Re: lxml question -- creating an etree.Element attribute with ':' in the name
On Mon, Dec 02, 2019 at 08:58:11PM -0800, gerem...@gmail.com wrote: > Date: Mon, 2 Dec 2019 20:58:11 -0800 (PST) > From: gerem...@gmail.com > To: python-list@python.org > Subject: Re: lxml question -- creating an etree.Element attribute with ':' > in the name > User-Agent: G2/1.0 > > Theanks a lot > -- > https://mail.python.org/mailman/listinfo/python-list you are welcoem -- GPG 40BE 5B0E C98E 1713 AFA6 5BC0 3BEA AC80 7D4F C89B -- https://mail.python.org/mailman/listinfo/python-list
Re: lxml question -- creating an etree.Element attribute with ':' in the name
Theanks a lot -- https://mail.python.org/mailman/listinfo/python-list
Re: lxml question -- creating an etree.Element attribute with ':' in the name
Roy Smith r...@panix.com writes: But, how do I handle something like: xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance;, since xmlns:xsi isn't a valid python identifier? Read about lxml's namespace support. -- https://mail.python.org/mailman/listinfo/python-list
Re: lxml question -- creating an etree.Element attribute with ':' in the name
Burak Arslan, 18.09.2013 21:35:
On 09/18/13 21:59, Roy Smith wrote:
I can create an Element with a 'foo' attribute by doing:
etree.Element('my_node_name', foo=spam)
But, how do I handle something like:
xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance;, since xmlns:xsi
isn't a valid python identifier?
xmlns: is a prefix with a special meaning: it defines an xml namespaces
prefix. you should read about how they work.
Absolutely. For the specific case of a namespaced attribute, one way to do
it goes like this:
el = etree.Element('my_node_name')
el.set('{http://www.w3.org/2001/XMLSchema-instance}xsi', 'int')
The following:
Element('{http://www.w3.org/2001/XMLSchema-instance}my_node_name')
will generate a proper xmlns declaration for you. It may not be the same
every time, but it will do the job just as well.
For this specific namespace, and also a couple of other well-known
namespace URIs, lxml will use the expected prefix by default.
Stefan
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lxml question -- creating an etree.Element attribute with ':' in the name
I can create an Element with a 'foo' attribute by doing:
etree.Element('my_node_name', foo=spam)
But, how do I handle something like:
xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance;, since xmlns:xsi isn't
a valid python identifier?
---
Roy Smith
r...@panix.com
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Re: lxml question -- creating an etree.Element attribute with ':' in the name
On Wed, Sep 18, 2013 at 1:59 PM, Roy Smith r...@panix.com wrote:
I can create an Element with a 'foo' attribute by doing:
etree.Element('my_node_name', foo=spam)
But, how do I handle something like:
xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance;, since xmlns:xsi
isn't a valid python identifier?
Try this:
etree.Element('my_node_with_invalid_identifiers_name', **{'xmlns:xsi': 'spam'})
HTH,
--
Zach
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Re: lxml question -- creating an etree.Element attribute with ':' in the name
On 09/18/13 21:59, Roy Smith wrote:
I can create an Element with a 'foo' attribute by doing:
etree.Element('my_node_name', foo=spam)
But, how do I handle something like:
xmlns:xsi=http://www.w3.org/2001/XMLSchema-instance;, since xmlns:xsi
isn't a valid python identifier?
xmlns: is a prefix with a special meaning: it defines an xml namespaces
prefix. you should read about how they work.
