Re: parsing RSS XML feed for item value
feed.entries[0].w_current
{'temperature': u'20.3', 'dewpoint': u'18.6', 'windgusts': u'29.6', 'rain':
u'0.6', 'humidity': u'90', 'pressure': u'0.0', 'windspeed': u'22.2',
'winddirection': u'SSW'}
in the above I get the subitem as shown. How do I extract the label, values
pairs?
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Fwd: parsing RSS XML feed for item value
Larry Wilson itd...@gmail.com via python.org
10:39 PM (10 hours ago) wrote:
Wanting to parse out the the temperature value in the
w:current element, just after the guid element using
ElementTree or xml.sax.
Since you aren't building up a complex data structure, xml.sax
will be an OK choice.
Here's a quick and dirty job:
import io
import xml.sax as sax
the_xml = io.StringIO(SNIPPED XML)
class WeatherHandler(sax.handler.ContentHandler):
def startDocument(self):
self.temperatures = []
def startElement(self, name, attrs):
if name == 'w:current': # Nice namespace handling, eh?
self.temperatures.append(attrs)
handler = WeatherHandler()
sax.parse(the_xml, handler)
for temp in handler.temperatures:
for key, val in temp.items():
print({}: {}.format(key, val))
Output (from your example):
windGusts: 29.6
dewPoint: 18.6
pressure: 0.0
windDirection: SSW
humidity: 90
rain: 0.6
temperature: 20.3
windSpeed: 22.2
For most jobs you would want to keep track of your nesting level, but
that's left out here. I didn't try to capture location or info you
might want but didn't specify, either; left that as an exercise.
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Re: parsing RSS XML feed for item value
On Wednesday 2013 November 20 05:44, Larry Wilson wrote:
{'temperature': u'20.3', 'dewpoint': u'18.6', 'windgusts': u'29.6', 'rain':
u'0.6', 'humidity': u'90', 'pressure': u'0.0', 'windspeed': u'22.2',
'winddirection': u'SSW'}
Python 2.7.2 (default, Oct 10 2011, 10:47:36)
[GCC 4.1.2 20061115 (prerelease) (SUSE Linux)] on linux2
Type help, copyright, credits or license for more information.
w_current = {'temperature': u'20.3', 'dewpoint': u'18.6', 'windgusts':
u'29.6', 'rain': u'0.6', 'humidity': u'90', 'pressure': u'0.0', 'windspeed':
u'22.2', 'winddirection': u'SSW'}
for label, value in w_current.iteritems():
... print label, value
...
pressure 0.0
windspeed 22.2
temperature 20.3
dewpoint 18.6
windgusts 29.6
winddirection SSW
rain 0.6
humidity 90
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strainers.
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Re: parsing RSS XML feed for item value
On Wednesday 2013 November 20 05:44, Larry Wilson wrote:
feed.entries[0].w_current
{'temperature': u'20.3', 'dewpoint': u'18.6', 'windgusts': u'29.6', 'rain':
u'0.6', 'humidity': u'90', 'pressure': u'0.0', 'windspeed': u'22.2',
'winddirection': u'SSW'}
in the above I get the subitem as shown. How do I extract the label, values
pairs?
Python 3.3.0 (default, Sep 30 2012, 09:02:56)
[GCC 4.1.2 20061115 (prerelease) (SUSE Linux)] on linux
Type help, copyright, credits or license for more information.
w_current = {'temperature': u'20.3', 'dewpoint': u'18.6', 'windgusts':
u'29.6', 'rain': u'0.6', 'humidity': u'90', 'pressure': u'0.0', 'windspeed':
u'22.2', 'winddirection': u'SSW'}
for label, value in w_current.items():
...print (label, value)
...
dewpoint 18.6
temperature 20.3
rain 0.6
pressure 0.0
windspeed 22.2
humidity 90
winddirection SSW
windgusts 29.6
--
Yonder nor sorghum stenches shut ladle gulls stopper torque wet
strainers.
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Re: parsing RSS XML feed for item value
Thank you folks, now I know what I don't know and have a solution. -- https://mail.python.org/mailman/listinfo/python-list
parsing RSS XML feed for item value
Wanting to parse out the the temperature value in the w:current element, just after the guid element using ElementTree or xml.sax. Still learning python and getting to know the XML terminology, so need to ask for help, many thank in advance. This RSS is from http://rss.weather.com.au/nsw/newcastle; === ?xml version=1.0 encoding=ISO-8859-1? !-- Weather.com.au RSS Feed must be used in accordance with the terms and conditions listed at http://www.weather.com.au/about/rss -- rss version=2.0 xmlns:w=http://rss.weather.com.au/w.dtd; channel titleWeather.com.au - Newcastle Weather/title linkhttp://www.weather.com.au/nsw/newcastle/link descriptionCurrent conditions and forecast for Newcastle, New South Wales./description languageen-au/language copyrightCopyright 2013 - Weather.com.au Pty Ltd/copyright pubDateTue, 19 Nov 2013 05:00:00 GMT/pubDate lastBuildDateTue, 19 Nov 2013 05:00:00 GMT/lastBuildDate ttl15/ttl item titleNewcastle Current Conditions/title linkhttp://www.weather.com.au/nsw/newcastle/current/link description ![CDATA[ bTemperature:/b 20.3deg;Cbr / bDew Point:/b 18.6deg;Cbr / bRelative Humidity:/b 90%br / bWind Speed:/b 22.2km/hbr / bWind Gusts:/b 29.6km/hbr / bWind Direction:/b SSWbr / bPressure:/b 0.0hPabr / bRain Since 9AM:/b 0.6mmbr / ]] /description pubDateTue, 19 Nov 2013 05:00:00 GMT/pubDate guid isPermaLink=falseC1384837200/guid w:current temperature=20.3 dewPoint=18.6 humidity=90 windSpeed=22.2 windGusts=29.6 windDirection=SSW pressure=0.0 rain=0.6 / /item item ...etc === -- https://mail.python.org/mailman/listinfo/python-list
Re: parsing RSS XML feed for item value
On Tuesday 2013 November 19 19:39, Larry Wilson wrote: Wanting to parse out the the temperature value in the w:current element, just after the guid element using ElementTree or xml.sax. When you get tired of that, take a look at Universal Feedparser, a Python Package: http://code.google.com/p/feedparser/ http://packages.python.org/feedparser -- Yonder nor sorghum stenches shut ladle gulls stopper torque wet strainers. -- https://mail.python.org/mailman/listinfo/python-list
