[R] how to find and use specific column after spliting dataframe

2007-11-28 Thread leeznar


Dear all: 


I am a new R-user and I have 2 questions
about it.  


1) I need to find specific sub-dataframe,
and then use specific column to calculate. 
For example, after splitting dataframe, I find specific the
sub-dataframe, such as “A.split [1]”. 
But, I don’t know how to find “time” and “concentration” columns of “A.split
[1]”.  


2) The equation used to sub-dataframe is
(time[i]-time[i-1])*(concentration[i]- concentration[i-1])*1/2.  I don’t know 
how to calculate it.  How can I find the specific column and use it to 
calculate ? 



 


x-rep(c(1.2,6.8),4)


y-rep(c(1, 2),4)


z-rep(c(1,2),4)


t-rep(c(0,1,2,3),length.out=8)


c-rep(c(0,0.5,1,2),length.out=8)


df-data.frame(pH=x, formulation=y,
subject=z, time=t, concentration=c)


A.split-split(df, list(df$pH
,df$formulation, df$subject) )


A.split [1] 




 


Best regards,


Hsin-Ya Lee






  
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[R] How can I read the actual value (?) defined by set.seed(?) earlier?

2007-11-28 Thread Johannes Reichl
Hi all
 
I need to get the seed value that has been set by set.seed() earlier. I
only do have the workfile *.Rdata so I can not simply look to the code.

Thanx for any help, J

Mag. Johannes Reichl
Abteilung Energiewirtschaft
Energieinstitut an der Johannes Kepler Universität Linz
Altenberger Straße 69
A-4040 Linz
*
Tel.: +43-732-2468-5652
Fax: +43-732-2468-5651
Email: [EMAIL PROTECTED]

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Re: [R] normalised Voigt random numbers

2007-11-28 Thread Ben Bolker



Waterman, DG (David) wrote:
 
 Dear list,
 
 I would like to generate random numbers from a Voigt distribution,
 hopefully in a way as simple as getting random numbers from a normal
 distribution with 'rnorm'. Is there any package to do this? Speed is an
 issue in this application. Or, as the Voigt distribution is a
 convolution of a Gaussian and a Lorentzian, can I simply combine random
 numbers from rnorm and rcauchy in some way (I'm not sure about the maths
 of this)?
 
 

  I spent a while with the wikipedia entry on the Voigt distribution, which
gives
an expression for the pdf that I don't understand ... but the answer to your
question appears very simple.

rvoight - function(n,sigma,gamma) {
   rnorm(n,sd=sigma)+rcauchy(n,scale=1/gamma)
}

 at least according to the formulas on the wikipedia page.

  Ben Bolker

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Re: [R] if condition and for cycles

2007-11-28 Thread ljantunes

Thanks. It did solve the problem.

Luis

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[R] windows vista

2007-11-28 Thread Suzuky Pinto
Hello there

Im suzuky Pinto from Mexico.
And Im buying a new computer and this have windows vista. Could I have any 
problem using R on it?
thabks
 
Suzuky**


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[R] Print Summary

2007-11-28 Thread dave mitchell
Dear All,
I am currently working on a project involving a rather redundant task.  I
have 11 files that I will be generating anova tables and plots for.  I am
contemplating writing a for loop to process each file, create an anova
table, the appropriate plots, and save them to my hard drive.  I've included
pseudo-code below.

files = c(,..,..,...,...)
for (i in 1:10){
read.csv(files[i])
plot(.)
bitmap(..) #or one of the many other plot saving functions
model = lm(.)
anova(model)


This is where I am stuck.  I'd like to have the anova table from all of my
respective models print to one nice file.  I know methods exist for
extracting coefficients and the like from an anova-data.frame-class object,
however is it possible to save the exact print-out without having to copy
and paste 12 times?  Any help is greatly appreciate.


It seems like a lot of work for saving a few minutes, but i'll be leaving
the script for another in our lab (who may or may not know R too well) when
I leave.


Best,
Dave Mitchell

Student
University of Illinois-Champaign Urbana

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[R] Fortran Code to R Code

2007-11-28 Thread Bryan Klingaman
How do you convert Fortran Code to R Code to use and execute in R?  Or how do 
you take Fortran code and make it run in R?  So what I'm getting at is, I have 
some code in fortran and I want to be able to run that same code for R.  Please 
email me back and let me know how to do that, thanks.
   
  Bryan
  Email: [EMAIL PROTECTED]

   
-

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Re: [R] GAM with constraints

2007-11-28 Thread lubaroz


Simon Wood-4 wrote:
 
 Are you interested in equality constraints or inequality constraints?
 
No, I am interested in 2 kinds of inequality constraints: 
1) monotonic splines
2) positive coefficients of the variables, which are not splines.
It seems that pcls should be able to deal with both of them, if smoothing
parameters are given, should it not?


Simon Wood-4 wrote:
 
 `pcls' is really useful for the inequality constraint case (e.g. when you
 want 
 shape preserving smooths). For fixed smoothing parameters you can embed
 this 
 in an IRLS loop for gam fitting also, but convergence can be tricky, and 
 smoothing parameter selection not so straightforward.
 
The question here is how one can obtain smoothing parameters, given
inequality constraints. I've read your article Monotonic smoothing splines
fitted by cross-validation, where you explain how the penalties are
calculated. Is there a routine in R that can do it? 

I want to build a GAM regression with constraints using performance
iteration, which updates the penalties taking the constraints in account. Do
you think this would improve the model compared to one where penalties are
generated without constraints, and then the coefficients are calculated
using pcls() with all the constraints?

  Luba
P.S. Thank you for your detailed answer.
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Re: [R] problem with plotting table

2007-11-28 Thread Bernardo Rangel Tura

On Tue, 2007-11-27 at 13:01 -0500, Carlos Gershenson wrote:
 Hi all,
 
 Let us have:
 
 x-1:10
 y-x/2
 plot(table(x), type=p)
 points(table(y), pch=2)
 
 
 Why does the last command plots the values of table(y) using the x  
 coordinates of table(x)???
 Am I doing something wrong?
 What would be a way of plotting the points of table(y) on their place?
 
 #this problem also occurs with:
 plot(table(y), type=p)
 points(table(x), pch=2)
 
 
 Thank you very much,
 Carlos


Hi Carlos 

In your command plot(table(y), type=p), you plot a numeric part of
table(y), in this case:

y
0.5   1 1.5   2 2.5   3 3.5   4 4.5   5 
  1   1   1   1   1   1   1   1   1   1

So you plot the number 1 always. Same for table (x).

Have two possible solutions:

plot(as.numeric(names(table(x))), type=p)
points(as.numeric(names(table(y))), pch=2)


OR

x-1:10
y-x/2
plot(x, type=p)
points(y, pch=2)

If you need more help send a mail



-- 
Bernardo Rangel Tura, M.D,MPH,Ph.D
National Institute of Cardiology
Brazil

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Re: [R] How can I read the actual value (?) defined by set.seed(?) earlier?

2007-11-28 Thread Prof Brian Ripley
On Wed, 28 Nov 2007, Johannes  Reichl wrote:

 I need to get the seed value that has been set by set.seed() earlier. I
 only do have the workfile *.Rdata so I can not simply look to the code.

You cannot: it is not stored at the time.  set.seed() sets .Random.seed, 
and you can save/restore that.  However, the workspace will only contain 
the current value, not the initial value.

Normally the history is saved when you save the workspace: perhaps you do 
still have that and can search it for your call to set.seed (if there is 
one: there need not be).

-- 
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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Re: [R] windows vista

2007-11-28 Thread Prof Brian Ripley

On Tue, 27 Nov 2007, Suzuky Pinto wrote:


Hello there

Im suzuky Pinto from Mexico.
And Im buying a new computer and this have windows vista. Could I have 
any problem using R on it?


Not from R itself.  See the rw-FAQ at

http://cran.r-project.org/bin/windows/base/rw-FAQ.html#Does-R-run-under-Windows-Vista_003f

for a discussion of this.  (People new to Vista often have trouble with 
installing/administering software, and some of their mistakes can be 
seen by searching the archives of this list.)



thabks

Suzuky**


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University of Oxford, Tel:  +44 1865 272861 (self)
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[R] Order observations in a dataframe

2007-11-28 Thread Serguei Kaniovski

Dear All,

Suppose I have the following dataframe:

country;weight;group
bul;10;1
cze;12;1
grc;12;1
hun;12;1
prt;12;1
rom14;1
fra;29;2
ita;29;2
gbr;29;2
aut;10;3
bel;12;3

The group variable denotes the id-number of a group of countries. How can
I re-label the groups in the descending order of their cumulative weight,
which wound be:

country;weight;group
fra;29;1
ita;29;1
gbr;29;1
bul;10;2
cze;12;2
grc;12;2
hun;12;2
prt;12;2
rom14;2
aut;10;3
bel;12;3

The first group has the largest sum of weights, the second, with the second
largest, and so on.

Thanks for your help,
Serguei Kaniovski


Austrian Institute of Economic Research (WIFO)

P.O.Box 91  Tel.: +43-1-7982601-231
1103 Vienna, AustriaFax: +43-1-7989386

Mail: [EMAIL PROTECTED]
http://www.wifo.ac.at/Serguei.Kaniovski
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[R] Odp: windows vista

2007-11-28 Thread Petr PIKAL
AFAIK No. At home I use R on Vista too. You just need to understand and 
follow Vista's protection and rights policy.

Petr
[EMAIL PROTECTED]

[EMAIL PROTECTED] napsal dne 27.11.2007 22:40:31:

 Hello there
 
 Im suzuky Pinto from Mexico.
 And Im buying a new computer and this have windows vista. Could I have 
any 
 problem using R on it?
 thabks
 
 Suzuky**
 
 
   Comparte video en la ventana de tus mensajes (y también tus fotos 
de Flickr). 
 Usa el nuevo Yahoo! Messenger versiĂłn Beta.
 http://mx.beta.messenger.yahoo.com/
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Re: [R] Different value between R variance and definition ofvariance

2007-11-28 Thread Stefano Calza
Hi!


maybe because sample variance has N-1 at the denominator (say degrees of 
freedom)?

so

all.equal((sum(x^2) - 100*mean(x)^2)/99, var(x)) ## TRUE 

but

(sum(x^2) - 100*mean(x)^2)/100 # == your value


Stef

On Wed, Nov 28, 2007 at 09:56:58AM +0100, Tine wrote:
TineHi!
Tine
TineLet us define random variable:
Tine  x = seq(0,1,length=100)
Tine
TineIf we calculate variance following definition E[(x-E(x))^2] we get:
Tine  mean( (x - mean(x))^2 ) # == mean(x^2) - mean(x)^2
Tine0.08501684
Tine
TineAnd if we use internal R function var:
Tine  var(x)
Tine0.08587559
Tine
TineCan anyone tells me why the difference?
Tine
Tine__
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Tineand provide commented, minimal, self-contained, reproducible code.

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[R] Different value between R variance and definition of variance

2007-11-28 Thread Tine
Hi!

Let us define random variable:
  x = seq(0,1,length=100)

If we calculate variance following definition E[(x-E(x))^2] we get:
  mean( (x - mean(x))^2 ) # == mean(x^2) - mean(x)^2
0.08501684

And if we use internal R function var:
  var(x)
0.08587559

Can anyone tells me why the difference?

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[R] fit linear regression with multiple predictor and constrained intercept

2007-11-28 Thread robert . ptacnik
Hi group,

I have this type of data
x(predictor), y(response), factor (grouping x into many groups, with 6-20
obs/group)

I want to fit a linear regression with one common intercept. 'factor'
should only modify the slopes, not the intercept. The intercept is expected
to be 0.

If I use
y~ x + factor, I get a different intercept for each factor level, but one
slope only

if I use
y~ x * factor, I get the interaction term I want, but the intercept is not
kept constant.
Also, if I constrain teh intercept in the regression model (y~a+x*factor),
I get estimates both for slope and intercept of each factor level.

Robert




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Re: [R] fit linear regression with multiple predictor and constrained intercept

2007-11-28 Thread Peter Dalgaard
[EMAIL PROTECTED] wrote:
 Hi group,

 I have this type of data
 x(predictor), y(response), factor (grouping x into many groups, with 6-20
 obs/group)

 I want to fit a linear regression with one common intercept. 'factor'
 should only modify the slopes, not the intercept. The intercept is expected
 to be 0.

 If I use
 y~ x + factor, I get a different intercept for each factor level, but one
 slope only

 if I use
 y~ x * factor, I get the interaction term I want, but the intercept is not
 kept constant.
 Also, if I constrain teh intercept in the regression model (y~a+x*factor),
 I get estimates both for slope and intercept of each factor level.

 Robert



   
You seem to be looking for the colon operator. In R, unlike certain
other statistical packages, the star implies inclusion of main effects:
a*b is a + b + a:b. There is some trickery about when you get factors
contrast coded in interaction terms (as far as I remember x:factor and
x+x:factor are two different parametrizations of the same model), but
you should be able to find that out by a little experimenting.

-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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Re: [R] fit linear regression with multiple predictor and constrained intercept

2007-11-28 Thread Prof Brian Ripley

I think you are looking for y ~ x + x:factor   E.g.


library(car)
lm(repwt ~ repht + repht:sex, data=Davis)


Coefficients:
(Intercept)repht   repht:sexM
  -59.30865  0.71412  0.05694

where the third term is the difference in slope between males and females.


lm(repwt ~ repht:sex, data=Davis)


Coefficients:
(Intercept)   repht:sexF   repht:sexM
   -59.3086   0.7141   0.7711

for separately reported slopes.

If you want to constrain the intercept, fit with and without and take the 
better fit (or look into package nnls, but that would be overkill here).



On Wed, 28 Nov 2007, [EMAIL PROTECTED] wrote:


Hi group,

I have this type of data
x(predictor), y(response), factor (grouping x into many groups, with 6-20
obs/group)

I want to fit a linear regression with one common intercept. 'factor'
should only modify the slopes, not the intercept. The intercept is expected
to be 0.

If I use
y~ x + factor, I get a different intercept for each factor level, but one
slope only

if I use
y~ x * factor, I get the interaction term I want, but the intercept is not
kept constant.
Also, if I constrain teh intercept in the regression model (y~a+x*factor),
I get estimates both for slope and intercept of each factor level.

Robert




--
NIVAs hovedkontor har flyttet til nye lokaler i CIENS - Forskningssenter
for miljø og samfunn; Gaustadalléen 21, 0349 Oslo. Meld deg på vårt
nyhetsbrev på www.niva.no
__
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--
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595__
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Re: [R] Plotting Vector Fields

2007-11-28 Thread Tomas Bacigal


Plotting vector fields as we know it from Wolfram Mathematica's
PlotVectorField[{f1(x1), f2(x2)}, {x1, min, max}, {x2, ymin, ymax},
PlotPoints - ...]