The following:
Element('{http://www.w3.org/2001/XMLSchema-instance}my_node_name')
will generate a proper xmlns declaration for you. It may not be the same
every time, but it will do the job just as well.
btw, if you need to generate xml schemas, have a look at spyne:
http://spyne.io
Specifically:
https://github.com/arskom/spyne/blob/master/examples/xml/schema.py
best,
burak
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Re: lxml question
mattia wrote: I would like to click on an image in a web page that I retrieve using urllib in order to trigger an event. Here is the piece of code with the image that I want to click: input type=image style=border-width: 0px; height: 22px; width: 49px; onclick=return checkPhoneField(document.contactFrm, 'mobile'); alt=sms src=images/button_sms.bmp id=smsToMobile name=smsToMobile/ I don't know how to do it (I'm trying using lxml, but any suggestion can help). Install something like HTTP-live-headers or Firebug and analyze what the actual HTTP-requests are. Then model these. Diez -- http://mail.python.org/mailman/listinfo/python-list
lxml question
I would like to click on an image in a web page that I retrieve using urllib in order to trigger an event. Here is the piece of code with the image that I want to click: input type=image style=border-width: 0px; height: 22px; width: 49px; onclick=return checkPhoneField(document.contactFrm, 'mobile'); alt=sms src=images/button_sms.bmp id=smsToMobile name=smsToMobile/ I don't know how to do it (I'm trying using lxml, but any suggestion can help). Thanks, Mattia -- http://mail.python.org/mailman/listinfo/python-list
Re: lxml question
On Wed, Sep 9, 2009 at 4:11 PM, mattiager...@gmail.com wrote: I would like to click on an image in a web page that I retrieve using urllib in order to trigger an event. Here is the piece of code with the image that I want to click: input type=image style=border-width: 0px; height: 22px; width: 49px; onclick=return checkPhoneField(document.contactFrm, 'mobile'); alt=sms src=images/button_sms.bmp id=smsToMobile name=smsToMobile/ I don't know how to do it (I'm trying using lxml, but any suggestion can help). You need to hook into an actual web browser since the event is JavaScript code. Cheers, Chris -- http://blog.rebertia.com -- http://mail.python.org/mailman/listinfo/python-list
Re: lxml question
Uwe Schmitt wrote: I have to parse some text which pretends to be XML. lxml does not want to parse it, because it lacks a root element. I think that this situation is not unusual, so: is there a way to force lxml to parse it ? My work around is wrapping the text with root.../root before feeding lxmls parser. Yes, you can do that. To avoid creating an intermediate string, you can use the feed parser and do something like this: parser = etree.XMLParser() parser.feed(root) parser.feed(your_xml_tag_sequence_data) parser.feed(/root) root = parser.close() Stefan -- http://mail.python.org/mailman/listinfo/python-list
lxml question
Hi, I have to parse some text which pretends to be XML. lxml does not want to parse it, because it lacks a root element. I think that this situation is not unusual, so: is there a way to force lxml to parse it ? My work around is wrapping the text with root.../root before feeding lxmls parser. Greetings, Uwe -- http://mail.python.org/mailman/listinfo/python-list
Re: lxml question
On Sep 26, 11:19 am, Uwe Schmitt [EMAIL PROTECTED] wrote: I have to parse some text which pretends to be XML. lxml does not want to parse it, because it lacks a root element. I think that this situation is not unusual, so: is there a way to force lxml to parse it ? By pretends to be XML you mean XML-like but not really XML? My work around is wrapping the text with root.../root before feeding lxmls parser. That's actually not a bad solution, if you know that the document is otherwise well-formed. Another thing you can do is use libxml2's recover mode which accommodates non-well-formed XML. parser = etree.XMLParser(recover=True) tree = etree.XML(your_xml_string, parser) You'll still need to use your wrapper root element, because recover mode will ignore everything after the first root closes (and it won't throw an error). -- Mark. -- http://mail.python.org/mailman/listinfo/python-list
Re: lxml question
On Sep 27, 1:19 am, Uwe Schmitt [EMAIL PROTECTED] wrote: I have to parse some text which pretends to be XML. lxml does not want to parse it, because it lacks a root element. Another option is BeautifulSoup, which handles badly formed XML really well: http://www.crummy.com/software/BeautifulSoup/ -- http://mail.python.org/mailman/listinfo/python-list
