Re: using target words from arrays in regex, pythons version of perls 'map'
I don't like string interpolation within REs, it pops me out of 'RE mode' as I scan the line. Maybe creating a dict of matchobjects could be used in the larger context?: dict( [(t, re.search(t+regexp_tail, file2) for t in targets] ) (untested). - Pad. -- http://mail.python.org/mailman/listinfo/python-list
Re: using target words from arrays in regex, pythons version of perls 'map'
Think about how well the above solutions scale as len(targets) increases. 1. Make targets a set, not a list. 2. Have *ONE* regex which includes a bracketed match for a generic target e.g. ([A-Z\s]+) 3. Do *ONE* regex search, not 1 per target 4. If successful, check if the bracketed gizmoid is in the set of targets. It's not 100% apparent whether it is possible that there can be more than one target in the inappropriately named file2 (it is a string, isn't it?). If so, then write your own findall-like loop wrapped around steps 2 3 above. Compile the regex in advance. HTH, John -- http://mail.python.org/mailman/listinfo/python-list
Re: using target words from arrays in regex, pythons version of perls 'map'
Would you believe steps 3 4? -- http://mail.python.org/mailman/listinfo/python-list
Re: using target words from arrays in regex, pythons version of perls 'map'
Dennis Lee Bieber [EMAIL PROTECTED] wrote in message
news:[EMAIL PROTECTED]
On Mon, 15 May 2006 19:41:39 -0500, Lance Hoffmeyer
[EMAIL PROTECTED] declaimed the following in comp.lang.python:
I would have something similar to perl above:
targets = ['OVERALL RATING',
'CLOTHING', ITEMS',
'ACCESSORIES',
'SHOES',
'FINE JEWELRY']
PROPOSED CODE:
match2 = re.search(targets[i].*?(?:(\d{1,3}\.\d)\s+){3} ', file2);m[i] =
match2.group(1)
I don't do regex's, and I also don't find packing multiple statements on
one line attractive.
I concur - this kind of multiple-statements-per-line-ishness feels
gratuitous. Yes, I know they line up nicely when all 6 statements are
printed out together, but the repetition of mNN = match2.group(1) ;print
mNN should tell you that this might be better done with a for loop. DRY.
However... Why don't you basically do what you say you do in
Python... Substitute you targets into the expression while inside a
loop...
targets = [ OVERALL RATING,
CLOTHING,
ITEMS,
ACCESSORIES,
SHOES,
FINE JEWELRY ]
results = []
for t in target:
m2 = re.search(%s.*?(?:(\d{1,3}\.\d)\s+){3} % t, file2)
results.append(m2.group(1))
--
# by contrast, here is a reasonably Pythonic one-liner, if one-liner it must
be
results = [ re.search(r%s.*?(?:(\d{1,3}\.\d)\s+){3} % t, file2).group(1)
for t in targets ]
# or for improved readability (sometimes 2 lines are better than 1):
reSearchFunc = lamdba tt,ff : re.search(tt + r.*?(?:(\d{1,3}\.\d)\s+){3},
ff).group(1)
results = [ reSearchFunc(t,file2) for t in targets ]
Resisting-the-urge-to-plug-pyparsing-ly yours,
-- Paul
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Re: using target words from arrays in regex, pythons version of perls 'map'
John Machin wrote: Would you believe steps 3 4? How about two pops and a pass? Quick! Lower the cone of silence! -- Edward Elliott UC Berkeley School of Law (Boalt Hall) complangpython at eddeye dot net -- http://mail.python.org/mailman/listinfo/python-list
using target words from arrays in regex, pythons version of perls 'map'
Hey all, in perl I was able to use the same regular expression multiple times
changing one part of it
via a previously defined array and put the results into a new array
IN PERL:
my @targets = ('OVERALL RATING',
'CLOTHING', '
ITEMS',
'ACCESSORIES',
'SHOES',
'FINE JEWELRY');
my @JA13 = map {
$file2 =~/$_.*?(?:(\d{1,3}\.\d)\s+){3}/s;
} @targets;
So, in python instead of
match2 = re.search('OVEWRALL RATING.*?(?:(\d{1,3}\.\d)\s+){3} ', file2);m01 =
match2.group(1) ;print m01
match2 = re.search('CLOTHING.*?(?:(\d{1,3}\.\d)\s+){3} ', file2); m02 =
match2.group(1) ;print m02
match2 = re.search('ITEMS.*?(?:(\d{1,3}\.\d)\s+){3} ', file2); m03 =
match2.group(1) ;print m03
match2 = re.search('ACCESSORIES.*?(?:(\d{1,3}\.\d)\s+){3} ', file2);m04 =
match2.group(1) ;print m04
match2 = re.search('SHOES.*?(?:(\d{1,3}\.\d)\s+){3} ', file2); m05 =
match2.group(1) ;print m05
match2 = re.search('FINE JEWELRY.*?(?:(\d{1,3}\.\d)\s+){3} ', file2); m06 =
match2.group(1) ;print m06
I would have something similar to perl above:
targets = ['OVERALL RATING',
'CLOTHING', ITEMS',
'ACCESSORIES',
'SHOES',
'FINE JEWELRY']
PROPOSED CODE:
match2 = re.search(targets[i].*?(?:(\d{1,3}\.\d)\s+){3} ', file2);m[i] =
match2.group(1)
Lance
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