[R] [R-pkgs] RSiteSearch package?

2009-05-05 Thread spencerg
	  A new RSiteSearch package is now available on CRAN.  This makes it 
much easier to find things among contributed packages (including all 
CRAN packages).  The capabilities are further

described in system.file('doc', 'RSiteSearch.pdf',
package='RSiteSearch').


  Spencer Graves
  Sundar Dorai-Raj
  Romain Francois

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Re: [R] Randomized-complete blocks design and R

2009-05-05 Thread Dieter Menne
alis villiyam aalisiyan at gmail.com writes:

 I am new in R.I am trying to analysis of variance for Randomized-complete
 blocks design. I have 4 treatments and 3 replication,
 
 Without intraction.then .I is going to use LSD test or Duncan test for
 comparison between average values of treatments.
 
 I want to know, is there any significant change between treatment and
 between weeks? Because I did experiment for 8 weeks.
 
Try lme in package nlme, but you need the documentation in the book
by Pinheiro/Bates to get started, otherwise there is little chance.

Something like (assuming repl is numeric, or a time)
 
  summary(lme(effect~treat*repl, data=mydata, random=~1|subject))

Possible followed by a multiple comparison test of the contrasts 
from package multcomp. 

If you only do it once, you might get results faster by using SPSS or
Systat (I avoid mentioning the three-letter alternative here)

Dieter

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Re: [R] levelplot question

2009-05-05 Thread Antje

Hi Greg and all the others,

thanks for your answer. The color-vector has the same length like the at-vector 
but the recycling cannot be the reason, because only values slightly above my 
threshold doe not appear blue.
I cannot find a good explanation of which colors are assigned to which value 
ranges.


I've made little example:

#
mat - matrix(seq(1,5, length.out = 12), nrow = 3)
mat[1,2] - 3.5

my.at - seq(0.5,5.5)
my.col.regions - rainbow(6)

graph - levelplot(t(mat[nrow(mat):1, ] ), at = my.at, col.regions = 
my.col.regions)

print(graph)

windows()
plot(1:10)
legend(topleft, legend = as.character(my.col.regions), col = my.col.regions, 
pch = 18)

#

As you can see the green (position 3 in my.col.regions) disappears completely 
in the levelplot (look at the color range at the right side!).

I guess it might also happen in my case...

I've tested several cases and it looks like the length of the color-vector 
should be one less than the at vector (which would make sense).


Then, the rule might apply:

[ at[1],at[2] ] = color[1]
( at[2],at[3] ] = color[2]
...
( at[n-1],at[n] ] = color[n-1]


Please correct me if I'm wrong!!!

Antje

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Re: [R] Hierarchical Diagram of Networks in sna or otherwise?

2009-05-05 Thread Gábor Csárdi
On Mon, May 4, 2009 at 8:31 PM, jebyrnes byr...@msi.ucsb.edu wrote:

 Nearly.  The algorithm turns up slightly different graphs each time (and
 set.seed doesn't seem to make it consistent)

Hmmm, that should not happen, I'll check it out.

 and periodically chokes.

Can you send me the graph for which this happens?

 But
 better than what I had.  Hrm.  I don't know much about the algorithm
 graphviz uses for dot.  Do you have a reference on hand?

No, I don't. Have you checked the graphviz homepage?

 If it's simple,
 I'd be willing to take a whack at it.

I doubt that it is simple, but I think it would be very useful to have
a free implementation. (I would have already ported the graphviz
layout algorithms to igraph, but their licenses are not compatible.)

Best,
Gabor


 Gábor Csárdi-2 wrote:

 Jarrett,

 the 'igraph' package has a layout called layout.reingold.tilford that
 is designed for trees, there is a slight chance that it is good enough
 for you.

 Best,
 Gabor

 On Wed, Apr 29, 2009 at 10:11 PM, jebyrnes byr...@msi.ucsb.edu wrote:

 I've been using sna to work with some networks, and am trying to
 visualize
 them easily.  My networks are hierarchical (food webs).  All of the
 layout
 engines I've tried with gplot don't seem to plot hierarchical networks,
 as
 one would using dot from graphviz.  While I could do all of this by
 outputting to dotfiles and running it through graphviz, the graphics I
 get
 from R are much cleaner, and more easily integrated into my analyses.

 Is there any good way to diagram a hierarchical network in R, either with
 the sna library or otherwise?  It strikes me that at least the Netindices
 package can calculate trophic levels.  Could this be used for node
 placement?


 -Jarrett
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 Gabor Csardi gabor.csa...@unil.ch     UNIL DGM

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-- 
Gabor Csardi gabor.csa...@unil.ch UNIL DGM

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[R] Heatmap without levelplot

2009-05-05 Thread Antje

Hi there,

as I'm not sure to understand the coloring levelplot uses, I'm looking for 
another easy way to create a heatmap like this:


library(lattice)
mat - matrix(seq(1,5, length.out = 12), nrow = 3)
mat[1,2] - 3.5

my.at - seq(0.5,5.5, length.out = 6)
my.col.regions - rainbow(5)

graph - levelplot(t(mat[nrow(mat):1, ] ), at = my.at, col.regions = 
my.col.regions)

print(graph)

Can anybody help me with some hints or little examples?

Antje

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[R] prob in predict(randomForest)

2009-05-05 Thread LWF
Hi at all,

maybe this question is quite simple for a statistician, but for me it is not. 
After reading a lot of mail in the R-help archive I`m still not quite sure I 
get it. 
When applying a randomForest to a new dataset with predict(randomForest) I have 
the option to get the output as probability (classification problem):
predict(myrf,...,type=prob)
I would like to know how I have to understand this output. Are this values the 
probability of an observation belonging to a predicted class? Say, I have a 
data-point as newdata, my rf-model predicts Class A and the probability is 
0,12301. Does this mean that this data-point belongs to class A only with a 
probability of 12%?

Thanks for every hint.

TIM

Just as a matter of form: I´m using R version 2.8.1, randomForest package 
4.5-28, OS: WinXP

---
 
Tim Häring
Bavarian State Institute of Forest Research 
Department of Forest Ecology
Am Hochanger 11
D-85354 Freising

E-Mail: tim.haer...@lwf.bayern.de
http://www.lwf.bayern.de

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[R] Time series ARIMAX and multivariate models

2009-05-05 Thread Ramanath Roy
Dear Lillian,

 I would request you if  you provide me the knowledge of how build ARIMAX model 
in R? It would be great help for me.

Thanks

Ramanath
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[R] smoothing spline in package gam

2009-05-05 Thread 楊 詩韻

dear all,

 

i have a little question, but it make me torment long time

 

hope you can help me and give some advices , thanks

 

 

i use smoothing spline in package gam

 

the model

 

 m1=gam(y~ost+wst+park10+sch50+comm+build+suite+y05+y06+y07+y99+y98+s(builarea)+s(age)+s(fl)+s(totfl)+s(cbd)+s(redl))


and summary(m1) can show the s(smoothing) variables' Signif. codes.

 

but i also want to know the Parametric coefficients and their Signif. codes. 
like ost, wst...etc.

 

is that possible to get the Parametric coefficients'  Signif. codes  (in 
package gam) ?

 

 

thanks~~

 

 

 

 

 

 

_


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Re: [R] About the Transfer Function Model(ARIMAX)

2009-05-05 Thread Ramanath Roy

Dear David,

Thanks for your reply. I would request you to please provide me an example 
where The ARIMAX model have been developed with two exogeneous variables.


I would be highly obliged if you kindly help me by providing me the same.

Regards

Ramanath


- Original Message - 
From: David Winsemius dwinsem...@comcast.net

To: Ramanath Roy r@decisioncraft.com
Cc: r-help@r-project.org
Sent: Monday, May 04, 2009 7:35 PM
Subject: Re: [R] About the Transfer Function Model(ARIMAX)



pages 43-54 of:

http://cran.r-project.org/doc/Rnews/Rnews_2006-4.pdf

... is an article by Uwe Ligges on accesssing source code.

On Apr 2, 2009, at 4:20 AM, Ramanath Roy wrote:


Dear ALL,

I would appreciate if someone help me by letting me know the code of 
above model in R.I would request you to please let me know how i could

make arimax model in auto.arima.




David Winsemius, MD
Heritage Laboratories
West Hartford, CT



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Re: [R] Support Vector Machines

2009-05-05 Thread excalibur

In the R-help of the svm function of the package e1071 it's explained that
this function also makes estimation of density.

But when i made for example
X-rnorm(1000)
m-svm(X)

I just have a binary classification of X like SVM do whereas i want an
estimation of the density which generates our sample X ...

I don't know if it's possible and if someone has already use this function
to do that.

Thanks.


David Winsemius wrote:
 
 
 On May 4, 2009, at 8:52 AM, excalibur wrote:
 

 This question is still unanswered.
 
 Unanswered questions are often those which do not comply with the  
 guidelines in the Posting Guide. Many people have gotten tired of  
 either making up examples or of writing  Read the Posting Guide, so  
 they just ignore them.
 
 
 Someone can explain me how use the svm function to make density  
 estimation ?
 
 If you post an executable bit of code that shows how you are doing  
 those operations, then I suspect someone will answer.
 
 excalibur wrote:


 Hi,
 i try to use function svm of package e1071 to estimate a density.

 But if my data are X=(X1,...,Xn) and m-svm(X) some values of m$SV  
 are
 less than 0.
 I don't see how i can get the estimation of the density with this
 function.

 Thanks for your help.

 Rémi

 
 David Winsemius, MD
 Heritage Laboratories
 West Hartford, CT
 
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[R] Can't build termstrc package from source

2009-05-05 Thread Chirantan Kundu
Hi,

I'm trying to build the termstrc 1.1 package from its source on R 2.7.2 on
Windows XP. However instead of building the package it just zips the entire
source into a .tar.gz file.
This is the first time I'm trying to build an R package from source. I
installed the R toolset for Windows and set RTools as well as Perl  MinGW
directories in the path.
Anybody tried this out? Any file missing in the source?

Any help is appreciated.

Thanks,
Chirantan


Visit us at http://www.2pirad.com

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Re: [R] Reversing axis label order

2009-05-05 Thread Jim Lemon

Steve Murray wrote:

Dear R Users,

I am executing the following command to produce a line graph:

matplot(aggregate_1986[,1], aggregate_1986[,2:3], type=l, col=2:3)

On the x-axis I have values of Latitude (in column 1) ranging from -60 to +80 
(left to right on the x-axis). However, I wish to have these values shown in 
reverse on the x-axis, going from +80 to -60 (ie. North to South in terms of 
Latitude). I have tried doing this by altering the command as follows:

matplot(-aggregate_1986[,1], aggregate_1986[,2:3], type=l, col=2:3)

...but this produces the inverse sign of the latitude values along the axis - 
ie. it goes from -80 to +60.

How do I reverse the display of the axis labels correctly and of course, 
maintain the associated data values correctly?

  

Hi Steve,
Have a look at rev.axis in the plotrix package.

Jim

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[R] noisy quantisation

2009-05-05 Thread William Simpson
The following creates a point process version of a sinewave (maybe
there's a better way):

p-amp*cos(2*pi*freq*(1:n)/n ) + 0.5
as.numeric(runif(1:n)p)

I get something like this:

1ooo ooo  oo o


0   ooo o  o o o o  ooo ooo

In case it's not obvious, this is a noisy version of
1  oooooo


0  oooooo


I was wondering if anyone can suggest a way to create a version where
I get 0s, 1s, and 2s something like a noisy version of this:

2  oo


1o  o o


0  ooo

I am looking for a version of the top graph except with 3 levels instead of 2.

Thanks very much for any help

Bill

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[R] limits

2009-05-05 Thread Hassan Mohamed
Hey,
what is the R function for the mathematical limit ?
e.g. to calculate  and return the amount that the expression
X^2 +X +2 
approach
as X approach 2
(X- 2)
thanks
hassan


  
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[R] stepAICc function (based on MASS:::stepAIC.default)

2009-05-05 Thread Christoph Scherber
Dear all,

I have tried to modify the code of MASS:::stepAIC.default(), dropterm() and 
addterm() to use AICc instead of AIC for model selection.

The code is appended below. Somehow the calculations are still not correct and 
I would be grateful if anyone could have a look at what might be wrong
with this code...

Here is a working example:

##
require(nlme)
model1=lme(distance ~ age + Sex, data = Orthodont, random =~1)
stepAICc.Christoph(model1)

##

this gives the correct initial AICc value, but wrong values inside the stepAICc 
(and probably dropterm.AICc) function. All three functions are
appended below.

Many thanks and best wishes,
Christoph


##

stepAICc.Christoph=function (object, scope, scale = 0, direction = c(both, 
backward,
forward), trace = 1, keep = NULL, steps = 1000, use.start = FALSE,
k = 2, ...)
{
mydeviance - function(x, ...) {
dev - deviance(x)
if (!is.null(dev))
dev
else extractAIC(x, k = 0)[2L]
}
cut.string - function(string) {
if (length(string)  1L)
string[-1L] - paste(\n, string[-1L], sep = )
string
}
re.arrange - function(keep) {
namr - names(k1 - keep[[1L]])
namc - names(keep)
nc - length(keep)
nr - length(k1)
array(unlist(keep, recursive = FALSE), c(nr, nc), list(namr,
namc))
}
step.results - function(models, fit, object, usingCp = FALSE) {
change - sapply(models, [[, change)
rd - sapply(models, [[, deviance)
dd - c(NA, abs(diff(rd)))
rdf - sapply(models, [[, df.resid)
ddf - c(NA, abs(diff(rdf)))
AICc - sapply(models, [[, AICc)
heading - c(Stepwise Model Path \nAnalysis of Deviance Table,
\nInitial Model:, deparse(as.vector(formula(object))),
\nFinal Model:, deparse(as.vector(formula(fit))),
\n)
aod - if (usingCp)
data.frame(Step = change, Df = ddf, Deviance = dd,
`Resid. Df` = rdf, `Resid. Dev` = rd, Cp = AICc,
check.names = FALSE)
else data.frame(Step = change, Df = ddf, Deviance = dd,
`Resid. Df` = rdf, `Resid. Dev` = rd, AICc = AICc,
check.names = FALSE)
attr(aod, heading) - heading
class(aod) - c(Anova, data.frame)
fit$anova - aod
fit
}
Terms - terms(object)
object$formula - Terms
if (inherits(object, lme))
object$call$fixed - Terms
else if (inherits(object, gls))
object$call$model - Terms
else object$call$formula - Terms
if (use.start)
warning('use.start' cannot be used with R's version of glm)
md - missing(direction)
direction - match.arg(direction)
backward - direction == both | direction == backward
forward - direction == both | direction == forward
if (missing(scope)) {
fdrop - numeric(0)
fadd - attr(Terms, factors)
if (md)
forward - FALSE
}
else {
if (is.list(scope)) {
fdrop - if (!is.null(fdrop - scope$lower))
attr(terms(update.formula(object, fdrop)), factors)
else numeric(0)
fadd - if (!is.null(fadd - scope$upper))
attr(terms(update.formula(object, fadd)), factors)
}
else {
fadd - if (!is.null(fadd - scope))
attr(terms(update.formula(object, scope)), factors)
fdrop - numeric(0)
}
}
models - vector(list, steps)
if (!is.null(keep))
keep.list - vector(list, steps)
if (is.list(object)  (nmm - match(nobs, names(object),
0))  0)
n - object[[nmm]]
else n - length(residuals(object))
fit - object
bAIC- extractAIC(fit, scale, k = k, ...)
edf - bAIC[1L] #extracts the number of parameters, k=edf

bAIC - bAIC[2L]+((2*edf*(edf+1))/(n-edf-1))

if (is.na(bAIC))
stop(AICc is not defined for this model, so stepAIC cannot proceed)
nm - 1
Terms - terms(fit)
if (trace) {
cat(Start:  AICc=, format(round(bAIC, 2)), \n, 
cut.string(deparse(as.vector(formula(fit,
\n\n, sep = )
utils::flush.console()
}
models[[nm]] - list(deviance = mydeviance(fit), df.resid = n -
edf, change = , AICc = bAIC)
if (!is.null(keep))
keep.list[[nm]] - keep(fit, bAIC)
usingCp - FALSE
while (steps  0) {
steps - steps - 1
AICc - bAIC
ffac - attr(Terms, factors)
if (!is.null(sp - attr(Terms, specials))  !is.null(st - 
sp$strata))
ffac - ffac[-st, ]
scope - factor.scope(ffac, list(add = fadd, drop = fdrop))
aod - NULL
change - NULL
if (backward  length(scope$drop)) {

aod - dropterm.AICc(fit, scope$drop, scale = scale, trace = max(0,
trace - 1), k = k, ...)

rn - row.names(aod)
row.names(aod) - c(rn[1L], paste(-, rn[-1L], sep =  ))
   

[R] JGR

2009-05-05 Thread r...@quantide.com

Dear R User
I am using JGR on a Linux Ubuntu Computer with 2 Cpus
When Opening JGR, one Cpu goes up to 100% even if no calculation is yet 
started

Did any of you already noticed this strange behaviour?
Thanks for your help
Andrea

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[R] problem with rgl package

2009-05-05 Thread Erin Hodgess
Dear R People:

Here is something strange.  I'm using Ubuntu 9.04 with R 2.9.0.