###  FUNCTION DEFINITION

#! Outer product with vector function ###
# expand.outer joins functionality of expand.grid and outer, so that
# a vector function can be applied, values of which are then stored in
collumns.
# Combinations of x and y are expanded into vectors of length n*m,
where
# n = length(x), m = length(y) and this ordering is preserved also in
'values'.
# Matrix of values (list item 'values') and expanded variables (list
items 'x','y') are returned.

expand.outer - function(x, y, vecfun) {
xy.pairs - expand.grid(x=x, y=y, KEEP.OUT.ATTRS = FALSE)
x.exp - xy.pairs$x
y.exp - xy.pairs$y
list(values=matrix(vecfun(x.exp,y.exp), nrow=2, byrow=TRUE), x=x.exp,
y=y.exp)
}

#! vector field plot function
# grid.points can be defined for both axes at once or separately

plotVectorField - function(vecfun, xlim, ylim, grid.points)   {
gp - if(length(grid.points)1) grid.points else rep(grid.points,2)
maxlength - c(diff(xlim),diff(ylim))/(gp-1)*0.9
#prepare data
x0 - seq(xlim[1], xlim[2], length=gp[1])
y0 - seq(ylim[1], ylim[2], length=gp[2])
xy.data - expand.outer(x0, y0, vecfun)
x0 - xy.data$x
y0 - xy.data$y
dx - xy.data$values[1,]
dy - xy.data$values[2,]
#scale
k - min( maxlength / c(max(abs(dx)),max(abs(dy))) )
x1 - x0 + k*dx
y1 - y0 + k*dy
#plot
plot.default(range(x0,x1), range(y0,y1), main=Vector field, xlab=,
ylab=, type=n, frame.plot=F)
arrows(x0,y0,x1,y1,length = 0.08, angle = 20, code = 2)
}

### FUNCTION CALL

plotVectorField(function(x1,x2) c(x2,-x1), c(-1,1), c(-1,1), 9)


Tomas Bacigal

---Original message 
From: [EMAIL PROTECTED]
Date: Fri 25 Jul 2003 - 10:47:03 EST

 Message-id: [EMAIL PROTECTED]

 Dear R List,

 Is there a function to plot vector fields in R?

 I'm looking for something similar to PlotVectorField in Mathematica
 (see below), e.g. given functions f(x) and f(y), I would like to plot
 the resulting field of vectors (f(x),f(y)) over some range of x and y.

 PlotVectorField[{f(x), f(y)}, {x, xmin, xmax}, {y, ymin, ymax}]

 Thanks for your help,
 Brian

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Re: [R] Print Summary

2007-11-28 Thread Henrique Dallazuanna
Perhaps:

?capture.output
?sink


On 28/11/2007, dave mitchell [EMAIL PROTECTED] wrote:

 Dear All,
 I am currently working on a project involving a rather redundant task.  I
 have 11 files that I will be generating anova tables and plots for.  I am
 contemplating writing a for loop to process each file, create an anova
 table, the appropriate plots, and save them to my hard drive.  I've
 included
 pseudo-code below.

 files = c(,..,..,...,...)
 for (i in 1:10){
 read.csv(files[i])
 plot(.)
 bitmap(..) #or one of the many other plot saving functions
 model = lm(.)
 anova(model)


 This is where I am stuck.  I'd like to have the anova table from all of my
 respective models print to one nice file.  I know methods exist for
 extracting coefficients and the like from an anova-data.frame-classobject,
 however is it possible to save the exact print-out without having to copy
 and paste 12 times?  Any help is greatly appreciate.


 It seems like a lot of work for saving a few minutes, but i'll be leaving
 the script for another in our lab (who may or may not know R too well)
 when
 I leave.


 Best,
 Dave Mitchell

 Student
 University of Illinois-Champaign Urbana

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-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O

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[R] Vacancy: UC Merced

2007-11-28 Thread Anthony Westerling
University of California Merced
Merced, CA
Programmer Analyst II/III (Research Assistant)
Job Code SSNRI723A
Open until filled.

In the Sierra Nevada Research Institute at UC Merced, act in support  
of research in applied climatology and statistical modeling for  
wildfire, energy and water resource management applications and  
assist the Principle Investigator with the development of software,  
management of data sets and design, modification, and implementation  
of systems for modeling and analysis.  Develop software libraries for  
the R statistical project for publication and use in the classroom  
environment.  Requires experience and demonstrated expertise in  
programming and data visualization.  Relevant programming experience  
includes R, Fortran and/or C.  HTML is also desired; background in  
statistics, physics, climatology, hydrology, fire ecology or a  
similar field (Masters preferred); strong problem solving;  
demonstrated written communication and programming skills.   A UC  
Merced job application, resume and cover letter are requested.  For  
more information and to apply call 1-866-669-JOBS or visit http:// 
jobs.ucmerced.edu/n/staff/position.jsf?positionId=723.  EOE


Anthony Westerling
School of Engineering
School of Social Sciences, Humanities, and Arts
University of California, Merced

http://tenaya.ucsd.edu/~westerli/westerling.html
[EMAIL PROTECTED]

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Re: [R] Order observations in a dataframe

2007-11-28 Thread Henrique Dallazuanna
Try this:


df$group - factor(df$group)
levels(df$group)- names(sort(tapply(df$weight, df$group, sum),
decreasing=T))


On 28/11/2007, Serguei Kaniovski [EMAIL PROTECTED] wrote:


 Dear All,

 Suppose I have the following dataframe:

 country;weight;group
 bul;10;1
 cze;12;1
 grc;12;1
 hun;12;1
 prt;12;1
 rom14;1
 fra;29;2
 ita;29;2
 gbr;29;2
 aut;10;3
 bel;12;3

 The group variable denotes the id-number of a group of countries. How
 can
 I re-label the groups in the descending order of their cumulative
 weight,
 which wound be:

 country;weight;group
 fra;29;1
 ita;29;1
 gbr;29;1
 bul;10;2
 cze;12;2
 grc;12;2
 hun;12;2
 prt;12;2
 rom14;2
 aut;10;3
 bel;12;3

 The first group has the largest sum of weights, the second, with the
 second
 largest, and so on.

 Thanks for your help,
 Serguei Kaniovski

 
 Austrian Institute of Economic Research (WIFO)

 P.O.Box 91  Tel.: +43-1-7982601-231
 1103 Vienna, AustriaFax: +43-1-7989386

 Mail: [EMAIL PROTECTED]
 http://www.wifo.ac.at/Serguei.Kaniovski
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-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O

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Re: [R] Fortran Code to R Code

2007-11-28 Thread Scionforbai
help.start(), then Writing R extensions.

You can link fortran subroutines to R by compiling them in a shared
library (.so or .dll depending on your system) by the command:

R CMD SHLIB file1.f file2.f -o myfortransubroutines.so

and then from R you first

dyn.load(myfortransubroutines.so)

and then you use the .Fortran function to call the fortran subroutines
with the right arguments. Pleas read the manual to have details of
implementations and variables types.

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[R] interaction of continuous terms

2007-11-28 Thread Irene Mantzouni
Hi all!
 
this is a rather statistical question:
is it meaningful to consider an interaction effect between 2 continuous 
covariates?
for example: lm(y~x1+x2+x1:x2) 
Should one of continuous x1, x2 be transformed to a categorical variable, 
i.e. be classified into groups?
Is it easier to interpret the effect if 1 or both are centered to the mean or 
z-transformed? 
 
Thank you!

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Re: [R] interaction of continuous terms

2007-11-28 Thread Prof Brian Ripley
It's meaningful, but not under the name 'interaction'.  The model is the 
same as

y ~ x1 + x2 + I(x1*x2)

that is, 'including a product term'.  However, needing product terms often 
indicates a missed transformation of y (e.g. it might be better to use 
log(y)).

On Wed, 28 Nov 2007, Irene Mantzouni wrote:

 Hi all!

 this is a rather statistical question:
 is it meaningful to consider an interaction effect between 2 continuous 
 covariates?
 for example: lm(y~x1+x2+x1:x2)
 Should one of continuous x1, x2 be transformed to a categorical variable, 
 i.e. be classified into groups?
 Is it easier to interpret the effect if 1 or both are centered to the mean or 
 z-transformed?

Depends on the context, but usually not.

-- 
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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[R] Http_proxy settings with autoproxy.php

2007-11-28 Thread Lusseau, David
Just installed R on a new machine which is on a server. I am trying to
download packages but seem to have trouble with our proxy settings. I
have read the 2.19 section in R for Windows and tried what was suggested
(setting http_proxy) but that did not help (still cannot connect). I
think my problem is that we do not have a fixed port but use instead
autoproxy. Has anyone encountered this problem and if so how can it be
fixed?
Thanks,
David


Dr. David Lusseau
Lecturer in Marine Populations

University of Aberdeen
School of Biological Sciences
Zoology Bldg, Tillydrone Avenue
Aberdeen, AB24 2TZ, UK
Phone: (0)1224 272843

Website: http://www.lusseau.org 

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Re: [R] Http_proxy settings with autoproxy.php

2007-11-28 Thread Prof Brian Ripley
On Wed, 28 Nov 2007, Lusseau, David wrote:

 Just installed R on a new machine which is on a server. I am trying to

Under Windows, I infer.

 download packages but seem to have trouble with our proxy settings. I
 have read the 2.19 section in R for Windows and tried what was suggested
 (setting http_proxy) but that did not help (still cannot connect). I
 think my problem is that we do not have a fixed port but use instead
 autoproxy. Has anyone encountered this problem and if so how can it be
 fixed?

Have you tried --internet2?  In most cases if Internet Explorer works with 
your proxy, so will Rgui --internet2.

Otherwise you need to ask the people who inflicted the proxy on you how to 
make use of it.  ('autoproxy' is not a well-defined term, BTW, as it has 
several meanings.)

-- 
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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[R] question about warning message in nlme model

2007-11-28 Thread Christine Calmes
I am writing to inquire about a warning message that I receive when 
trying to model a random slope and intercept at the second level of a 
3-level model.  Specifically, I am testing a 3-level model in which 
time (WEEK) is nested in participants (PARTICIP) and participants are 
nested in dyads (DYADID). The goal is to examine how an interpersonal 
style (CORUMTO) one week predicts changes in depression the following 
week (BDIAFTER) controlling for levels of depression (BDI) from the 
previous week.  I have approximately 80 dyads and approximately 160 
participants.

When modeling a random slope and intercept at the second level (the
participant or person level), I receive output, and I also receive the
following error message.

Warning message
Fewer observations than random effects in all level 2 groups

I was wondering what this error message means and if it may be 
suggesting that the results after the summary statement are incorrect.

I also want to verify that the following syntax is appropriate for
modeling a random intercept and slope on the variable CORUMTO at the
participant level and a random intercept and fixed slope at the dyad 
level.

intercept-lme(BDIAFTER~BDI+WEEK+CORUMTO, random=list(DYADID=~1, 
PARTICIP=~CORUMTO), data=weeklydata)

Any help you can give would be much appreciated.

Thank you for your time.

Sincerely, 
Christine Calmes

Christine Calmes, M.A.
Doctoral Candidate, Clinical Psychology
University at Buffalo: The State University at New York
Department of Psychology; Park Hall
North Campus
Buffalo NY, 14260

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Re: [R] windows vista

2007-11-28 Thread aaront

If the administrator account does not exist, this info provided for another
software program I use may be helpful:

Some Windows Vista installations may have the Administrator account turned
off. If so, it is easy to turn the true Administrator account on. To do so,
open the Control Panel and open the User Accounts applet. If you do not see
any accounts named Administrator, this account is disabled. To enable the
Administrator account, do the following:

* Click Start, type cmd into the search pane, wait until the system
displays the cmd.exe item at the top.
* Right click the item and choose Run as administrator.
* In the opened command prompt, type net user administrator /active:yes
and click Enter, then log off.
* There will now be an Administrator account enabled.
* Log in as the Administrator to install and to activate Manifold.

From: http://www.manifold.net/tech/vista_admin.shtml

http://cran.r-project.org/bin/windows/base/rw-FAQ.html#Does-R-run-under-Windows-Vista_003f
 

Suzuky Pinto wrote:
 
 Hello there
 
 Im suzuky Pinto from Mexico.
 And Im buying a new computer and this have windows vista. Could I have any
 problem using R on it?
 thabks
  
 Suzuky**
 
 
   Comparte video en la ventana de tus mensajes (y también tus fotos
 de Flickr). 
 Usa el nuevo Yahoo! Messenger versión Beta.
 http://mx.beta.messenger.yahoo.com/
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-- 
View this message in context: 
http://www.nabble.com/windows-vista-tf4887031.html#a13993446
Sent from the R help mailing list archive at Nabble.com.

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Re: [R] Antwort: Re: Order observations in a dataframe

2007-11-28 Thread Richard . Cotton
 How
 can
  I re-label the groups in the descending order of their cumulative
 weight,

 foo = data.frame(country=c(bul, cze, grc, hun, prt, rom,
 fra, ita, gbr, aut, bel),
 weight=c(10,12,12,12,12,4,29,29,29,10,12),
 group=c(1,1,1,1,1,1,2,2,2,3,3))
 
 #Find the cumulative weights by group
 cumweights = with(foo, tapply(weight, group, sum)
 
 #Incorporate the weights  into the data frame
 foo$cumweights = numeric(nrow(foo))
 for(i in 1:nrow(foo)) foo$cumweights[i] =
 cumweights[as.character(foo$group[i])==names(cumweights)]
 
 #Sort by cumweight
 ooo = with(foo, order(cumweights, country, decreasing=TRUE))
 foo = foo[ooo,]

 Thanks Richard,
 
 but how do you renumerate the group variable accordingly?

Try this:

sizeofgroups = summary(as.factor(foo$group))
orderofgroups = order(cumweights, decreasing=TRUE)
foo$newgroup = rep(orderofgroups, times=sizeofgroups)

Regards,
Richie.

Mathematical Sciences Unit
HSL



ATTENTION:

This message contains privileged and confidential inform...{{dropped:20}}

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[R] Fail to open R 2.6.1

2007-11-28 Thread Luis Ridao Cruz
R-help,

I opened an R session ( R 2.6.0 on Windows) and got the following
pop-up window:

This application has failed to start because tk84.dll was not found.
Re-installing the application may fix the problem
 
I have now upgraded to R 2.6.1 but the same fatal error comes up.

Can someone let me know what is going on?


Thanks in advance.

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[R] Fail to open R 2.6.1 - additional information

2007-11-28 Thread Luis Ridao Cruz

This is additional information to my previous email (pasted below)


## I opened an R session ( R 2.6.0 on Windows) and got the following
pop-up window:

## This application has failed to start because tk84.dll was not
found. Re-installing the application may fix the problem
 
## I have now upgraded to R 2.6.1 but the same fatal error comes up.

## Can someone let me know what is going on?


I have started an empty R session and tried to load the workspace I
can't open (above)
I get the error message:

 load(E:\\WORKSPACE_I CANNOT OPEN)
Loading Tcl/Tk interface ...Error in dyn.load(file, ...) : 
  unable to load shared library
'C:/PROGRA~1/R/R-26~1.1/library/tcltk/libs/tcltk.dll':
  LoadLibrary failure:  The specified module could not be found. 
Error: .onLoad failed in 'loadNamespace' for 'tcltk'


How can I fix it?

