Re: [Rd] Testing for vectors

2018-07-08 Thread Hadley Wickham
On Sat, Jul 7, 2018 at 11:19 PM, Gabe Becker  wrote:
> Hadley,
>
>
> On Sat, Jul 7, 2018 at 1:32 PM, Hadley Wickham  wrote:
>>
>> On Sat, Jul 7, 2018 at 1:50 PM, Gabe Becker  wrote:
>> > Hadley,
>> >
>> >>
>> >> I was thinking primarily of completing the set of is.matrix() and
>> >> is.array(), or generally, how do you say: is `x` a 1d dimensional
>> >> thing?
>> >
>> >
>> > Can you clarify what you mean by dimensionality sense and specifically
>> > 1d
>> > here?
>>
>> What do we call a vector that is not an array? (or matrix)
>>
>> What do we call an object that acts 1-dimensional? (i.e. has
>> length(dim()) %in% c(0, 1)) ?
>
>
>
> Right, or even (length(dim()) == 0 || sum(dim() > 1) <= 1)
>
>  but that is exactly my point, those two(/three) sets of things are not the
> same. 1d arrays meet the second definition but not the first. Matrices and
> arrays that don't meet either of yours would still meet mine. Which
> definition are you proposing strictly define what a vector is?

I am not proposing any definition. I am enquiring if there is a
definition in base R. The answer appears to be now.

> Another completely unrelated way to define vector, btw, is via the vector
> interface (from what I recall this is roughly [, [[, length, and format
> methods, though I'm probably forgetting some). This is (more or less)
> equivalent to defining a vector as "a thing that can be the column of a
> data.frame and have all the base-provided machinery work".

I don't know if that definition is adequate because a call would be a
vector by that definition. I'm pretty sure a call does not make sense
as a data frame column.

Also technically data frames don't require their columns to have equal
length(), but equal NROW(). So the spirit of that definition would
imply that a matrices and arrays are also vectors, which seems like it
might be undesirable.

Hadley

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Re: [Rd] Testing for vectors

2018-07-08 Thread Hadley Wickham
On Sat, Jul 7, 2018 at 3:48 PM, Ott Toomet  wrote:
> Thanks, Hadley for bringing this up:-)
>
> I am teaching R and I can suggest 5 different definitions of 'vector':
>
> a) vector as a collection of homogeneous objects, indexed by [ ] (more
> precisely atomic vector).  Sometimes you hear that in R, "everything is a
> vector", but this is only true for atomic objects.
> b) vector as a collection of objects, indexed by either [ ] and [[ ]].  This
> includes atomic vectors and lists.
> c) vector versus scalar.  It pops up when teaching math and stats, and is
> somewhat confusing, in particular if my previous claim was that "R does not
> have scalars".
> d) vector versus matrix (or other arrays).  Again, it only matters when
> doing matrix operations where 'vectors', i.e. objects with NULL dimension,
> behave their own way.
> e) finally, 'is.vector' has it's own understanding what constitutes a
> vector.

Yes!

And to add to the confusion there are three meanings to numeric vector:

* As an alias for double (i.e. numeric() and as.numeric())
* To refer to integer and double types jointly (as is S3 and S4 class)
* A vector that behaves as if it is a number (e.g. is.numeric(), which
excludes factors)

Hadley

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Re: [Rd] Testing for vectors

2018-07-07 Thread Ott Toomet
Gabe,
I agree that

If by standard you mean commonly used/understood, though, I doubt
> most R users would understand a list to be a vector. I think most people
> think of atomic vectors exclusively when they hear "vector" unless they've
> very specifically been trained not to do so.


However, a common way to create lists is by a construct like
'vector("list", n)'.  Also, 'is.vector' reports TRUE for lists (but FALSE
for many other vectors).  This causes quite a bit of confusion, unless
everyone understands the different 'vector' concepts, embedded in R.