I need to have the rgl package.  Here are my results from installing:

 install.packages(rgl)
Warning in install.packages(rgl) :
  argument 'lib' is missing: using '/usr/local/lib/R/site-library'
--- Please select a CRAN mirror for use in this session ---
Loading Tcl/Tk interface ... done
trying URL 'http://cran.cnr.Berkeley.edu/src/contrib/rgl_0.84.tar.gz'
Content type 'application/x-gzip' length 1670659 bytes (1.6 Mb)
opened URL
==
downloaded 1.6 Mb

* Installing *source* package 'rgl' ...
checking for gcc... gcc -std=gnu99
checking for C compiler default output file name... a.out
checking whether the C compiler works... yes
checking whether we are cross compiling... no
checking for suffix of executables...
checking for suffix of object files... o
checking whether we are using the GNU C compiler... yes
checking whether gcc -std=gnu99 accepts -g... yes
checking for gcc -std=gnu99 option to accept ISO C89... none needed
checking how to run the C preprocessor... gcc -std=gnu99 -E
checking for gcc... (cached) gcc -std=gnu99
checking whether we are using the GNU C compiler... (cached) yes
checking whether gcc -std=gnu99 accepts -g... (cached) yes
checking for gcc -std=gnu99 option to accept ISO C89... (cached) none needed
checking for libpng-config... yes
configure: using libpng-config
configure: using libpng dynamic linkage
checking for X... no
configure: error: X11 not found but required, configure aborted.
ERROR: configuration failed for package 'rgl'
** Removing '/usr/local/lib/R/site-library/rgl'

The downloaded packages are in
/tmp/RtmpiJh20a/downloaded_packages
Warning message:
In install.packages(rgl) :
  installation of package 'rgl' had non-zero exit status

So presumably there is not an X11.  But when I put in capabilities,
it seems to be there.

 capabilities()
jpeg  png tifftcltk  X11 aqua http/ftp  sockets
TRUE TRUE TRUE TRUE TRUEFALSE TRUE TRUE
  libxml fifo   clediticonv  NLS  profmemcairo
TRUE TRUE TRUE TRUE TRUE TRUE TRUE


Has anyone run into this, please?  What are the solutions, please?

thanks,
Erin

-- 
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodg...@gmail.com

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Re: [R] problem with rgl package

2009-05-05 Thread Duncan Murdoch

On 05/05/2009 5:55 AM, Erin Hodgess wrote:

Dear R People:

Here is something strange.  I'm using Ubuntu 9.04 with R 2.9.0.

I need to have the rgl package.  Here are my results from installing:


install.packages(rgl)

Warning in install.packages(rgl) :
  argument 'lib' is missing: using '/usr/local/lib/R/site-library'
--- Please select a CRAN mirror for use in this session ---
Loading Tcl/Tk interface ... done
trying URL 'http://cran.cnr.Berkeley.edu/src/contrib/rgl_0.84.tar.gz'
Content type 'application/x-gzip' length 1670659 bytes (1.6 Mb)
opened URL
==
downloaded 1.6 Mb

* Installing *source* package 'rgl' ...
checking for gcc... gcc -std=gnu99
checking for C compiler default output file name... a.out
checking whether the C compiler works... yes
checking whether we are cross compiling... no
checking for suffix of executables...
checking for suffix of object files... o
checking whether we are using the GNU C compiler... yes
checking whether gcc -std=gnu99 accepts -g... yes
checking for gcc -std=gnu99 option to accept ISO C89... none needed
checking how to run the C preprocessor... gcc -std=gnu99 -E
checking for gcc... (cached) gcc -std=gnu99
checking whether we are using the GNU C compiler... (cached) yes
checking whether gcc -std=gnu99 accepts -g... (cached) yes
checking for gcc -std=gnu99 option to accept ISO C89... (cached) none needed
checking for libpng-config... yes
configure: using libpng-config
configure: using libpng dynamic linkage
checking for X... no
configure: error: X11 not found but required, configure aborted.
ERROR: configuration failed for package 'rgl'
** Removing '/usr/local/lib/R/site-library/rgl'

The downloaded packages are in
/tmp/RtmpiJh20a/downloaded_packages
Warning message:
In install.packages(rgl) :
  installation of package 'rgl' had non-zero exit status

So presumably there is not an X11.  But when I put in capabilities,
it seems to be there.


capabilities()

jpeg  png tifftcltk  X11 aqua http/ftp  sockets
TRUE TRUE TRUE TRUE TRUEFALSE TRUE TRUE
  libxml fifo   clediticonv  NLS  profmemcairo
TRUE TRUE TRUE TRUE TRUE TRUE TRUE

Has anyone run into this, please?  What are the solutions, please?


Sounds as though you don't have the development libraries for X11, or 
perhaps the rgl configure script isn't finding them.  Do you have 
libx11-dev installed?


Duncan Murdoch

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Re: [R] Can't build termstrc package from source

2009-05-05 Thread Peter Dalgaard
Chirantan Kundu wrote:
 Hi,
 
 I'm trying to build the termstrc 1.1 package from its source on R 2.7.2 on
 Windows XP. However instead of building the package it just zips the entire
 source into a .tar.gz file.
 This is the first time I'm trying to build an R package from source. I
 installed the R toolset for Windows and set RTools as well as Perl  MinGW
 directories in the path.
 Anybody tried this out? Any file missing in the source?
 
 Any help is appreciated.

It's hard to tell what you did wrong when you don't tell what you did.

I suspect you need to study the difference between

R CMD build
R CMD INSTALL
R CMD check
R CMD build --binary

-- 
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
 (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
~~ - (p.dalga...@biostat.ku.dk)  FAX: (+45) 35327907

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Re: [R] problem with rgl package

2009-05-05 Thread Barry Rowlingson
On Tue, May 5, 2009 at 10:55 AM, Erin Hodgess erinm.hodg...@gmail.com wrote:
 Dear R People:

 Here is something strange.  I'm using Ubuntu 9.04 with R 2.9.0.

 I need to have the rgl package.  Here are my results from installing:

 install.packages(rgl)
 Warning in install.packages(rgl) :
[]
 checking for X... no
 configure: error: X11 not found but required, configure aborted.
 ERROR: configuration failed for package 'rgl'
 ** Removing '/usr/local/lib/R/site-library/rgl'

 So presumably there is not an X11.  But when I put in capabilities,
 it seems to be there.

 R will have X11 capabilities if you have the X11 _binary_ library
installed. To compile a package from source that needs to link with
the X11 library you need the development headers. They come in another
package.

 From the command line, do:

 sudo apt-get install libx11-dev

and that should pull them from the Ubuntu repository. You'll need the
root password for this.

 It's possible you may need some other development headers once you
get past the X11 problem!

Barry

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Re: [R] Support Vector Machines

2009-05-05 Thread David Winsemius


On May 5, 2009, at 3:49 AM, excalibur wrote:



In the R-help of the svm function of the package e1071 it's  
explained that

this function also makes estimation of density.

But when i made for example
X-rnorm(1000)
m-svm(X)

I just have a binary classification of X like SVM do whereas i want an
estimation of the density which generates our sample X ...

I don't know if it's possible and if someone has already use this  
function

to do that.


Use str() to look at the object returned by svm. The example in svm's  
help page uses the svm object's index variable although there are  
other components that are available for extraction. The fitted  
vector looks to have similar binary properties to index and the SV  
vector appears to be a distance measure.


--
David




Thanks.


David Winsemius wrote:



On May 4, 2009, at 8:52 AM, excalibur wrote:



This question is still unanswered.


Unanswered questions are often those which do not comply with the
guidelines in the Posting Guide. Many people have gotten tired of
either making up examples or of writing  Read the Posting Guide, so
they just ignore them.



Someone can explain me how use the svm function to make density
estimation ?


If you post an executable bit of code that shows how you are doing
those operations, then I suspect someone will answer.

excalibur wrote:




Hi,
i try to use function svm of package e1071 to estimate a density.

But if my data are X=(X1,...,Xn) and m-svm(X) some values of m$SV
are
less than 0.
I don't see how i can get the estimation of the density with this
function.

Thanks for your help.

Rémi



David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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David Winsemius, MD
Heritage Laboratories
West Hartford, CT

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Re: [R] noisy quantisation

2009-05-05 Thread Dieter Menne
William Simpson william.a.simpson at gmail.com writes:

 
 p-amp*cos(2*pi*freq*(1:n)/n ) + 0.5
 
 I was wondering if anyone can suggest a way to create a version where
 I get 0s, 1s, and 2s something like a noisy version of this:
 
 2  oo
 
 1o  o o
 
 0  ooo
 

# It's always polite to add the trivial parts that
# make the example run out of the box
amp = 1
freq = 5
n = 100
p = 0.1

# Well, this is not a noisy version, but one with added spikes
# If that's ok for you, take it
p = amp*cos(2*pi*freq*(1:n)/n ) + 0.5* as.numeric(runif(1:n)p)
plot(p,type=l)

# Note: the example must be modified for other values of amp
pquant = ((p+1)*3) %/% 3  -1
lines(pquant)

#-

Dieter

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Re: [R] Heatmap without levelplot

2009-05-05 Thread Dieter Menne
Antje niederlein-rstat at yahoo.de writes:

 as I'm not sure to understand the coloring levelplot uses, I'm looking for 
 another easy way to create a heatmap like this:
 
 library(lattice)
 mat - matrix(seq(1,5, length.out = 12), nrow = 3)
 mat[1,2] - 3.5
 
 my.at - seq(0.5,5.5, length.out = 6)
 my.col.regions - rainbow(5)
 
 graph - levelplot(t(mat[nrow(mat):1, ] ), at = my.at, col.regions = 
 my.col.regions)
 print(graph)
 

Looks fine to me, so what's wrong? Maybe have a look at RColorBrewer
to get more pleasing colors.

Dieter

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Re: [R] problem with rgl package

2009-05-05 Thread Dirk Eddelbuettel

On 5 May 2009 at 04:55, Erin Hodgess wrote:
| Dear R People:
| 
| Here is something strange.  I'm using Ubuntu 9.04 with R 2.9.0.
| 
| I need to have the rgl package.  Here are my results from installing:

So run

   sudo apt-get install r-cran-rgl

to install the pre-build binary.  If you must or want to build it yourself,
use the packaging system to get the build-dependencies installed:

   sudo apt-get build-dep r-cran-rgl


|  install.packages(rgl)
| Warning in install.packages(rgl) :
|   argument 'lib' is missing: using '/usr/local/lib/R/site-library'
| --- Please select a CRAN mirror for use in this session ---
| Loading Tcl/Tk interface ... done
| trying URL 'http://cran.cnr.Berkeley.edu/src/contrib/rgl_0.84.tar.gz'
| Content type 'application/x-gzip' length 1670659 bytes (1.6 Mb)
| opened URL
| ==
| downloaded 1.6 Mb
| 
| * Installing *source* package 'rgl' ...
| checking for gcc... gcc -std=gnu99
| checking for C compiler default output file name... a.out
| checking whether the C compiler works... yes
| checking whether we are cross compiling... no
| checking for suffix of executables...
| checking for suffix of object files... o
| checking whether we are using the GNU C compiler... yes
| checking whether gcc -std=gnu99 accepts -g... yes
| checking for gcc -std=gnu99 option to accept ISO C89... none needed
| checking how to run the C preprocessor... gcc -std=gnu99 -E
| checking for gcc... (cached) gcc -std=gnu99
| checking whether we are using the GNU C compiler... (cached) yes
| checking whether gcc -std=gnu99 accepts -g... (cached) yes
| checking for gcc -std=gnu99 option to accept ISO C89... (cached) none needed
| checking for libpng-config... yes
| configure: using libpng-config
| configure: using libpng dynamic linkage
| checking for X... no
| configure: error: X11 not found but required, configure aborted.

You don't have X11 headers. Run the second command above if you really want
to build the package.

| ERROR: configuration failed for package 'rgl'
| ** Removing '/usr/local/lib/R/site-library/rgl'
| 
| The downloaded packages are in
|   /tmp/RtmpiJh20a/downloaded_packages
| Warning message:
| In install.packages(rgl) :
|   installation of package 'rgl' had non-zero exit status
| 
| So presumably there is not an X11.  But when I put in capabilities,
| it seems to be there.
| 
|  capabilities()
| jpeg  png tifftcltk  X11 aqua http/ftp  sockets
| TRUE TRUE TRUE TRUE TRUEFALSE TRUE TRUE
|   libxml fifo   clediticonv  NLS  profmemcairo
| TRUE TRUE TRUE TRUE TRUE TRUE TRUE
| 

That means you are using an R binary capable of _running_ under X11. This
says nothing about compiling.

| Has anyone run into this, please?  What are the solutions, please?

As (almost) always: get the proper -dev packages for headers and libs.

Dirk

| 
| thanks,
| Erin
| 
| -- 
| Erin Hodgess
| Associate Professor
| Department of Computer and Mathematical Sciences
| University of Houston - Downtown
| mailto: erinm.hodg...@gmail.com
| 
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| and provide commented, minimal, self-contained, reproducible code.

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Re: [R] problem with rgl package

2009-05-05 Thread G. Jay Kerns
Dear Erin,

On Tue, May 5, 2009 at 5:55 AM, Erin Hodgess erinm.hodg...@gmail.com wrote:
 Dear R People:

 Here is something strange.  I'm using Ubuntu 9.04 with R 2.9.0.

 I need to have the rgl package.  Here are my results from installing:

 install.packages(rgl)
 Warning in install.packages(rgl) :
  argument 'lib' is missing: using '/usr/local/lib/R/site-library'
 --- Please select a CRAN mirror for use in this session ---
 Loading Tcl/Tk interface ... done
 trying URL 'http://cran.cnr.Berkeley.edu/src/contrib/rgl_0.84.tar.gz'
 Content type 'application/x-gzip' length 1670659 bytes (1.6 Mb)
 opened URL
 ==
 downloaded 1.6 Mb

 * Installing *source* package 'rgl' ...
 checking for gcc... gcc -std=gnu99
 checking for C compiler default output file name... a.out
 checking whether the C compiler works... yes
 checking whether we are cross compiling... no
 checking for suffix of executables...
 checking for suffix of object files... o
 checking whether we are using the GNU C compiler... yes
 checking whether gcc -std=gnu99 accepts -g... yes
 checking for gcc -std=gnu99 option to accept ISO C89... none needed
 checking how to run the C preprocessor... gcc -std=gnu99 -E
 checking for gcc... (cached) gcc -std=gnu99
 checking whether we are using the GNU C compiler... (cached) yes
 checking whether gcc -std=gnu99 accepts -g... (cached) yes
 checking for gcc -std=gnu99 option to accept ISO C89... (cached) none needed
 checking for libpng-config... yes
 configure: using libpng-config
 configure: using libpng dynamic linkage
 checking for X... no
 configure: error: X11 not found but required, configure aborted.
 ERROR: configuration failed for package 'rgl'
 ** Removing '/usr/local/lib/R/site-library/rgl'


I had the same problem a few days ago, and followed the
recommendations of this message:

http://tolstoy.newcastle.edu.au/R/e6/help/09/03/9250.html

which fixed it for me.