Thanks in advance

 version
   _   
platform   i386-pc-mingw32 
arch   i386
os mingw32 
system i386, mingw32   
status 
major  2   
minor  6.1 
year   2007
month  11  
day26  
svn rev43537   
language   R   
version.string R version 2.6.1 (2007-11-26)

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[R] Replacing values job

2007-11-28 Thread Serguei Kaniovski

Hallo,

I have two vectors of different lengths which contain the same set of
values:

X  -c(2,6,1,7,4,3,5)
Y - c(1,1,6,4,6,1,4,1,2,3,6,6,1,2,4,4,5,4,1,7,6,6,4,4,7,1,2)

How can I replace the values in Y with the index (!) of the corresponding
values in X. So 2 appears in X in the first coordinate, so all 2’s in Y
should be replaced by 1, etc.

Thank you for your help,
Serguei


Austrian Institute of Economic Research (WIFO)

P.O.Box 91  Tel.: +43-1-7982601-231
1103 Vienna, AustriaFax: +43-1-7989386

Mail: [EMAIL PROTECTED]
http://www.wifo.ac.at/Serguei.Kaniovski
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[R] using names with functions..

2007-11-28 Thread vito muggeo
Dear all,
I have the following (rather) strange problem..
For some reasons, I finally work with a variable whose name includes an 
R function, a.log(z), say. And that is a problem when I call it in a 
formula, for instance:

  myname-a.log(z)
  dd-data.frame(a.log(z)=1:10,y=rnorm(10))
  o-lm(y~1,data=dd)
  fo-as.formula(paste(.~.+,paste(myname, collapse = +)))
  fo
. ~ . + a.log(z)
  update(o,formula=fo)
Error in eval(expr, envir, enclos) : could not find function a.log
 

How can fit the model? namely how can I use a.log(z) in the example above?

Many thanks,
vito


-- 

Vito M.R. Muggeo
Dip.to Sc Statist e Matem `Vianelli'
Università di Palermo
viale delle Scienze, edificio 13
90128 Palermo - ITALY
tel: 091 6626240
fax: 091 485726/485612

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Re: [R] windows vista

2007-11-28 Thread Gabor Grothendieck
R works on Vista provided you have learned enough about Vista to get around
the enhanced security model.

Microsoft One Care software and the overall better security of Vista
is, in my opinion,
much superior to Norton/Symantec/XP.

Many people use Skype these days and Skype is not officially supported on Vista
so if you want to use that it may or may not work.  My Vista system
crashed shortly
after I tried Skype and reverted back to a prior checkpoint at which
point I lost
several programs I had installed including Skype although I did not
lose any files
that I had created myself.  It may have been a driver issue and not
Skype, per se,
though the fact that Skype is not officially supported makes Skype a prime
suspect. My Vista system had never crashed before that nor has it crashed since
then.  If you search the net you see some people having problems with Skype on
Vista whereas others say they have run it daily with no problem.

There are significant changes in Microsoft Office 2007 including new XML based
file formats rather than the old formats (although you can read and
write the old formats
too), substantial changes in Office user interfaces and a focus on
.Net in place of COM although
COM is still supported enough in Office 2007 to run old software.  R
packages supporting .Net,
similar to the R packages rcom and RDCOMClient for COM, would be nice
to properly support
Vista but I don't think such R packages exist yet.

Other than the lack of Skype support I do like Vista and have been able to get
rid of numerous small utilities that I used under XP since Vista has
many of these
facilities built in.

On Nov 27, 2007 4:40 PM, Suzuky Pinto [EMAIL PROTECTED] wrote:
 Hello there

 Im suzuky Pinto from Mexico.
 And Im buying a new computer and this have windows vista. Could I have any 
 problem using R on it?
 thabks

 Suzuky**


  Comparte video en la ventana de tus mensajes (y también tus fotos de 
 Flickr).
 Usa el nuevo Yahoo! Messenger versión Beta.
 http://mx.beta.messenger.yahoo.com/
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[R] Clustering

2007-11-28 Thread Eleni Christodoulou
Hello all!

I am performingsome clustering analysis on microarray data using
agnes{cluster} and I have created my own dissimilarity matrix according to a
distance measure different from euclidean or manhattan etc. My question
is,  if I choose for example method=complete, how are the distances
between the elements calculated? Are they taken form the dissimilarity
matrix I have provided as the first argument?
clust.complete.agnes-agnes(as.dist(D),diss=TRUE,method=complete)


Thank you very much,
Eleni

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[R] simulating a 2-parameter integrated ornstein-uhlenbeck process?

2007-11-28 Thread Farzad Noubary
hello everyone,

i'm trying to simulate a 2-parameter integrated ornstein-uhlenbeck (IOU) 
process, but i'm not sure exactly where to start (which package, which 
function). the motivation is the paper by taylor et. al. (JASA 1994) a 
stochastic model for the analysis of longitudinal aids data. the model they 
suggest consists of a combination of fixed and random effects, a stochastic 
process, and measurement error. 

the 2-parameter IOU process they suggest has cov[W(s), W(t)] = 
(sigma^2/(2alpha^3)[2alpha min(s,t)+exp(-alpha* t) +exp(-alpha* s)-1 
-exp(alpha*|t-s|)).

any insight into either fitting the model or simulating a 2-parameter IOU 
process would be appreciated.

thanks,
farzad





  

Be a better sports nut!  Let your teams follow you 

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Re: [R] Questions on RWeka classifiers?

2007-11-28 Thread Hans W. Borchers
Li Li lilycai2007 at gmail.com writes:

 
 Hi,
 
 I am using some classifiers in RWeka packages and met a couple problems.
 
 (1) J48 implements C45 classifier, the C45 should be able to handle missing
  values in both training set and test set. But I found the J48
 classifier can
  not be evaluated on test set with missing values--it just ignore them.

Why don't you ask this question on the WEKA mailing list at, for instance,
http://news.gmane.org/gmane.comp.ai.weka !

If I remember correctly, C4.5 is smart enough to simply drop examples with
missing values, while C5.0 will handle them more intelligently. It will also
address numerical attributes more sensible than C4.5 or CART.

Unfortunately, C5.0 is commercial software, but you can get a 2-weeks demo from
Quinlan's site.

 (2) The ensemble classifiers in RWeka such as bagging and boosting: there
  is a control argument as W to describe which base classifier should
 be used.
  I use W=J48 to boost C45 tree, but I am not sure how to down size the
 tree
 to be a weak learner. Based on what I observed, the default boosted
 J48 tree
 gets worse performance.

This is difficult to answer without any concrete data. From my own experince I
can say that in many cases results have distinctively improved when applying
Adaboost.

 
 Thanks for any discussion and help,
 
 Li
 

Regards,  Hans Werner Borchers

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Re: [R] Fail to open R 2.6.1 - additional information

2007-11-28 Thread Duncan Murdoch
On 11/28/2007 9:41 AM, Luis Ridao Cruz wrote:
 This is additional information to my previous email (pasted below)
 
 
 ## I opened an R session ( R 2.6.0 on Windows) and got the following
 pop-up window:
 
 ## This application has failed to start because tk84.dll was not
 found. Re-installing the application may fix the problem
  
 ## I have now upgraded to R 2.6.1 but the same fatal error comes up.
 
 ## Can someone let me know what is going on?
 
 
 I have started an empty R session and tried to load the workspace I
 can't open (above)
 I get the error message:
 
 load(E:\\WORKSPACE_I CANNOT OPEN)
 Loading Tcl/Tk interface ...Error in dyn.load(file, ...) : 
   unable to load shared library
 'C:/PROGRA~1/R/R-26~1.1/library/tcltk/libs/tcltk.dll':
   LoadLibrary failure:  The specified module could not be found. 
 Error: .onLoad failed in 'loadNamespace' for 'tcltk'
 
 
 How can I fix it?

I suspect you installed R without Support files for TCLTK.

Your workspace appears to have something in it that refers to the tcltk 
package, and it needs TCLTK installed to work.

Duncan Murdoch

 
 Thanks in advance
 
 version
_   
 platform   i386-pc-mingw32 
 arch   i386
 os mingw32 
 system i386, mingw32   
 status 
 major  2   
 minor  6.1 
 year   2007
 month  11  
 day26  
 svn rev43537   
 language   R   
 version.string R version 2.6.1 (2007-11-26)
 
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Re: [R] Replacing values job

2007-11-28 Thread Ingmar Visser
does this do what you want?

sapply(y,function(y){which(y==x)})

hth, Ingmar

On 28 Nov 2007, at 15:53, Serguei Kaniovski wrote:


 Hallo,

 I have two vectors of different lengths which contain the same set of
 values:

 X  -c(2,6,1,7,4,3,5)
 Y - c(1,1,6,4,6,1,4,1,2,3,6,6,1,2,4,4,5,4,1,7,6,6,4,4,7,1,2)

 How can I replace the values in Y with the index (!) of the  
 corresponding
 values in X. So 2 appears in X in the first coordinate, so all 2’s  
 in Y
 should be replaced by 1, etc.

 Thank you for your help,
 Serguei

 
 Austrian Institute of Economic Research (WIFO)

 P.O.Box 91  Tel.: +43-1-7982601-231
 1103 Vienna, AustriaFax: +43-1-7989386

 Mail: [EMAIL PROTECTED]
 http://www.wifo.ac.at/Serguei.Kaniovski
   [[alternative HTML version deleted]]

 __
 R-help@r-project.org mailing list
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 PLEASE do read the posting guide http://www.R-project.org/posting- 
 guide.html
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Ingmar Visser
Department of Psychology, University of Amsterdam
Roetersstraat 15
1018 WB Amsterdam
The Netherlands
t: +31-20-5256723



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[R] Simulate an AR(1) process via distributions? (without specifying a model specification)

2007-11-28 Thread Pedro.Rodriguez
Dear All,

 

Is it possible to simulate an AR(1) process via a distribution? 

 

I have simulated an AR(1) process the usual way (that is, using a model
specification and using the random deviates in the error), and used the
generated time series to estimate 3- and 4-parameter distributions (for
instance, GLD). However, the random deviates generated from these
distributions do not follow the specified AR process.   

 

Any comment and feedback will be more than welcome.

 

Thanks for your time.

 

Pedro N. Rodriguez

 


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Re: [R] Replacing values job

2007-11-28 Thread markleeds
From: Serguei Kaniovski [EMAIL PROTECTED]
Date: 2007/11/28 Wed AM 08:53:34 CST
To: [EMAIL PROTECTED]
Subject: [R] Replacing values job

newY-sapply(1:length(Y), function(.element) 
match(Y[.element],X))

i hope it helps you.




Hallo,

I have two vectors of different lengths which contain the same set of
values:

X  -c(2,6,1,7,4,3,5)
Y - c(1,1,6,4,6,1,4,1,2,3,6,6,1,2,4,4,5,4,1,7,6,6,4,4,7,1,2)

How can I replace the values in Y with the index (!) of the corresponding
values in X. So 2 appears in X in the first coordinate, so all 2’s in Y
should be replaced by 1, etc.

Thank you for your help,
Serguei


Austrian Institute of Economic Research (WIFO)

P.O.Box 91  Tel.: +43-1-7982601-231
1103 Vienna, AustriaFax: +43-1-7989386

Mail: [EMAIL PROTECTED]
http://www.wifo.ac.at/Serguei.Kaniovski
[[alternative HTML version deleted]]



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Re: [R] windows vista

2007-11-28 Thread Wolfgang Raffelsberger
Dear Suzuky,

basically you can run R on Vista like you can on Windows XP.

However, there is one issue about installing additional packages :
When launching R under Vista, by default you won't launch as 
administrator, and in consequence you can't install additional packages 
(i.e. installing conveniently from within R) in the path where the other 
packages are located (since this is usually in Program Files).  Note 
that you still CAN install and run the packages but (in this case) 
you'll be installing the packages in a new folder in Contacts/Documents/ 
, which is -in my opinion- not the best place to store them (and they 
won't be available for other users on the same PC).  So, if you know 
you'll be installing I suggest you to launch R with a right click and 
select as administrator and then you can install new packages in 
proper way.

Wolfgang

Suzuky Pinto a écrit :
 Hello there

 Im suzuky Pinto from Mexico.
 And Im buying a new computer and this have windows vista. Could I have any 
 problem using R on it?
 thabks
  
 Suzuky**


   Comparte video en la ventana de tus mensajes (y también tus fotos de 
 Flickr). 
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-- 

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

Wolfgang Raffelsberger, PhD
Laboratoire de BioInformatique et Génomique Intégratives
CNRS UMR7104, IGBMC
1 rue Laurent Fries,  67404 Illkirch  Strasbourg,  France
Tel (+33) 388 65 3300 Fax (+33) 388 65 3276
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Re: [R] Replacing values job

2007-11-28 Thread jim holtman
?match

 X
[1] 2 6 1 7 4 3 5
 Y
 [1] 1 1 6 4 6 1 4 1 2 3 6 6 1 2 4 4 5 4 1 7 6 6 4 4 7 1 2
 match(Y,X)
 [1] 3 3 2 5 2 3 5 3 1 6 2 2 3 1 5 5 7 5 3 4 2 2 5 5 4 3 1



On Nov 28, 2007 9:53 AM, Serguei Kaniovski [EMAIL PROTECTED] wrote:

 Hallo,

 I have two vectors of different lengths which contain the same set of
 values:

 X  -c(2,6,1,7,4,3,5)
 Y - c(1,1,6,4,6,1,4,1,2,3,6,6,1,2,4,4,5,4,1,7,6,6,4,4,7,1,2)

 How can I replace the values in Y with the index (!) of the corresponding
 values in X. So 2 appears in X in the first coordinate, so all 2's in Y
 should be replaced by 1, etc.

 Thank you for your help,
 Serguei

 
 Austrian Institute of Economic Research (WIFO)

 P.O.Box 91  Tel.: +43-1-7982601-231
 1103 Vienna, AustriaFax: +43-1-7989386

 Mail: [EMAIL PROTECTED]
 http://www.wifo.ac.at/Serguei.Kaniovski
[[alternative HTML version deleted]]


 __
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 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.





-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem you are trying to solve?

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Re: [R] using names with functions..

2007-11-28 Thread Gabor Grothendieck
Names not conforming to the usual R syntax can be placed
in backquotes:

 `log(x)` - 1:10
 lm(`log(x)` ~ 1)

Call:
lm(formula = `log(x)` ~ 1)

Coefficients:
(Intercept)
5.5


On Nov 28, 2007 9:52 AM, vito muggeo [EMAIL PROTECTED] wrote:
 Dear all,
 I have the following (rather) strange problem..
 For some reasons, I finally work with a variable whose name includes an
 R function, a.log(z), say. And that is a problem when I call it in a
 formula, for instance:

   myname-a.log(z)
   dd-data.frame(a.log(z)=1:10,y=rnorm(10))
   o-lm(y~1,data=dd)
   fo-as.formula(paste(.~.+,paste(myname, collapse = +)))
   fo
 . ~ . + a.log(z)
   update(o,formula=fo)
 Error in eval(expr, envir, enclos) : could not find function a.log
  

 How can fit the model? namely how can I use a.log(z) in the example above?

