substitute filename with self.filename than it should work
All the best
Horst Düster
Am 24.03.2014 17:45, schrieb Suryo Miles:
I make plugin in QGIS to open and read XML file, then parse it and show
scale map from it, its a big xml file and line with scale information have
format like this
gmd:denominatorgco:IntegerScaleValue/gco:Integer/gmd:denominator
and i try code like this to open xml file and then parse it:
from PyQt4 import QtCore, QtGuifrom ui_latih import Ui_latih# create
the dialog for zoom to point
class latihDialog(QtGui.QDialog):
def __init__(self):
QtGui.QDialog.__init__(self)
# Set up the user interface from Designer.
self.ui = Ui_latih()
self.ui.setupUi(self)
cariButton = self.ui.btnCari
QtCore.QObject.connect(cariButton,
QtCore.SIGNAL('clicked()'),self.cari)
def cari(self, event=None):
#open dialog
filename = QtGui.QFileDialog.getOpenFileName(self, 'Open File',
'*.xml')
self.ui.lineFile.setText(filename)
#call text
self.isiDataFile(filename)
def isiDataFile(self, nmfile):
#open with read mode
teksFile = open(nmfile, 'r').read()
self.ui.textFile.setText(teksFile)
import xml.etree.ElementTree as ET
tree = ET.parse(filename)
doc = tree.getroot()
for elem in doc.findall('Default_Config/gmd:denominator'):
x = elem.tag, elem.text
self.ui.lineSkala.setText(x)
for elem in doc.findall('Default_Config/gmd:MD_Format'):
y = elem.tag, elem.text
self.ui.lineFitur.setText(y)
I try using Element Tree to parse and show ScaleValue in LineEdit because
its integrated in python, but i have error message like this :
NameError: name 'filename' is not defined
i am really newbie in python and xml parser, can i pass the xml location
from open xml code to
tree = ET.parse( )
because i plan to open more than one xml file and scale in one and another
xml file have different value as well
Can Someone help me?
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