HTH,
Jay







***
G. Jay Kerns, Ph.D.
Associate Professor
Department of Mathematics  Statistics
Youngstown State University
Youngstown, OH 44555-0002 USA
Office: 1035 Cushwa Hall
Phone: (330) 941-3310 Office (voice mail)
-3302 Department
-3170 FAX
E-mail: gke...@ysu.edu
http://www.cc.ysu.edu/~gjkerns/

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Re: [R] levelplot question

2009-05-05 Thread Dieter Menne
Antje niederlein-rstat at yahoo.de writes:

 thanks for your answer. The color-vector has the same length like the 
 at-vector  but the recycling cannot be the reason, because only values 
 slightly above my  threshold doe not appear blue.
 I cannot find a good explanation of which colors are assigned to which 
 value  ranges.

This has nothing to do with the plotting, the question should be
How are float converted to integers. 

You had asked for that before; check my earlier reply. You implicitly assume 
that
there is a round() function involved, but something like floor() is used.

Make sure that all your numbers are integers.

Dieter

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Re: [R] Can't build termstrc package from source

2009-05-05 Thread Chirantan Kundu
Thanks, Peter.
R CMD build --binary did it for me.

On Tue, May 5, 2009 at 3:36 PM, Peter Dalgaard p.dalga...@biostat.ku.dkwrote:

 Chirantan Kundu wrote:
  Hi,
 
  I'm trying to build the termstrc 1.1 package from its source on R 2.7.2
 on
  Windows XP. However instead of building the package it just zips the
 entire
  source into a .tar.gz file.
  This is the first time I'm trying to build an R package from source. I
  installed the R toolset for Windows and set RTools as well as Perl 
 MinGW
  directories in the path.
  Anybody tried this out? Any file missing in the source?
 
  Any help is appreciated.

 It's hard to tell what you did wrong when you don't tell what you did.

 I suspect you need to study the difference between

 R CMD build
 R CMD INSTALL
 R CMD check
 R CMD build --binary

 --
   O__   Peter Dalgaard Øster Farimagsgade 5, Entr.B
  c/ /'_ --- Dept. of Biostatistics PO Box 2099, 1014 Cph. K
  (*) \(*) -- University of Copenhagen   Denmark  Ph:  (+45) 35327918
 ~~ - (p.dalga...@biostat.ku.dk)  FAX: (+45) 35327907




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[R] RMySQL insert statements?

2009-05-05 Thread Martijn Ras
Heya Folks,

I can not find anything on executing insert statement through RMySQL,
can someone please enlighten me?

All i've found so far on getting data into a database is the write
table functionality. Reading all data into memory appending additional
information and writing that into a table is fine on my test
environment, but won't be possible on the production environment
because of the amount of data it will contain.

Mazzel,

Martijn.

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Re: [R] noisy quantisation

2009-05-05 Thread William Simpson
If this helps, here is what I have currently

mean.p- .5
contrast-1
amp- contrast*mean.p
freq- 3
n- 100
p-amp*cos(2*pi*freq*(1:n)/n ) + mean.p
plot(p)
dens-as.numeric(runif(1:n)p)
plot(p, type=l)
points(dens, col=red)

I would like some dots having y-value=0.5 in the middle of the plot.
These will reduce the error of approximation.

Thanks for any help.

Bill

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[R] Lattice: use levelplot as panel for wireframe

2009-05-05 Thread Anton Bossenbroek

Hi,

I want to draw a figure similar to http://dsarkar.fhcrc.org/lattice/book/images/Figure_13_07_stdBW.png 
 from http://lmdvr.r-forge.r-project.org/figures/figures.html (figure  
13.7) . However instead of using a contour plot as a panel for the  
wireframe I want to use a levelplot. Can somebody help me with this?


Thanks in advance for any help,

Kind regards,

Anton Bossenbroek

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Re: [R] noisy quantisation; Bernoulli scheme

2009-05-05 Thread William Simpson
If I am right, the original version was a sinusoidally-modulated
(nonstationary) Bernoulli process. I want 3 possible values, not 2,
which makes it a Bernoulli scheme
http://en.wikipedia.org/wiki/Bernoulli_scheme

Not sure how to the create a sinusoidally modulated Bernoulli scheme
with values 0, 0.5, 1.

Bill

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[R] Lattice: use levelplot as panel for wireframe

2009-05-05 Thread Anton Bossenbroek

Hi,

I want to draw a figure similar to http://dsarkar.fhcrc.org/lattice/book/images/Figure_13_07_stdBW.png 
 from http://lmdvr.r-forge.r-project.org/figures/figures.html (figure  
13.7) . However instead of using a contour plot as a panel for the  
wireframe I want to use a levelplot. Can somebody help me with this?


Thanks in advance for any help,

Kind regards,

Anton Bossenbroek

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[R] Working with R from Remote desktop

2009-05-05 Thread Madan Mohan

Hi Friends,
Kindly let me know whether is it possible to install R project in a Server
(Remote) desktop, which can be accessed by many users by logging in with
their credentials...
Another concern is if i want to work with huge dataset (millions of records)
what should be the system configuration? (currently i am getting an error :
Cannot allocate vector of size 16.7 Mb)

Regards,
Madana
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[R] Find cyclically identical binary sequences

2009-05-05 Thread Michael Kubovy
Dear R-helpers,

I need to generate all the binary sequences of length n (here n = 8)  
that start with 1 and have no fewer than two of each digit, and are  
not cyclic permutations of each other. Here is what I have done:

len - 8
df - as.data.frame(numeric(2^(len - 1)) %o% numeric(len))
require(partitions)
for (i in 1:2^(len - 1)) df[i, ] - binary(i, dim = len)[[1]]
df - df[which(df[, 1] == 1), ]
df - df[which(rowSums(df)  1), ]
df - df[which(rowSums(df)  len - 1), ]

The following are cyclic permutations of each other:
df[which(rowSums(df) == 3), ][c(2, 15), ]

I would like to retain the larger of the two (if considered a binary  
number).

Can someone suggest an algorithm?

Thanks,
Michael

_
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University of Virginia
Department of Psychology
USPS: P.O.Box 400400Charlottesville, VA 22904-4400
Parcels:Room 102Gilmer Hall
McCormick RoadCharlottesville, VA 22903
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Re: [R] Working with R from Remote desktop

2009-05-05 Thread Uwe Ligges



Madan Mohan wrote:

Hi Friends,
Kindly let me know whether is it possible to install R project in a Server
(Remote) desktop, which can be accessed by many users by logging in with
their credentials...


Just install it, that's it.


Another concern is if i want to work with huge dataset (millions of records)
what should be the system configuration? (currently i am getting an error :
Cannot allocate vector of size 16.7 Mb)


It depends on your definition of huge. The error messsage just tells 
you about the last (but not final, since R cannot know about that) 
memory allocation, hence meaningless.

See ?Memory to get a point to start.

Uwe Ligges



Regards,
Madana


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Re: [R] limits

2009-05-05 Thread Jorge Ivan Velez
Dear Hassam,
Take a look at the section 5.8 in [1].

HTH,

Jorge

[1] http://cran.r-project.org/web/packages/Ryacas/vignettes/Ryacas.pdf


On Tue, May 5, 2009 at 5:39 AM, Hassan Mohamed
hassan_hany_fa...@yahoo.comwrote:

 Hey,
 what is the R function for the mathematical limit ?
 e.g. to calculate  and return the amount that the expression
 X^2 +X +2
 approach
 as X approach 2
 (X- 2)
 thanks
 hassan



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Re: [R] Optim function in the loop

2009-05-05 Thread Uwe Ligges

Hard to say without seeing Linn() and maybe other relevant data.

Uwe Ligges


Rstarer wrote:
Thanks for the reply. 


optim(initpar,Linn,NULL,method=BFGS,hessian=TRUE,control=list(trace=1,REPORT=1,maxit=300))

The optim is to minimize the negative likelihood function which is performed
in function Linn,
Every time the code stops right after optim, for example, the output looks
like:


iter  16 value 42.818394
iter  16 value 42.818394
final  value 42.818394 
converged


It seems from the code that the loop should continue to run, at least
calculate u values... but it does not...

Thank you.


Hi all, 
I wrote the following lines of codes try to do some iterations to find the

global optimal values, but the function does not execute properly. Every
time codes stop after one iteration right after executing the optim()
function. Does anyone could have me to take a look? Thanks.
if (count0){

k=k+0.05;

mu0=c(83+k,0,0)

Sigma0= diag(0.4,3)

initpar=c(.1+10*k,10*k,10*k,10*k) # initial parameters for Phi[1,1], the 2
Q’s and R

est=optim(initpar,Linn,NULL,method=BFGS,hessian=TRUE,control=list(trace=1,REPORT=1,maxit=300))

stderr=sqrt(diag(solve(est$hessian)))

estimate=est$par

u=cbind(estimate,stderr)

if (u[1]0  u[2]0  u[3]0  u[4]0){

print(mu0=);print(mu0);

print(initpar=);print(initpar)

#break

} else {count=-1;

}

}





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Re: [R] JGR

2009-05-05 Thread Uwe Ligges



r...@quantide.com wrote:

Dear R User
I am using JGR on a Linux Ubuntu Computer with 2 Cpus
When Opening JGR, one Cpu goes up to 100% even if no calculation is yet 
started

Did any of you already noticed this strange behaviour?


Does it take very long? On the first start it builds some databases and 
that takes some time if you have installed many packages.


Uwe Ligges



Thanks for your help
Andrea

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[R] Cox Proportional Hazard with missing covariate data

2009-05-05 Thread Philipp Rappold
Dear friends,

I have used R for some time now and have a tricky question about the 
coxph-function: To sum it up, I am not sure whether I can use coxph in 
conjunction with missing covariate data in a model with time-variant 
covariates. The point is: I know how old every piece that I oberserve is, but 
do not have fully historical information about the corresponding covariates. 
Maybe you have some advice for me, although this problem might only be 70% R 
and 30% statistically-related. Here's a detailled explanation:

SITUATION  OBJECTIVE:
I want to analyze the effect of environmental effects (i.e.
temperature and humidity) on the lifetime of some wear-parts. The
study should be conducted on a yearly basis, meaning that I have
collected empirical data on every wearpart at the end of every year.

DATA:
I have collected the following data:
- Status of the wear-part: Equals 0 if part is still alive, equals
1 if part has died (my event variable)
- Environmental data: Temperature and humidity have been measured at
each of the wear-parts on a yearly basis (because each wear-part is at
a different location, I have different data for each wear-part)

PROBLEM:
I started collecting data between 2001 and 2007. In 2001, a vast
amount of of wearparts has already been in use. I DO KNOW for every
part how long it has been used (even if it was employed before 2001),
but I DO NOT have any information about environmental conditions like
temperature or humidity before 2001 (I call this semi-left-censored).
Of course, one could argue that I should simply exclude these parts
from my analysis, but I don't want to loose valuable information, also
because the amount of new parts that have been employed between 2001
and 2007 is rather small.

Additionally, I cannot make any assumption about the underlying
lifetime distribution. Therefore I have to use a non-parametrical
model for estimation (most likely cox).

QUESTION:
From an econometric perspective, is it possible to use Cox
Proportional Hazard model in this setting? As mentioned before, I have
time-variant covariates for each wearpart, as well as what I call
semi-left-censored data that I want to use. If not, what kind of
analysis would you suggest?

Thanks a lot for your great help, I really appreciate it.

All the best
Philipp

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Re: [R] limits

2009-05-05 Thread Uwe Ligges



Hassan Mohamed wrote:

Hey,
what is the R function for the mathematical limit ?
e.g. to calculate  and return the amount that the expression
X^2 +X +2 
approach

as X approach 2
(X- 2)



So you want some software that can do symbolic calculations? In that 
case use other software. R is designed for numerical analyses.


Uwe Ligges



thanks
hassan


  
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Re: [R] Splitting a vector into equal groups

2009-05-05 Thread Uwe Ligges



utkarshsinghal wrote:

Hi All,

I have vector of length 52, say, x=sample(30,52,replace=T). I want to 
sort x and split into five *nearly equal groups*. Note that the 
observations are repeated in x so in case of a tie I want both the 
observations to fall in same group.
This seems a very common task to do, but still I couldn't find an R 
function to do this. Any help would be highly appreciated.



See ?cut for groups equal in in its range or
?co.intervals in package lattice for intervals somewhat equal in number 
of observations.


Uwe Ligges





Regards
Utkarsh



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Re: [R] prob in predict(randomForest)

2009-05-05 Thread Liaw, Andy
In short, yes.

Andy 

From: Haring, Tim (LWF)
 
 Hi at all,
 
 maybe this question is quite simple for a statistician, but 
 for me it is not. After reading a lot of mail in the R-help 
 archive I`m still not quite sure I get it. 
 When applying a randomForest to a new dataset with 
 predict(randomForest) I have the option to get the output as 
 probability (classification problem):
 predict(myrf,...,type=prob)
 I would like to know how I have to understand this output. 
 Are this values the probability of an observation belonging 
 to a predicted class? Say, I have a data-point as newdata, my 
 rf-model predicts Class A and the probability is 0,12301. 
 Does this mean that this data-point belongs to class A only 
 with a probability of 12%?
 
 Thanks for every hint.
 
 TIM
 
 Just as a matter of form: I´m using R version 2.8.1, 
 randomForest package 4.5-28, OS: WinXP
 
 --
 - 
 Tim Häring
 Bavarian State Institute of Forest Research 
 Department of Forest Ecology
 Am Hochanger 11
 D-85354 Freising
 
 E-Mail: tim.haer...@lwf.bayern.de
 http://www.lwf.bayern.de
 
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Re: [R] Support Vector Machines

2009-05-05 Thread Liaw, Andy
svm() in the e1071 package is an interface to the libsvm code.  Look at the 
link provided in the help page for that function.  You will have to read up how 
density estimation is achieved via one-class SVM.

Andy 

From: excalibur
 
 In the R-help of the svm function of the package e1071 it's 
 explained that
 this function also makes estimation of density.
 
 But when i made for example
 X-rnorm(1000)
 m-svm(X)
 
 I just have a binary classification of X like SVM do whereas i want an
 estimation of the density which generates our sample X ...
 
 I don't know if it's possible and if someone has already use 
 this function
 to do that.
 
 Thanks.
 
 
 David Winsemius wrote:
  
  
  On May 4, 2009, at 8:52 AM, excalibur wrote:
  
 
  This question is still unanswered.
  
  Unanswered questions are often those which do not comply with the  
  guidelines in the Posting Guide. Many people have gotten tired of  
  either making up examples or of writing  Read the Posting 
 Guide, so  
  they just ignore them.
  
  
  Someone can explain me how use the svm function to make density  
  estimation ?
  
  If you post an executable bit of code that shows how you are doing  
  those operations, then I suspect someone will answer.
  
  excalibur wrote:
 
 
  Hi,
  i try to use function svm of package e1071 to estimate a density.
 
  But if my data are X=(X1,...,Xn) and m-svm(X) some 
 values of m$SV  
  are
  less than 0.
  I don't see how i can get the estimation of the density with this
  function.
 
  Thanks for your help.
 
  Rémi
 
  
  David Winsemius, MD
  Heritage Laboratories
  West Hartford, CT
  
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Re: [R] Can't build termstrc package from source

2009-05-05 Thread Chirantan Kundu
Thanks, Uwe.
I've managed to get it done with R CMD BUILD -binary.

2009/5/5 Uwe Ligges lig...@statistik.tu-dortmund.de

 I guess you asked R to:

   R CMD build ...

 which builds the source package, but you need

   R CMD INSTALL ...

 in order to install the package or

 R CMD INSTALL --build  ...

 in order to install *and* build a binary package. See the manual R
 Installation and Administration.