 Many thanks,
 vito


 --
 
 Vito M.R. Muggeo
 Dip.to Sc Statist e Matem `Vianelli'
 Università di Palermo
 viale delle Scienze, edificio 13
 90128 Palermo - ITALY
 tel: 091 6626240
 fax: 091 485726/485612

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Re: [R] using names with functions..

2007-11-28 Thread Duncan Murdoch
On 11/28/2007 9:52 AM, vito muggeo wrote:
 Dear all,
 I have the following (rather) strange problem..
 For some reasons, I finally work with a variable whose name includes an 
 R function, a.log(z), say. And that is a problem when I call it in a 
 formula, for instance:
 
   myname-a.log(z)
   dd-data.frame(a.log(z)=1:10,y=rnorm(10))
   o-lm(y~1,data=dd)
   fo-as.formula(paste(.~.+,paste(myname, collapse = +)))
   fo
 . ~ . + a.log(z)
   update(o,formula=fo)
 Error in eval(expr, envir, enclos) : could not find function a.log
  
 
 How can fit the model? namely how can I use a.log(z) in the example above?

You can make just about anything into a name by quoting in in backticks, 
e.g. `a.log(z)` should always be seen as a name.  However, there is a 
fair bit of code in contributed packages that converts things to 
character vectors and then reparses it (like your example above!), and 
that code may well get confused by such a name.

For example,

  deparse(quote(`a.log(z)`))
[1] a.log(z)

The package writer could avoid this by using

  deparse(quote(`a.log(z)`), backtick=T)
[1] `a.log(z)`

You also need to worry about the fact that by default, data.frame() will 
convert the name of the first column to a.log.z.

So you could get everything you want with this variation on your example:

  myname-`a.log(z)`
  dd-data.frame(a.log(z)=1:10,y=rnorm(10), check.names=FALSE)
  o-lm(y~1,data=dd)
  fo-as.formula(paste(.~.+,paste(myname, collapse = +)))
  fo
. ~ . + `a.log(z)`
  update(o,formula=fo)

Call:
lm(formula = y ~ `a.log(z)`, data = dd)

Coefficients:
(Intercept)   `a.log(z)`
 -0.3931   0.0753

However, I'd suggest avoiding the use of such a name.

Duncan Murdoch

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Re: [R] Replacing values job

2007-11-28 Thread Peter Dalgaard
Ingmar Visser wrote:
 does this do what you want?

 sapply(y,function(y){which(y==x)})
   
Maybe, but match(Y,X) would be more to the point.

 hth, Ingmar

 On 28 Nov 2007, at 15:53, Serguei Kaniovski wrote:

   
 Hallo,

 I have two vectors of different lengths which contain the same set of
 values:

 X  -c(2,6,1,7,4,3,5)
 Y - c(1,1,6,4,6,1,4,1,2,3,6,6,1,2,4,4,5,4,1,7,6,6,4,4,7,1,2)

 How can I replace the values in Y with the index (!) of the  
 corresponding
 values in X. So 2 appears in X in the first coordinate, so all 2�s  
 in Y
 should be replaced by 1, etc.

 Thank you for your help,
 Serguei

 
 Austrian Institute of Economic Research (WIFO)

 P.O.Box 91  Tel.: +43-1-7982601-231
 1103 Vienna, AustriaFax: +43-1-7989386

 Mail: [EMAIL PROTECTED]
 http://www.wifo.ac.at/Serguei.Kaniovski
  [[alternative HTML version deleted]]

 __
 R-help@r-project.org mailing list
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 guide.html
 and provide commented, minimal, self-contained, reproducible code.
 

 Ingmar Visser
 Department of Psychology, University of Amsterdam
 Roetersstraat 15
 1018 WB Amsterdam
 The Netherlands
 t: +31-20-5256723



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-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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Re: [R] using names with functions..

2007-11-28 Thread Peter Dalgaard
vito muggeo wrote:
 Dear all,
 I have the following (rather) strange problem..
 For some reasons, I finally work with a variable whose name includes an 
 R function, a.log(z), say. And that is a problem when I call it in a 
 formula, for instance:

   myname-a.log(z)
   dd-data.frame(a.log(z)=1:10,y=rnorm(10))
   o-lm(y~1,data=dd)
   fo-as.formula(paste(.~.+,paste(myname, collapse = +)))
   fo
 . ~ . + a.log(z)
   update(o,formula=fo)
 Error in eval(expr, envir, enclos) : could not find function a.log
  

 How can fit the model? namely how can I use a.log(z) in the example above?

 Many thanks,
 vito


   
Use backquotes as in `a.log(z)`, I think.

myname-a.log(z)
o-lm(y~1,data=dd)
dd-data.frame(a.log(z)=1:10,y=rnorm(10),check.names=F)
fo-as.formula(paste(.~.+,paste(deparse(as.name(myname), backtick=T),
collapse = +)))
update(o,formula=fo)

or, actually nicer, use

fo - bquote(. ~ . + .(as.name(myname)))


-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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Re: [R] Different value between R variance and definition of variance

2007-11-28 Thread Daniel Nordlund
 -Original Message-
 From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf
 Of Tine
 Sent: Wednesday, November 28, 2007 12:57 AM
 To: r-help@r-project.org
 Subject: [R] Different value between R variance and definition of variance
 
 Hi!
 
 Let us define random variable:
   x = seq(0,1,length=100)
 
 If we calculate variance following definition E[(x-E(x))^2] we get:
   mean( (x - mean(x))^2 ) # == mean(x^2) - mean(x)^2
 0.08501684
 
 And if we use internal R function var:
   var(x)
 0.08587559
 
 Can anyone tells me why the difference?
 

I haven't seen a response, so I will chime in.  R calculates an unbiased 
estimate of the population variance from which your x is assumed to be a simple 
random sample of size n (in your case n=100).  See any basic book on 
statistics.  So, using your formula, R in effect calculates

 mean((x-mean(x)^2) * n/(n-1)

Hope this is helpful,

Dan 

Daniel Nordlund
Bothell, WA USA

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Re: [R] Clustering

2007-11-28 Thread Birgit Lemcke
Hello Eleni,

as far as I understood and used agnes() the method argument  
determines only the clustering method.
If you use diss=TRUE the distances should be taken from the distance  
matrix.

Birgit

Am 28.11.2007 um 12:18 schrieb Eleni Christodoulou:

 Hello all!

 I am performingsome clustering analysis on microarray data using
 agnes{cluster} and I have created my own dissimilarity matrix  
 according to a
 distance measure different from euclidean or manhattan etc. My  
 question
 is,  if I choose for example method=complete, how are the distances
 between the elements calculated? Are they taken form the dissimilarity
 matrix I have provided as the first argument?
 clust.complete.agnes-agnes(as.dist(D),diss=TRUE,method=complete)


 Thank you very much,
 Eleni

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Birgit Lemcke
Institut für Systematische Botanik
Zollikerstrasse 107
CH-8008 Zürich
Switzerland
Ph: +41 (0)44 634 8351
[EMAIL PROTECTED]

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Re: [R] Replacing values job

2007-11-28 Thread Barry Rowlingson
jim holtman wrote:
 ?match
 
 X
 [1] 2 6 1 7 4 3 5
 Y
  [1] 1 1 6 4 6 1 4 1 2 3 6 6 1 2 4 4 5 4 1 7 6 6 4 4 7 1 2
 match(Y,X)
  [1] 3 3 2 5 2 3 5 3 1 6 2 2 3 1 5 5 7 5 3 4 2 2 5 5 4 3 1
 

  I quite like this solution:

   X[X[X[X[X[X[X[X[X[X[X]][Y]
[1] 3 3 2 5 2 3 5 3 1 6 2 2 3 1 5 5 7 5 3 4 2 2 5 5 4 3 1

  but somehow I don't think its general enough...

Barry

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Re: [R] [OT] putting URLs in Latex

2007-11-28 Thread Mike Prager
Edna Bell [EMAIL PROTECTED] wrote:

 Hi R Gurus!
 
 This is definitely off topic, but I thought I'd try:  what is the way
 to put in url's into a Latex file, please?

In future, you might want to post such questions in group
comp.text.tex

Mike

-- 
Mike Prager, NOAA, Beaufort, NC
* Opinions expressed are personal and not represented otherwise.
* Any use of tradenames does not constitute a NOAA endorsement.

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Re: [R] Clustering

2007-11-28 Thread Dave Roberts
Eleni,

 The method= argument is in reference to how clusters are 
constructed, not how the dissimilarity or distance is calculated.  If 
you pass agnes diss=TRUE then it will use the distances you have 
calculated by whatever means.  method=complete means that clusters are 
evaluated by the maximum distance of a candidate sample to the set of 
samples in the cluster, rather than the average.  Yo can find 
descriptions of these algorithms in most any text on clustering.

Dave Roberts

Eleni Christodoulou wrote:
 Hello all!
 
 I am performingsome clustering analysis on microarray data using
 agnes{cluster} and I have created my own dissimilarity matrix according to a
 distance measure different from euclidean or manhattan etc. My question
 is,  if I choose for example method=complete, how are the distances
 between the elements calculated? Are they taken form the dissimilarity
 matrix I have provided as the first argument?
 clust.complete.agnes-agnes(as.dist(D),diss=TRUE,method=complete)
 
 
 Thank you very much,
 Eleni
 
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Re: [R] Simulate an AR(1) process via distributions? (without specifying a model specification)

2007-11-28 Thread Prof Brian Ripley
On Wed, 28 Nov 2007, [EMAIL PROTECTED] wrote:

 Is it possible to simulate an AR(1) process via a distribution?

Any distribution *of errors*, yes.  Of the process values, not in general.

 I have simulated an AR(1) process the usual way (that is, using a model
 specification and using the random deviates in the error), and used the
 generated time series to estimate 3- and 4-parameter distributions (for
 instance, GLD). However, the random deviates generated from these
 distributions do not follow the specified AR process.

How do you know that?  Please give us the reproducible example we asked 
for (in the posting guide, at the bottom of every message), and we should 
be able to explain it to you.

-- 
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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[R] Can't make affylmGUI work

2007-11-28 Thread Feifei
Hi,

Can anyone help me of the affylmGUI package, I can't get it work and
searched for google but can't find any proper solutions.

I get the error information each time when I load my cells files, which
are shown in the following links.
-
http://clarezoe.googlepages.com/1.png
http://clarezoe.googlepages.com/2.png
http://clarezoe.googlepages.com/3.png
-

Errors also show in the terminal as below,
-
  Error: no function to return from, jumping to top level
  In addition: Warning messages:
  1: read.phenoData is deprecated, use read.AnnotatedDataFrame instead 
  2: The phenoData class is deprecated, use AnnotatedDataFrame (with
ExpressionSet) instead 
  Error in exprs(RawAffyData) : 
  no function to return from, jumping to top level
--

I'm running R version 2.6.1 under Linux Ubuntu 7.10

--

My sessionInfo is shown below,

--
  sessionInfo()
 R version 2.6.1 (2007-11-26) 
 i486-pc-linux-gnu 

 locale:

LC_CTYPE=en_US.UTF-8;LC_NUMERIC=C;LC_TIME=en_US.UTF-8;LC_COLLATE=en_US.UTF-8;LC_MONETARY=en_US.UTF-8;LC_MESSAGES=en_US.UTF-8;LC_PAPER=en_US.UTF-8;LC_NAME=C;LC_ADDRESS=C;LC_TELEPHONE=C;LC_MEASUREMENT=en_US.UTF-8;LC_IDENTIFICATION=C

 attached base packages:
 [1] tools tcltk stats graphics  grDevices utils
datasets 
 [8] methods   base 

 other attached packages:
 [1] affylmGUI_1.12.0 affy_1.12.2  affyio_1.6.1 Biobase_1.16.1  
 [5] limma_2.12.0

 loaded via a namespace (and not attached):
 [1] rcompgen_0.1-17


Can anyone help me with that? I really need it to work ASAP.

Thanks a lot!

Sincerely 
Feifei

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Re: [R] alternatives to traditional least squares method in linear regression ?

2007-11-28 Thread Gabor Grothendieck
You could use the weights= argument of lm or if these points represent
a different factor you could add a dummy variable which is one for those
points and 0 otherwise. Also check out quantile regression in the
quantreg package.

On Nov 28, 2007 11:14 AM, Wolfgang Raffelsberger
[EMAIL PROTECTED] wrote:
 Dear list,

 I have encountered a special case for searching a linear regression
 where I'm not satisfied with the results obtained using the traditional
 least squares method (sometimes called OLS) for estimating/optimizing
 the residues to the regression line (see code below).  Basically, a
 group of my x-y data are a bit off the diagonal line (in my case the
 diagonal represents the ideal or theoretical fit between x and y, which
 are in the same scale) and thus these points have sufficient power to
 impose a slope deviating (too much) from the diagonal. Using rlm()
 didn't help since this is not a problem of rare outliers.
  From a pragmatic point of  view using a linear regression approach does
 fit very well the nature of the data  comparison I'd like to perform,
 so that's why I'd like to stay with something linear.

 Has anybody already implemented a function or package in R allowing to
 modify the exponent (of the least squares method) or more general
 allowing to define the model to be used for estimating/optimizing the
 residues ?

 Thank's in advance
 Wolfgang Raffelsberger


   plot(x,y)# x and y are my data
   regr - lm(y~x)
   abline(regr)
   # I'm not satisfied with the line since there is one group of points
 following very well the diagonal but the regression is deviated by
 another group of points ...
  
   sessionInfo()
 R version 2.6.0 (2007-10-03)
 i386-pc-mingw32

 locale:
 LC_COLLATE=French_France.1252;LC_CTYPE=French_France.1252;LC_MONETARY=French_France.1252;LC_NUMERIC=C;LC_TIME=French_France.1252

 attached base packages:
 [1] stats graphics  grDevices datasets  tcltk utils methods
 [8] base

 other attached packages:
 [1] svSocket_0.9-5 svIO_0.9-5 R2HTML_1.58svMisc_0.9-5   svIDE_0.9-5

 loaded via a namespace (and not attached):
 [1] tools_2.6.0




 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

 Wolfgang Raffelsberger, PhD
 Laboratoire de BioInformatique et Génomique Intégratives
 CNRS UMR7104, IGBMC
 1 rue Laurent Fries,  67404 Illkirch  Strasbourg,  France
 Tel (+33) 388 65 3300 Fax (+33) 388 65 3276
 [EMAIL PROTECTED]

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Re: [R] simulating a 2-parameter integrated ornstein-uhlenbeck process?