Cheers,
Ott

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Re: [Rd] Testing for vectors

2018-07-07 Thread Gabe Becker
Hadley,


On Sat, Jul 7, 2018 at 1:32 PM, Hadley Wickham  wrote:

> On Sat, Jul 7, 2018 at 1:50 PM, Gabe Becker  wrote:
> > Hadley,
> >
> >>
> >> I was thinking primarily of completing the set of is.matrix() and
> >> is.array(), or generally, how do you say: is `x` a 1d dimensional
> >> thing?
> >
> >
> > Can you clarify what you mean by dimensionality sense and specifically 1d
> > here?
>
> What do we call a vector that is not an array? (or matrix)
>
> What do we call an object that acts 1-dimensional? (i.e. has
> length(dim()) %in% c(0, 1)) ?
>


Right, or even (length(dim()) == 0 || sum(dim() > 1) <= 1)

 but that is exactly my point, those two(/three) sets of things are not the
same. 1d arrays meet the second definition but not the first. Matrices and
arrays that don't meet either of yours would still meet mine. Which
definition are you proposing strictly define what a vector is?

Before we have a function which performs the test we need to actually know
what is being tested. So again I would mirror Duncan's question: What code
do you have now or are you planning to write that needs to check this, and
how would it feel about the various types of objects being discussed here?

In other words, in what cases do you actually need to strictly check if
something "is a vector"?

Another completely unrelated way to define vector, btw, is via the vector
interface (from what I recall this is roughly [, [[, length, and format
methods, though I'm probably forgetting some). This is (more or less)
equivalent to defining a vector as "a thing that can be the column of a
data.frame and have all the base-provided machinery work".

> You can also have an n x 1 matrix, which technically has 2 dimensions but
> > conceptually is equivalent to a 1d array and/or a vector.
>
> Yes. You can also have array that's n x 1 x 1.
>
> > Also, are you including lists in your conceptions of 1d vector here? I'm
> > with Duncan here, in that i'm having trouble understanding exactly what
> you
> > want to do without a bit more context.
>
> Isn't it standard terminology that a vector is the set of atomic vectors +
> list?
>

Maybe. If by standard you mean commonly used/understood, though, I doubt
most R users would understand a list to be a vector. I think most people
think of atomic vectors exclusively when they hear "vector" unless they've
very specifically been trained not to do so.

Best,
~G



>
> Hadley
>
> --
> http://hadley.nz
>



-- 
Gabriel Becker, Ph.D
Scientist
Bioinformatics and Computational Biology
Genentech Research

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Re: [Rd] Testing for vectors

2018-07-07 Thread Ott Toomet
Thanks, Hadley for bringing this up:-)

I am teaching R and I can suggest 5 different definitions of 'vector':

a) vector as a collection of homogeneous objects, indexed by [ ] (more
precisely atomic vector).  Sometimes you hear that in R, "everything is a
vector", but this is only true for atomic objects.
b) vector as a collection of objects, indexed by either [ ] and [[ ]].
This includes atomic vectors and lists.
c) vector versus scalar.  It pops up when teaching math and stats, and is
somewhat confusing, in particular if my previous claim was that "R does not
have scalars".
d) vector versus matrix (or other arrays).  Again, it only matters when
doing matrix operations where 'vectors', i.e. objects with NULL dimension,
behave their own way.
e) finally, 'is.vector' has it's own understanding what constitutes a
vector.

Maybe there are more...  I don't think there are any easy answers but both
me and my students would appreciate more consistent terminology.

Cheers,
Ott



On Sat, Jul 7, 2018 at 1:32 PM, Hadley Wickham  wrote:

> On Sat, Jul 7, 2018 at 1:50 PM, Gabe Becker  wrote:
> > Hadley,
> >
> >>
> >> I was thinking primarily of completing the set of is.matrix() and
> >> is.array(), or generally, how do you say: is `x` a 1d dimensional
> >> thing?
> >
> >
> > Can you clarify what you mean by dimensionality sense and specifically 1d
> > here?
>
> What do we call a vector that is not an array? (or matrix)
>
> What do we call an object that acts 1-dimensional? (i.e. has
> length(dim()) %in% c(0, 1)) ?
>
> > You can also have an n x 1 matrix, which technically has 2 dimensions but
> > conceptually is equivalent to a 1d array and/or a vector.
>
> Yes. You can also have array that's n x 1 x 1.
>
> > Also, are you including lists in your conceptions of 1d vector here? I'm
> > with Duncan here, in that i'm having trouble understanding exactly what
> you
> > want to do without a bit more context.
>
> Isn't it standard terminology that a vector is the set of atomic vectors +
> list?
>
> Hadley
>
> --
> http://hadley.nz
>
> __
> R-devel@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-devel
>

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Re: [Rd] Testing for vectors

2018-07-07 Thread Hadley Wickham
On Sat, Jul 7, 2018 at 1:50 PM, Gabe Becker  wrote:
> Hadley,
>
>>
>> I was thinking primarily of completing the set of is.matrix() and
>> is.array(), or generally, how do you say: is `x` a 1d dimensional
>> thing?
>
>
> Can you clarify what you mean by dimensionality sense and specifically 1d
> here?