 Uwe Ligges







 Chirantan Kundu wrote:

 Hi,

 I'm trying to build the termstrc 1.1 package from its source on R 2.7.2 on
 Windows XP. However instead of building the package it just zips the
 entire
 source into a .tar.gz file.
 This is the first time I'm trying to build an R package from source. I
 installed the R toolset for Windows and set RTools as well as Perl  MinGW
 directories in the path.
 Anybody tried this out? Any file missing in the source?

 Any help is appreciated.

 Thanks,
 Chirantan

 
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[R] Create Pie chart from .csv file

2009-05-05 Thread DonkeyRhubarb

Hi all,

I am looking to create a pie chart from a given column in a .csv file. 

My class variables are as follows:

entry_type, uniquekey,  types, title,url, abstract, journal, 
author, month,
year, howpublished

So say I want to export a pie chart that groups together all  entries under
'types' e.g. 3 x statistics 2x education etc. Im looking to have a piechart
represent this graphically that shows which type of entry is in most
frequently. Preferably I'd like to export to a PDF chart and while I can do
this by typing variables directly into the R console, I cannot manage it
from a .csv file.

If you cannot help me with this specific problem, just knowing how to create
a generic pie chart would be a great help.

This is part of my final software project which is due in one week. I would
very much appreciate any help.

Many thanks in advance

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Re: [R] JGR

2009-05-05 Thread r...@quantide.com

The point is that one Cpu stays at 100% for all time JGR is up.
Any ideas?
Andrea

Uwe Ligges wrote:



r...@quantide.com wrote:

Dear R User
I am using JGR on a Linux Ubuntu Computer with 2 Cpus
When Opening JGR, one Cpu goes up to 100% even if no calculation is 
yet started

Did any of you already noticed this strange behaviour?


Does it take very long? On the first start it builds some databases 
and that takes some time if you have installed many packages.


Uwe Ligges



Thanks for your help
Andrea

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Re: [R] Cox Proportional Hazard with missing covariate data

2009-05-05 Thread Philipp Rappold
Hi,

Arthur, thanks a lot for your super-fast reply!

In fact I am using the time when the part has been used for the first time, so 
your example should work in my case.
Moreover, as I have time-variant covariates, the example should look like this 
in my specific case:

start   stopstatus  temphumid
5   6   0   32  43
6   7   1   34  42

Just two more things:
(1) I am quite a newbie to cox-regression, so I wonder what you think about the 
approach that I mentioned above? Don't worry, I won't nail you down to this, 
just want to make sure I am not totally off track!
(2) I don't think that you'd call this left-truncated observations, because I 
DO know the time when the part was used for the first time, I just don't have 
covariate values for its whole time of life, e.g. just the last two years in 
the example above. Left truncation in my eyes would mean that I did not even 
observe a specific part, e.g. because it has died before the study started.

Again, thanks a lot, I'll be happy to provide valuable help on this list as 
soon as my R-skills are advancing.

All the best
Philipp

Arthur Allignol wrote:
 Hi,
 
 In fact, you have left-truncated observations.
 
 What timescale do you use, time 0 is the
 study entry, or when the wear-part has been used for the
 first time?
 
 If it is the latter, you can specify the age of the wear part
 at study entry in Surv(). For example, if a wear part has been
 used for 5 years before study entry, and dies 2 years after,
 the data will look like that:
 start stop status
 57  1
 
 Hope this helps,
 Arthur Allignol
 
 
 Philipp Rappold wrote:
 Dear friends,

 I have used R for some time now and have a tricky question about the
 coxph-function: To sum it up, I am not sure whether I can use coxph in
 conjunction with missing covariate data in a model with time-variant
 covariates. The point is: I know how old every piece that I
 oberserve is, but do not have fully historical information about the
 corresponding covariates. Maybe you have some advice for me, although
 this problem might only be 70% R and 30% statistically-related. Here's
 a detailled explanation:

 SITUATION  OBJECTIVE:
 I want to analyze the effect of environmental effects (i.e.
 temperature and humidity) on the lifetime of some wear-parts. The
 study should be conducted on a yearly basis, meaning that I have
 collected empirical data on every wearpart at the end of every year.

 DATA:
 I have collected the following data:
 - Status of the wear-part: Equals 0 if part is still alive, equals
 1 if part has died (my event variable)
 - Environmental data: Temperature and humidity have been measured at
 each of the wear-parts on a yearly basis (because each wear-part is at
 a different location, I have different data for each wear-part)

 PROBLEM:
 I started collecting data between 2001 and 2007. In 2001, a vast
 amount of of wearparts has already been in use. I DO KNOW for every
 part how long it has been used (even if it was employed before 2001),
 but I DO NOT have any information about environmental conditions like
 temperature or humidity before 2001 (I call this semi-left-censored).
 Of course, one could argue that I should simply exclude these parts
 from my analysis, but I don't want to loose valuable information, also
 because the amount of new parts that have been employed between 2001
 and 2007 is rather small.

 Additionally, I cannot make any assumption about the underlying
 lifetime distribution. Therefore I have to use a non-parametrical
 model for estimation (most likely cox).

 QUESTION:
 From an econometric perspective, is it possible to use Cox
 Proportional Hazard model in this setting? As mentioned before, I have
 time-variant covariates for each wearpart, as well as what I call
 semi-left-censored data that I want to use. If not, what kind of
 analysis would you suggest?

 Thanks a lot for your great help, I really appreciate it.

 All the best
 Philipp

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Re: [R] problem with rgl package

2009-05-05 Thread Dirk Eddelbuettel

(off list)

On 5 May 2009 at 05:15, Erin Hodgess wrote:
| I also needed libglu1-mesa-dev, but now all is well.

a) You still haven't explained why you need to rebuild it when 
   sudo apt-get install r-cran-rgl
   gets you a binary
   
b) Yes, as 
   sudo apt-get build-dep r-cran-rgl
   would have found out for you.

We do _a lot of work_ for R on Debian/Ubuntu. Use it, you even have a
money-back guarantee. And ...

c) This rgl header business has been discussed at least a hundred times on
   the R-help list. Use RSiteSearch()

Dirk

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[R] Find cyclically identical binary sequences (corrected)

2009-05-05 Thread Michael Kubovy

Dear R-helpers,

I need to generate all the binary sequences of length n (here n = 8)
that start with 1 and have no fewer than two of each digit, and are
not cyclic permutations of each other. Here is what I have done:

len - 8
df - as.data.frame(numeric(2^(len - 1)) %o% numeric(len))
require(wle)
for (i in 1:2^(len - 1)) df[i, ] - binary(i, dim = len)[[1]]
df - df[which(df[, 1] == 1), ]
df - df[which(rowSums(df)  1), ]
df - df[which(rowSums(df)  len - 1), ]

The following are cyclic permutations of each other:
df[which(rowSums(df) == 3), ][c(2, 15), ]

I would like to retain the larger of the two (if considered a binary
number).

Can someone suggest an algorithm?

Thanks,
Michael

_
Professor Michael Kubovy
University of Virginia
Department of Psychology
USPS: P.O.Box 400400Charlottesville, VA 22904-4400
Parcels:Room 102Gilmer Hall
   McCormick RoadCharlottesville, VA 22903
Office:B011+1-434-982-4729
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Re: [R] Support Vector Machines

2009-05-05 Thread excalibur

I see that index is giving me the group for the classification problem.

But my problem is not the same. I had a sample X-rnorm(1000) for example.

I don't want to make classification (i have only one group in fact) but i
want to estimate the density which generates my sample (like i can do with
others methods like kernel density estimation, wavelets estimations, splines
...). 

So, logically, i hope i will find an approximation of the Gaussian density.

But i don't see how i can obtain this density estimation with the function
svm.

Thanks


David Winsemius wrote:
 
 
 On May 5, 2009, at 3:49 AM, excalibur wrote:
 

 In the R-help of the svm function of the package e1071 it's  
 explained that
 this function also makes estimation of density.

 But when i made for example
 X-rnorm(1000)
 m-svm(X)

 I just have a binary classification of X like SVM do whereas i want an
 estimation of the density which generates our sample X ...

 I don't know if it's possible and if someone has already use this  
 function
 to do that.
 
 Use str() to look at the object returned by svm. The example in svm's  
 help page uses the svm object's index variable although there are  
 other components that are available for extraction. The fitted  
 vector looks to have similar binary properties to index and the SV  
 vector appears to be a distance measure.
 
 -- 
 David
 


 Thanks.


 David Winsemius wrote:


 On May 4, 2009, at 8:52 AM, excalibur wrote:


 This question is still unanswered.

 Unanswered questions are often those which do not comply with the
 guidelines in the Posting Guide. Many people have gotten tired of
 either making up examples or of writing  Read the Posting Guide, so
 they just ignore them.


 Someone can explain me how use the svm function to make density
 estimation ?

 If you post an executable bit of code that shows how you are doing
 those operations, then I suspect someone will answer.

 excalibur wrote:


 Hi,
 i try to use function svm of package e1071 to estimate a density.

 But if my data are X=(X1,...,Xn) and m-svm(X) some values of m$SV
 are
 less than 0.
 I don't see how i can get the estimation of the density with this
 function.

 Thanks for your help.

 Rémi


 David Winsemius, MD
 Heritage Laboratories
 West Hartford, CT

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 David Winsemius, MD
 Heritage Laboratories
 West Hartford, CT
 
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[R] calibration plot

2009-05-05 Thread abbas tavassoli
Hi, 
I have a binary variable and corresponding predicted probability (using 
logistic regression on some explanatoey variables); 
I want to check that the model is well-calibrated using a calibration plot.
how can I have the calibration plot for my data?
thanks.



  
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[R] ERPs analysis

2009-05-05 Thread Patrik Pluchino

Good morning to Everyone,

   I'm an Italian PhD student 
that is working on ERPs experiment (cognitive psychology) and I would 
like to know if there are R packages for this kind of analysis.
I'm using BrainAmp to record the data and this program gives me three 
different files (an *.eeg, an *.vmrk and *.vhdr).



Thank You in advance.



Patrik

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[R] text mining in italian

2009-05-05 Thread Laura Arsanto



Hello everybody,

I'm trying to do text mining on a serie of texts in italian.

I would like to know if it is possible to find the italian synonyms and/or if 
something like WordNet database for English exists also for italian.

Thank you very much in advance.

Regards,

Laura

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[R] View cluster results of large data sets

2009-05-05 Thread Wade Wall
Hi all,

I am trying to run a cluster analysis with a relatively large data set
(545 samples) and obviously am having trouble viewing the results
using standard plot() method.  Is there a way to plot the results of a
large cluster analysis in a window with a scroll bar.  Any
recommendations would be appreciated because I have looked around for
a solution to no avail.

Thanks

Wade Wall

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Re: [R] Heatmap without levelplot

2009-05-05 Thread Antje

Hi Uwe,

I tried to explain my problem with the given example.
I don't see any documentation which tells me that the length of col.regions 
should be one less than at. (At least I assume now that it should be this way...)
If it's equal or longer some colors (in the middle of the color-vector) are 
simply not used.
Just try the example below with rainbow(5) and rainbow(6) and compare the 
results... both plot will use 5 colors!
Sorry, but this behaviour is not really self-explaining to me... maybe I'm to 
blind to find the documentation which says that only one color less will ensure 
the usage of all colors.


(It is so important for me because I need to display a heatmap with colors 
let's say

* all lower data outliers green,
* all higher data outliers blue and
* everything else within the color range yellow to red.
I've seen that some values do not get blue or green though they are outliers...
I've attached one graph, I've generated - maybe it helps to understand)

Any wrong assumption?

Ciao,
Antje


Uwe Ligges schrieb:



Antje wrote:

Hi there,

as I'm not sure to understand the coloring levelplot uses, I'm looking 
for another easy way to create a heatmap like this:


library(lattice)
mat - matrix(seq(1,5, length.out = 12), nrow = 3)
mat[1,2] - 3.5

my.at - seq(0.5,5.5, length.out = 6)
my.col.regions - rainbow(5)

graph - levelplot(t(mat[nrow(mat):1, ] ), at = my.at, col.regions = 
my.col.regions)

print(graph)

Can anybody help me with some hints or little examples?



Dear Antje,

since you are asking the same question again now, maybe you can explain 
what you are going to get? In fact, I do not undertsand where your 
problem is. R places the colors according to the values in your matrix 
very well including the legend and I thought up to today that the plot 
is self explaining.


Best wishes,
Uwe Ligges





Antje

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Re: [R] calibration plot

2009-05-05 Thread Jorge Ivan Velez
Dear Abbas,
Take a look at the results of

require(Hmisc)
require(Design)
apropos(calibrate)
?calibrate
?plot.calibrate

HTH,

Jorge


On Tue, May 5, 2009 at 9:41 AM, abbas tavassoli tavassoli...@yahoo.comwrote:

 Hi,
 I have a binary variable and corresponding predicted probability (using
 logistic regression on some explanatoey variables);
 I want to check that the model is well-calibrated using a calibration plot.
 how can I have the calibration plot for my data?
 thanks.




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Re: [R] calibration plot

2009-05-05 Thread Liaw, Andy
I believe something like:

scatter.smooth(est.prob, as.numeric(y == level of interest))

would be close.  You may want to use a larger span than default.

Andy 

From: abbas tavassoli
 
 Hi, 
 I have a binary variable and corresponding predicted 
 probability (using 
 logistic regression on some explanatoey variables); 
 I want to check that the model is well-calibrated using a 
 calibration plot.
 how can I have the calibration plot for my data?
 thanks.
 
 
 
   
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 http://www.R-project.org/posting-guide.html
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Re: [R] Create Pie chart from .csv file

2009-05-05 Thread Richard . Cotton
 I am looking to create a pie chart from a given column in a .csv file. 
 
 My class variables are as follows:
 
 entry_type,   uniquekey,   types, title,url, abstract, journal, 
 author, month,
 year, howpublished
 
 So say I want to export a pie chart that groups together all  entries 
under
 'types' e.g. 3 x statistics 2x education etc. Im looking to have a 
piechart
 represent this graphically that shows which type of entry is in most
 frequently. Preferably I'd like to export to a PDF chart and while I can 
do
 this by typing variables directly into the R console, I cannot manage it
 from a .csv file.
 
 If you cannot help me with this specific problem, just knowing how to 
create
 a generic pie chart would be a great help.

Split the problem up into different stages.

1. Read in your data form the csv file.
?read.csv

2. Plot something.
?pie if you really must, but a bar chart will almost certainly be better. 
See ?barplot and ?barchart (lattice package).

3. Export the graph to PDF.
?pdf

Regards,
Richie.

Mathematical Sciences Unit
HSL




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[R] Stepwise logistic regression with significance testing - stepAIC

2009-05-05 Thread Peter-Heinz Fox
Hello R-Users,
 
I have one binary dependent variable and a set of independent variables 
(glm(formula,…,family=”binomial”) ) and I am using the function stepAIC 
(“MASS”) for choosing an optimal model. However I am not sure if stepAIC 
considers significance properties like Likelihood ratio test and Wald test (see 
example below).  
 
 y - rbinom(30,1,0.4)
 x1 - rnorm(30)
 x2 - rnorm(30)
 x3 - rnorm(30)
 xdata - data.frame(x1,x2,x3)
 
 fit1 - glm(y~ . ,family=binomial,data=xdata)
 stepAIC(fit1,trace=FALSE)
 
Call:  glm(formula = y ~ x3, family = binomial, data = xdata) 
 
Coefficients:
(Intercept)           x3  
    -0.3556       0.8404  
 
Degrees of Freedom: 29 Total (i.e. Null);  28 Residual
Null Deviance:      40.38 
Residual Deviance: 37.86        AIC: 41.86 
 
 fit - glm( stepAIC(fit1,trace=FALSE)$formula  ,family=binomial)
 my.summ - summary(fit)
 # Wald Test 
 print(my.summ$coeff[,4])
(Intercept)          x3 
  0.3609638   0.1395215 
 
 my.anova - anova(fit,test=Chisq)
 #LR Test
 print(my.anova$P[2])
[1] 0.1121783
  
 
Is there an alternative function or a possible way of checking if the added 
variable and the new model are significant within the regression steps? 
 