2007-11-28 Thread Ravi Varadhan
You may want to check the package sde that can simulate from a number of
different stochastic differential equations, including the OU process.  

Ravi.




---

Ravi Varadhan, Ph.D.

Assistant Professor, The Center on Aging and Health

Division of Geriatric Medicine and Gerontology 

Johns Hopkins University

Ph: (410) 502-2619

Fax: (410) 614-9625

Email: [EMAIL PROTECTED]

Webpage:  http://www.jhsph.edu/agingandhealth/People/Faculty/Varadhan.html

 





-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of Farzad Noubary
Sent: Wednesday, November 28, 2007 7:58 AM
To: r-help@r-project.org
Subject: [R] simulating a 2-parameter integrated ornstein-uhlenbeck process?

hello everyone,

i'm trying to simulate a 2-parameter integrated ornstein-uhlenbeck (IOU)
process, but i'm not sure exactly where to start (which package, which
function). the motivation is the paper by taylor et. al. (JASA 1994) a
stochastic model for the analysis of longitudinal aids data. the model they
suggest consists of a combination of fixed and random effects, a stochastic
process, and measurement error. 

the 2-parameter IOU process they suggest has cov[W(s), W(t)] =
(sigma^2/(2alpha^3)[2alpha min(s,t)+exp(-alpha* t) +exp(-alpha* s)-1
-exp(alpha*|t-s|)).

any insight into either fitting the model or simulating a 2-parameter IOU
process would be appreciated.

thanks,
farzad





 


Be a better sports nut!  Let your teams follow you 

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Re: [R] Fortran Code to R Code

2007-11-28 Thread Dave Roberts
Bryan,

 The previous responses will point you in the right direction.  I 
have found, however, that it takes a while to get used to the 
requirements, and there are many possible sources of error.

1) You have to convert the main program to a subroutine.  Any arrays 
declared in the main program or any nested subroutine have to created in 
R before the subroutine is called, and passed to the subroutine.  On the 
other hand, this provides the advantage of allocatable array size in 
FORTRAN 77.

2) You have to make sure that you are very careful about storage.  I 
have reluctantly decided that attempting minimize storage by using 
integer*2 and real*4 is not worth it, and I now use just integer and 
double precision to minimize problems with R.

3) Consider casting every variable passed in the .Fortran() call.  Many 
of them would be correct by default possibly, but it is easier to simply 
cast them all, e.g. as.integer() for all integers, as.double() for real 
numbers.  These get the storage right, and strip of any attributes 
besides he actual values.  Fortunately, R and FORTRAN agree about 
storage order in arrays and you don't have to micro-manage that.

4) When you get it wrong, the probability of a seg fault and hard crash 
is very high.  So, every time you modify the R function that calls the 
.Fortran you have written, do a save.image() before you try the code. 
Otherwise you lose all your changes.  If you have the luxury of working 
in linux (and presumably other *nixes), you can use write(6,*) 
whatever debug statements in your code and the output goes to your R 
session.  In Windows, you have to use the specific debug routines 
described in the R manuals.

5) Managing the returned values has to handled in the .Fortran() call by 
giving the argument a name.  Then, that name can be used as the 
component name of the returned object.  Just below is an example from 
labdsv that converts any dissimilarity or distance matrix to the nearest 
euclidean distance object.  The PACKAGE= argument is used when the 
routine is pat of a package; it's not necessary for ad hoc functions.

euclidify - function (x,upper=FALSE,diag=FALSE)
{
 x - as.dist(x)
 tmp - .Fortran(euclid,
 x=as.matrix(x),
 as.integer(attr(x,Size)),
 PACKAGE='labdsv')
 tmp2 - as.dist(tmp$x)
 attr(tmp2, Labels) - dimnames(x)[[1]]
 attr(tmp2, Diag) - diag
 attr(tmp2, Upper) - upper
 attr(tmp2, method) - paste(euclidify, attr(x, method))
 attr(tmp2, call) - match.call()
 tmp2
}

Dave Roberts


Bryan Klingaman wrote:
 How do you convert Fortran Code to R Code to use and execute in R?  Or how do 
 you take Fortran code and make it run in R?  So what I'm getting at is, I 
 have some code in fortran and I want to be able to run that same code for R.  
 Please email me back and let me know how to do that, thanks.

   Bryan
   Email: [EMAIL PROTECTED]
 

 -
 
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[R] Graphics after invoking R from the command line

2007-11-28 Thread Mithun Jacob
I've tried running graphics commands like plot by invoking R at the
command line but the graphics window does not appear. I'm using
R-2.6.0 on Windows XP and am using the cmd shell. Here's a sample
session:

R --slave --save --file=-
x-c(1,2,3,4)
plot(x,x)

This leads to nothing. I've found a way around it, but the graph
window is frozen and commands to it have to be sent twice for the data
to appear.

R --slave --save --file=-
x-c(1,2,3,4)
windows()
plot(x,x)
plot(x,x)

Am I doing something wrong here? It would be nice if I could display a
graphics window which isn't frozen.

Regards,
Mithun

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Re: [R] PCA with NA

2007-11-28 Thread Birgit Lemcke
Hello,

unfortunately I can not find the pcaMethods package.

Birgit

Am 26.11.2007 um 16:26 schrieb Kevin Wright:

 The pcaMethods package offers a collection of different algorithms for
 PCA, some of which (NIPALS and others) can be used on data that have
 missing values.

 Kevin Wright


 On Nov 24, 2007 4:59 PM, Hartmut Oldenbürger [EMAIL PROTECTED]  
 wrote:
 Hi Birgit, and All

 Possibly you should not consider the case completed ;-)
 There is an important alternative to imputing means, or estimates  
 from
 first or second order
 regression (Frane, Psychometrica, BMDP):  partial-least-squares  
 (Wold),
 which uses as much
 information from the data as possible to estimate the principal
 components, or the missing data.

 Stephane Dray, also from Lyon, provides 'nipals' here:
 http://biomserv.univ-lyon1.fr/~dray/software.php
 There is also an interesting paper.  - In case, you use PLS to  
 estimate
 and impute, set the
 number of factors as high as reasonably possible, e.g. m-1, when m is
 the number of variables.
 best - Hartmut  
 Oldenbürger
 ---
 [EMAIL PROTECTED]
 http://www.wipaed.wiso.uni-goettingen.de/~holdenb1


 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting- 
 guide.html
 and provide commented, minimal, self-contained, reproducible code.


Birgit Lemcke
Institut für Systematische Botanik
Zollikerstrasse 107
CH-8008 Zürich
Switzerland
Ph: +41 (0)44 634 8351
[EMAIL PROTECTED]

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Re: [R] Replacing values job

2007-11-28 Thread Peter Dalgaard
Barry Rowlingson wrote:
 jim holtman wrote:
   
 ?match

 
 X
   
 [1] 2 6 1 7 4 3 5
 
 Y
   
  [1] 1 1 6 4 6 1 4 1 2 3 6 6 1 2 4 4 5 4 1 7 6 6 4 4 7 1 2
 
 match(Y,X)
   
  [1] 3 3 2 5 2 3 5 3 1 6 2 2 3 1 5 5 7 5 3 4 2 2 5 5 4 3 1

 

   I quite like this solution:

X[X[X[X[X[X[X[X[X[X[X]][Y]
 [1] 3 3 2 5 2 3 5 3 1 6 2 2 3 1 5 5 7 5 3 4 2 2 5 5 4 3 1

   but somehow I don't think its general enough...
   
!!

Grin

order(X)[Y] 

is a little more general. Still only works when X is a permutation of
1:N, of course.

 Barry

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-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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Re: [R] problem with plotting table

2007-11-28 Thread Carlos Gershenson
Thank you very much Duncan, that did the works.

Thank you also Gavin and Bernardo for your feedback.

Best regards,
Carlos

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Re: [R] Graphics after invoking R from the command line

2007-11-28 Thread Duncan Murdoch
On 11/28/2007 12:05 PM, Mithun Jacob wrote:
 I've tried running graphics commands like plot by invoking R at the
 command line but the graphics window does not appear. I'm using
 R-2.6.0 on Windows XP and am using the cmd shell. Here's a sample
 session:
 
 R --slave --save --file=-
 x-c(1,2,3,4)
 plot(x,x)
 
 This leads to nothing. I've found a way around it, but the graph
 window is frozen and commands to it have to be sent twice for the data
 to appear.
 
 R --slave --save --file=-
 x-c(1,2,3,4)
 windows()
 plot(x,x)
 plot(x,x)
 
 Am I doing something wrong here? It would be nice if I could display a
 graphics window which isn't frozen.

Do you really need to run R --slave?  R is assuming it is running 
non-interactively, and won't leave any time free to handle events and 
update the window.  If you just used R or Rterm as your command, 
you'd get an interactive command-line version of R running, and 
everything should work.

Duncan Murdoch

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Re: [R] PCA with NA

2007-11-28 Thread Paul Hewson
Hello,
It's on bioconductor.   Try changing the repository when installing packages

Best

Paul


-=-=-=-=-=-=-=-=-=-=-=-=
Paul Hewson
Lecturer in Statistics
School of Mathematics and Statistics
University of Plymouth
Drake Circus
Plymouth PL4 8AA

tel (01752) 232778 (Campus)
tel (01752) 764437 (Tamar Science Park)
fax (01752) 232780

email: [EMAIL PROTECTED]
web: http://www.plymouth.ac.uk/staff/phewson
-=-=-=-=-=-=-=-=-=-=-=-=




-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Birgit Lemcke
Sent: 28 November 2007 17:05
To: Kevin Wright
Cc: R Hilfe
Subject: Re: [R] PCA with NA

Hello,

unfortunately I can not find the pcaMethods package.

Birgit

Am 26.11.2007 um 16:26 schrieb Kevin Wright:

 The pcaMethods package offers a collection of different algorithms for
 PCA, some of which (NIPALS and others) can be used on data that have
 missing values.

 Kevin Wright


 On Nov 24, 2007 4:59 PM, Hartmut Oldenbürger [EMAIL PROTECTED]
 wrote:
 Hi Birgit, and All

 Possibly you should not consider the case completed ;-)
 There is an important alternative to imputing means, or estimates
 from
 first or second order
 regression (Frane, Psychometrica, BMDP):  partial-least-squares
 (Wold),
 which uses as much
 information from the data as possible to estimate the principal
 components, or the missing data.

 Stephane Dray, also from Lyon, provides 'nipals' here:
 http://biomserv.univ-lyon1.fr/~dray/software.php
 There is also an interesting paper.  - In case, you use PLS to
 estimate
 and impute, set the
 number of factors as high as reasonably possible, e.g. m-1, when m is
 the number of variables.
 best - Hartmut
 Oldenbürger
 ---
 [EMAIL PROTECTED]
 http://www.wipaed.wiso.uni-goettingen.de/~holdenb1


 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-
 guide.html
 and provide commented, minimal, self-contained, reproducible code.


Birgit Lemcke
Institut für Systematische Botanik
Zollikerstrasse 107
CH-8008 Zürich
Switzerland
Ph: +41 (0)44 634 8351
[EMAIL PROTECTED]

__
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Re: [R] Graphics after invoking R from the command line

2007-11-28 Thread Prof Brian Ripley
On Wed, 28 Nov 2007, Mithun Jacob wrote:

 I've tried running graphics commands like plot by invoking R at the
 command line but the graphics window does not appear. I'm using
 R-2.6.0 on Windows XP and am using the cmd shell. Here's a sample
 session:

 R --slave --save --file=-
 x-c(1,2,3,4)
 plot(x,x)

 This leads to nothing. I've found a way around it, but the graph
 window is frozen and commands to it have to be sent twice for the data
 to appear.

 R --slave --save --file=-
 x-c(1,2,3,4)
 windows()
 plot(x,x)
 plot(x,x)

 Am I doing something wrong here? It would be nice if I could display a
 graphics window which isn't frozen.

So use R interactively, rather than in batch mode typing at stdin. (Using 
--file puts you into batch mode.) Only in interactive use does the event 
loop give time to windows such as the screen device, pagers, data frame 
viewers 

I have no idea where you got the idea of 'R --slave --save --file=-' from: 
the way to use R 'at the command line' on Windows is to use Rterm.
'Rterm --slave --save' would do the same without the freezing, but most 
people do find prompts useful.

-- 
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Graphics after invoking R from the command line

2007-11-28 Thread Prof Brian Ripley
On Wed, 28 Nov 2007, Mithun Jacob wrote:

 Duncan Murdoch

 I wish to run R with Visual C++ as a front end. So I was hoping to run
 a file such as graph.r in the following manner:

 R --slave --save --file=graph.r

 But when the plot function runs, it does not display the graph.

 Prof Brian Ripley:

Eh, that's not me you are quoting!

 So would I be correct to assume that it's not possible to run graphics
 in batch mode?

Running the on-screen device is not intended to be done in batch mode, no. 
(It would be useless as it would disappear at the end of the 
computations.)  You can pipe to stdin and use --ess to force R to behave 
interactively.  Better, you could use an embedded R via (D)COM or 
Rserve or otherwise (see `Writing R Extensions').

In future, please consider posing your real problem rather than asking 
about a solution to an unstated problem that few of us would have 
contemplated.

AND mention 'Windows' in your subject line, as all this is specific to 
Windows.


 Thanks for all the help!

 Regards,
 Mithun

 On 11/28/07, Prof Brian Ripley [EMAIL PROTECTED] wrote:
 On Wed, 28 Nov 2007, Mithun Jacob wrote:

 I've tried running graphics commands like plot by invoking R at the
 command line but the graphics window does not appear. I'm using
 R-2.6.0 on Windows XP and am using the cmd shell. Here's a sample
 session:

 R --slave --save --file=-
 x-c(1,2,3,4)
 plot(x,x)

 This leads to nothing. I've found a way around it, but the graph
 window is frozen and commands to it have to be sent twice for the data
 to appear.

 R --slave --save --file=-
 x-c(1,2,3,4)
 windows()
 plot(x,x)
 plot(x,x)

 Am I doing something wrong here? It would be nice if I could display a
 graphics window which isn't frozen.

 So use R interactively, rather than in batch mode typing at stdin. (Using
 --file puts you into batch mode.) Only in interactive use does the event
 loop give time to windows such as the screen device, pagers, data frame
 viewers 

 I have no idea where you got the idea of 'R --slave --save --file=-' from:
 the way to use R 'at the command line' on Windows is to use Rterm.
 'Rterm --slave --save' would do the same without the freezing, but most
 people do find prompts useful.

-- 
Brian D. Ripley,  [EMAIL PROTECTED]
Professor of Applied Statistics,  http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel:  +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UKFax:  +44 1865 272595

__
R-help@r-project.org mailing list
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.


Re: [R] Graphics after invoking R from the command line

2007-11-28 Thread Duncan Murdoch
On 11/28/2007 12:52 PM, Mithun Jacob wrote:

 I wish to run R with Visual C++ as a front end. So I was hoping to run
 a file such as graph.r in the following manner:
 
 R --slave --save --file=graph.r

I'd set things up to save the graphics to a file, and get your C++ 
program to display the file.

