Lists of list
Hi All I am having problem with delete line if its belong to another one , example ['0132442\n', '13\n', '24\n'] the 2nd and 3rd are already in the first line , how can do this !!! Thanks -- http://mail.python.org/mailman/listinfo/python-list
List of strings
Hi All Thanks for your reply , what i am doing is , i am reading from file , using readlines() , I would like to check in these lines , if there is line belong to another one or not , if it is , then i would like to delete it ['0132442\n', '13\n', '24\n'] '13' is already in '0132442' '24' is already in '0132442' Thanks -- http://mail.python.org/mailman/listinfo/python-list
Re: List of string
> > > > > >Mohammed Altaj wrote: > > >>Hi All >> >>I am having problem with delete line if its belong to another one , example >> >> > >I think, you mean to remove all lines that are substrings of another >line. > >l = ['0132442\n', '13\n', '24\n'] >l = [e.strip() for e in l] > >i = 0 >while True: > try: >for j in range(len(l)): > if i == j: >continue > if l[j].find(l[i]) >= 0: ># line 'j' is superstring of line 'i' >del l[i] >break >else: # doesn't have superstring > i += 1 > except IndexError: >break > >Basically, I try all n*n combinations, and remove substring lines >"in-place". > >BranoZ > > > > > Thanks , but , this work for an ordered substrings , just like what we had ['0132442\n', '13\n', '24\n'] , I would like to remove all substrings from the list , example ['0134314244133', '132443', '234'] 2nd and 3rd strings are also substrings from the 1st one , so it should be removed Thanks -- http://mail.python.org/mailman/listinfo/python-list
split function
Hi All I am reading data from file using readlines() to list , my question is how to deal with space between any two numbers , I mean , my data looks like 1 3 3 4 5 2 6 1 I tried to with my data as it, but i couldn't , so i removed the spaces 13 34 52 61 But when i deal with large number > 9 , i tried to use split function , but doesn't work , I can attach my code if its good idea to do ,, Thanks -- http://mail.python.org/mailman/listinfo/python-list
split function
Dear All
What i want to do is , my input is like
0 2
0 3
0 4
1 2
1 4
2 3
3 4
I am comparing and put the number in group , like ,the first three lines
, all has zero as first input for each line, so the out put should look
like
0 2 3 4
and so on
1 2 4
2 3
3 4
I managed to do what i need , but i did in this case , there is no space
between numbers , like
02
03
04
12
14
23
34
so , how can i do this with spaces between numbers
This is my code
def belong_to(x,a):
c=-1
for i in range(len(a)-1):
if x==int(a[i]):
c=i
return c
def list_belong(x,a): # This function to check if this line
c=-1 # line has been searched
before or not
for i in range(len(a)):
if a[i]==x:
c=1
break
return c
x=0
occur=[]
in_file=open('data.dat','r')
out_file=open('result.dat','w')
fileList = in_file.readlines()
for k in fileList:
v=k
occur.append(k)
n=len(v)-1
for i in range(n):
temp=int(v[i])
print temp,
out_file.write(str(temp))
for line in fileList:
if v!=line:
if list_belong(line,occur)!=1:
if belong_to(temp,line) != -1:
j=belong_to(temp,line)
for i in range(len(line)-1):
if i!=j:
print line[i],
out_file.write(line[i])
print
out_file.write("\n")
out_file.close()
in_file.close()
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split function
Dear all
Sorry , I confused between two things , what i said in the last e-mail i
already managed to do using C code , But what i need to do using python
is : my input data :
0 2 3 4
1 2 4
2 3
3 4
what i suppose to do is , using the first line and start searching
number by number ,first i have 0 search in the rest of lines if there is
0 print out the all numbers except 0 , after that , start searching
using the 2ed element in the first line which is 2 , in the 2ed line we
have 1 , 4 . in the 3rd line we have 3 , in the 4th line we do not have
2. And so on for 3 and 4 , and also for the 2nd , 3rd lines , so the
output should be
0 2 1 4 3 3 2 4 4 1 2 3
1 2 3 4 3
2 3
3 4
And i managed to do this , but i did in the case of no space between
numbers,when i am reading from file , like
0234
124
23
34
I want my code be able to deal with the space between numbers , and this
is my code again
def belong_to(x,a):
c=-1
for i in range(len(a)-1):
if x==int(a[i]):
c=i
return c
def list_belong(x,a):# This function to check if this line
c=-1 # line has been searched before or not
for i in range(len(a)):
if a[i]==x:
c=1
break
return c
x=0
occur=[]
in_file=open('data.dat','r')
out_file=open('result.dat','w')
fileList = in_file.readlines()
for k in fileList:
v=k
occur.append(k)
n=len(v)-1
for i in range(n):
temp=int(v[i])
print temp,
out_file.write(str(temp))
for line in fileList:
if v!=line:
if list_belong(line,occur)!=1:
if belong_to(temp,line) != -1:
j=belong_to(temp,line)
for i in range(len(line)-1):
if i!=j:
print line[i],
out_file.write(line[i])
print
out_file.write("\n")
out_file.close()
in_file.close()
Thanks
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how to deal with space between numbers
Dear All
This is my problem again , I tried to sort it out , but i couldn't , I
am reading data from file using readlines , my input like :
0 1 2 4
1 2 4
2 3
3 4
What i am doing is , starting with the first element in the first line (
which is 0 in this case )and do search in the other lines , if i found
another 0 , i will save (print out) all the elements except 0 , (in this
is case i have no 0 elsewhere) so i will print only 0. Now do search by
the 2nd element in the first line (which is 1 in this case) , in the 2nd
line we have 1 , so i should save(print out) all elements except 1 which
are 2 4 , and so on for the rest of the first line , and for the rest of
the file , my out put should be
0 1 2 4 2 1 4 3 4 1 2 3
1 2 3 4 3
2 3 4
3 4
I managed to do all these things , but i did it in the way that i am
reading my data as strings ( no space between numbers) something like
0124
124
23
34
what i would like to know or to do is , how can i deal with my data
after reading it as strings(i need the space between numbers) because i
had problem when dealing with number larger than 9 , example :
0 1 5 9
1 12 10
4 6 7
10 9
so , when i remove the space between numbers , i loose all my data , i
mean it will look like
0159
11210
467
509
This is my code :
def belong_to(x,a):
c=-1
for i in range(len(a)-1):
if x==int(a[i]):
c=i
return c
def list_belong(x,a):# This function to check if this line
c=-1 # line has been searched before or not
for i in range(len(a)):
if a[i]==x:
c=1
break
return c
x=0
occur=[]
in_file=open('data.dat','r')
out_file=open('result.dat','w')
fileList = in_file.readlines()
for k in fileList:
v=k
occur.append(k)
n=len(v)-1
for i in range(n):
temp=int(v[i])
print temp,
out_file.write(str(temp))
for line in fileList:
if v!=line:
if list_belong(line,occur)!=1:
if belong_to(temp,line) != -1:
j=belong_to(temp,line)
for i in range(len(line)-1):
if i!=j:
print line[i],
out_file.write(line[i])
print
out_file.write("\n")
out_file.close()
in_file.close()
Thank you all
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Re:how to deal with space between numbers
> > >Read my answers to your two previous posts. >(in short : use str.split() - but *do* read my answers if you want to >save you a lot of pain) > > > > > > > Thanks a lot for your valuable answer, i like the way you code , but i would like to use my own, so if it is possible for you and if you have time, please could you fix my code, so that i can do what i want. Because i am using the this out put to another one , and i have the same problem. I will really appreciate it !!! Regards -- http://mail.python.org/mailman/listinfo/python-list