Thanks in advance for your help
 
Regards
 
Peter-Heinz Fox



  
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Re: [R] FOURIER INTEGRALS IN R

2009-05-05 Thread A Achilleos

Ok thanks..

No, my function is not smooth.

Actually, I am dealing with an integral having the following form, for
example:


\int cos(tx) (1-t^2)^3 \exp(0.5*t^2) dt


I want to estimate this Fourier Cosine integral for a given value of x.

Thanks for the help.


AA


On Tue, May 5, 2009 2:34 am, andrew wrote:

integrate offers some one-dimensional algorithms, but you need to
start with a smooth function to get it to converge properly.  With a
cosine integral, there may be certain routines that offer better value
for money: the Clenshaw-Curtis integration, or perhaps the FFT.  You
would have to recast your problem by doing some sort of substitution.

Perhaps post some latex code to show the exact type of integral you
are wanting to calculate.

Regards,

On May 5, 6:32 am, Achilleas Achilleos ma...@bristol.ac.uk wrote:

Hi,

I am wondering whether there exist any function in R (any package) that
calculates Fourier Integrals.

Particularly, I am interested for estimation of a Cosine Fourier
integral...

I would be much obliged if you could help me on this..

Thanks.

Andreas

--

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--
A Achilleos
ma...@bristol.ac.uk

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[R] Stepwise logistic Regression with significance testing - stepAIC

2009-05-05 Thread Peter-Heinz Fox
Hello R-Users,
 
I have one binary dependent variable and a set of independent variables 
(glm(formula,…,family=”binomial”) ) and I am using the function stepAIC 
(“MASS”) for choosing an optimal model. However I am not sure if stepAIC 
considers significance properties like Likelihood ratio test and Wald test (see 
example below).  
 
 y - rbinom(30,1,0.4)
 x1 - rnorm(30)
 x2 - rnorm(30)
 x3 - rnorm(30)
 xdata - data.frame(x1,x2,x3)
 
 fit1 - glm(y~ . ,family=binomial,data=xdata)
 stepAIC(fit1,trace=FALSE)
 
Call:  glm(formula = y ~ x3, family = binomial, data = xdata) 
 
Coefficients:
(Intercept)           x3  
    -0.3556       0.8404  
 
Degrees of Freedom: 29 Total (i.e. Null);  28 Residual
Null Deviance:      40.38 
Residual Deviance: 37.86        AIC: 41.86 
 
 fit - glm( stepAIC(fit1,trace=FALSE)$formula  ,family=binomial)
 my.summ - summary(fit)
 # Wald Test 
 print(my.summ$coeff[,4])
(Intercept)          x3 
  0.3609638   0.1395215 
 
 my.anova - anova(fit,test=Chisq)
 #LR Test
 print(my.anova$P[2])
[1] 0.1121783

 
 
Is there an alternative function or a possible way of checking if the added 
variable and the new model are significant within the regression steps? 
 
Thanks in advance for your help
 
Regards
 
Peter-Heinz Fox


  
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[R] Re : Support Vector Machines

2009-05-05 Thread justin bem
there is a SVM function in svmpath by Trevor Hastie. Before use it take time to 
read this 

http://www-stat.stanford.edu/~hastie/Papers/svmpath.pdf

If you install then svmpath library ! run the attach source file.


Justin BEM
BP 1917 Yaoundé
Tél (237) 99597295
(237) 22040246 





De : excalibur servien.rem...@yahoo.fr
À : r-help@r-project.org
Envoyé le : Mardi, 5 Mai 2009, 8h49mn 49s
Objet : Re: [R] Support Vector Machines


In the R-help of the svm function of the package e1071 it's explained that
this function also makes estimation of density.

But when i made for example
X-rnorm(1000)
m-svm(X)

I just have a binary classification of X like SVM do whereas i want an
estimation of the density which generates our sample X ...

I don't know if it's possible and if someone has already use this function
to do that.

Thanks.


David Winsemius wrote:
 
 
 On May 4, 2009, at 8:52 AM, excalibur wrote:
 

 This question is still unanswered.
 
 Unanswered questions are often those which do not comply with the  
 guidelines in the Posting Guide. Many people have gotten tired of  
 either making up examples or of writing  Read the Posting Guide, so  
 they just ignore them.
 
 
 Someone can explain me how use the svm function to make density  
 estimation ?
 
 If you post an executable bit of code that shows how you are doing  
 those operations, then I suspect someone will answer.
 
 excalibur wrote:


 Hi,
 i try to use function svm of package e1071 to estimate a density.

 But if my data are X=(X1,...,Xn) and m-svm(X) some values of m$SV  
 are
 less than 0.
 I don't see how i can get the estimation of the density with this
 function.

 Thanks for your help.

 Rémi

 
 David Winsemius, MD
 Heritage Laboratories
 West Hartford, CT
 
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View this message in context: 
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[R] Stepwise logistic regression with significance testing - stepAIC

2009-05-05 Thread Peter-Heinz Fox
Hello R-Users,
 
I have one binary dependent variable and a set of independent variables 
(glm(formula,…,family=”binomial”) ) and I am using the function stepAIC 
(“MASS”) for choosing an optimal model. However I am not sure if stepAIC 
considers significance properties like Likelihood ratio test and Wald test (see 
example below).  
 
 y - rbinom(30,1,0.4)
 x1 - rnorm(30)
 x2 - rnorm(30)
 x3 - rnorm(30)
 xdata - data.frame(x1,x2,x3)
 
 fit1 - glm(y~ . ,family=binomial,data=xdata)
 stepAIC(fit1,trace=FALSE)
 
Call:  glm(formula = y ~ x3, family = binomial, data = xdata) 
 
Coefficients:
(Intercept)           x3  
    -0.3556       0.8404  
 
Degrees of Freedom: 29 Total (i.e. Null);  28 Residual
Null Deviance:      40.38 
Residual Deviance: 37.86        AIC: 41.86 
 
 fit - glm( stepAIC(fit1,trace=FALSE)$formula  ,family=binomial)
 my.summ - summary(fit)
 # Wald Test 
 print(my.summ$coeff[,4])
(Intercept)          x3 
  0.3609638   0.1395215 
 
 my.anova - anova(fit,test=Chisq)
 #LR Test
 print(my.anova$P[2])
[1] 0.1121783
  
 
Is there an alternative function or a possible way of checking if the added 
variable and the new model are significant within the regression steps? 
 
Thanks in advance for your help
 
Regards
 
Peter-Heinz Fox



  
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Re: [R] FOURIER INTEGRALS IN R

2009-05-05 Thread Ravi Varadhan
Your integrand is smooth. 

What are the limits of integration: 0 to 1 or 0 to infinity?  Main challenge
is that it is increasingly oscillatory as x and/or t increase.  You can find
the zeros of the cosine function and add up the integrals between successive
zeros.  In what context does this inttegral arise?  It must have been
studied well using asymptotic approximation and such.  

Ravi.


---

Ravi Varadhan, Ph.D.

Assistant Professor, The Center on Aging and Health

Division of Geriatric Medicine and Gerontology 

Johns Hopkins University

Ph: (410) 502-2619

Fax: (410) 614-9625

Email: rvarad...@jhmi.edu

Webpage:  http://www.jhsph.edu/agingandhealth/People/Faculty/Varadhan.html







-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of A Achilleos
Sent: Tuesday, May 05, 2009 10:18 AM
To: r-help@r-project.org
Subject: Re: [R] FOURIER INTEGRALS IN R

Ok thanks..

No, my function is not smooth.

Actually, I am dealing with an integral having the following form, for
example:


\int cos(tx) (1-t^2)^3 \exp(0.5*t^2) dt


I want to estimate this Fourier Cosine integral for a given value of x.

Thanks for the help.


AA


On Tue, May 5, 2009 2:34 am, andrew wrote:
 integrate offers some one-dimensional algorithms, but you need to 
 start with a smooth function to get it to converge properly.  With a 
 cosine integral, there may be certain routines that offer better value 
 for money: the Clenshaw-Curtis integration, or perhaps the FFT.  You 
 would have to recast your problem by doing some sort of substitution.

 Perhaps post some latex code to show the exact type of integral you 
 are wanting to calculate.

 Regards,

 On May 5, 6:32 am, Achilleas Achilleos ma...@bristol.ac.uk wrote:
 Hi,

 I am wondering whether there exist any function in R (any package) 
 that calculates Fourier Integrals.

 Particularly, I am interested for estimation of a Cosine Fourier 
 integral...

 I would be much obliged if you could help me on this..

 Thanks.

 Andreas

 --

 __
 r-h...@r-project.org mailing
 listhttps://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting
 guidehttp://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.

 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
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 and provide commented, minimal, self-contained, reproducible code.


--
A Achilleos
ma...@bristol.ac.uk

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Re: [R] Cox Proportional Hazard with missing covariate data

2009-05-05 Thread Arthur Allignol

(1) Makes sense. Another approach is to use
the time since study entry and include the age
of the part in the model. A related discussion
here: http://tolstoy.newcastle.edu.au/R/e2/help/07/02/9831.html


(2) It is left-truncation. A part is observed only if it has
survived until study entry. Of course, if you reset the clock
at study entry, there's no delayed entries anymore.


Philipp Rappold wrote:

Hi,

Arthur, thanks a lot for your super-fast reply!

In fact I am using the time when the part has been used for the first time, so 
your example should work in my case.
Moreover, as I have time-variant covariates, the example should look like this 
in my specific case:

start   stopstatus  temphumid
5   6   0   32  43
6   7   1   34  42

Just two more things:
(1) I am quite a newbie to cox-regression, so I wonder what you think about the approach 
that I mentioned above? Don't worry, I won't nail you down to this, just want to make 
sure I am not totally off track!
(2) I don't think that you'd call this left-truncated observations, because I 
DO know the time when the part was used for the first time, I just don't have covariate 
values for its whole time of life, e.g. just the last two years in the example above. 
Left truncation in my eyes would mean that I did not even observe a specific part, e.g. 
because it has died before the study started.

Again, thanks a lot, I'll be happy to provide valuable help on this list as 
soon as my R-skills are advancing.

All the best
Philipp

Arthur Allignol wrote:

Hi,

In fact, you have left-truncated observations.

What timescale do you use, time 0 is the
study entry, or when the wear-part has been used for the
first time?

If it is the latter, you can specify the age of the wear part
at study entry in Surv(). For example, if a wear part has been
used for 5 years before study entry, and dies 2 years after,
the data will look like that:
start stop status
57  1

Hope this helps,
Arthur Allignol


Philipp Rappold wrote:

Dear friends,

I have used R for some time now and have a tricky question about the
coxph-function: To sum it up, I am not sure whether I can use coxph in
conjunction with missing covariate data in a model with time-variant
covariates. The point is: I know how old every piece that I
oberserve is, but do not have fully historical information about the
corresponding covariates. Maybe you have some advice for me, although
this problem might only be 70% R and 30% statistically-related. Here's
a detailled explanation:

SITUATION  OBJECTIVE:
I want to analyze the effect of environmental effects (i.e.
temperature and humidity) on the lifetime of some wear-parts. The
study should be conducted on a yearly basis, meaning that I have
collected empirical data on every wearpart at the end of every year.

DATA:
I have collected the following data:
- Status of the wear-part: Equals 0 if part is still alive, equals
1 if part has died (my event variable)
- Environmental data: Temperature and humidity have been measured at
each of the wear-parts on a yearly basis (because each wear-part is at
a different location, I have different data for each wear-part)

PROBLEM:
I started collecting data between 2001 and 2007. In 2001, a vast
amount of of wearparts has already been in use. I DO KNOW for every
part how long it has been used (even if it was employed before 2001),
but I DO NOT have any information about environmental conditions like
temperature or humidity before 2001 (I call this semi-left-censored).
Of course, one could argue that I should simply exclude these parts
from my analysis, but I don't want to loose valuable information, also
because the amount of new parts that have been employed between 2001
and 2007 is rather small.

Additionally, I cannot make any assumption about the underlying
lifetime distribution. Therefore I have to use a non-parametrical
model for estimation (most likely cox).

QUESTION:

From an econometric perspective, is it possible to use Cox

Proportional Hazard model in this setting? As mentioned before, I have
time-variant covariates for each wearpart, as well as what I call
semi-left-censored data that I want to use. If not, what kind of
analysis would you suggest?

Thanks a lot for your great help, I really appreciate it.

All the best
Philipp

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[R] Bristol mirror GPG problem ubuntu repository

2009-05-05 Thread Daniel Brewer
Hello,

I am getting a GPG error with the ubuntu repository at the bristol UK
mirror.

When my source.list has this line:

deb http://www.stats.bris.ac.uk/R/bin/linux/ubuntu/ intrepid/

On an apt-get update you get this:

W: GPG error: http://www.stats.bris.ac.uk intrepid/ Release: The
following signatures were invalid: BADSIG D67FC6EAE2A11821 Vincent
Goulet vincent.gou...@act.ulaval.ca

Whereas if I use another mirror e.g.:

deb http://cran.cnr.berkeley.edu/bin/linux/ubuntu/ intrepid/

I don't get such an error.

It could be a problem this end but I think it is more likely that
something is going wrong with the GPG signing at bristol.

Dan

-- 
**
Daniel Brewer, Ph.D.

Institute of Cancer Research
Molecular Carcinogenesis
Email: daniel.bre...@icr.ac.uk
**

The Institute of Cancer Research: Royal Cancer Hospital, a charitable Company 
Limited by Guarantee, Registered in England under Company No. 534147 with its 
Registered Office at 123 Old Brompton Road, London SW7 3RP.

This e-mail message is confidential and for use by the a...{{dropped:2}}

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[R] setting trellis auto.key color values

2009-05-05 Thread Steve_Friedman


I'm working with Lattice graphics and I would like very much to color code
the auto.key fill color with the same corresponding colors that I use in
the panels.  I've looked on the web for clues, and on the CRAN-R help sites
searching on trellis auto.key color and variations, unfortunately the
responses there are not very specific.

 Would someone please explain   I have the Book, if you can point me to the
pages that explain this I'd appreciate that too



 graph.sets - list(axis.text = list(cex = 0.65),
  par.ylab.text = list(cex = 1.25),
  par.xlab.text = list(cex = 1.25))


   barchart(gator_IR$MEAN ~ gator_IR$Hydro |
as.factor(gator_IR$IR_ID),layout=c(4,1),col = c(3:5),
 groups=gator_IR$Rain, ylim=c(0,1), par.settings =
graph.sets,
 main = Alligator Nesting Performance, ylab= Mean HSI,
 auto.key = list(top, columns=3, col=c(3:5))


this script creates the graph nicely, with the qualification that the color
for the key titles are the correct, but the filling colors are default
pastels.  Where do I change them ?


Windows XP  with R 2.8.1

Thank you.

Steve

Steve Friedman Ph. D.
Spatial Statistical Analyst
Everglades and Dry Tortugas National Park
950 N Krome Ave (3rd Floor)
Homestead, Florida 33034

steve_fried...@nps.gov
Office (305) 224 - 4282
Fax (305) 224 - 4147

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[R] Plotting pairs of bars

2009-05-05 Thread Steve Murray

Dear all,

I have a matrix called combine86 which looks as follows:

 combine86
 Sim Mean   Obs Mean  Sim Sum Obs Sum
AMAZON  1172.0424  1394.44604  553204  659573
NILE 262.4440   164.23921   67973   41881
CONGO682.8007   722.63971  205523  214624
MISSISSIPPI  363.0758   142.59883  124535   49054
AMUR 143.585789.30434   36040   22594
PARANA   702.3793   388.03030  162952   89635
YENISEI  208.1396   174.52722   83464   70509
OB   197.0399   162.82697   79013   63991
LENA 118.110077.49638   48307   32161
NIGER374.8258   212.25714   66719   37145
ZAMBEZI  500.   485.87610   57000   54904
YANGTZE  358.4172   256.80246   58422   41602


For each of the rivers (which are the row names of this matrix), I wish to plot 
a bar for Simulated Mean and another for the Observed Mean. So far I've only 
been able to get R to stack the bars (using 'barplot) on top of one another, 
which isn't really what I want! I was hoping more for a pairing of bars (one 
'Sim' and one 'Mean') followed by a gap, then the next pair of bars for the 
next river, a gap, and so on. Is this possible to do in R? If so, how?!