Duncan Murdoch

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Re: [R] How to create data frame from data with unequal length

2007-11-28 Thread Peter Dalgaard
tom soyer wrote:
 Hi,

 I have two sets of data that I would like to put into a data frame. But
 since they have different length, I am not sure how to do this. Here is an
 example of my data:

 data set one:
 date growth
 1/1/2007   10
 1/2/2007   10.2
 1/3/2007   10.4
 1/4/2007   10.6

 data set two:
  date growth
 1/1/2007   22
 1/2/2007   22.5
 1/4/2007   22.4

 I would like to combine the two data sets and create a data frame like this:
  date growthAgrowthB
 1/1/2007   1022
 1/2/2007   10.2 22.5
 1/3/2007   10.4 NA
 1/4/2007   10.6 22.4

 Or skipping the missing data point all together, like this:
  date growthAgrowthB
 1/1/2007   1022
 1/2/2007   10.2 22.5
 1/4/2007   10.6 22.4

 Right now I am doing this by hand, and it is really time consuming. I am
 wondering if there is an easier way of creating data frames from unequal
 length data using existing R functions. Is there a way to create data
 with equal length based on the date column? I would appreciate any help from
 the group.

 Thanks,

   
I'd have a look at merge() if I were you.

-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - ([EMAIL PROTECTED])  FAX: (+45) 35327907

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[R] ggplot2 melt function value

2007-11-28 Thread Felipe Carrillo
Hi:I recently started using the melt function and
found that it is very useful and powerful,however I
can't seem to find the way to change the default
column header value to my custom column name. Does
anyone know how to go about this? any suggestions are
very appreciated. Thanks

Felipe D. Carrillo
  Fishery Biologist
  US Fish  Wildlife Service
  California, USA



  

Never miss a thing.  Make Yahoo your home page.

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[R] How to create data frame from data with unequal length

2007-11-28 Thread tom soyer
Hi,

I have two sets of data that I would like to put into a data frame. But
since they have different length, I am not sure how to do this. Here is an
example of my data:

data set one:
date growth
1/1/2007   10
1/2/2007   10.2
1/3/2007   10.4
1/4/2007   10.6

data set two:
 date growth
1/1/2007   22
1/2/2007   22.5
1/4/2007   22.4

I would like to combine the two data sets and create a data frame like this:
 date growthAgrowthB
1/1/2007   1022
1/2/2007   10.2 22.5
1/3/2007   10.4 NA
1/4/2007   10.6 22.4

Or skipping the missing data point all together, like this:
 date growthAgrowthB
1/1/2007   1022
1/2/2007   10.2 22.5
1/4/2007   10.6 22.4

Right now I am doing this by hand, and it is really time consuming. I am
wondering if there is an easier way of creating data frames from unequal
length data using existing R functions. Is there a way to create data
with equal length based on the date column? I would appreciate any help from
the group.

Thanks,

-- 
Tom

[[alternative HTML version deleted]]

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Re: [R] How to create data frame from data with unequal length

2007-11-28 Thread tom soyer
Merge worked! Thanks!!!

On 11/28/07, Matthew Keller [EMAIL PROTECTED] wrote:

 Tom,

 Check out ?merge. Does exactly what you need

 Matt

 On Nov 28, 2007 11:27 AM, tom soyer [EMAIL PROTECTED] wrote:
  Hi,
 
  I have two sets of data that I would like to put into a data frame. But
  since they have different length, I am not sure how to do this. Here is
 an
  example of my data:
 
  data set one:
  date growth
  1/1/2007   10
  1/2/2007   10.2
  1/3/2007   10.4
  1/4/2007   10.6
 
  data set two:
   date growth
  1/1/2007   22
  1/2/2007   22.5
  1/4/2007   22.4
 
  I would like to combine the two data sets and create a data frame like
 this:
   date growthAgrowthB
  1/1/2007   1022
  1/2/2007   10.2 22.5
  1/3/2007   10.4 NA
  1/4/2007   10.6 22.4
 
  Or skipping the missing data point all together, like this:
   date growthAgrowthB
  1/1/2007   1022
  1/2/2007   10.2 22.5
  1/4/2007   10.6 22.4
 
  Right now I am doing this by hand, and it is really time consuming. I am
  wondering if there is an easier way of creating data frames from unequal
  length data using existing R functions. Is there a way to create data
  with equal length based on the date column? I would appreciate any help
 from
  the group.
 
  Thanks,
 
  --
  Tom
 
  [[alternative HTML version deleted]]
 
  __
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  PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
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 --
 Matthew C Keller
 Asst. Professor of Psychology
 University of Colorado at Boulder
 www.matthewckeller.com




-- 
Tom

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Re: [R] How to create data frame from data with unequal length

2007-11-28 Thread Henrique Dallazuanna
Try this:

merge(df1, df2, by.y=1, by.x=1, all=T)
merge(df1, df2, by.y=1, by.x=1)

On 28/11/2007, tom soyer [EMAIL PROTECTED] wrote:
 Hi,

 I have two sets of data that I would like to put into a data frame. But
 since they have different length, I am not sure how to do this. Here is an
 example of my data:

 data set one:
 date growth
 1/1/2007   10
 1/2/2007   10.2
 1/3/2007   10.4
 1/4/2007   10.6

 data set two:
  date growth
 1/1/2007   22
 1/2/2007   22.5
 1/4/2007   22.4

 I would like to combine the two data sets and create a data frame like this:
  date growthAgrowthB
 1/1/2007   1022
 1/2/2007   10.2 22.5
 1/3/2007   10.4 NA
 1/4/2007   10.6 22.4

 Or skipping the missing data point all together, like this:
  date growthAgrowthB
 1/1/2007   1022
 1/2/2007   10.2 22.5
 1/4/2007   10.6 22.4

 Right now I am doing this by hand, and it is really time consuming. I am
 wondering if there is an easier way of creating data frames from unequal
 length data using existing R functions. Is there a way to create data
 with equal length based on the date column? I would appreciate any help from
 the group.

 Thanks,

 --
 Tom

 [[alternative HTML version deleted]]

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.



-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40 S 49° 16' 22 O

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Re: [R] How to create data frame from data with unequal length

2007-11-28 Thread Matthew Keller
Tom,

Check out ?merge. Does exactly what you need

Matt

On Nov 28, 2007 11:27 AM, tom soyer [EMAIL PROTECTED] wrote:
 Hi,

 I have two sets of data that I would like to put into a data frame. But
 since they have different length, I am not sure how to do this. Here is an
 example of my data:

 data set one:
 date growth
 1/1/2007   10
 1/2/2007   10.2
 1/3/2007   10.4
 1/4/2007   10.6

 data set two:
  date growth
 1/1/2007   22
 1/2/2007   22.5
 1/4/2007   22.4

 I would like to combine the two data sets and create a data frame like this:
  date growthAgrowthB
 1/1/2007   1022
 1/2/2007   10.2 22.5
 1/3/2007   10.4 NA
 1/4/2007   10.6 22.4

 Or skipping the missing data point all together, like this:
  date growthAgrowthB
 1/1/2007   1022
 1/2/2007   10.2 22.5
 1/4/2007   10.6 22.4

 Right now I am doing this by hand, and it is really time consuming. I am
 wondering if there is an easier way of creating data frames from unequal
 length data using existing R functions. Is there a way to create data
 with equal length based on the date column? I would appreciate any help from
 the group.

 Thanks,

 --
 Tom

 [[alternative HTML version deleted]]

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
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-- 
Matthew C Keller
Asst. Professor of Psychology
University of Colorado at Boulder
www.matthewckeller.com

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Re: [R] Can't make affylmGUI work

2007-11-28 Thread Martin Morgan
Feifei -- 

Ask on the Bioconductor mailing list http://bioconductor.org. Update
your Bioc packages following instructions on the 'install - how to'
page linked from the main bioconductor page -- your affy is out of
date.

Best, Martin

Feifei [EMAIL PROTECTED] writes:

 Hi,

 Can anyone help me of the affylmGUI package, I can't get it work and
 searched for google but can't find any proper solutions.

 I get the error information each time when I load my cells files, which
 are shown in the following links.
 -
 http://clarezoe.googlepages.com/1.png
 http://clarezoe.googlepages.com/2.png
 http://clarezoe.googlepages.com/3.png
 -

 Errors also show in the terminal as below,
 -
   Error: no function to return from, jumping to top level
   In addition: Warning messages:
   1: read.phenoData is deprecated, use read.AnnotatedDataFrame instead 
   2: The phenoData class is deprecated, use AnnotatedDataFrame (with
 ExpressionSet) instead 
   Error in exprs(RawAffyData) : 
   no function to return from, jumping to top level
 --

 I'm running R version 2.6.1 under Linux Ubuntu 7.10

 --

 My sessionInfo is shown below,

 --
   sessionInfo()
  R version 2.6.1 (2007-11-26) 
  i486-pc-linux-gnu 

  locale:

 LC_CTYPE=en_US.UTF-8;LC_NUMERIC=C;LC_TIME=en_US.UTF-8;LC_COLLATE=en_US.UTF-8;LC_MONETARY=en_US.UTF-8;LC_MESSAGES=en_US.UTF-8;LC_PAPER=en_US.UTF-8;LC_NAME=C;LC_ADDRESS=C;LC_TELEPHONE=C;LC_MEASUREMENT=en_US.UTF-8;LC_IDENTIFICATION=C

  attached base packages:
  [1] tools tcltk stats graphics  grDevices utils
 datasets 
  [8] methods   base 

  other attached packages:
  [1] affylmGUI_1.12.0 affy_1.12.2  affyio_1.6.1 Biobase_1.16.1  
  [5] limma_2.12.0

  loaded via a namespace (and not attached):
  [1] rcompgen_0.1-17
 

 Can anyone help me with that? I really need it to work ASAP.

 Thanks a lot!

 Sincerely 
 Feifei

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Re: [R] visualizing nucleotide sequence properties

2007-11-28 Thread Jean lobry
Hi there,

I am looking for R-packages that can help me visualize properties on
nucleotide sequences. I want to display sequences in the 1-100K base range
as lines and plot features above and below those lines.

Any ideas would be welcome.

Thanks,

Bernd

Hi Bernd,

not sure to understand what you mean by properties. Let's say the
property you are interested in is the GC-skew. You can try something
along these lines:

#
# Load DNA sequence data:
#
library(seqinr)
myseq - read.fasta(as.string = TRUE)
#
# Define a function to compute the GC skew:
#
gcskew - function(x) {
   if (!is.character(x) || length(x)  1)
   stop(single string expected)
   tmp - tolower(s2c(x))
   nC - sum(tmp == c)
   nG - sum(tmp == g)
   if (nC + nG == 0) return(NA)
   return(100 * (nC - nG)/(nC + nG))
}
#
# Moving window along the sequence:
#
step - 1
wsize - 1
starts - seq(from = 1, to = nchar(myseq), by = step)
starts - starts[-length(starts)]
n - length(starts)
result - numeric(n)
for (i in seq_len(n)) {
   result[i] - gcskew(substr(myseq, starts[i], starts[i] + wsize - 1))
}
#
# Plot the result:
#
xx - starts/1000 # in Kbp
yy - result
n - length(result)
hline - 0
plot(yy ~ xx, type = n, axes = FALSE, ann = FALSE)
polygon(c(xx[1], xx, xx[n]), c(min(yy), yy, min(yy)),
   col = black, border = NA)
usr - par(usr)
rect(usr[1], usr[3], usr[2], hline, col = white, border = NA)
lines(xx, yy)
abline(h = hline)
box()
axis(1, at = seq(0, 1000, by = 200))
axis(2, las = 1)
title(xlab = position (Kbp), ylab = (C-G)/(C+G) [percent],
   main = expression(paste(GC skew in , italic(Chlamydia~trachomatis
arrows(800, 5.5, 720, 0.5, length = 0.1, lwd = 2)
text(800, 5.5, origin of\nreplication, pos = 4)

HTH,

Jean
-- 
Jean R. Lobry([EMAIL PROTECTED])
Laboratoire BBE-CNRS-UMR-5558, Univ. C. Bernard - LYON I,
43 Bd 11/11/1918, F-69622 VILLEURBANNE CEDEX, FRANCE
allo  : +33 472 43 27 56 fax: +33 472 43 13 88
http://pbil.univ-lyon1.fr/members/lobry/

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[R] Rmpi : openmpi and mpi.spawn.Rslaves

2007-11-28 Thread Paul Hewson
Hello,

I'm using R on a 10 blade dual quad core Rocks Cluster, and trying to use Rpmi 
and snow.   I basically wondered if at the moment I ought to install Rmpi 
against another form of mpi (not openmpi) and wondered whether anyone could 
pass on any experience.

I'm mainly worried about (a) the R server taking up 100% cpu time (I think this 
is a known issue with Rmpi and openmpi) and (b) checking that my slaves are 
running on separate nodes rather than all piling onto the same nodes (on the 
server).   Some very crude experiments in snow imply that slave processes might 
well be getting passed on to separate nodes beyond the server.

However, it's a little harder convincing myself which nodes are doing what.   
When looking directly in Rmpi, lamhosts() reports all the hosts correctly, 
unfortunately mpi.universe.size reports 1 node (I think this is as documented). 
  More importantly, I have the issue with mpi.spawn.Rslaves() freezing.   This 
has been mentioned before:
http://tolstoy.newcastle.edu.au/R/e2/help/07/06/18573.html

I wondered if anyone would mind supplying pointers.   I'm specifically 
wondering if I need to check the version of openmpi, and whether at the moment 
it would be better to use another flavour of mpi.

I would be extremely grateful for any advice.

Thanks

Paul

-=-=-==-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
Paul Hewson
Lecturer in Statistics
University of Plymouth
Drake Circus
Plymouth PL4 8AA

tel ++44(0)1752 232778
email [EMAIL PROTECTED]
web http://www.plymouth.ac.uk/staff/phewson

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[R] Problem using Tobit models in R (Testing and controlling for distributional assumptions and endogeneity)

2007-11-28 Thread Malte Brockmann

Dear R-Community,

I am currently using Tobit models (survreg in the survival package).

1a) Does R provide a straight-forward way to test distributional assumptions 
for tobit models?
1b) If not: I tried to apply the Hausman-test proposed in Newey (1987), Journal 
of Econometrics, on the Tobit estimator and the symmetrically censored least 
squares estimator proposed by Powell (1986) (quantreg package). Unfortunately, 
quantreg only provides covariance matrices based on the bootstrap which are not 
positive semi-definite, therefore the hausman test statistic based on the 
difference between both covariance matrices can be negative. Newey proposes 2 
ways to calculate positive semi-definite covariance matrices: Is there a way to 
implement any of these without manually coding (or adapting) the tobit and SCLS 
estimation procedures to extract the necessary information needed for the 
estimation (first derivative of loglik w.r.t. theta, etc.)?

