Regular expression worries
folks I am new to python, so excuse me if i am asking stupid questions. I have a txt file and here are some lines of it Document Keyword Keyword Keyword Keyword Keyword Keyword Keyword Keyword Keyword Keywordhttp://mail.python.org/mailman/listinfo/python-list
stripping parts of elements in a list
folks, I am new to python. I have a list made of elements ['amjad\n', 'kiki\n', 'jijiji\n'] I am trying to get rid of '\n' after each name. to get list as ['amjad','kiki','jijiji'] But list does not have a strip function as string does have. is there any solutions Is there a way this can be done?? -- http://mail.python.org/mailman/listinfo/python-list
looping through two list simultenously
folks
I have two lists
i am trying to loop thorough them simultenously.
Here is the code i am using
f1 = os.popen('ls chatlog*.out')
data1=f1.readlines()
f1.close()
data1=[x.strip() for x in data1]
f1 = os.popen('ls chatlog*.txt')
data=f1.readlines()
f1.close()
for eachline in data1 and line in data:
filename='/root/Desktop/project/'+ eachline
print filename
outfile=open(filename,'r')
filename1='/root/Desktop/project/' + line
print filename1
I get the error that line is not defined.
Traceback (most recent call last):
File "list.py", line 16, in ?
for eachline in data1 and line in data:
NameError: name 'line' is not defined
Is there any efficient doing this
--
http://mail.python.org/mailman/listinfo/python-list
Replacing line in a text file
Folks I am trying to read a file This file has a line containing string 'disable = yes' I want to change this line to 'disable = no' The concern here is that , i plan to take into account the white spaces also. I tried copying all file int list and then tried to manipulate that list But the search is not working Any answer thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: getting from command line options to file
On Apr 16, 1:08 pm, Michael Hoffman <[EMAIL PROTECTED]> wrote:
> CSUIDL PROGRAMMEr wrote:
> > hi folks
> > I am new to python. I have a module does call a os.command(cmd) where
> > cmd is a rpm command.
> > Instead of using os.command and getting the results on command line ,
> > i would like to dump the output in a file. Is os.command(cmd >
> > filename) the most efficient command??
>
> I think the best thing to do would be something like this (Python 2.5):
>
> from __future__ import with_statement
> import subprocess
>
> with file("test.out", "w") as outfile:
> subprocess.check_call(["ls", "/etc"], stdout=outfile)
> --
> Michael Hoffman
but what if i have python which is 2.4??
--
http://mail.python.org/mailman/listinfo/python-list
Redirection problem
I am new to python. so be patient with me
I am trying to redirect the output of os.popen command to a file. I
want to append to that file. but instead of appending. The file only
shows last command that was writtenn to it.
filehandle= open("/root/yhpc-2.0/installer/yhpc-log" ,"a+");
filehandle.write(" Command executed is " + cmd);
try:
pipe= os.popen('%s > /root/yhpc-2.0/installer/yhpc-log' %cmd );
except : IOError;
filehandle.close();
Any suggestion would help.
filehandle.close();
--
http://mail.python.org/mailman/listinfo/python-list
defining user exceptions
I am trying to write a user defined exception that will catch for failed dependencies when a rpm is installed try: rpm -ivh xxx.rpm --force; except RPMError: print RPM failed dependency Can some one tell me how to define this RPMError. I looked at python docs but they were not useful. -- http://mail.python.org/mailman/listinfo/python-list
RPM error
Hi folks I am trying to write a program that will install RPM. IS there any built in Exception in python that will catch the faied dependencies in python. Also if not how can i write one ?? thanks -- http://mail.python.org/mailman/listinfo/python-list
RPM error
Hi folks I am new to python I am trying to write a program that will install rpm using rpm -ivh xxx.rpm I want to know if python has in-built exceptions to catch no- dependencies error. If not how can i build them thanks -- http://mail.python.org/mailman/listinfo/python-list
getting from command line options to file
hi folks I am new to python. I have a module does call a os.command(cmd) where cmd is a rpm command. Instead of using os.command and getting the results on command line , i would like to dump the output in a file. Is os.command(cmd > filename) the most efficient command?? thanks -- http://mail.python.org/mailman/listinfo/python-list
getting the name of hyperlinks in a file
folks, I am trying to write a script that would open a download server and download all the files and store them in a list for example Download server is http://download.fedora.redhat.com/pub/fedora/linux/core/updates/5/SRPMS/ is there any way this can be done in python?? -- http://mail.python.org/mailman/listinfo/python-list
parsing a file name
I have a filename cairo-2.3.4.src.rpm Is there any way i can only get 2.3.4 from this file name thanks -- http://mail.python.org/mailman/listinfo/python-list
url lib
Hello
I am a novice python progammer
I am just writing a script that will automatically write my /etc/
yum.repos.d/* files in linux.
the problem is i am trying to connect to a secure repo and pass
username and password to the baseurl .
here is the baseurl
baseurl=http://USERNAME:passw...@ydl.net/yum/6.1/../../../.
I have tried using the urllib2 in python
the code i tried was
req=urllib2.Request("http://USERNAME:passw...@ydl.net/cell/yum/6.1/
base)
try: urllib2.urlopen(req)
except urllib2.URLError,e:
Where Username:PASSWORD are speciefied by user
The Error i got was
File "/usr/lib/python2.4/urllib2.py", line 130, in urlopen
return _opener.open(url, data)
File "/usr/lib/python2.4/urllib2.py", line 358, in open
response = self._open(req, data)
File "/usr/lib/python2.4/urllib2.py", line 376, in _open
'_open', req)
File "/usr/lib/python2.4/urllib2.py", line 337, in _call_chain
result = func(*args)
File "/usr/lib/python2.4/urllib2.py", line 1021, in http_open
return self.do_open(httplib.HTTPConnection, req)
File "/usr/lib/python2.4/urllib2.py", line 980, in do_open
h = http_class(host) # will parse host:port
File "/usr/lib/python2.4/httplib.py", line 592, in __init__
self._set_hostport(host, port)
File "/usr/lib/python2.4/httplib.py", line 604, in _set_hostport
raise InvalidURL("nonnumeric port: '%s'" % host[i+1:])
httplib.InvalidURL: nonnumeric port: 'passw...@ydl.net'
How can i connect to the site with password?? Do i have to implement
the ssl certification??
--
http://mail.python.org/mailman/listinfo/python-list