Many thanks,

Steve


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[R] Sampling a matrix with different probability distributions

2009-05-05 Thread Silvia Lomascolo

I need to sample a matrix according to different distributions, instead of
just randomly.  Here is some code that will hopefully clarify what I need:

I have a matrix M of 1287 interactions between species in rows and species
in columns, according to their abundance:

pla- c(10, 9, 6, 5, 3) #abundance of pla species
pol- c(14, 10, 9, 4, 2) #abundance of pol species
M-pla%*%t(pol) #matrix of 1287 interactions according to pla and pol
abundance
M
 [,1] [,2] [,3] [,4] [,5]
[1,]  140  100   90   40   20
[2,]  126   90   81   36   18
[3,]   84   60   54   24   12
[4,]   70   50   45   20   10
[5,]   42   30   27   126

Thanks to help from people in this forum, I was able to randomly sample 800
interactions from matrix M and obtain a subset of the interactions in a
smaller matrix called reduced.M:

M.index - 1:length(M)
reduced.M - matrix(table( factor( sample(rep(M.index,M),800),
M.index)),nr=5)
reduced.M

 [,1] [,2] [,3] [,4] [,5]
[1,]   77   62   56   25   15
[2,]   83   53   51   21   11
[3,]   57   34   28   18   10
[4,]   51   31   21   144
[5,]   27   21   1965

Now I need to sample again, not randomly, but according to different
distributions.  For example, I need to sample according to the abundance of
species pla, (pla vector written above).  The result should be that I sample
my first row more intensely than my second row, and the last row should be
the least intensely sampled, in proportion to my row species abundance. In
the same token, I want to sample with a uniform distribution as well.  How
do I do this? 

Thanks, as usual! Silvia.
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Re: [R] levelplot question

2009-05-05 Thread Greg Snow
The function that is doing the color assignments is level.colors in the lattice 
package.  Looking at the code confirms that the number of colors should be 1 
less than the length of the at variable (the documentation implies that it 
should be 1 more, looks like a documentation bug to me).

It is possible that at one time the author intended to prepend -Inf and append 
Inf to the at vector so that it did not need to span the entire range of the 
data, but that was not implemented.  I think I would prefer that fix to 
changing the documentation.

The level.colors function uses the cut function to decide on which color to 
use, by default cut will put a value that matches a cutpoint in the group to 
the left, so to answer you original question 3.5 goes into the (2.5,3.5] range 
rather than the (3.5,4.5] group.  level.colors does not allow for changing this 
(hard coded), so if you want the other behaiviour, you either need to rewrite 
level.colors, or add a very small number to your data to shift 3.5 and the like 
into the right bin.

Hope this helps,

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: Antje [mailto:niederlein-rs...@yahoo.de]
 Sent: Tuesday, May 05, 2009 1:00 AM
 To: Greg Snow; r-h...@stat.math.ethz.ch
 Subject: Re: [R] levelplot question
 
 Hi Greg and all the others,
 
 thanks for your answer. The color-vector has the same length like the
 at-vector
 but the recycling cannot be the reason, because only values slightly
 above my
 threshold doe not appear blue.
 I cannot find a good explanation of which colors are assigned to which
 value
 ranges.
 
 I've made little example:
 
 #
 mat - matrix(seq(1,5, length.out = 12), nrow = 3)
 mat[1,2] - 3.5
 
 my.at - seq(0.5,5.5)
 my.col.regions - rainbow(6)
 
 graph - levelplot(t(mat[nrow(mat):1, ] ), at = my.at, col.regions =
 my.col.regions)
 print(graph)
 
 windows()
 plot(1:10)
 legend(topleft, legend = as.character(my.col.regions), col =
 my.col.regions,
 pch = 18)
 #
 
 As you can see the green (position 3 in my.col.regions) disappears
 completely
 in the levelplot (look at the color range at the right side!).
 I guess it might also happen in my case...
 
 I've tested several cases and it looks like the length of the color-
 vector
 should be one less than the at vector (which would make sense).
 
 Then, the rule might apply:
 
 [ at[1],at[2] ] = color[1]
 ( at[2],at[3] ] = color[2]
 ...
 ( at[n-1],at[n] ] = color[n-1]
 
 
 Please correct me if I'm wrong!!!
 
 Antje

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Re: [R] setting trellis auto.key color values

2009-05-05 Thread Sundar Dorai-Raj
Set the colors in graph.sets and not auto.key.

graph.sets - list(axis.text = list(cex = 0.65),
  par.ylab.text = list(cex = 1.25),
  par.xlab.text = list(cex = 1.25),
  superpose.polygon = list(col = 3:5))

Then remove the col = 3:5 from auto.key and barchart.

Also, you can simplify your code by removing gator_IR$ and including
data = gator_IR. I.e.

 barchart(MEAN ~ Hydro | as.factor(IR_ID),
 data = gator_IR, layout = c(4, 1),
 groups = Rain, ylim = c(0, 1), ...)

HTH,

--sundar

On Tue, May 5, 2009 at 8:32 AM,  steve_fried...@nps.gov wrote:


 I'm working with Lattice graphics and I would like very much to color code
 the auto.key fill color with the same corresponding colors that I use in
 the panels.  I've looked on the web for clues, and on the CRAN-R help sites
 searching on trellis auto.key color and variations, unfortunately the
 responses there are not very specific.

  Would someone please explain   I have the Book, if you can point me to the
 pages that explain this I'd appreciate that too



 graph.sets - list(axis.text = list(cex = 0.65),
              par.ylab.text = list(cex = 1.25),
              par.xlab.text = list(cex = 1.25))


   barchart(gator_IR$MEAN ~ gator_IR$Hydro |
 as.factor(gator_IR$IR_ID),layout=c(4,1),col = c(3:5),
                 groups=gator_IR$Rain, ylim=c(0,1), par.settings =
 graph.sets,
                 main = Alligator Nesting Performance, ylab= Mean HSI,
                 auto.key = list(top, columns=3, col=c(3:5))


 this script creates the graph nicely, with the qualification that the color
 for the key titles are the correct, but the filling colors are default
 pastels.  Where do I change them ?


 Windows XP  with R 2.8.1

 Thank you.

 Steve

 Steve Friedman Ph. D.
 Spatial Statistical Analyst
 Everglades and Dry Tortugas National Park
 950 N Krome Ave (3rd Floor)
 Homestead, Florida 33034

 steve_fried...@nps.gov
 Office (305) 224 - 4282
 Fax     (305) 224 - 4147

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Re: [R] Create Pie chart from .csv file

2009-05-05 Thread Thomas Roth (geb. Kaliwe)

Sorry for mailing to you personally...

for types

read.csv(file.choose())
freqTable = table(types)
pie(freqTable)


##example for some data
temp = data.frame(types = 1:10)
pie(table(temp))

Thomas Roth

PS: use barplot instead of pie

DonkeyRhubarb schrieb:

Hi all,

I am looking to create a pie chart from a given column in a .csv file. 


My class variables are as follows:

entry_type, uniquekey,  types, title,url, abstract, journal, 
author, month,
year, howpublished

So say I want to export a pie chart that groups together all  entries under
'types' e.g. 3 x statistics 2x education etc. Im looking to have a piechart
represent this graphically that shows which type of entry is in most
frequently. Preferably I'd like to export to a PDF chart and while I can do
this by typing variables directly into the R console, I cannot manage it
from a .csv file.

If you cannot help me with this specific problem, just knowing how to create
a generic pie chart would be a great help.

This is part of my final software project which is due in one week. I would
very much appreciate any help.

Many thanks in advance




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Re: [R] Heatmap without levelplot

2009-05-05 Thread Greg Snow
The image function in base graphics does the same type of plot, just different 
names and structure of the data (and the documentation says that the number of 
breaks should be 1 more than the number of colors).

Hope this helps,

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Antje
 Sent: Tuesday, May 05, 2009 1:12 AM
 To: r-h...@stat.math.ethz.ch
 Subject: [R] Heatmap without levelplot
 
 Hi there,
 
 as I'm not sure to understand the coloring levelplot uses, I'm looking
 for
 another easy way to create a heatmap like this:
 
 library(lattice)
 mat - matrix(seq(1,5, length.out = 12), nrow = 3)
 mat[1,2] - 3.5
 
 my.at - seq(0.5,5.5, length.out = 6)
 my.col.regions - rainbow(5)
 
 graph - levelplot(t(mat[nrow(mat):1, ] ), at = my.at, col.regions =
 my.col.regions)
 print(graph)
 
 Can anybody help me with some hints or little examples?
 
 Antje
 
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[R] how to modify a function in a R package calling other (invisible?) functions

2009-05-05 Thread Krusty the Klown

Hey hey kids! I'm facing this rough problem: I have to modify a function in a
R package (namely, homals) but I'm not able to do it from the R interface,
since this function recalls other functions which looks like invisible... I
downloaded the source package from CRAN,
http://cran.r-project.org/src/contrib/homals_0.9-10.tar.gz
http://cran.r-project.org/src/contrib/homals_0.9-10.tar.gz 
how can I work it out?
Yours, KtK:-D
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[R] A question about using “by” in GAM model fitting of interaction between smooth terms and factor

2009-05-05 Thread willow1980

I am a little bit confusing about the following help message on how to fit a
GAM model with interaction between factor and smooth terms from
http://rss.acs.unt.edu/Rdoc/library/mgcv/html/gam.models.html:
“Sometimes models of the form: 
E(y)=b0+f(x)z
need to be estimated (where f is a smooth function, as usual.) The
appropriate formula is:
y~z+s(x,by=z)
- the by argument ensures that the smooth function gets multiplied by
covariate z, but GAM smooths are centred (average value zero), so the z+
term is needed as well (f is being represented by a constant plus a centred
smooth). If we'd wanted: 
E(y)=f(x)z
then the appropriate formula would be: y~z+s(x,by=z)-1.”
When I tried two scripts, I found they gave the same results. That is, the
codes “y~z+s(x,by=z)” and “y~z+s(x,by=z)-1” gave the same results. The
following is my result:
###
“anova(model1,model2,test=Chisq)
Analysis of Deviance Table

Model 1: FLBS ~ SES + s(FAFR, by = SES) + s(byear, by = SES) + s(FAFR,
byear, by = SES)
Model 2: FLBS ~ SES + s(FAFR, by = SES) + s(byear, by = SES) + s(FAFR,
byear, by = SES) - 1
   Resid. Df Resid. Dev Df  Deviance P(|Chi|)
1 1.2076e+03 1458.4   
2 1.2076e+03 1458.4 1.9099e-11 5.030e-10 2.074e-10”
###
Is this in conflict with above statement that “If we'd wanted: E(y)=f(x)z
then the appropriate formula would be: y~z+s(x,by=z)-1.”? Also, if you are
familiar with GAM modelling, please have a look at my modelling process.
That is, I want to study how one factor together with two smooth terms will
influence the response. In model2, I also fitted the interaction between two
smooth terms, together with the interaction of this interaction with factor.
Is model 2 reasonable? I find it is rather complicated to interpret the plot
of model 2.
Thank you very much for helping!

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and provide commented, minimal, self-contained, reproducible code.


Re: [R] Stepwise logistic regression with significance testing - stepAIC

2009-05-05 Thread Greg Snow
There is not a meaningful alternative way since the way you propose is not 
meaningful.  The Wald tests have some know problems even in the well defined 
cases.  Both types of tests are designed to test a predefined hypothesis, not a 
conditional hypothesis on the stepwise procedure.  It is best to use other 
approaches than stepwise selection (it has been shown to give biased results) 
such as the lasso.  If you need to use stepwise, then you should bootstrap the 
entire selection process to get better estimates/standard errors.  

Frank Harrell's book and package go into more detail on this and provide some 
tools to help (as well as the other packages that can be used).

Hope this helps,

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Peter-Heinz Fox
 Sent: Tuesday, May 05, 2009 8:02 AM
 To: r-help@r-project.org
 Subject: [R] Stepwise logistic regression with significance testing -
 stepAIC
 
 Hello R-Users,
 
 I have one binary dependent variable and a set of independent variables
 (glm(formula,…,family=”binomial”) ) and I am using the function stepAIC
 (“MASS”) for choosing an optimal model. However I am not sure if
 stepAIC considers significance properties like Likelihood ratio test
 and Wald test (see example below).
 
  y - rbinom(30,1,0.4)
  x1 - rnorm(30)
  x2 - rnorm(30)
  x3 - rnorm(30)
  xdata - data.frame(x1,x2,x3)
 
  fit1 - glm(y~ . ,family=binomial,data=xdata)
  stepAIC(fit1,trace=FALSE)
 
 Call:  glm(formula = y ~ x3, family = binomial, data = xdata)
 
 Coefficients:
 (Intercept)   x3
     -0.3556   0.8404
 
 Degrees of Freedom: 29 Total (i.e. Null);  28 Residual
 Null Deviance:  40.38
 Residual Deviance: 37.86    AIC: 41.86
 
  fit - glm( stepAIC(fit1,trace=FALSE)$formula  ,family=binomial)
  my.summ - summary(fit)
  # Wald Test
  print(my.summ$coeff[,4])
 (Intercept)  x3
   0.3609638   0.1395215
 
  my.anova - anova(fit,test=Chisq)
  #LR Test
  print(my.anova$P[2])
 [1] 0.1121783
 
 
 Is there an alternative function or a possible way of checking if the
 added variable and the new model are significant within the regression
 steps?
 
 Thanks in advance for your help
 
 Regards
 
 Peter-Heinz Fox
 
 
 
 
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[R] Re : Re : Support Vector Machines

2009-05-05 Thread justin bem
Of course SVM is for supervise learning method (classification or regression). 
You cannot use a boat to fly man !
 
Justin BEM
BP 1917 Yaoundé
Tél (237) 99597295
(237) 22040246 







Envoyé le : Mardi, 5 Mai 2009, 16h07mn 10s
Objet : Re : [R] Support Vector Machines


Thank you.

I will look this later but I think i've saw this function and i'm not sure that 
we can make density estimation with this but only classification.


 :


Objet: Re : [R] Support Vector Machines

Cc: R Maillist r-h...@stat.math.ethz.ch
Date: Mardi 5 Mai 2009, 16h43


there is a SVM function in svmpath by Trevor Hastie. Before use it take time to 
read this 

http://www-stat.stanford.edu/~hastie/Papers/svmpath.pdf

If you install then svmpath library ! run the attach source file.


Justin BEM
BP 1917 Yaoundé
Tél (237) 99597295
(237) 22040246 






À : r-help@r-project.org
Envoyé le : Mardi, 5 Mai 2009, 8h49mn 49s
Objet : Re: [R] Support Vector Machines


In the R-help of the svm function of the package e1071 it's explained that
this function also makes estimation of density.

But when i made for example
X-rnorm(1000)
m-svm(X)

I just have a binary classification of X like SVM do whereas i want an
estimation of the density which generates our sample X ...

I don't know if it's possible and if someone has already use this function
to do that.

Thanks.


David Winsemius wrote:
 
 
 On May 4, 2009, at 8:52 AM, excalibur wrote:
 

 This question is still unanswered.
 
 Unanswered questions are often those which do not comply with the  
 guidelines in the Posting Guide. Many people have gotten tired of  
 either making up examples or of writing  Read the Posting Guide, so  
 they just ignore them.
 
 
 Someone can explain me how use the svm function to make density  
 estimation ?
 