2) I apply the test for endogeneity proposed by Smith and Blundell (1986), 
Econometrica, and one of my variables turns out to be endogenous. Does R have a 
package for simultaneous equations with censored dependent variables? As far as 
I know, the sem package does estimate these types of equations.

Thanks in advance
Malte
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Re: [R] voronoi/Delaunay/Dirichlet tessellation on sphere in R or S?

2007-11-28 Thread Sandrine-et-Francois
Hi Jan,
In case you don't know it already, the reference book for Voronoi diagrams 
and co. is :
Spatial Tessellations: Concepts and Applications of Voronoi Diagrams
by Okabe et al. (Ed. Wiley). It's a bit old now ... but it's 'a' good 
reference.
HTH,
Best regards,
François

- Original Message - 
From: Galkowski, Jan [EMAIL PROTECTED]
To: r-help@r-project.org
Sent: Tuesday, November 27, 2007 5:51 PM
Subject: [R] voronoi/Delaunay/Dirichlet tessellation on sphere in R or S?


 There's Renka's STRIPACK, and TRIPACK, respectively, ACM TOMS Algorithms
 772 and 751, and there's the R package deldir which does the Delaunay
 for a plane, but does anyone have or know of the tessellation in R for a
 sphere?

 Also, is there a standard indexing scheme for Delaunay facets, and
 perhaps of edges in such facets?  I'd expect that to be a publication
 reference, or even textbook.

 TIA,

 - Jan



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Re: [R] Problem using Tobit models in R (Testing and controlling for distributional assumptions and endogeneity)

2007-11-28 Thread roger koenker

url:www.econ.uiuc.edu/~rogerRoger Koenker
email[EMAIL PROTECTED]Department of Economics
vox: 217-333-4558University of Illinois
fax:   217-244-6678Champaign, IL 61820


On Nov 28, 2007, at 2:45 PM, Malte Brockmann wrote:


 Dear R-Community,

 I am currently using Tobit models (survreg in the survival package).

 1a) Does R provide a straight-forward way to test distributional  
 assumptions for tobit models?
 1b) If not: I tried to apply the Hausman-test proposed in Newey  
 (1987), Journal of Econometrics, on the Tobit estimator and the  
 symmetrically censored least squares estimator proposed by Powell  
 (1986) (quantreg package).

This symmetrically censored least squares estimator  is NOT what is  
computed by the quantreg package.
What is computed is the Powell quantile regression estimator.

 Unfortunately, quantreg only provides covariance matrices based on  
 the bootstrap which are not positive semi-definite,

The bootstrapped covariance provided by quantreg is the usual sample  
covariance matrix of the bootstrapped
realizations and is therefore necessarily positive semi-definite.   
Perhaps what you meant to say was that the
difference between the two covariance matrices that you have computed  
was not psd;  this could easily happen.
Nothing ensures that the Powell QR estimate is less efficient than  
the usual (normal theory) tobit estimator,
indeed there are very plausible conditions under which this is not  
the case.

 therefore the hausman test statistic based on the difference  
 between both covariance matrices can be negative. Newey proposes 2  
 ways to calculate positive semi-definite covariance matrices: Is  
 there a way to implement any of these without manually coding (or  
 adapting) the tobit and SCLS estimation procedures to extract the  
 necessary information needed for the estimation (first derivative  
 of loglik w.r.t. theta, etc.)?

 2) I apply the test for endogeneity proposed by Smith and Blundell  
 (1986), Econometrica, and one of my variables turns out to be  
 endogenous. Does R have a package for simultaneous equations with  
 censored dependent variables? As far as I know, the sem package  
 does estimate these types of equations.

 Thanks in advance
 Malte
 __
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 guide.html
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[R] Dates in R

2007-11-28 Thread Irina Burmenko
Hi,

I have dates in the following format: 4/8/2006 (MM/DD/).  I need to have R 
compare date A to date B to figure out which one is more recent.  Is there a 
way to do that?  Simply using the '' or '' signs doesn't seem to work.  I 
think in this case R treats '/' as a division sign and gives me erroneous 
results.

Thanks a lot for your help.
Irina


  

Never miss a thing.  Make Yahoo your home page. 

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[R] Power Spectral Sensity

2007-11-28 Thread stephen sefick
I am working with a dissolved oxygen dataset.  continuous readings are taken
at 15 minute intervals and we have been recording these data at 12 stations
along the savannah river for two years now.  The longest set of readings
that are continuous without interuption is 53 days.  I would like to look at
the power spectral density at each of these sites (most likely one day will
be the overridding trend due to photosynthesis and respiration).  I would
also like to look at the cross spectrums between to contiguous site to look
for advective transport from the upstream sections.I have used spectrum to
get a periodogram.  This I don't believe is the power spectral density.  If
it is I am unsure how to determine the # in the  span argument to smooth the
periodogram.  I imagine that I am overlooking something- I appreciate all of
your help.

stephen

-- 
Let's not spend our time and resources thinking about things that are so
little or so large that all they really do for us is puff us up and make us
feel like gods.  We are mammals, and have not exhausted the annoying little
problems of being mammals.

-K. Mullis

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Re: [R] Dates in R

2007-11-28 Thread jim holtman
Convert to Date and then compare;


 x - as.Date(4/8/2006, %m/%d/%Y)
 y - as.Date(5/10/2007, %m/%d/%Y)
 xy
[1] FALSE


On Nov 28, 2007 2:44 PM, Irina Burmenko [EMAIL PROTECTED] wrote:
 Hi,

 I have dates in the following format: 4/8/2006 (MM/DD/).  I need to have 
 R compare date A to date B to figure out which one is more recent.  Is there 
 a way to do that?  Simply using the '' or '' signs doesn't seem to work.  I 
 think in this case R treats '/' as a division sign and gives me erroneous 
 results.

 Thanks a lot for your help.
 Irina


  
 
 Never miss a thing.  Make Yahoo your home page.

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 and provide commented, minimal, self-contained, reproducible code.




-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem you are trying to solve?

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and provide commented, minimal, self-contained, reproducible code.


[R] Heatmap or Heatmap.2---hclust

2007-11-28 Thread affy snp
Hi list,

I used heatmap() and heatmap.2() to draw the dendrogram
and got error messages for both. They were:

heatmap(as.matrix(y3),col=rainbow(256),scale = column);dev.off();
Error in hclustfun(distfun(x)) :
  NA/NaN/Inf in foreign function call (arg 11)

Does anybody know how to correct this? I do see some NAs in
the dataset.

Thanks a lot!
 Allen

[[alternative HTML version deleted]]

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Re: [R] ftable as latex (with Hmisc?)

2007-11-28 Thread Richard M. Heiberger
I think this does what you are asking for.  It should be
relatively easy to write a method

latex.ftable()

based on this.  One or two row.vars and one or two col.vars
should be straightforward (with n.rgroup and n.cgroup used
for the second row and column).

Rich

 start here
df = data.frame(drug=sample(c(P,V),100,TRUE),
Hist1=sample(c(Pos,Neg),100,TRUE),
Hist2=sample(c(Pos,Neg),100,TRUE))
ft.df - ftable(drug~Hist1+Hist2,data=df)
str(ft.df)

tmp - unclass(ft.df)[,]
dimnames(tmp) - list(rep(attr(ft.df, row.vars)[[2]], 2),
  attr(ft.df, col.vars)[[1]])
ft.latex - latex(tmp,
  rgroup=attr(ft.df, row.vars)[[1]],
  n.rgroup=c(2,2),
  cgroup=names(attr(ft.df, col.vars))[1])

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Re: [R] Dates in R

2007-11-28 Thread Horace Tso
Irina, you must have them in character format. You need to convert to Date type.

mydates = as.Date(mydates, %m/%d/%Y)

HTH.

Horace

-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Irina Burmenko
Sent: Wednesday, November 28, 2007 11:44 AM
To: Horace Tso; r-help@r-project.org
Subject: [R] Dates in R

Hi,

I have dates in the following format: 4/8/2006 (MM/DD/).  I need to have R 
compare date A to date B to figure out which one is more recent.  Is there a 
way to do that?  Simply using the '' or '' signs doesn't seem to work.  I 
think in this case R treats '/' as a division sign and gives me erroneous 
results.

Thanks a lot for your help.
Irina


  

Never miss a thing.  Make Yahoo your home page.

[[alternative HTML version deleted]]

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[R] trouble for building R package in Windows

2007-11-28 Thread aminzoll
Dear All,
I think I have followed everything for building my first R package  
(Downloading Rtools, necessary files in necessary locations, no space  
in path and...). But when in command Prompt I write Rcmd check  
mypackage the first few steps are OK but then it gives the  
following error:
checking whether package roots can be installed.ERROR
installation failed
see roots.Rcheck/00install.out for details
and this is the contents of the file:

installing R.css in c:/removethis/R/R2.6.1/bin/roots.Rcheck


-- Making package roots 
   adding build stamp to DESCRIPTION
   making DLL ...
making fifrt.d from fifrt.c
gcc-sjlj  -std=gnu99  -Ic:/removethis/R/R2.6.1/include -O3 -Wall   
-c fifrt.c -o fifrt.o
windres --preprocessor=gcc-sjlj -E -xc -DRC_INVOKED -I  
c:/removethis/R/R2.6.1/include  -i roots_res.rc -o roots_res.o
gcc-sjlj  -std=gnu99  -shared -s  -o roots.dll roots.def fifrt.o  
roots_res.o  -Lc:/removethis/R/R2.6.1/bin-lR
   ... DLL made
   installing DLL
   installing R files
   installing man source files
rm: failed to get attributes of `/': No such file or directory
make[2]: ***  
[c:/removethis/R/R2.6.1/bin/roots.Rcheck/roots/man/roots.Rd.gz] Error 1
make[1]: *** [all] Error 2
make: *** [pkg-roots] Error 2
*** Installation of roots failed ***

Removing 'c:/removethis/R/R2.6.1/bin/roots.Rcheck/roots'


I appreciate any suggestion.
Thank you,

Amin Zollanvari
Genomic Signal Processing Lab.
Texas AM University,
College Station, Texas

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[R] Designs with many periods

2007-11-28 Thread Michael Kubovy
Dear R-helpers,

Jones  Kenward (2003)¶ discuss balanced designs with many periods  
(p). It is my impression the algorithmic design packages (AlgDesign,  
crossdes, conf.design) in R do not handle cases in which the number of  
treatments (t) is  p. Am I mistaken?

To be concrete: I am designing an experiment with t = 12 in a  
factorial design (3x4) with p = [12,18] (we have our subjects for an  
hour, which allows us about 18 blocks). We can run in the ballpark of  
30 subjects.

Pointers welcome.

___
¶ @BOOK{JonesKenward2003,
   title = {Design and analysis of cross-over trial},
   publisher = {Chapman \ Hall/CRC},
   year = {2003},
   address = {Boca Raton, FL, USA},
   edition = {2nd},
   author = {Byron Jones and Michael G. Kenward}
}

_
Professor Michael Kubovy
University of Virginia
Department of Psychology
USPS: P.O.Box 400400Charlottesville, VA 22904-4400
Parcels:Room 102Gilmer Hall
 McCormick RoadCharlottesville, VA 22903
Office:B011+1-434-982-4729
Lab:B019+1-434-982-4751
Fax:+1-434-982-4766
WWW:http://www.people.virginia.edu/~mk9y/

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[R] boxplot with datapoint

2007-11-28 Thread Yupu Liang
Hi,

I'm using boxplot in R to show box-whiskers plots for about 15  
categories of data.  I'd like to display ALL of the data points--not  
just the outliers.  Does anyone know if there's a parameter setting  
that will accomplish this with boxplot?  Other options would be to  
overlay the plotted points on top of the boxes?

Thanks a lot!
Yupu

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[R] Power model in R

2007-11-28 Thread Milton Cezar Ribeiro
Dear all,

How can I fit a power model in R.

Thanks in advance,

miltinho



 para armazenamento!

[[alternative HTML version deleted]]

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[R] how to read in a txt file with some blanks

2007-11-28 Thread affy snp
Hi list,
Is there a way to read in a txt file with some blanks? The ideal way could
be to replace blanks with NAs.

Thanks a lot!

Allen

[[alternative HTML version deleted]]

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Re: [R] Power model in R

2007-11-28 Thread Ruben Roa Ureta
 Dear all,

 How can I fit a power model in R.

 Thanks in advance,

 miltinho



  para armazenamento!

   [[alternative HTML version deleted]]

Try the approach below with the lognormal distribution for the data. The
data is real.
Rubén


y-c(2841,1151,1579,1491,1306,2294,1781,1472,2709,1845,1882,2113,3683,2852,794,1965,3417,4478,3523,
2414,2769,5216,3590,4057,2770,3171,3208,6265,4411,2319,3044,1771,3472,4394,3169,4225,4934,3916,4120,
5168,4461,5980,5670,5806,5479,3644,5529,5011,7826,3964,6942,4285,4301,4696,4288,4921,7138,
9881,5025,5181,7110,5413,8279,7803,4652,5114,3127,5798,4048,7459,4741,5798,6738,3562,6235,8015,
5140,5852,4634,5006,5937,5014,9608,2134,7649,7649,6634,5028,5943,4732,7782,7035,8147,6583,5085,
5743,10932,6935,5716,5716,5839,6356,10398,9709,11937,5955,9385,17764,15560,13834,20396,20961)
x-c(8.0,8.5,8.5,9.0,9.0,9.0,10.0,10.8,11.0,11.0,11.2,11.5,11.5,11.5,11.6,12.0,12.0,12.0,12.0,12.5,12.5,12.6,
12.8,12.8,12.9,13.0,13.0,13.5,13.5,13.5,13.7,14.0,14.0,14.0,14.0,14.2,14.5,14.5,14.5,14.8,15.0,15.0,15.5,15.5,
15.5,15.5,15.9,16.0,16.0,16.0,16.0,16.0,16.0,16.5,16.5,16.5,16.5,16.5,16.5,16.5,16.5,16.5,16.5,16.5,16.6,17.0,
17.0,17.0,17.0,17.0,17.0,17.0,17.0,17.5,17.5,17.5,17.5,17.5,17.5,17.5,17.7,18.0,18.0,18.0,18.0,18.0,18.0,18.0,
18.0,18.5,18.5,19.0,19.0,19.0,19.0,19.0,19.5,19.5,19.5,19.5,19.5,19.5,20.0,20.5,21.0,22.0,24.5,26.5,26.5,26.8,
28.0,30.0)

f1=2   #starting value for parameter
f0=20  #starting value for parameter
y.mod-f0*(x)^f1
plot(x,y)
lines(x,y.mod)
fn-function(p){
 y.mod-p[1]*x^p[2];
 squdiff-(log(y)-log(y.mod))^2;
 lik=(length(y)/2)*log(sum(squdiff)/length(y)) #lognormal
 }
y.lik-nlm(fn,p=c(20,2),hessian=TRUE)
y.lik

f0-y.lik$estimate[1]
f1-y.lik$estimate[2]
covmat-solve(y.lik$hessian) #estimated covariance matrix
covmat

sef0-sqrt(covmat[1,1]) #standard error
sef1-sqrt(covmat[2,2]) #standard error
covf0f1-covmat[1,2]
sef0
sef1
y.fit-f0*x^f1
plot(x,y,pch=19,xlab=,ylab=)
lines(x,y.fit,lwd=par(3))
text(x=10,y=2,expression(paste(y=,19.9*x^1.98)))

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Re: [R] how to read in a txt file with some blanks

2007-11-28 Thread jim holtman
If the data is fixed field, then read.fwf.  Else blanks are normally
allowed delimiters.  How do you want to interprete blanks?  There are
number of ways, none of which you have specified.

