfo/python-list
global var
hello, How to have a global var in python ? thank you. raver2046 http://raver2046.ath.cx -- http://mail.python.org/mailman/listinfo/python-list
Re: global var
raver2046 wrote: How to have a global var in python ? global var will give you a global variable named var. -- Michael Hoffman -- http://mail.python.org/mailman/listinfo/python-list
Re: global var
raver2046 wrote: How to have a global var in python ? You can, but you probably don't want to. What's your use case? Example code and what you'd like it to do would be helpful. STeVe -- http://mail.python.org/mailman/listinfo/python-list