 If you post an executable bit of code that shows how you are doing  
 those operations, then I suspect someone will answer.
 
 excalibur wrote:


 Hi,
 i try to use function svm of package e1071 to estimate a density.

 But if my data are X=(X1,...,Xn) and m-svm(X) some values of m$SV 
 are
 less than 0.
 I don't see how i can get the estimation of the density with this
 function.

 Thanks for your help.

 Rémi

 
 David Winsemius, MD
 Heritage Laboratories
 West Hartford, CT
 
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[R] method for calculating grey level occurrence matrices (GLCM) with R

2009-05-05 Thread Hans-Joachim Klemmt

hello,

does anybody know a method for calculating grey-level co-occurrence 
matrices (GLCM) for RGB-pictures with R?
(unfortunately i haven't found a solution for this problem neither via 
(scholar)google nor via r-project helplist)


thank you very much!

best regards

Hans-Joachim Klemmt

--
--

Dr. Hans-Joachim Klemmt

Forstoberrat
Organisationsprogrammierer IHK


Bayerische Landesanstalt für Wald und Forstwirtschaft

zugewiesen an

Lehrstuhl für Waldwachstumskunde
Technische Universität München
Am Hochanger 13

85354 Freising

Tel.: 08161/ 7147-14
Fax : 08161/ 7147-21

eMail: h-j.kle...@lrz.tum.de

Skype: hajo_klemmt

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Re: [R] smoothing spline in package gam

2009-05-05 Thread willow1980

Strangely, summary.gam(m1) should give you significance results of parametric
terms such as ost, wst, park10, sch50, comm, build and suite. These results
should be located above the summary results for smooth terms.
Please using summary.gam(m1) to have a look if there is the information you
need.
Good luck!


楊 詩韻 wrote:
 
 
 dear all,
 
  
 
 i have a little question, but it make me torment long time
 
  
 
 hope you can help me and give some advices , thanks
 
  
 
  
 
 i use smoothing spline in package gam
 
  
 
 the model
 
  
 
 m1=gam(y~ost+wst+park10+sch50+comm+build+suite+y05+y06+y07+y99+y98+s(builarea)+s(age)+s(fl)+s(totfl)+s(cbd)+s(redl))
 
 
 and summary(m1) can show the s(smoothing) variables' Signif. codes.
 
  
 
 but i also want to know the Parametric coefficients and their Signif.
 codes. like ost, wst...etc.
 
  
 
 is that possible to get the Parametric coefficients'  Signif. codes  (in
 package gam) ?
 
  
 
  
 
 thanks~~
 
  
 
  
 
  
 
  
 
  
 
  
 
 _
 
 
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Re: [R] Stepwise logistic regression with significance testing - stepAIC

2009-05-05 Thread Dimitris Rizopoulos

Greg Snow wrote:
There is not a meaningful alternative way since the way you propose is not meaningful.  The Wald tests have some know problems even in the well defined cases.  Both types of tests are designed to test a predefined hypothesis, not a conditional hypothesis on the stepwise procedure.  It is best to use other approaches than stepwise selection (it has been shown to give biased results) such as the lasso.  If you need to use stepwise, then you should bootstrap the entire selection process to get better estimates/standard errors.  


For bootstrapping the stepAIC procedure you may have a look at package 
bootStepAIC.


Best,
Dimitris



Frank Harrell's book and package go into more detail on this and provide some 
tools to help (as well as the other packages that can be used).

Hope this helps,



--
Dimitris Rizopoulos
Assistant Professor
Department of Biostatistics
Erasmus University Medical Center

Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands
Tel: +31/(0)10/7043478
Fax: +31/(0)10/7043014

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Re: [R] Plotting pairs of bars

2009-05-05 Thread Greg Snow
Look at the beside argument to the barplot function.

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Steve Murray
 Sent: Tuesday, May 05, 2009 9:52 AM
 To: r-help@r-project.org
 Subject: [R] Plotting pairs of bars
 
 
 Dear all,
 
 I have a matrix called combine86 which looks as follows:
 
  combine86
  Sim Mean   Obs Mean  Sim Sum Obs Sum
 AMAZON  1172.0424  1394.44604  553204  659573
 NILE 262.4440   164.23921   67973   41881
 CONGO682.8007   722.63971  205523  214624
 MISSISSIPPI  363.0758   142.59883  124535   49054
 AMUR 143.585789.30434   36040   22594
 PARANA   702.3793   388.03030  162952   89635
 YENISEI  208.1396   174.52722   83464   70509
 OB   197.0399   162.82697   79013   63991
 LENA 118.110077.49638   48307   32161
 NIGER374.8258   212.25714   66719   37145
 ZAMBEZI  500.   485.87610   57000   54904
 YANGTZE  358.4172   256.80246   58422   41602
 
 
 For each of the rivers (which are the row names of this matrix), I wish
 to plot a bar for Simulated Mean and another for the Observed Mean. So
 far I've only been able to get R to stack the bars (using 'barplot) on
 top of one another, which isn't really what I want! I was hoping more
 for a pairing of bars (one 'Sim' and one 'Mean') followed by a gap,
 then the next pair of bars for the next river, a gap, and so on. Is
 this possible to do in R? If so, how?!
 
 Many thanks,
 
 Steve
 
 
 _
 [[elided Hotmail spam]]
 
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Re: [R] setting trellis auto.key color values

2009-05-05 Thread Steve_Friedman
Sundar,

Thanks for the assistance.

Much appreciated.

Steve



Steve Friedman Ph. D.
Spatial Statistical Analyst
Everglades and Dry Tortugas National Park
950 N Krome Ave (3rd Floor)
Homestead, Florida 33034

steve_fried...@nps.gov
Office (305) 224 - 4282
Fax (305) 224 - 4147


   
 Sundar Dorai-Raj  
 sdorai...@gmail. 
 com   To 
   steve_fried...@nps.gov  
 05/05/2009 09:08   cc 
 AM MSTr-help@r-project.org
   Subject 
   Re: [R] setting trellis auto.key
   color values
   
   
   
   
   
   




Set the colors in graph.sets and not auto.key.

graph.sets - list(axis.text = list(cex = 0.65),
  par.ylab.text = list(cex = 1.25),
  par.xlab.text = list(cex = 1.25),
  superpose.polygon = list(col = 3:5))

Then remove the col = 3:5 from auto.key and barchart.

Also, you can simplify your code by removing gator_IR$ and including
data = gator_IR. I.e.

 barchart(MEAN ~ Hydro | as.factor(IR_ID),
 data = gator_IR, layout = c(4, 1),
 groups = Rain, ylim = c(0, 1), ...)

HTH,

--sundar

On Tue, May 5, 2009 at 8:32 AM,  steve_fried...@nps.gov wrote:


 I'm working with Lattice graphics and I would like very much to color
code
 the auto.key fill color with the same corresponding colors that I use in
 the panels.  I've looked on the web for clues, and on the CRAN-R help
sites
 searching on trellis auto.key color and variations, unfortunately the
 responses there are not very specific.

  Would someone please explain   I have the Book, if you can point me to
the
 pages that explain this I'd appreciate that too



 graph.sets - list(axis.text = list(cex = 0.65),
              par.ylab.text = list(cex = 1.25),
              par.xlab.text = list(cex = 1.25))


   barchart(gator_IR$MEAN ~ gator_IR$Hydro |
 as.factor(gator_IR$IR_ID),layout=c(4,1),col = c(3:5),
                 groups=gator_IR$Rain, ylim=c(0,1), par.settings =
 graph.sets,
                 main = Alligator Nesting Performance, ylab= Mean HSI,
                 auto.key = list(top, columns=3, col=c(3:5))


 this script creates the graph nicely, with the qualification that the
color
 for the key titles are the correct, but the filling colors are default
 pastels.  Where do I change them ?


 Windows XP  with R 2.8.1

 Thank you.

 Steve

 Steve Friedman Ph. D.
 Spatial Statistical Analyst
 Everglades and Dry Tortugas National Park
 950 N Krome Ave (3rd Floor)
 Homestead, Florida 33034

 steve_fried...@nps.gov
 Office (305) 224 - 4282
 Fax     (305) 224 - 4147

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Re: [R] Hierarchical Diagram of Networks in sna or otherwise?

2009-05-05 Thread jebyrnes

No worries.  I've actually switched to using Rgraphviz from bioconductor, and
the results are pretty great (after the initial head-pounding to get it
setup).


Gábor Csárdi-2 wrote:
 
 On Mon, May 4, 2009 at 8:31 PM, jebyrnes byr...@msi.ucsb.edu wrote:

 Nearly.  The algorithm turns up slightly different graphs each time (and
 set.seed doesn't seem to make it consistent)
 
 Hmmm, that should not happen, I'll check it out.
 
 and periodically chokes.
 
 Can you send me the graph for which this happens?
 
 But
 better than what I had.  Hrm.  I don't know much about the algorithm
 graphviz uses for dot.  Do you have a reference on hand?
 
 No, I don't. Have you checked the graphviz homepage?
 
 If it's simple,
 I'd be willing to take a whack at it.
 
 I doubt that it is simple, but I think it would be very useful to have
 a free implementation. (I would have already ported the graphviz
 layout algorithms to igraph, but their licenses are not compatible.)
 
 Best,
 Gabor
 

 Gábor Csárdi-2 wrote:

 Jarrett,

 the 'igraph' package has a layout called layout.reingold.tilford that
 is designed for trees, there is a slight chance that it is good enough
 for you.

 Best,
 Gabor

 On Wed, Apr 29, 2009 at 10:11 PM, jebyrnes byr...@msi.ucsb.edu wrote:

 I've been using sna to work with some networks, and am trying to
 visualize
 them easily.  My networks are hierarchical (food webs).  All of the
 layout
 engines I've tried with gplot don't seem to plot hierarchical networks,
 as
 one would using dot from graphviz.  While I could do all of this by
 outputting to dotfiles and running it through graphviz, the graphics I
 get
 from R are much cleaner, and more easily integrated into my analyses.

 Is there any good way to diagram a hierarchical network in R, either
 with
 the sna library or otherwise?  It strikes me that at least the
 Netindices
 package can calculate trophic levels.  Could this be used for node
 placement?


 -Jarrett
 --
 View this message in context:
 http://www.nabble.com/Hierarchical-Diagram-of-Networks-in-sna-or-otherwise--tp23301819p23301819.html
 Sent from the R help mailing list archive at Nabble.com.

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 --
 Gabor Csardi gabor.csa...@unil.ch     UNIL DGM

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 --
 View this message in context:
 http://www.nabble.com/Hierarchical-Diagram-of-Networks-in-sna-or-otherwise--tp23301819p23374024.html
 Sent from the R help mailing list archive at Nabble.com.

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 -- 
 Gabor Csardi gabor.csa...@unil.ch UNIL DGM
 
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Re: [R] Sampling a matrix with different probability distributions

2009-05-05 Thread Greg Snow
The sample function has a prob argument that can be used to sample with unequal 
probabilities.  It sounds like you can just pass in the species abundance 
vector to prob and it will do what you want.

-- 
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111


 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Silvia Lomascolo
 Sent: Tuesday, May 05, 2009 9:52 AM
 To: r-help@r-project.org
 Subject: [R] Sampling a matrix with different probability distributions
 
 
 I need to sample a matrix according to different distributions, instead
 of
 just randomly.  Here is some code that will hopefully clarify what I
 need:
 
 I have a matrix M of 1287 interactions between species in rows and
 species
 in columns, according to their abundance:
 
 pla- c(10, 9, 6, 5, 3) #abundance of pla species
 pol- c(14, 10, 9, 4, 2) #abundance of pol species
 M-pla%*%t(pol) #matrix of 1287 interactions according to pla and pol
 abundance
 M
  [,1] [,2] [,3] [,4] [,5]
 [1,]  140  100   90   40   20
 [2,]  126   90   81   36   18
 [3,]   84   60   54   24   12
 [4,]   70   50   45   20   10
 [5,]   42   30   27   126
 
 Thanks to help from people in this forum, I was able to randomly sample
 800
 interactions from matrix M and obtain a subset of the interactions in a
 smaller matrix called reduced.M:
 
 M.index - 1:length(M)
 reduced.M - matrix(table( factor( sample(rep(M.index,M),800),
 M.index)),nr=5)
 reduced.M
 
  [,1] [,2] [,3] [,4] [,5]
 [1,]   77   62   56   25   15
 [2,]   83   53   51   21   11
 [3,]   57   34   28   18   10
 [4,]   51   31   21   144
 [5,]   27   21   1965
 
 Now I need to sample again, not randomly, but according to different
 distributions.  For example, I need to sample according to the
 abundance of
 species pla, (pla vector written above).  The result should be that I
 sample
 my first row more intensely than my second row, and the last row should
 be
 the least intensely sampled, in proportion to my row species abundance.
 In
 the same token, I want to sample with a uniform distribution as well.
 How
 do I do this?
 
 Thanks, as usual! Silvia.
 --
 View this message in context: http://www.nabble.com/Sampling-a-matrix-
 with-different-probability-distributions-tp23390324p23390324.html
 Sent from the R help mailing list archive at Nabble.com.
 
 __
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[R] quick square root axes

2009-05-05 Thread Markus Loecher
Dear R users,
while I enjoy the built-in log argument to the plot() function, I wished it
would be as easy to create more general custom transformed axes such as
sqrt(), logit, etc...

for example, instead of
 plot(x=exp(rnorm(10)), y=(1:10)^4, log = xy), sth. along the lines of
 plot(x=exp(rnorm(10)), y=(1:10)^4, trans = list(x = log, y = sqrt))
to encode the desired transfomation.

This involves just transforming the xy values and creating nice tick marks
at the appropriate positions.
Before trying to write my own function, I wanted to see if that
functionality already exists in another package ?

Thanks!

Markus
.

[[alternative HTML version deleted]]

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[R] big databases

2009-05-05 Thread Pseudo Phobic
Dear all,

I have a .dta database which is about 400 MB. I cannot open it though I have
no problem to import smaller ones (80 MB or even 174 MB).

I tried to modify some options with --max-mem-size=2047M --max-vsize=2047M.
But it does not seem to be enough.

I do not know the exact meaning of these options : vsize seems to be made
for vectors.

I have got Monte Carlo simulations running in another R window. Can MCMC
simulations take enough memory so as to prevent me from opening this
database ?

Thank you very much for any help.

Best Regards

[[alternative HTML version deleted]]

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Re: [R] Sampling a matrix with different probability distributions

2009-05-05 Thread Silvia Lomascolo



Greg Snow-2 wrote:
 
 The sample function has a prob argument that can be used to sample with
 unequal probabilities.  It sounds like you can just pass in the species
 abundance vector to prob and it will do what you want.
 
 It might be that my question is even more basic than it sounds:  I have
 tried what you say, but I may just be writing it wrong as I get an error
 message.  I wrote:
 
 reduced.M - matrix(table( factor( sample(rep(M.index,M),800), M.index
 prob=pla)),nr=5)
 
 but I get and error message saying that the prob argument is unused.  I
 have also tried prob=unif, or directly prob=c(10, 9, 6, 5, 3), but I get
 the same error message. Any hints as to how I am passing the prob argument
 wrong? This is probably too basic...
 