What do we call a vector that is not an array? (or matrix)

What do we call an object that acts 1-dimensional? (i.e. has
length(dim()) %in% c(0, 1)) ?

> You can also have an n x 1 matrix, which technically has 2 dimensions but
> conceptually is equivalent to a 1d array and/or a vector.

Yes. You can also have array that's n x 1 x 1.

> Also, are you including lists in your conceptions of 1d vector here? I'm
> with Duncan here, in that i'm having trouble understanding exactly what you
> want to do without a bit more context.

Isn't it standard terminology that a vector is the set of atomic vectors + list?

Hadley

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Re: [Rd] Testing for vectors

2018-07-07 Thread Gabe Becker
Hadley,


> I was thinking primarily of completing the set of is.matrix() and
> is.array(), or generally, how do you say: is `x` a 1d dimensional
> thing?
>

Can you clarify what you mean by dimensionality sense and specifically 1d
here?

You can have a 1d array which is different from what your proposed function
would call a vector. So is.null(dim(x)) doesn't seem the same as 1d, right?

> x = array(1:10)

> x

 [1]  1  2  3  4  5  6  7  8  9 10

> class(x)

[1] "array"

> dim(x)

[1] 10

> dim(1:10)

NULL


You can also have an n x 1 matrix, which *technically* has 2 dimensions but
conceptually is equivalent to a 1d array and/or a vector.

Also, are you including lists in your conceptions of 1d vector here? I'm
with Duncan here, in that i'm having trouble understanding exactly what you
want to do without a bit more context.

Best,
~G



>
> (I don't have any feel for whether the check should be is.null(dim(x))
> vs. length(dim(x)) <= 1)
>
> Hadley
> --
> http://hadley.nz
>
> __
> R-devel@r-project.org mailing list
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>
>


-- 
Gabriel Becker, Ph.D
Scientist
Bioinformatics and Computational Biology
Genentech Research

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Re: [Rd] Testing for vectors

2018-07-07 Thread Hadley Wickham
On Sat, Jul 7, 2018 at 12:54 PM, Duncan Murdoch
 wrote:
> On 07/07/2018 1:20 PM, Hadley Wickham wrote:
>>
>> Hi all,
>>
>> Is there are base function that I've missed that tests if an object is
>> a vector in the dimensionality sense, rather than the data structure
>> sense? i.e. something that checks is.null(dim(x)) ?
>>
>> is.vector() is trivially disqualified since it also checks for the
>> presence of non-names attributes:
>>
>> x <- factor(c("a", "a", "b"))
>> is.vector(x)
>> #> [1] FALSE
>>
>> is.null(dim(x))
>> #> [1] TRUE
>>
>
> I don't know of one.  I can't think of nontrivial cases where that
> distinction matters; do you know of any where base functions act differently
> on vectors and 1D arrays?  (A trivial example is that dimnames(x) gives
> different results for a named vector and an array with dimnames.)

I was thinking primarily of completing the set of is.matrix() and
is.array(), or generally, how do you say: is `x` a 1d dimensional
thing?

(I don't have any feel for whether the check should be is.null(dim(x))
vs. length(dim(x)) <= 1)

Hadley
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Re: [Rd] Testing for vectors

2018-07-07 Thread Duncan Murdoch

On 07/07/2018 1:20 PM, Hadley Wickham wrote:

Hi all,

Is there are base function that I've missed that tests if an object is
a vector in the dimensionality sense, rather than the data structure
sense? i.e. something that checks is.null(dim(x)) ?

is.vector() is trivially disqualified since it also checks for the
presence of non-names attributes:

x <- factor(c("a", "a", "b"))
is.vector(x)
#> [1] FALSE

is.null(dim(x))
#> [1] TRUE



I don't know of one.  I can't think of nontrivial cases where that 
distinction matters; do you know of any where base functions act 
differently on vectors and 1D arrays?  (A trivial example is that 
dimnames(x) gives different results for a named vector and an array with 
dimnames.)


Duncan Murdoch

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