On Nov 28, 2007 6:46 PM, affy snp [EMAIL PROTECTED] wrote:
 Hi list,
 Is there a way to read in a txt file with some blanks? The ideal way could
 be to replace blanks with NAs.

 Thanks a lot!

 Allen

[[alternative HTML version deleted]]

 __
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 and provide commented, minimal, self-contained, reproducible code.




-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem you are trying to solve?

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Re: [R] Survreg(), Surv() and interval-censored data

2007-11-28 Thread Mohammad Ehsanul Karim
Can anybody give me a neat example of interval censored data analysis codes in 
R?

Given that suvreg(Surv(c(1,1,NA,3),c(2,NA,2,3),type=interval2)~1) 
works why does 
 survreg(Surv(data[,1],data[,2],type=interval2)~1)
not work where 
data is :
 T.1  T.2 Status
1  0.000   0.62873036  1
2  0.000   2.07039068  1
3  0.000   1.40297214  1
4  0.000   0.09112871  1
5  0.000   0.75115280  1
6  0.000   2.36476839  1
7  0.000   2.47483937  1
8  0.000   1.16913097  1
9  0.000   0.21498251  1
10 0.000   1.89557501  1
11 0.9286723   1.09883334  1
12 0.3428920   1.16436088  1
13 0.5924055   2.20572832  1
14 0.7985962   1.73894982  1
15 1.7493239 999.  0
16 0.8653470 999.  0
17 0.6917203 999.  0
18 1.1452119 999.  0
19 2.2587688 999.  0
20 0.7854710 999.  0
21 1.5986105 999.  0
22 2.2189803 999.  0
23 0.7905505 999.  0
24 1.3111472 999.  0
25 2.3394220 999.  0
26 1.3667469 999.  0
27 0.3094596 999.  0
28 1.6855216 999.  0
29 1.7934033 999.  0


Thanks in advance.

Ehsan



Re: [R] Survreg(), Surv() and interval-censored data
This message: [ Message body ] [ More options ] 
Related messages: [ Next message ] [ Previous message ] [ In reply to ] [ Re: 
[R] Survreg(), Surv() and interval-censored data ] 
From: Thomas Lumley tlumley_at_u.washington.edu 
Date: Thu 16 Feb 2006 - 07:58:26 EST

On Mon, 13 Feb 2006, Stephen Richards wrote: 
 Can survreg() handle interval-censored data like the documentation 
 says? I ask because the command: 
 
 survreg(Surv(start, stop, event) ~ 1, data = heart) 
 
 fails with the error message 
 
 Invalid survival type 
 
 yet the documentation for Surv() states: 
 
 Presently, the only methods allowing interval censored data are 
 the parametric models computed by 'survreg' 
 
 Any pointers as to what I'm missing? 
 

You are specifying left-truncated, right-censored data, not interval-censored. 
You need the type= argument, eg 
 Surv(c(1,1,NA,3),c(2,NA,2,3),type=interval2) 
[1] [1, 2] 1+ 2- 3 
specifies interval censoring at [1,2], right-censoring at 1, left-censoring at 
2, and an observed event at 3. 
 -thomas

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[R] convert an S plus file to R?

2007-11-28 Thread filame uyaco

hi!

i send again my question because there was a problem earlier that 
someone did not see my attached file.   If you really can't download it,
this is the attached file.


Please help me how to convert this S plus file to R.  
Is there a quick method to do it?  I don't have an S plus
installer here.


---

# Computes a possible choice for the optimal k value
# of the Hill estimator by minimizing estimates of 
# the asumptotic mean squared error (Section 4.7ii)
#
# Estimates can be based on the estimates of the second
# order parameters gamma, b and beta obtained with the
# function Hill.2oQV
#
# If addtoHill=TRUE then the optimal k value is added to
# the plot of the Hill estimates (given the plot is available)
#
# If plot=TRUE then the estimates of the AMSE are plotted
# as a function of k and the optimal k value is added to it


Hill.AMSE.kopt - function(Hill.2oQV, addtoHill=FALSE, plot=FALSE, ...) {
 
 K - Hill.2oQV$k
 gamma - Hill.2oQV$gamma
 b - Hill.2oQV$b
 beta - Hill.2oQV$beta
 
 AMSE.Hill - (gamma^2)/K + (b/(1+beta))^2
 AMSE.Hill.min - min(AMSE.Hill, na.rm = T)
 kopt - K[AMSE.Hill==AMSE.Hill.min]
 
### plots if TRUE

if ( addtoHill ) {  ### add optimal k value to Hill-plot
 abline(v=kopt,lty=3,col=4)
}

if ( plot ){   ### plot estimates of AMSE as function of k
 plot(K, AMSE.Hill, type=l, ylab=AMSE gamma, xlab=k, main=AMSE estimates 
of extreme value index, ...)
 abline(v=kopt,lty=3,col=4)
}

### output list with values of k, corresponding
### estimates of AMSE Hill and optimal k value kopt

list(K=K, AMSE.Hill=AMSE.Hill, kopt=kopt)

}


Thanks for the help.


Filame

   
-
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[R] help!!!

2007-11-28 Thread guowei
Hi,

I want to ask a question about expression for object.
In the example parts, I saw
 trig.exp - expression(sin(cos(x + y^2)))
 D(trig.exp, c(x, y))

Now, I want to define a complex function in expression, for example,
f1(x)=...
 f2(y)=..
 final f=f2(f1(x)+4)

may I define such expression with many statements?
thanks.

regards,
wei


-- 
Wei Guo
Department of Statistics
The Ohio State University
Columbus, Ohio 43210
Tel: 001-614-292-4713(o)
e-mail: [EMAIL PROTECTED]

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Re: [R] boxplot with datapoint

2007-11-28 Thread Charilaos Skiadas
On Nov 28, 2007, at 5:59 PM, Yupu Liang wrote:

 Hi,

 I'm using boxplot in R to show box-whiskers plots for about 15
 categories of data.  I'd like to display ALL of the data points--not
 just the outliers.  Does anyone know if there's a parameter setting
 that will accomplish this with boxplot?  Other options would be to
 overlay the plotted points on top of the boxes?

I think you will want to overlay the points. E.g.:

x-rnorm(30)
y-factor(rep(4:6,10), labels=LETTERS[1:3])
boxplot(x~y)
points(y,x)


 Thanks a lot!
 Yupu

Haris Skiadas
Department of Mathematics and Computer Science
Hanover College

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Re: [R] convert an S plus file to R?

2007-11-28 Thread Steven McKinney


Hi,

The function you show below performs
relatively simple S language stuff, and
looks as if it will run as is in R.

Looks like you'll need an output object
Hill.2oQV (I'm guessing from a function
of the same name).  That Hill.2oQV() function
may need some work, but the Hill.AMSE.kopt()
function below should work as is.

Best

Steve McKinney




-Original Message-
From: [EMAIL PROTECTED] on behalf of filame uyaco
Sent: Wed 11/28/2007 6:51 PM
To: [EMAIL PROTECTED]
Subject: [R] convert an S plus file to R?
 

hi!

i send again my question because there was a problem earlier that 
someone did not see my attached file.   If you really can't download it,
this is the attached file.


Please help me how to convert this S plus file to R.  
Is there a quick method to do it?  I don't have an S plus
installer here.


---

# Computes a possible choice for the optimal k value
# of the Hill estimator by minimizing estimates of 
# the asumptotic mean squared error (Section 4.7ii)
#
# Estimates can be based on the estimates of the second
# order parameters gamma, b and beta obtained with the
# function Hill.2oQV
#
# If addtoHill=TRUE then the optimal k value is added to
# the plot of the Hill estimates (given the plot is available)
#
# If plot=TRUE then the estimates of the AMSE are plotted
# as a function of k and the optimal k value is added to it


Hill.AMSE.kopt - function(Hill.2oQV, addtoHill=FALSE, plot=FALSE, ...) {

 K - Hill.2oQV$k
 gamma - Hill.2oQV$gamma
 b - Hill.2oQV$b
 beta - Hill.2oQV$beta

 AMSE.Hill - (gamma^2)/K + (b/(1+beta))^2
 AMSE.Hill.min - min(AMSE.Hill, na.rm = T)
 kopt - K[AMSE.Hill==AMSE.Hill.min]

### plots if TRUE

if ( addtoHill ) {  ### add optimal k value to Hill-plot
 abline(v=kopt,lty=3,col=4)
}

if ( plot ){   ### plot estimates of AMSE as function of k
 plot(K, AMSE.Hill, type=l, ylab=AMSE gamma, xlab=k, main=AMSE estimates 
of extreme value index, ...)
 abline(v=kopt,lty=3,col=4)
}

### output list with values of k, corresponding
### estimates of AMSE Hill and optimal k value kopt

list(K=K, AMSE.Hill=AMSE.Hill, kopt=kopt)

}


Thanks for the help.


Filame

   

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Re: [R] how to read in a txt file with some blanks

2007-11-28 Thread jim holtman
The question is what do the 'blanks' mean?  I assume that they are
separating the variables since that is the default for read.table.

So what is the difference between:

1) 1 2   one blank
2) 1  2  two blanks
3) 1   2 three blanks
4)

How are these different conditions supposed to be interpreted?  Now
you replace the blanks with commas and that might do it for you. This
would mean that 1  2 (which would be two variables where there are 2
blanks) would now be 1,,2  which would be three variables.  So you
need to define what is supposed to happen in these cases.

On Nov 28, 2007 8:21 PM, affy snp [EMAIL PROTECTED] wrote:
 Hi Jim,

 Thanks a lot! I would like the blanks to be read as NAs.
 I tried

 cgh-read.table(file= WM115A.txt,header = TRUE,fill = TRUE,na.strings =
 NA)

 but the blanks were just filled by their flanking columns.

 Best,
  Allen




 On Nov 28, 2007 7:42 PM, jim holtman [EMAIL PROTECTED] wrote:
  If the data is fixed field, then read.fwf.  Else blanks are normally
  allowed delimiters.  How do you want to interprete blanks?  There are
  number of ways, none of which you have specified.
 
 
 
 
  On Nov 28, 2007 6:46 PM, affy snp  [EMAIL PROTECTED] wrote:
   Hi list,
   Is there a way to read in a txt file with some blanks? The ideal way
 could
   be to replace blanks with NAs.
  
   Thanks a lot!
  
   Allen
  
 
 
 
  [[alternative HTML version deleted]]
  
   __
   R-help@r-project.org mailing list
   https://stat.ethz.ch/mailman/listinfo/r-help
   PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
   and provide commented, minimal, self-contained, reproducible code.
  
 
 
 
  --
  Jim Holtman
  Cincinnati, OH
  +1 513 646 9390
 
  What is the problem you are trying to solve?
 





-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem you are trying to solve?

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Re: [R] how to read in a txt file with some blanks

2007-11-28 Thread affy snp
Hi Jim,
Thanks a lot! I would like the blanks to be read as NAs.
I tried

cgh-read.table(file=WM115A.txt,header = TRUE,fill = TRUE,na.strings =
NA)

but the blanks were just filled by their flanking columns.

Best,
 Allen



On Nov 28, 2007 7:42 PM, jim holtman [EMAIL PROTECTED] wrote:

 If the data is fixed field, then read.fwf.  Else blanks are normally
 allowed delimiters.  How do you want to interprete blanks?  There are
 number of ways, none of which you have specified.

 On Nov 28, 2007 6:46 PM, affy snp [EMAIL PROTECTED] wrote:
  Hi list,
  Is there a way to read in a txt file with some blanks? The ideal way
 could
  be to replace blanks with NAs.
 
  Thanks a lot!
 
  Allen
 
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 --
 Jim Holtman
 Cincinnati, OH
 +1 513 646 9390

 What is the problem you are trying to solve?


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Re: [R] how to find and use specific column after spliting dataframe

2007-11-28 Thread Hsin-Ya Lee

Dear Dallazuanna:

  Thanks for your reply.  It really has solved my problems.  
However, I have another question.  How can I do, if I need to calculate such
equation in all sub-dataframe?  I try to use A.split[] to catch all
sub-dataframe, but it seems can not catch the columns of all sub-dataframe. 
In other words, if the dataframe can split into 2 sub-dataframe, I need
calculate the equation in these 2 sub-dataframe.

x-rep(c(1.2,6.8),4)
y-rep(c(1, 2),4)
z-rep(c(1,2),4)
t-rep(c(0,1,2,3),length.out=8)
c-rep(c(0,0.5,1,2),length.out=8)
df-data.frame(pH=x, formulation=y, subject=z, time=t, concentration=c)
A.split-split(df, list(df$pH ,df$formulation, df$subject) )
A.split []

Best regards, 
Hsin-Ya Lee



Henrique Dallazuanna wrote:
 
 Try this:
 
 A.split[[1]][time]
 A.split[[1]][[concentration]]
 
 test - NULL
 for(i in 2:4){
 test[i] - (A.split[[1]][[time]][i] - A.split[[1]][[time]][i-1]) *
(A.split[[1]][[concentration]][i] -
 A.split[[1]][[concentration]][i-1])
 * 0.5
 }
 
 
 On 28/11/2007, leeznar [EMAIL PROTECTED] wrote:



 Dear all:


 I am a new R-user and I have 2 questions
 about it.


 1) I need to find specific sub-dataframe,
 and then use specific column to calculate.
 For example, after splitting dataframe, I find specific the
 sub-dataframe, such as A.split [1].
 But, I don't know how to find time and concentration columns of
 A.split
 [1].
 
 2) The equation used to sub-dataframe is
 (time[i]-time[i-1])*(concentration[i]- concentration[i-1])*1/2.  I don't
 know how to calculate it.  How can I find the specific column and use it
 to
 calculate ?
 x-rep(c(1.2,6.8),4)
 y-rep(c(1, 2),4)
 z-rep(c(1,2),4)
 t-rep(c(0,1,2,3),length.out=8)
 c-rep(c(0,0.5,1,2),length.out=8)
 df-data.frame(pH=x, formulation=y,
 subject=z, time=t, concentration=c)
 A.split-split(df, list(df$pH
 ,df$formulation, df$subject) )
 A.split [1]
 
 Best regards,
 
 Hsin-Ya Lee
 
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 -- 
 Henrique Dallazuanna
 Curitiba-Paran¨¢-Brasil
 25¡ã 25' 40 S 49¡ã 16' 22 O
 
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