 Thanks, Silvia.
 -- 
 Gregory (Greg) L. Snow Ph.D.
 Statistical Data Center
 Intermountain Healthcare
 greg.s...@imail.org
 801.408.8111
 
 
 -Original Message-
 From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
 project.org] On Behalf Of Silvia Lomascolo
 Sent: Tuesday, May 05, 2009 9:52 AM
 To: r-help@r-project.org
 Subject: [R] Sampling a matrix with different probability distributions
 
 
 I need to sample a matrix according to different distributions, instead
 of
 just randomly.  Here is some code that will hopefully clarify what I
 need:
 
 I have a matrix M of 1287 interactions between species in rows and
 species
 in columns, according to their abundance:
 
 pla- c(10, 9, 6, 5, 3) #abundance of pla species
 pol- c(14, 10, 9, 4, 2) #abundance of pol species
 M-pla%*%t(pol) #matrix of 1287 interactions according to pla and pol
 abundance
 M
  [,1] [,2] [,3] [,4] [,5]
 [1,]  140  100   90   40   20
 [2,]  126   90   81   36   18
 [3,]   84   60   54   24   12
 [4,]   70   50   45   20   10
 [5,]   42   30   27   126
 
 Thanks to help from people in this forum, I was able to randomly sample
 800
 interactions from matrix M and obtain a subset of the interactions in a
 smaller matrix called reduced.M:
 
 M.index - 1:length(M)
 reduced.M - matrix(table( factor( sample(rep(M.index,M),800),
 M.index)),nr=5)
 reduced.M
 
  [,1] [,2] [,3] [,4] [,5]
 [1,]   77   62   56   25   15
 [2,]   83   53   51   21   11
 [3,]   57   34   28   18   10
 [4,]   51   31   21   144
 [5,]   27   21   1965
 
 Now I need to sample again, not randomly, but according to different
 distributions.  For example, I need to sample according to the
 abundance of
 species pla, (pla vector written above).  The result should be that I
 sample
 my first row more intensely than my second row, and the last row should
 be
 the least intensely sampled, in proportion to my row species abundance.
 In
 the same token, I want to sample with a uniform distribution as well.
 How
 do I do this?
 
 Thanks, as usual! Silvia.
 --
 View this message in context: http://www.nabble.com/Sampling-a-matrix-
 with-different-probability-distributions-tp23390324p23390324.html
 Sent from the R help mailing list archive at Nabble.com.
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide http://www.R-project.org/posting-
 guide.html
 and provide commented, minimal, self-contained, reproducible code.
 
 __
 R-help@r-project.org mailing list
 https://stat.ethz.ch/mailman/listinfo/r-help
 PLEASE do read the posting guide
 http://www.R-project.org/posting-guide.html
 and provide commented, minimal, self-contained, reproducible code.
 
 

-- 
View this message in context: 
http://www.nabble.com/Sampling-a-matrix-with-different-probability-distributions-tp23390324p23392352.html
Sent from the R help mailing list archive at Nabble.com.

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Re: [R] quick square root axes

2009-05-05 Thread Duncan Murdoch

On 5/5/2009 1:05 PM, Markus Loecher wrote:

Dear R users,
while I enjoy the built-in log argument to the plot() function, I wished it
would be as easy to create more general custom transformed axes such as
sqrt(), logit, etc...

for example, instead of
 plot(x=exp(rnorm(10)), y=(1:10)^4, log = xy), sth. along the lines of
 plot(x=exp(rnorm(10)), y=(1:10)^4, trans = list(x = log, y = sqrt))
to encode the desired transfomation.

This involves just transforming the xy values and creating nice tick marks
at the appropriate positions.
Before trying to write my own function, I wanted to see if that
functionality already exists in another package ?


I don't know of such a thing, but it may well exist.

If you do write your own, the hardest part will be picking the nice tick 
marks.  They should be approximately evenly spaced, but at nice round 
values of the original variable:  that's hard to do in general.  R has 
the pretty() function for the linear scale, and doesn't do too badly on 
log axes, but you'll need to work out your own rules for the sqrt or 
other scales.


Duncan Murdoch

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Re: [R] Heatmap without levelplot

2009-05-05 Thread Uwe Ligges



Antje wrote:

Hi Uwe,

I tried to explain my problem with the given example.
I don't see any documentation which tells me that the length of 
col.regions should be one less than at. (At least I assume now that 
it should be this way...)
If it's equal or longer some colors (in the middle of the color-vector) 
are simply not used.
Just try the example below with rainbow(5) and rainbow(6) and compare 
the results... both plot will use 5 colors!
Sorry, but this behaviour is not really self-explaining to me... maybe 
I'm to blind to find the documentation which says that only one color 
less will ensure the usage of all colors.


Well, of you have 5 at locations (i.e. breaks), then you have 4 
intervals in between and that's the amount of colors that is sensible.



(It is so important for me because I need to display a heatmap with 
colors let's say

* all lower data outliers green,
* all higher data outliers blue and
* everything else within the color range yellow to red.
I've seen that some values do not get blue or green though they are 
outliers...

I've attached one graph, I've generated - maybe it helps to understand)

Any wrong assumption?


Maybe:

Say you want everything below -1 be considered as a lower outlier and 
all above 1 is a higher outlier, then you can say:



levelplot(matrix(c(1,2,0,-2), nrow=2),
at = c(-Inf, seq(-1, 1, length=10), Inf),
col.regions = c(rgb(0,1,0),
 hcl(seq(20, 80, length=10), c=400),
 rgb(0,0,1)))

Then below -1 is green (rgb(0,1,0)), above 1 is blue (rgb(0,0,1)) and in 
between we have 10 regions from -1 to 1 each with a color between some 
kind of yellow and red in hcl() space.



Uwe Ligges





Ciao,
Antje


Uwe Ligges schrieb:



Antje wrote:

Hi there,

as I'm not sure to understand the coloring levelplot uses, I'm 
looking for another easy way to create a heatmap like this:


library(lattice)
mat - matrix(seq(1,5, length.out = 12), nrow = 3)
mat[1,2] - 3.5

my.at - seq(0.5,5.5, length.out = 6)
my.col.regions - rainbow(5)

graph - levelplot(t(mat[nrow(mat):1, ] ), at = my.at, col.regions = 
my.col.regions)

print(graph)

Can anybody help me with some hints or little examples?



Dear Antje,

since you are asking the same question again now, maybe you can 
explain what you are going to get? In fact, I do not undertsand where 
your problem is. R places the colors according to the values in your 
matrix very well including the legend and I thought up to today that 
the plot is self explaining.


Best wishes,
Uwe Ligges





Antje

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Re: [R] quick square root axes

2009-05-05 Thread baptiste auguie


On 5 May 2009, at 19:28, Duncan Murdoch wrote:


On 5/5/2009 1:05 PM, Markus Loecher wrote:

Dear R users,
while I enjoy the built-in log argument to the plot() function, I  
wished it
would be as easy to create more general custom transformed axes  
such as

sqrt(), logit, etc...

for example, instead of
plot(x=exp(rnorm(10)), y=(1:10)^4, log = xy), sth. along the  
lines of

plot(x=exp(rnorm(10)), y=(1:10)^4, trans = list(x = log, y = sqrt))
to encode the desired transfomation.

This involves just transforming the xy values and creating nice  
tick marks

at the appropriate positions.
Before trying to write my own function, I wanted to see if that
functionality already exists in another package ?





Have you tried ggplot2? I think Hadley has given a lot of thinking on  
this sort of issues.


http://had.co.nz/ggplot2/
http://had.co.nz/ggplot2/coord_trans.html

baptiste




I don't know of such a thing, but it may well exist.

If you do write your own, the hardest part will be picking the nice  
tick

marks.  They should be approximately evenly spaced, but at nice round
values of the original variable:  that's hard to do in general.  R has
the pretty() function for the linear scale, and doesn't do too badly  
on

log axes, but you'll need to work out your own rules for the sqrt or
other scales.

Duncan Murdoch

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_

Baptiste Auguié

School of Physics
University of Exeter
Stocker Road,
Exeter, Devon,
EX4 4QL, UK

Phone: +44 1392 264187

http://newton.ex.ac.uk/research/emag

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Re: [R] quick square root axes

2009-05-05 Thread hadley wickham
 If you do write your own, the hardest part will be picking the nice tick
 marks.  They should be approximately evenly spaced, but at nice round values
 of the original variable:  that's hard to do in general.  R has the pretty()
 function for the linear scale, and doesn't do too badly on log axes, but
 you'll need to work out your own rules for the sqrt or other scales.

This seems like a nice (if smallish) research problem...

Hadley


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[R] documenting quirky behavior of as.POSIXct, as.POSIX.lt regarding AM/PM, possibly other cases

2009-05-05 Thread Galkowski, Jan
 
I wanted to put this on the R Wiki, but found the suitable pages were 
read-only.  I wanted to get it out in public to save people work.

I was converting dates like 2009/03/26 01:00:00 AM using as.POSIXct.  I found 
that using a format of %Y/%m/%d %I:%M:%S %p did not work correctly to 
distinguish AM from PM.  Both were converted into the same timestamp.  Indeed, 
what I found worked was affixing a space after the string timestamp to produce 
2009/03/26 01:00:00 AM  or 2009/03/26 01:00:00 PM .  That works.

Didn't see this documented in the associated pages anywhere. 

I wonder if the help system might benefit from user comments like for instance 
PHP has?

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Re: [R] Error building package: LaTeX error when creating PDF version

2009-05-05 Thread Patrick Perry

I recently came across the same problem reported here:

http://tolstoy.newcastle.edu.au/R/e6/help/09/04/12383.html

The fix was to edit $R_HOME/etc/Renviron and change

R_PDFLATEXCMD=${R_PDFLATEXCMD-${PDFLATEX-'/usr/texbin/pdflatex'}}

to

R_PDFLATEXCMD=${R_PDFLATEXCMD-${PDFLATEX-'pdflatex'}}

with similar modifications to the other TeX-related commands.


Patrick

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Re: [R] R 2.9 and XML

2009-05-05 Thread Ian Kennedy

 After I installed R 2.9.0 my XML package cannot load; I get an error
This
 application has failed to start because iconv.dll was not found.
 Re-installing the application may fix this problem. I already
re-installed
 both but the problem persists. Does anyone know what is going on? I would
 appreciate any help. Thanks a lot

I had this problem (after installing XML through install.packages() ) and
worked around it by making a copy of Riconv.dll (in the R-2.9.0/biin
directory) and naming it iconv.dll. The XML package seems to be working
now, but I'd like to know if there's a better way.

Ian Kennedy

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[R] re shape package - use one cast() instead of many

2009-05-05 Thread jwg20

I have a data set that I'm trying to melt and cast in a specific way using
the reshape package. (I'll use the ff_d dataset from reshape so I don't have
to post a toy data set here. )

Lets say I'm looking for the interaction of treatment with each type of
variable in ff_d. Using the command below gets me this. Subject will get a
column and each treatment type by each variable will also get a column with
values for each.

cast(ff_d, subject~treatment+variable)
   subject 1_potato 1_buttery 1_grassy 1_rancid 1_painty 2_potato 2_buttery
  3_painty
13   1818   18   18   18   1818 
   
   18
...

Now, if I want to look at just the  the values for each variable by subject
I can run the following command.
cast(ff_d, subject~variable)
   subject potato buttery grassy rancid painty
13 54  54 54 54 54
...

What I'm wondering now, is run one cast() call and get both of these in one
data.frame? Essentially, the values for each separate condition and
interactions between them? cast() doesn't let me repeat variable names as
that's what I first tried.  Right now, i'm just running two separate cast()
calls and cbinding/merging them together. Is there a better way?  
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Re: [R] re shape package - use one cast() instead of many

2009-05-05 Thread jwg20

Thanks for your help! I wasn't sure what the margins variable did, but I'm
beginning to understand. I'm almost there, but with my data (and with ff_d)
I tried to margin over two variable names, however it only does one of them.
So with ff_d I set margins=c(treatment,variable); however I only ever
get 1_(all) 2_(all) and 3_(all)... never something like (all)_painty. (This
also happens for margins=TRUE)

To further exemplify, with my data I have the call to cast() as:
cast(data.melted,Subject~CogStat+Animacy,mean,margins=c(CogStat,Animacy))

which results in:

  Subject COG_aCOG_i COG_(all)nCOG_anCOG_i nCOG_(all)
1 100  794. 676.5556  728.0833  810.7778  798.4103   800.7292
...

I would like additionally to get (all)_i (all)_a. It seems to just apply the
margin to the first part of the formula before + (i.e. I can change it to
Animacy+CogStat and get a_COG,a_nCOG,   a_(all), etc.)


hadley wrote:
 
 On Tue, May 5, 2009 at 3:03 PM, jwg20 jason.gulli...@gmail.com wrote:

 I have a data set that I'm trying to melt and cast in a specific way
 using
 the reshape package. (I'll use the ff_d dataset from reshape so I don't
 have
 to post a toy data set here. )

 Lets say I'm looking for the interaction of treatment with each type of
 variable in ff_d. Using the command below gets me this. Subject will
 get a
 column and each treatment type by each variable will also get a column
 with
 values for each.

 cast(ff_d, subject~treatment+variable)
   subject 1_potato 1_buttery 1_grassy 1_rancid 1_painty 2_potato
 2_buttery
   3_painty
 1        3       18        18       18       18       18       18      
  18
    18
 ...

 Now, if I want to look at just the  the values for each variable by
 subject
 I can run the following command.
 cast(ff_d, subject~variable)
   subject potato buttery grassy rancid painty
 1        3     54      54     54     54     54
 ...

 What I'm wondering now, is run one cast() call and get both of these in
 one
 data.frame? Essentially, the values for each separate condition and
 interactions between them? cast() doesn't let me repeat variable names as
 that's what I first tried.  Right now, i'm just running two separate
 cast()
 calls and cbinding/merging them together. Is there a better way?
 
 Have a look at the margins argument.
 
 Hadley
 
 
 -- 
 http://had.co.nz/
 
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Re: [R] self organizing map advice for categorical data

2009-05-05 Thread Thomas Petzoldt

George Chen schrieb:

Hello,

Could anybody offer any advice about implementing a Kohonen self organizing map 
for categorical data?  Specifically I am wondering if there are any 
pre-existent packages that can deal with categorical data and/or how one would 
compare the input vector of categoricals with the self organizing map nodes.

Thanks in advance.

George Chen



Yes, there is a very nice one with excellent graphics, see article:

Ron Wehrens, Lutgarde M. C. Buydens (2007) Self- and Super-organizing 
Maps in R: The kohonen Package. Journal of Statistical Software	21(5). 
http://www.jstatsoft.org/v21/i05



Hope it helps

Thomas Petzoldt

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[R] ellipse

2009-05-05 Thread Antonio Lucadamo

Dear all,
I'm using the ellipse package and I would like to verify if the
confidence region that I build with this package can be equivalent to  
an Union Intersection Test. I used different value for the t-statistic  
but I can not find the right equivalence.

Does someone know how to choose the right value?

Thanks a lot.
Antonio





--
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Dipartimento di Scienze Economiche e Metodi Quantitativi
Università del Piemonte Orientale A. Avogadro
via Perrone, 18 - 28100 Novara
fax:  +39 0321 375305
phone:+39 0321 375338
mobile phone: +39 3385973881
skype contact: antonio.lucadamo

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[R] illegal levels in yaImpute() / AsciiGridImpute()

2009-05-05 Thread Seth W Bigelow
I'm using randomForest in yaImpute to create a yai-type object which 
associates L with landscape features. Then I use the sp() package to 
impute L to a landscape consisting of four ascii files) I keep getting the 
message NA's generated due to illegal level(s) when I do the imputation. 
It's probably because one of the landscape features (as, for 
aspect/slope) is stored in numeric form but is treated as a factor when 
the yai object is created. as is also stored in numeric form in the 
ascii grids, of course. I included an xtypes argument in the 
AsciiGridImpute statement, but that did 
not help. Some relevant statements are:

xfiles - list(DEM_10 = dem_10.asc, EASTING = easting.asc, 
NORTHING = northing.asc, as = asp_slop.asc)

AsciiGridImpute(yai_ob, xfiles, outfiles,
xtypes=list(numeric, numeric, integer, character))

Any insights will be appreciated. I'd particularly like to know how to 
gain access to the invisible list, VALUE, containing unexpectedNA's, 
illegal levels, and other information that would help me to troubleshoot 
the issue.

Dr. Seth  W. Bigelow
Biologist, USDA-FS Sierra Nevada Research Center
1731 Research Park Drive, Davis California
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[R] yacas

2009-05-05 Thread Hassan Mohamed
Hi,
as I find problems with yacas package...
is there any R function equivalent to the yacas function Factor ?
the factor function which i found in the R help is not the same.
it doesn't factor an algebraic expression..
thanks
hassan



  
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